CBSE Class 12 Maths 2023 Question Paper 65/2/3 with Solutions
All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/2/3 (2023),
with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.
The position vectors of three consecutive vertices of a parallelogram ABCD are A (4i^+2j^−6k^), B (5i^−3j^+k^) and C (12i^+4j^+5k^). The position vector of D is given by
The corner points of the feasible region of a linear programming problem are (0, 4), (8, 0) and (320,34). If Z = 30x + 24y is the objective function, then (maximum value of Z − minimum value of Z) is equal to
Assertion (A) : If a line makes angles α,β,γ with positive direction of the coordinate axes, then sin2α+sin2β+sin2γ=2. Reason (R) : The sum of squares of the direction cosines of a line is 1.
(A)Both (A) and (R) are true and (R) is the correct explanation of (A).
(B)Both (A) and (R) are true, but (R) is not the correct explanation of (A).
(C)(A) is true, but (R) is false.
(D)(A) is false, but (R) is true.
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Answer: (A) Both (A) and (R) are true and (R) is the correct explanation of (A).
(R) is true: cos2α+cos2β+cos2γ=1.
Then sin2α+sin2β+sin2γ=3−(cos2α+cos2β+cos2γ)=3−1=2.
If equal sides of an isosceles triangle with fixed base 10 cm are increasing at the rate of 4 cm/sec, how fast is the area of triangle increasing at an instant when all sides become equal ?
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Answer:340 cm2/sec, i.e. 3403 cm2/sec
Let each equal side be x cm. Height =x2−25, so area A=21×10×x2−25=5x2−25.
dtdA=x2−255xdtdx.
When all sides are equal, x=10: dtdA=7550×4=53200=340 cm2/sec.
Solve the following Linear Programming problem graphically : Maximize : Z = 3x + 3.5y subject to constraints : x+2y≥240, 3x+1.5y≥270, 1.5x+2y≤310, x≥0, y≥0.
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Answer: Maximum Z = 595 at x = 140, y = 50
Lines: x+2y=240 through (240, 0), (0, 120); 3x+1.5y=270 through (90, 0), (0, 180); 1.5x+2y=310 through (3620,0), (0, 155).
Intersections: first and second lines at (40, 100); first and third at (140, 50); second and third at (20, 140).
The feasible region is the triangle with corners (20, 140), (40, 100), (140, 50) (on the y-axis, y ≥ 180 and y ≤ 155 cannot both hold).
Q313 marksShort AnswerProbabilityNot in current syllabus
Two numbers are selected from first six even natural numbers at random without replacement. If X denotes the greater of two numbers selected, find the probability distribution of X.
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Answer: X = 4, 6, 8, 10, 12 with P = 151,152,153,154,155
The numbers are 2, 4, 6, 8, 10, 12; number of ways of choosing two is 6C2=15.
X = greater number can be 4, 6, 8, 10, 12.
Pairs with greater number 4: 1; 6: 2; 8: 3; 10: 4; 12: 5.
A fair coin and an unbiased die are tossed. Let A be the event, “Head appears on the coin” and B be the event, “3 comes on the die”. Find whether A and B are independent events or not.
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Answer: A and B are independent.
Sample space has 2 × 6 = 12 equally likely outcomes.
A function f: [−4, 4] → [0, 4] is given by f(x)=16−x2. Show that f is an onto function but not a one-one function. Further, find all possible values of ‘a’ for which f(a)=7.
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Answer: f is onto, not one-one; a = ±3
Not one-one: f(−4)=0=f(4) but −4=4.
Onto: for any y∈[0,4], take x=16−y2∈[0,4]⊂[−4,4]; then f(x)=16−(16−y2)=y.
So every element of [0, 4] has a pre-image; f is onto.
Find the equations of the diagonals of the parallelogram PQRS whose vertices are P(4, 2, −6), Q(5, −3, 1), R(12, 4, 5) and S(11, 9, −2). Use these equations to find the point of intersection of diagonals.
A line l passes through point (−1, 3, −2) and is perpendicular to both the lines 1x=2y=3z and −3x+2=2y−1=5z+1. Find the vector equation of the line l. Hence, obtain its distance from origin.
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Answer:r=(−i^+3j^−2k^)+λ(2i^−7j^+4k^); distance =695 units
Direction of l∥(i^+2j^+3k^)×(−3i^+2j^+5k^)=4i^−14j^+8k^∥2i^−7j^+4k^.
l: r=(−i^+3j^−2k^)+λ(2i^−7j^+4k^).
Distance of O from l=∣b∣∣a×b∣ with a=−i^+3j^−2k^, b=2i^−7j^+4k^.
Recent studies suggest that roughly 12% of the world population is left handed. Depending upon the parents, the chances of having a left handed child are as follows : A : When both father and mother are left handed : Chances of left handed child is 24%. B : When father is right handed and mother is left handed : Chances of left handed child is 22%. C : When father is left handed and mother is right handed : Chances of left handed child is 17%. D : When both father and mother are right handed : Chances of left handed child is 9%. Assuming that P(A) = P(B) = P(C) = P(D) = 41 and L denotes the event that child is left handed. Based on the above information, answer the following questions : (i) Find P(L/C) (1) (ii) Find P(L/A) (1) (iii) Find P(A/L) (2) OR Find the probability that a randomly selected child is left handed given that exactly one of the parents is left handed. (2)
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Answer: (i) 0.17 (ii) 0.76 (iii) 31; OR 0.195
(i) P(L/C) = 17% = 0.17.
(ii) P(L/A) = 1 - 0.24 = 0.76.
(iii) P(L) =41(0.24+0.22+0.17+0.09)=40.72=0.18.
P(A/L) =0.1841×0.24=0.180.06=31.
OR: exactly one parent left handed is B ∪ C, with P(B) = P(C).
P(L/B ∪ C) =41+4141(0.22)+41(0.17)=20.39=0.195.
Engine displacement is the measure of the cylinder volume swept by all the pistons of a piston engine. The piston moves inside the cylinder bore The cylinder bore in the form of circular cylinder open at the top is to be made from a metal sheet of area 75π cm2. Based on the above information, answer the following questions : (i) If the radius of cylinder is r cm and height is h cm, then write the volume V of cylinder in terms of radius r. (1) (ii) Find drdV. (1) (iii) Find the radius of cylinder when its volume is maximum. (2) OR For maximum volume, h > r. State true or false and justify. (2)
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Answer: (i) V=2π(75r−r3) (ii) drdV=2π(75−3r2) (iii) r = 5 cm; OR False, h = r = 5 cm
Open cylinder: 2πrh+πr2=75π, so h=2r75−r2.
(i) V=πr2h=2πr(75−r2)=2π(75r−r3).
(ii) drdV=2π(75−3r2).
(iii) drdV=0 gives r2=25, r = 5; dr2d2V=−3πr<0, so V is maximum at r = 5 cm.
OR: at r = 5, h=1075−25=5, so h = r; the statement h > r is false.
The use of electric vehicles will curb air pollution in the long run. The use of electric vehicles is increasing every year and estimated electric vehicles in use at any time t is given by the function V : V(t)=51t3−25t2+25t−2 where t represents the time and t = 1, 2, 3.... corresponds to year 2001, 2002, 2003, ....... respectively. Based on the above information, answer the following questions : (i) Can the above function be used to estimate number of vehicles in the year 2000 ? Justify. (2) (ii) Prove that the function V(t) is an increasing function. (2)
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Answer: (i) No, the year 2000 corresponds to t = 0 and V(0) = −2 < 0, which is impossible for a number of vehicles (ii) Proved.
(i) Year 2000 corresponds to t = 0. V(0) = −2, a negative number of vehicles, which is not possible; so the function cannot be used for 2000.
(ii) V′(t)=53t2−5t+25.
Its discriminant is 25−4×53×25=25−60=−35<0 and the leading coefficient 53>0.
So V′(t)>0 for all t; hence V(t) is an increasing function.