Q273 marksShort AnswerMatricesCBSE 2026 · 65/4/1 If A=310240005, then compute A2−7A+10I. Show answer & solution Answer: A2−7A+10I=O (the 3×3 zero matrix) A2=1170141800025.7A=2170142800035, 10I=100001000010.A2−7A+10I=000000000.
Q273 marksShort AnswerMatricesCBSE 2026 · 65/4/2 If A=122212221, then compute A2−4A−5I. Show answer & solution Answer: A2−4A−5I=O (the 3×3 zero matrix) A2=988898889.4A=488848884, 5I=500050005.A2−4A−5I=000000000.
Q273 marksShort AnswerMatricesCBSE 2026 · 65/4/3 If A=22101−1130, then compute A2−5A+4I. Show answer & solution Answer: −1−1−5−1−34−3−102 A2=590−1−2−125−2.5A=1010505−55150, 4I=400040004.A2−5A+4I=−1−1−5−1−34−3−102.