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CBSE Class 12 Maths 2024 Question Paper 65/5/2 with Solutions

All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/5/2 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 65/1/1Set 65/1/2Set 65/1/3Set 65/2/1Set 65/2/2Set 65/2/3Set 65/3/1Set 65/3/2Set 65/3/3Set 65/4/1Set 65/4/2Set 65/4/3Set 65/5/1Set 65/5/2Set 65/5/3

Derivative of with respect to is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Let , .
  2. , .
  3. .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q21 markMCQDeterminants

If A is a square matrix of order 2 and , then value of is :

  1. (A)–50
  2. (B)–10
  3. (C)10
  4. (D)50
Show answer & solution
Answer: (A) –50
  1. For order 2, , and .
  2. .

The function has a local minima at x equal to :

  1. (A)2
  2. (B)1
  3. (C)0
  4. (D)–2
Show answer & solution
Answer: (A) 2
  1. .
  2. ; , .
  3. So f has a local minimum at .
Also asked in: 2024 65/5/1, 2024 65/5/3

Given a curve and x increases at the rate of 2 units per second. The rate at which the slope of the curve is changing, when is :

  1. (A)–60 units/sec
  2. (B)60 units/sec
  3. (C)–70 units/sec
  4. (D)–140 units/sec
Show answer & solution
Answer: (A) –60 units/sec
  1. Slope .
  2. .
  3. The slope is changing at –60 units/sec.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q51 markMCQMatrices

The product of matrix P and Q is equal to a diagonal matrix. If the order of matrix Q is 3 × 2, then order of matrix P is :

  1. (A)2 × 2
  2. (B)3 × 3
  3. (C)2 × 3
  4. (D)3 × 2
Show answer & solution
Answer: (C) 2 × 3
  1. A diagonal matrix is square.
  2. For PQ to exist, P must have 3 columns; then PQ has order (rows of P) × 2.
  3. PQ square means P has 2 rows, so P is 2 × 3.

A function defined as is :

  1. (A)injective but not surjective.
  2. (B)surjective but not injective.
  3. (C)both injective and surjective.
  4. (D)neither injective nor surjective.
Show answer & solution
Answer: (D) neither injective nor surjective.
  1. but , so f is not injective.
  2. , so the range is ; for example 0 has no pre-image.
  3. So f is not surjective either: neither injective nor surjective.
Also asked in: 2024 65/5/1, 2024 65/5/3

If , then is equal to :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. means , a constant.
  2. Differentiating constant: .
  3. .
Q81 markMCQMatrices

If inverse of matrix is the matrix , then value of is :

  1. (A)–4
  2. (B)1
  3. (C)3
  4. (D)4
Show answer & solution
Answer: (D) 4
  1. The product of a matrix and its inverse is I.
  2. Entry (1, 2) of the product: .
  3. , so .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q91 markMCQMatrices

Find the matrix , where is a 2 × 2 matrix whose elements are given by = maximum (i, j) – minimum (i, j) :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. , , , .
  2. .
  3. .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q101 markMCQDeterminants

If A is a square matrix of order 3 such that the value of , then the value of is :

  1. (A)
  2. (B)
  3. (C)8
  4. (D)
Show answer & solution
Answer: (D)
  1. For order n = 3, .
  2. So , giving .
  3. ; of the options only fits.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q111 markMCQIntegrals

The value of is :

  1. (A)
  2. (B)
  3. (C)0
  4. (D)
Show answer & solution
Answer: (A)
  1. Put , ; , .
  2. Integral .
Q121 markMCQIntegrals

The integral is equal to :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. .

The area of the region bounded by the curve and is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. The region is symmetric about the X-axis; above it .
  2. Area .

The general solution of the differential equation
is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. .
  2. Integrating: , i.e. .

The angle which the line makes with the positive direction of Y-axis is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Direction ratios 1, –1, 0; magnitude .
  2. , so .
Also asked in: 2024 65/5/1, 2024 65/5/3

The Cartesian equation of the line passing through the point (1, –3, 2) and parallel to the line :
is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , so the direction ratios are 1, 1, 2.
  2. Line through (1, –3, 2): .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q171 markMCQProbability

If A and B are events such that , then :

  1. (A), but
  2. (B)A = B
  3. (C)
  4. (D)P(A) = P(B)
Show answer & solution
Answer: (D) P(A) = P(B)
  1. with .
  2. Cancelling, P(A) = P(B).
Also asked in: 2024 65/5/1, 2024 65/5/3
Q181 markMCQVector Algebra

The position vectors of points P and Q are and respectively. The point R divides line segment PQ in the ratio 3 : 1 and S is the mid-point of line segment PR. The position vector of S is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. .
  2. .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q191 markAssertion–ReasonVector Algebra

Assertion (A) : The vectors , , represent the sides of a right angled triangle.
Reason (R) : Three non-zero vectors of which none of two are collinear forms a triangle if their resultant is zero vector or sum of any two vectors is equal to the third.

  1. (A)Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (B) Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).
  1. , and no two of the vectors are collinear, so they form a triangle.
  2. , so the triangle is right angled. A is true.
  3. R is a true statement of the condition for three vectors to form a triangle.
  4. R only shows a triangle is formed; the right angle comes from , which R does not explain.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q201 markAssertion–ReasonInverse Trigonometric Functions

Assertion (A) : Domain of is [–1, 1].
Reason (R) : The range of the principal value branch of is .

  1. (A)Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. is defined for , so A is true.
  2. The principal value branch of has range (it includes ), so R is false.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q212 marksVery Short AnswerInverse Trigonometric Functions

If and

then find the value of a + b.

Show answer & solution
Answer:
  1. , , so .
  2. , , so .
  3. .
Q222 marksVery Short AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. , so the integral is .
  2. Put , : .
  3. .
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q22 (OR) (OR)2 marksVery Short AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. .
  2. .
  3. .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q232 marksVery Short AnswerApplication of Derivatives

Sand is pouring from a pipe at the rate of 15 cm³/minute. The falling sand forms a cone on the ground such that the height of the cone is always one-third of the radius of the base. How fast is the height of the sand cone increasing at the instant when the height is 4 cm ?

Show answer & solution
Answer: cm/minute
  1. , so .
  2. .
  3. At h = 4: cm/minute.
Q242 marksVery Short AnswerThree Dimensional Geometry

Find the vector equation of the line passing through the point (2, 3, –5) and making equal angles with the co-ordinate axes.

Show answer & solution
Answer:
  1. Equal angles: and , so the direction ratios can be taken as 1, 1, 1.
  2. Line through (2, 3, –5): .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q252 marksVery Short AnswerContinuity and Differentiability

Verify whether the function f defined by

is continuous at or not.

Show answer & solution
Answer: f is continuous at .
  1. For , since .
  2. As , , so (sandwich theorem).
  3. This equals , so f is continuous at .
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q25 (OR) (OR)2 marksVery Short AnswerContinuity and Differentiability

Check for differentiability of the function f defined by , at the point .

Show answer & solution
Answer: f is not differentiable at .
  1. LHD .
  2. RHD .
  3. LHD RHD, so f is not differentiable at .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q263 marksShort AnswerDifferential Equations

Find the particular solution of the differential equation
; y(0) = 5.

Show answer & solution
Answer:
  1. Linear equation with , ; I.F. .
  2. .
  3. y(0) = 5 gives .
  4. Particular solution: .
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q26 (OR) (OR)3 marksShort AnswerDifferential Equations

Solve the following differential equation :

Show answer & solution
Answer:
  1. , which is homogeneous. Put .
  2. .
  3. .
  4. ; with : .
  5. General solution: .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q273 marksShort AnswerContinuity and Differentiability

Find the values of a and b so that the following function is differentiable for all values of x :

Show answer & solution
Answer: a = 3,
  1. Each piece is a polynomial, so only needs checking.
  2. Continuity at : must equal , so .
  3. Differentiability: LHD at ; RHD .
  4. .
  5. So a = 3, .
Q283 marksShort AnswerContinuity and Differentiability

Find , if .

Show answer & solution
Answer:
  1. Taking logs: .
  2. Differentiate: .
  3. .
  4. .
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q28 (OR) (OR)3 marksShort AnswerContinuity and Differentiability

If , prove that .

Show answer & solution
Answer: Proved.
  1. Put , : .
  2. .
  3. So , i.e. .
  4. (a constant).
  5. Differentiate: .
  6. Hence .
Q293 marksShort AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. Let .
  2. Using and : .
  3. Adding: .
  4. .
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q29 (OR) (OR)3 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Let .
  2. .
  3. : , . : , . Coefficient of : , .
  4. Integral
  5. .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q303 marksShort AnswerVector Algebra

Given , and . Find a vector which is perpendicular to both and and .

Show answer & solution
Answer:
  1. is parallel to .
  2. Let .
  3. .
  4. .
Q313 marksShort AnswerProbability

Bag I contains 3 red and 4 black balls, Bag II contains 5 red and 2 black balls. Two balls are transferred at random from Bag I to Bag II and then a ball is drawn at random from Bag II. Find the probability that the drawn ball is red in colour.

Show answer & solution
Answer:
  1. Let , , : the two balls transferred are 2 red, 1 red and 1 black, 2 black.
  2. , , .
  3. Bag II then has 9 balls with 7, 6, 5 red: , , .
  4. .
Q325 marksLong AnswerThree Dimensional Geometry

Find the co-ordinates of the foot of the perpendicular drawn from the point (2, 3, –8) to the line .
Also, find the perpendicular distance of the given point from the line.

Show answer & solution
Answer: Foot (2, 6, –2); distance units
  1. The line is ; general point .
  2. for P(2, 3, –8).
  3. line: .
  4. Foot Q = (2, 6, –2).
  5. Distance units.
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q32 (OR) (OR)5 marksLong AnswerThree Dimensional Geometry

Find the shortest distance between the lines & given below :
: The line passing through (2, –1, 1) and parallel to
: .

Show answer & solution
Answer: units
  1. : .
  2. : .
  3. ; .
  4. ; .
  5. S.D. units.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q335 marksLong AnswerDeterminants

If , then find and hence solve the following system of equations :


Show answer & solution
Answer: ; , ,
  1. .
  2. Cofactors: , , ; , , ; , , .
  3. , .
  4. The system is with , so .
  5. , , .
Also asked in: 2024 65/5/1, 2024 65/5/3
OR
Q33 (OR) (OR)5 marksLong AnswerDeterminants

Find the product of the matrices and hence solve the system of linear equations :


Show answer & solution
Answer: Product ; , ,
  1. Row 1: ; similarly rows 2 and 3 give and .
  2. So , where P is the first matrix and Q the second; hence .
  3. The system is with , so .
  4. .
  5. , , .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q345 marksLong AnswerApplication of Integrals

Find the area of the region bounded by the curve using integration.

Show answer & solution
Answer: sq units
  1. : an ellipse with a = 3, b = 6, symmetric about both axes.
  2. In the first quadrant , .
  3. Area .
  4. sq units.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q355 marksLong AnswerLinear Programming

Solve the following Linear Programming problem graphically :
Maximise Z = 300x + 600y
Subject to


.

Show answer & solution
Answer: Maximum Z = 3600, at every point of the segment joining (4, 4) and (0, 6)
  1. Draw , and (i.e. ) in the first quadrant.
  2. The feasible region is bounded, with corner points (5, 0), (6, 0), (4, 4), (0, 6), (0, 4).
  3. Z at the corners: (5, 0): 1500; (6, 0): 1800; (4, 4): 3600; (0, 6): 3600; (0, 4): 2400.
  4. The maximum 3600 occurs at both (4, 4) and (0, 6), so at every point of the segment joining them (Z is parallel to ).
Q364 marksCase StudyProbability

A departmental store sends bills to charge its customers once a month. Past experience shows that 70% of its customers pay their first month bill in time. The store also found that the customer who pays the bill in time has the probability of 0.8 of paying in time next month and the customer who doesn’t pay in time has the probability of 0.4 of paying in time the next month.
Based on the above information, answer the following questions :
(i) Let and respectively denote the event of customer paying or not paying the first month bill in time. Find , .
(ii) Let A denotes the event of customer paying second month’s bill in time, then find and .
(iii) Find the probability of customer paying second month’s bill in time.
OR (iii) Find the probability of customer paying first month’s bill in time if it is found that customer has paid the second month’s bill in time.

Show answer & solution
Answer: (i) , (ii) , (iii) 0.68 OR (iii)
  1. (i) 70% pay in time: , .
  2. (ii) Given directly: , .
  3. (iii) .
  4. OR (iii) By Bayes' theorem, .
Also asked in: 2024 65/5/1, 2024 65/5/3
Q374 marksCase StudyRelations and Functions

Students of a school are taken to a railway museum to learn about railways heritage and its history.
An exhibit in the museum depicted many rail lines on the track near the railway station. Let L be the set of all rail lines on the railway track and R be the relation on L defined by
is parallel to
On the basis of the above information, answer the following questions :
(i) Find whether the relation R is symmetric or not.
(ii) Find whether the relation R is transitive or not.
(iii) If one of the rail lines on the railway track is represented by the equation y = 3x + 2, then find the set of rail lines in R related to it.
OR Let S be the relation defined by is perpendicular to check whether the relation S is symmetric and transitive.

Show answer & solution
Answer: (i) Symmetric (ii) Transitive (iii) is a line , OR S is symmetric but not transitive
  1. (i) If then , so : R is symmetric.
  2. (ii) If and then : R is transitive.
  3. (iii) Lines related to y = 3x + 2 are the lines parallel to it, i.e. with slope 3: the set .
  4. OR If then , so S is symmetric. If and then (in a plane), so : S is not transitive.
Also asked in: 2024 65/5/1, 2024 65/5/3
Q384 marksCase StudyApplication of Derivatives

A rectangular visiting card is to contain 24 sq.cm. of printed matter. The margins at the top and bottom of the card are to be 1 cm and the margins on the left and right are to be 1½ cm as shown below :
On the basis of the above information, answer the following questions :
(i) Write the expression for the area of the visiting card in terms of x.
(ii) Obtain the dimensions of the card of minimum area.

Diagram for CBSE 2024 Class 12 Maths question 38
Show answer & solution
Answer: (i) (ii) 9 cm × 6 cm (width × height)
  1. (i) Printed matter is x cm by y cm with , so . Card is cm by cm.
  2. .
  3. (ii) (x > 0); , so minimum.
  4. Then ; card dimensions cm × cm = 9 cm × 6 cm (minimum area 54 sq cm).
Also asked in: 2024 65/5/1, 2024 65/5/3
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