Relations and Functions: 1 mark Questions (CBSE Class 12)
5 different 1 mark questions on Relations and Functions from CBSE Class 12 Maths board exams 2026, newest first.
A relation R on set A={1,2,3} defined as R={(1,1),(2,2),(1,2)} is
- (A)Reflexive only
- (B)Reflexive and Transitive
- (C)Symmetric and Transitive
- (D)Transitive only
Show answer & solution
Answer: (D) Transitive only
- (3,3)∈/R, so R is not reflexive.
- (1,2)∈R but (2,1)∈/R, so R is not symmetric.
- The only pairs that chain are (1,1),(1,2) giving (1,2)∈R and (1,2),(2,2) giving (1,2)∈R, so R is transitive.
- Hence R is transitive only.
A relation R on set A={1,2,3} defined as R={(1,2),(2,1),(2,2)} is
- (A)Reflexive only
- (B)Reflexive and Transitive
- (C)Symmetric and Transitive
- (D)Symmetric only
Show answer & solution
Answer: (D) Symmetric only
- (1,1)∈/R, so R is not reflexive.
- (1,2) and (2,1) both belong to R and (2,2) is its own reverse, so R is symmetric.
- (1,2),(2,1)∈R but (1,1)∈/R, so R is not transitive.
- Hence R is symmetric only.
A relation R on set A={1,2,3} is defined as R={(1,3),(3,3),(1,1),(2,2),(3,1)} is
- (A)only reflexive and symmetric
- (B)reflexive only
- (C)only reflexive and transitive
- (D)reflexive, symmetric and transitive
Show answer & solution
Answer: (D) reflexive, symmetric and transitive
- (1,1),(2,2),(3,3)∈R: reflexive.
- (1,3)∈R and (3,1)∈R: symmetric.
- (1,3),(3,1)⇒(1,1)∈R; (3,1),(1,3)⇒(3,3)∈R; all other chains involve a pair (a,a) and give a pair already in R: transitive.
- R is reflexive, symmetric and transitive.
Assertion (A) : A function f:N→N given by f(x)=x3+2,∀x∈N is one-one but not onto.
Reason (R) : Since ∀y∈N (Codomain), there does not exist x=(y−2)1/3 in N (Domain) such that f(x)=x3+2=y.
- (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- (C)Assertion (A) is true, but Reason (R) is false.
- (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
- x13+2=x23+2⇒x1=x2, so f is one-one.
- y=1 (or 2) has no pre-image in N, so f is not onto. A is true.
- R says that for every y∈N no such x exists, which is false: for y=3, x=1∈N.
- So A is true but R is false.
Assertion (A): A relation R on the set {1, 2, 3} defined as R = {(1, 1), (1, 2), (2, 1), (2, 2), (3, 3)} is an equivalence relation.
Reason (R): A relation that is reflexive, symmetric and transitive is an equivalence relation.
- (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- (C)Assertion (A) is true, but Reason (R) is false.
- (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both A and R are true and R is the correct explanation of A.
- Reflexive: (1, 1), (2, 2), (3, 3) are in R.
- Symmetric: (1, 2) and (2, 1) are both in R.
- Transitive: (1, 2), (2, 1) give (1, 1) in R; (2, 1), (1, 2) give (2, 2) in R; all other cases are trivial.
- So R is an equivalence relation; R is the definition of an equivalence relation and explains A.
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