CBSE Class 12 Maths 2025 Question Paper 65/4/2 with Solutions
All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/4/2 (2025),
with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.
The corner points of the feasible region of a Linear Programming Problem are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). If Z = ax + by; (a, b > 0) be the objective function, and maximum value of Z is obtained at (0, 2) and (3, 0), then the relation between a and b is :
(A)a = b
(B)a = 3b
(C)b = 6a
(D)3a = 2b
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Answer: (D) 3a = 2b
Equal values at the two points: Z(0,2)=2b and Z(3,0)=3a.
Assertion (A): If A and B are two events such that P(A∩B)=0, then A and B are independent events. Reason (R): Two events are independent if the occurrence of one does not effect the occurrence of the other.
(A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
(B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
(C)Assertion (A) is true, but Reason (R) is false.
(D)Assertion (A) is false, but Reason (R) is true.
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Answer: (D) Assertion (A) is false, but Reason (R) is true.
Independence needs P(A∩B)=P(A)P(B). If P(A∩B)=0 with P(A),P(B)>0, then P(A)P(B)=0, so A and B are not independent (they are mutually exclusive). A is false.
Assertion (A): In a Linear Programming Problem, if the feasible region is empty, then the Linear Programming Problem has no solution. Reason (R): A feasible region is defined as the region that satisfies all the constraints.
(A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
(B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
(C)Assertion (A) is true, but Reason (R) is false.
(D)Assertion (A) is false, but Reason (R) is true.
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Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
R is the definition of the feasible region, so R is true.
If this region is empty, no point satisfies all constraints, so there is no feasible (hence no optimal) solution. A is true and follows from R.
Q26 (OR) (OR)3 marksShort AnswerProbabilityNot in current syllabus
A coin is tossed twice. Let X be a random variable defined as number of heads minus number of tails. Obtain the probability distribution of X and also find its mean.
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Answer: X: – 2, 0, 2 with P(X): 41,21,41; mean = 0
Outcomes: HH gives X = 2; HT, TH give X = 0; TT gives X = –2.
Let A = {1, 2, 3} and B = {4, 5, 6}. A relation R from A to B is defined as R={(x,y):x+y=6,x∈A,y∈B}. (i) Write all elements of R. (ii) Is R a function ? Justify. (iii) Determine domain and range of R.
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Answer: (i) R = {(1, 5), (2, 4)} (ii) No, 3 ∈ A has no image (iii) Domain = {1, 2}, Range = {4, 5}
(i) x = 1 gives y = 5 ∈ B; x = 2 gives y = 4 ∈ B; x = 3 gives y = 3 ∉ B. So R = {(1, 5), (2, 4)}.
(ii) R is not a function from A to B, because the element 3 of A is not related to any element of B.
Consider the experiment of tossing a coin. If the coin shows head, toss it again; but if it shows a tail, then throw a die. Find the conditional probability of the event A : ‘the die shows a number greater than 3’ given that B : ‘there is at least one tail’.
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Answer:31
Sample space: HH, HT (each probability 41) and T1, T2, ..., T6 (each probability 121).
B = {HT, T1, ..., T6}: P(B)=41+126=43.
A∩B = {T4, T5, T6}: P(A∩B)=123=41.
P(A∣B)=3/41/4=31.
OR
Q29 (OR) (OR)3 marksShort AnswerProbabilityNot in current syllabus
The probability distribution of a random variable X is given as : X: 1, 2, 3, 2λ, 3λ, 4λ P(X): 3011, 151, 101, 103, 151, 101 (i) Calculate λ, if E(X) = 3.2. (2) (ii) Find P(X > 1). (1)
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Answer: (i) λ=2 (ii) 3019
(i) E(X)=3011+152+103+2λ⋅103+3λ⋅151+4λ⋅101.
=3024+3036λ. Setting this equal to 3.2=3096 gives 36λ=72, so λ=2.
(ii) With λ=2 the values are 1, 2, 3, 4, 6, 8, so P(X>1)=1−P(X=1)=1−3011=3019.
The relation between the height of the plant (y cm) with respect to exposure to sunlight is governed by the equation y=4x−21x2, where x is the number of days exposed to sunlight. (i) Find the rate of growth of the plant with respect to sunlight. (2) (ii) In how many days will the plant attain its maximum height ? What is the maximum height ? (3)
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Answer: (i) dxdy=4−x cm per day (ii) 4 days; maximum height 8 cm
(i) Rate of growth =dxdy=4−x.
(ii) dxdy=0⇒x=4; dx2d2y=−1<0, so y is maximum at x = 4.
Maximum height =4(4)−21(16)=16−8=8 cm, attained in 4 days.
Show that the area of a parallelogram whose diagonals are represented by a and b is given by 21∣a×b∣. Also find the area of a parallelogram whose diagonals are 2i^−j^+k^ and i^+3j^−k^.
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Answer: Proved; area =262 sq. units
Let the adjacent sides be p,q; then a=p+q, b=q−p (or p−q).
Find the equation of a line in vector and cartesian form which passes through the point (1, 2, – 4) and is perpendicular to the lines 3x−8=−16y+19=7z−10, and r=15i^+29j^+5k^+μ(3i^+8j^−5k^).
Some students are having a misconception while comparing decimals. For example, a student may mention that 78.56 > 78.9 as 7856 > 789. In order to assess this concept, a decimal comparison test was administered to the students of class VI through the following question : In the recently held Sports Day in the school, 5 students participated in a javelin throw competition. The distances to which they have thrown the javelin are shown below in the table : Name of student: Ajay, Bijoy, Kartik, Dinesh, Devesh Distance of javelin (in meters): 47.7, 47.07, 43.09, 43.9, 45.2 The students were asked to identify who has thrown the javelin the farthest. Based on the test attempted by the students, the teacher concludes that 40% of the students have the misconception in the concept of decimal comparison and the rest do not have the misconception. 80% of the students having misconception answered Bijoy as the correct answer in the paper. 90% of the students who are identified with not having misconception, did not answer Bijoy as their answer. On the basis of the above information, answer the following questions : (i) What is the probability of a student not having misconception but still answers Bijoy in the test ? (1) (ii) What is the probability that a randomly selected student answers Bijoy as his answer in the test ? (1) (iii) What is the probability that a student who answered as Bijoy is having misconception ? (2) OR (iii) What is the probability that a student who answered as Bijoy is amongst students who do not have the misconception ? (2)
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Answer: (i) 0.06 (ii) 0.38 (iii) 1916; OR 193
Let M: has misconception, N: no misconception, B: answers Bijoy. P(M) = 0.4, P(N) = 0.6, P(B|M) = 0.8, P(B|N) = 1 – 0.9 = 0.1.
An engineer is designing a new metro rail network in a city. Initially, two metro lines, Line A and Line B, each consisting of multiple stations are designed. The track for Line A is represented by l1:3x−2=−2y+1=4z−3, while the track for Line B is represented by l2:2x−1=1y−3=−3z+2. Based on the above information, answer the following questions : (i) Find whether the two metro tracks are parallel. (1) (ii) Solar panels are to be installed on the rooftop of the metro stations. Determine the equation of the line representing the placement of solar panels on the rooftop of Line A’s stations, given that panels are to be positioned parallel to Line A’s track (l1) and pass through the point (1, – 2, – 3). (1) (iii) To connect the stations, a pedestrian pathway perpendicular to the two metro lines is to be constructed which passes through point (3, 2, 1). Determine the equation of the pedestrian walkway. (2) OR (iii) Find the shortest distance between Line A and Line B. (2)
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Answer: (i) Not parallel (ii) 3x−1=−2y+2=4z+3 (iii) 2x−3=17y−2=7z−1; OR 34231=33831 units
(i) Direction ratios 3, –2, 4 and 2, 1, –3 are not proportional (23=1−2), so the tracks are not parallel.
(ii) Line through (1, –2, –3) with direction 3, –2, 4: 3x−1=−2y+2=4z+3.
During a heavy gaming session, the temperature of a student’s laptop processor increases significantly. After the session, the processor begins to cool down, and the rate of cooling is proportional to the difference between the processor’s temperature and the room temperature (25∘C). Initially the processor’s temperature is 85∘C. The rate of cooling is defined by the equation dtd(T(t))=−k(T(t)−25), where T(t) represents the temperature of the processor at time t (in minutes) and k is a constant. Based on the above information, answer the following questions : (i) Find the expression for temperature of processor, T(t) given that T(0)=85∘C. (2) (ii) How long will it take for the processor’s temperature to reach 40∘C ? Given that k = 0.03, loge4=1.3863. (2)
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Answer: (i) T(t)=25+60e−kt (ii) about 46.21 minutes