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CBSE Class 12 Maths 2024 Question Paper 65/2/1 with Solutions

All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/2/1 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 65/1/1Set 65/1/2Set 65/1/3Set 65/2/1Set 65/2/2Set 65/2/3Set 65/3/1Set 65/3/2Set 65/3/3Set 65/4/1Set 65/4/2Set 65/4/3Set 65/5/1Set 65/5/2Set 65/5/3
Q11 markMCQMatrices

If the sum of all the elements of a scalar matrix is 9, then the product of all its elements is :

  1. (A)0
  2. (B)9
  3. (C)27
  4. (D)729
Show answer & solution
Answer: (A) 0
  1. A scalar matrix has equal diagonal elements k and all other elements 0.
  2. Sum of elements = 3k = 9, so k = 3.
  3. The six off-diagonal elements are 0, so the product of all elements is 0.
Also asked in: 2024 65/2/2, 2024 65/2/3

Let be defined as , where is the set of all non-negative real numbers. Then, f is :

  1. (A)one-one
  2. (B)onto
  3. (C)bijective
  4. (D)neither one-one nor onto
Show answer & solution
Answer: (C) bijective
  1. for , so f is strictly increasing on and hence one-one.
  2. and as ; f is continuous, so its range is , which equals the codomain.
  3. So f is onto as well, i.e. bijective.
Also asked in: 2024 65/2/3
Q31 markMCQDeterminants

If , then the value of k is :

  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)4
Show answer & solution
Answer: (D) 4
  1. Take a, b, c common from columns 1, 2, 3: determinant .
  2. Expanding: .
  3. So the determinant is and k = 4.
Also asked in: 2024 65/2/2, 2024 65/2/3

The number of points of discontinuity of is :

  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)infinite
Show answer & solution
Answer: (B) 1
  1. Each piece is continuous on its own interval, so only x = −3 and x = 3 need checking.
  2. At x = −3: LHL , RHL , f(−3) = 6, so f is continuous.
  3. At x = 3: LHL , RHL , so f is discontinuous.
  4. Number of points of discontinuity = 1.
Also asked in: 2024 65/2/2, 2024 65/2/3

The function is :

  1. (A)strictly decreasing on R
  2. (B)strictly increasing on R
  3. (C)neither strictly increasing nor strictly decreasing on R
  4. (D)strictly decreasing on
Show answer & solution
Answer: (B) strictly increasing on R
  1. for all real x.
  2. So f is strictly increasing on R.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q61 markMCQIntegrals

is equal to :

  1. (A)
  2. (B)Zero (0)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B) Zero (0)
  1. Let I be the integral. Using with :
  2. .
  3. So 2I = 0, i.e. I = 0.

The differential equation will not be a homogeneous differential equation, if F(x, y) is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. F(x, y) gives a homogeneous equation when (degree zero).
  2. Options (B), (C), (D) depend only on y/x or x/y, so they are homogeneous of degree zero.
  3. In (A), in general, so (A) is not homogeneous.
Also asked in: 2024 65/2/3
Q81 markMCQVector Algebra

For any two vectors and , which of the following statements is always true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. and .
  2. So always (equality when the vectors are in the same direction or one is zero).
Also asked in: 2024 65/2/2, 2024 65/2/3

The coordinates of the foot of the perpendicular drawn from the point (0, 1, 2) on the x-axis are given by :

  1. (A)(1, 0, 0)
  2. (B)(2, 0, 0)
  3. (C)
  4. (D)(0, 0, 0)
Show answer & solution
Answer: (D) (0, 0, 0)
  1. The foot of the perpendicular from (a, b, c) on the x-axis is (a, 0, 0).
  2. Here a = 0, so the foot is (0, 0, 0).
Also asked in: 2024 65/2/2, 2024 65/2/3
Q101 markMCQLinear Programming

The common region determined by all the constraints of a linear programming problem is called :

  1. (A)an unbounded region
  2. (B)an optimal region
  3. (C)a bounded region
  4. (D)a feasible region
Show answer & solution
Answer: (D) a feasible region
  1. The region common to all the constraints (including non-negativity) is, by definition, the feasible region.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q111 markMCQProbability

Let E be an event of a sample space S of an experiment, then

  1. (A)
  2. (B)P(E)
  3. (C)1
  4. (D)0
Show answer & solution
Answer: (C) 1
  1. .
Also asked in: 2024 65/2/2, 2024 65/2/3
Q121 markMCQMatrices

If be a matrix, where , then which of the following is false ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. , true.
  2. , , sum , true.
  3. , , so is false and is true.
Also asked in: 2024 65/2/3

The derivative of w.r.t. x is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .

The degree of the differential equation is :

  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)not defined
Show answer & solution
Answer: (D) not defined
  1. The equation contains , so it is not a polynomial in the derivatives.
  2. Hence its degree is not defined.
Also asked in: 2024 65/2/2
Q151 markMCQVector Algebra

The unit vector perpendicular to both vectors and is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. Unit vector .
Also asked in: 2024 65/2/2, 2024 65/2/3

Direction ratios of a vector parallel to line are :

  1. (A)2, −1, 6
  2. (B)2, 1, 6
  3. (C)2, 1, 3
  4. (D)2, −1, 3
Show answer & solution
Answer: (D) 2, −1, 3
  1. Write the line in standard form: .
  2. So the direction ratios are 2, −1, 3.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q171 markMCQMatrices

If and , then the value of k is :

  1. (A)1
  2. (B)2
  3. (C)0
  4. (D)−2
Show answer & solution
Answer: (B) 2
  1. has top-left block and last diagonal entry 1.
  2. So and k = 2.
Also asked in: 2024 65/2/2

If a line makes an angle of with the positive direction of x-axis, with the positive direction of y-axis, then the angle which it makes with the positive direction of z-axis is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. .
  2. , so .
  3. .
Also asked in: 2024 65/2/2, 2024 65/2/3
Q191 markAssertion–ReasonMatrices

Assertion (A) : For any symmetric matrix A, is a skew-symmetric matrix.
Reason (R) : A square matrix P is skew-symmetric if .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. since .
  2. So is symmetric, not skew-symmetric (in general); the Assertion is false.
  3. The Reason is the definition of a skew-symmetric matrix, so it is true.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q201 markAssertion–ReasonVector Algebra

Assertion (A) : For two non-zero vectors and , .
Reason (R) : For two non-zero vectors and , .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. The dot product is commutative, so the Assertion is true.
  2. , which is not equal to unless ; the Reason is false.
Also asked in: 2024 65/2/2
Q212 marksVery Short AnswerInverse Trigonometric Functions

Find the value of .

Show answer & solution
Answer:
  1. .
  2. .
  3. , and .
  4. Sum .
Also asked in: 2024 65/2/2
OR
Q21 (OR) (OR)2 marksVery Short AnswerInverse Trigonometric Functions

Find the domain of the function . Also, find its range.

Show answer & solution
Answer: Domain ; range
  1. We need , i.e. .
  2. So : domain .
  3. On this domain takes every value in [−1, 1].
  4. So the range is .
Also asked in: 2024 65/2/2
Q222 marksVery Short AnswerContinuity and Differentiability

If , then find the value of at .

Show answer & solution
Answer:
  1. Near , is near where , so .
  2. .
  3. .
  4. .
Also asked in: 2024 65/2/3
OR
Q22 (OR) (OR)2 marksVery Short AnswerContinuity and Differentiability

If , then prove that .

Show answer & solution
Answer: Proved.
  1. Let , so with , where .
  2. Then .
  3. .
  4. So , i.e. .
Also asked in: 2024 65/2/3
Q232 marksVery Short AnswerApplication of Derivatives

If M and m denote the local maximum and local minimum values of the function respectively, find the value of .

Show answer & solution
Answer:
  1. gives .
  2. : , so x = −1 is a point of local maximum, M = f(−1) = −2.
  3. , so x = 1 is a point of local minimum, m = f(1) = 2.
  4. .
Also asked in: 2024 65/2/2, 2024 65/2/3
Q242 marksVery Short AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Divide numerator and denominator by : integrand .
  2. Put , .
  3. Integral .
Also asked in: 2024 65/2/3
Q252 marksVery Short AnswerApplication of Derivatives

Show that is strictly increasing in its domain.

Show answer & solution
Answer: Proved.
  1. The domain of f is R.
  2. .
  3. (AM ≥ GM) and .
  4. So for all real x, hence f is strictly increasing in its domain.
Also asked in: 2024 65/2/2
Q263 marksShort AnswerContinuity and Differentiability

If and , prove that .

Show answer & solution
Answer: Proved.
  1. and .
  2. .
  3. .
  4. .
OR
Q26 (OR) (OR)3 marksShort AnswerContinuity and Differentiability

Show that :

Show answer & solution
Answer: Proved.
  1. For x > 0, |x| = x, so .
  2. For x < 0, |x| = −x, so .
  3. (Equivalently, and .)
  4. Hence for .
Q273 marksShort AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. Multiply inside by : .
  2. .
  3. The second integrand is odd, so its integral is 0.
  4. .
Also asked in: 2024 65/2/2, 2024 65/2/3
OR
Q27 (OR) (OR)3 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Put , : integral .
  2. .
  3. Integral .
Also asked in: 2024 65/2/2, 2024 65/2/3
Q283 marksShort AnswerDifferential Equations

Find the particular solution of the differential equation given by ; y = 2, when x = 1.

Show answer & solution
Answer: (i.e. )
  1. , a homogeneous equation. Put y = vx.
  2. , so .
  3. gives , i.e. .
  4. x = 1, y = 2: , so C = −1.
  5. , i.e. .
Also asked in: 2024 65/2/2, 2024 65/2/3
OR
Q28 (OR) (OR)3 marksShort AnswerDifferential Equations

Find the general solution of the differential equation :

Show answer & solution
Answer:
  1. , i.e. , linear in x.
  2. I.F. (taking y > 0).
  3. .
  4. General solution: .
Also asked in: 2024 65/2/2, 2024 65/2/3
Q293 marksShort AnswerVector Algebra

The position vectors of vertices of are , and . Find all the angles of .

Show answer & solution
Answer: , ,
  1. , , .
  2. , , .
  3. .
  4. .
  5. , so .
  6. So , , .
Also asked in: 2024 65/2/3
Q303 marksShort AnswerProbabilityNot in current syllabus

A pair of dice is thrown simultaneously. If X denotes the absolute difference of the numbers appearing on top of the dice, then find the probability distribution of X.

Show answer & solution
Answer: X: 0, 1, 2, 3, 4, 5 with P(X):
  1. There are 36 equally likely outcomes; X can be 0, 1, 2, 3, 4, 5.
  2. X = 0: 6 outcomes; X = 1: 10; X = 2: 8; X = 3: 6; X = 4: 4; X = 5: 2.
  3. P(X = 0) = 6/36 = 1/6, P(X = 1) = 10/36 = 5/18, P(X = 2) = 8/36 = 2/9.
  4. P(X = 3) = 6/36 = 1/6, P(X = 4) = 4/36 = 1/9, P(X = 5) = 2/36 = 1/18.
  5. Check: the probabilities add to 1.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q313 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Put , ; then .
  2. Integral .
  3. By parts: .
  4. (put t = sin θ).
  5. So .
  6. Integral .
Also asked in: 2024 65/2/2
Q325 marksLong AnswerRelations and Functions

Show that a function defined by is neither one-one nor onto. Further, find set A so that the given function becomes an onto function.

Show answer & solution
Answer: Proved; A = [−1, 1]
  1. and , but ; so f is not one-one.
  2. Let . Then .
  3. For y ≠ 0, real x exists only if , i.e. ; y = 0 comes from x = 0.
  4. So the range of f is [−1, 1]; e.g. 2 ∈ R has no pre-image, so f is not onto R.
  5. Taking A = [−1, 1] (the range), is onto.
Also asked in: 2024 65/2/2
OR
Q32 (OR) (OR)5 marksLong AnswerRelations and Functions

A relation R is defined on (where N is the set of natural numbers) as :

Show that R is an equivalence relation.

Show answer & solution
Answer: Proved.
  1. Reflexive: for any (a, b), a − a = 0 = b − b, so (a, b) R (a, b).
  2. Symmetric: if (a, b) R (c, d), then a − c = b − d, so c − a = d − b, i.e. (c, d) R (a, b).
  3. Transitive: if (a, b) R (c, d) and (c, d) R (e, f), then a − c = b − d and c − e = d − f.
  4. Adding, a − e = b − f, so (a, b) R (e, f).
  5. Hence R is an equivalence relation.
Also asked in: 2024 65/2/2
Q335 marksLong AnswerThree Dimensional Geometry

Find the equation of the line which bisects the line segment joining points A(2, 3, 4) and B(4, 5, 8) and is perpendicular to the lines and .

Show answer & solution
Answer:
  1. The line passes through the mid-point of AB: (3, 4, 6).
  2. Its direction is perpendicular to and .
  3. .
  4. Direction ratios: 2, 3, 6.
  5. Equation: .
Q345 marksLong AnswerDeterminants

Solve the following system of equations, using matrices :
, ,
where

Show answer & solution
Answer: x = 2, y = 3, z = 5
  1. Put : AX = B with , , .
  2. .
  3. Cofactors: ; ; .
  4. .
  5. , so x = 2, y = 3, z = 5.
Also asked in: 2024 65/2/3
OR
Q34 (OR) (OR)5 marksLong AnswerMatrices

If , show that .

Show answer & solution
Answer: Proved.
  1. , and .
  2. and .
  3. .
  4. and .
  5. So .
Also asked in: 2024 65/2/3
Q355 marksLong AnswerApplication of Integrals

If denotes the area of region bounded by , x = 1 and x-axis in the first quadrant and denotes the area of region bounded by , x = 4, find .

Show answer & solution
Answer:
  1. .
  2. The region bounded by and x = 4 lies on both sides of the x-axis (symmetric).
  3. .
  4. .
Also asked in: 2024 65/2/2, 2024 65/2/3
Q364 marksCase StudyApplication of Derivatives

Overspeeding increases fuel consumption and decreases fuel economy as a result of tyre rolling friction and air resistance. While vehicles reach optimal fuel economy at different speeds, fuel mileage usually decreases rapidly at speeds above 80 km/h.
The relation between fuel consumption F (l/100 km) and speed V (km/h) under some constraints is given as .
On the basis of the above information, answer the following questions :
(i) Find F, when V = 40 km/h. (1)
(ii) Find . (1)
(iii) (a) Find the speed V for which fuel consumption F is minimum. (2)
OR
(iii) (b) Find the quantity of fuel required to travel 600 km at the speed V at which . (2)

Diagram for CBSE 2024 Class 12 Maths question 36
Show answer & solution
Answer: (i) F = 7.2 l/100 km (ii) (iii)(a) V = 62.5 km/h OR (iii)(b) 37.2 litres
  1. (i) l/100 km.
  2. (ii) .
  3. (iii)(a) gives V = 62.5; , so F is minimum at V = 62.5 km/h.
  4. (iii)(b) gives , V = 60 km/h.
  5. F(60) = 7.2 − 15 + 14 = 6.2 l/100 km.
  6. Fuel for 600 km = 6 × 6.2 = 37.2 litres.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q374 marksCase StudyLinear Programming

The month of September is celebrated as the Rashtriya Poshan Maah across the country. Following a healthy and well-balanced diet is crucial in order to supply the body with the proper nutrients it needs. A balanced diet also keeps us mentally fit and promotes improved level of energy.
A dietician wishes to minimize the cost of a diet involving two types of foods, food X (x kg) and food Y (y kg) which are available at the rate of ₹ 16/kg and ₹ 20/kg respectively. The feasible region satisfying the constraints is shown in Figure-2.
On the basis of the above information, answer the following questions :
(i) Identify and write all the constraints which determine the given feasible region in Figure-2. (2)
(ii) If the objective is to minimize cost Z = 16x + 20y, find the values of x and y at which cost is minimum. Also, find minimum cost assuming that minimum cost is possible for the given unbounded region. (2)

Diagram for CBSE 2024 Class 12 Maths question 37
Show answer & solution
Answer: (i) , , , , (ii) x = 2, y = 4; minimum cost ₹ 112
  1. (i) The shaded region lies on the side away from the origin of the lines x + 2y = 10, x + y = 6 and 3x + y = 8, in the first quadrant.
  2. Constraints: , , , , .
  3. (ii) Corner points: D(0, 8): Z = 160; C(1, 5): Z = 16 + 100 = 116; B(2, 4): Z = 32 + 80 = 112; A(10, 0): Z = 160.
  4. Smallest value is 112 at B(2, 4). The half-plane 16x + 20y < 112, i.e. 4x + 5y < 28, has no point in common with the feasible region, so 112 is the minimum.
  5. Minimum cost ₹ 112 when x = 2 kg and y = 4 kg.
Also asked in: 2024 65/2/2, 2024 65/2/3
Q384 marksCase StudyProbability

Airplanes are by far the safest mode of transportation when the number of transported passengers are measured against personal injuries and fatality totals.
Previous records state that the probability of an airplane crash is 0.00001%. Further, there are 95% chances that there will be survivors after a plane crash. Assume that in case of no crash, all travellers survive.
Let be the event that there is a plane crash and be the event that there is no crash. Let A be the event that passengers survive after the journey.
On the basis of the above information, answer the following questions :
(i) Find the probability that the airplane will not crash. (1)
(ii) Find . (1)
(iii) (a) Find P(A). (2)
OR
(iii) (b) Find . (2)

Show answer & solution
Answer: (i) 0.9999999 (ii) 1.95 (iii)(a) 0.999999995 OR (iii)(b) (about 0.9999999)
  1. , so (i) .
  2. (ii) , , so the sum is 1.95.
  3. (iii)(a) .
  4. (iii)(b) .
Also asked in: 2024 65/2/2, 2024 65/2/3
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