CBSE Class 12 Maths 2024 Question Paper 65/3/2 with Solutions
All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/3/2 (2024),
with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.
If a line makes an angle of 4π with the positive directions of both x-axis and z-axis, then the angle which it makes with the positive direction of y-axis is :
Find the position vector of point C which divides the line segment joining points A and B having position vectors i^+2j^−k^ and −i^+j^+k^ respectively in the ratio 4 : 1 externally. Further, find ∣AB∣:∣BC∣.
The chances of P, Q and R getting selected as CEO of a company are in the ratio 4 : 1 : 2 respectively. The probabilities for the company to increase its profits from the previous year under the new CEO, P, Q or R are 0.3, 0.8 and 0.5 respectively. If the company increased the profits from the previous year, find the probability that it is due to the appointment of R as CEO.
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Answer:31
P(E1)=74, P(E2)=71, P(E3)=72 for P, Q, R selected. Let A: profits increase.
It is given that function f(x)=x4−62x2+ax+9 attains local maximum value at x = 1. Find the value of ‘a’, hence obtain all other points where the given function f(x) attains local maximum or local minimum values.
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Answer: a = 120; local minimum at x = – 6 and at x = 5 (no other local maximum).
f′(x)=4x3−124x+a. f′(1)=0 gives 4−124+a=0, so a = 120.
The perimeter of a rectangular metallic sheet is 300 cm. It is rolled along one of its sides to form a cylinder. Find the dimensions of the rectangular sheet so that volume of cylinder so formed is maximum.
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Answer: 100 cm × 50 cm (the 100 cm side forms the circumference of the base).
Let the sides be x and y with 2(x+y)=300, so y=150−x. Roll so that side x becomes the base circumference and y the height.
2πr=x, so r=2πx. V=πr2h=4πx2(150−x).
dxdV=4π300x−3x2=0 gives x = 100 (x ≠ 0).
dx2d2V=4π300−6x=−4π300<0 at x = 100, so V is maximum.
Find the equation of the line passing through the point of intersection of the lines 1x=2y−1=3z−2 and 0x−1=−3y=2z−7 and perpendicular to these given lines.
Two vertices of the parallelogram ABCD are given as A(–1, 2, 1) and B(1, –2, 5). If the equation of the line passing through C and D is 1x−4=−2y+7=2z−8, then find the distance between sides AB and CD. Hence, find the area of parallelogram ABCD.
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Answer: Distance =326 units; area =226 sq units.
AB=2i^−4j^+4k^, parallel to b=i^−2j^+2k^ (direction of CD). ∣AB∣=6, ∣b∣=3.
Distance between AB and CD = distance of A from line CD. Take P(4, –7, 8) on CD: AP=5i^−9j^+7k^.
A relation R on set A = {x : – 10 ≤ x ≤ 10, x ∈ Z} is defined as R = {(x, y) : (x – y) is divisible by 5}. Show that R is an equivalence relation. Also, write the equivalence class [5].
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Answer: R is an equivalence relation; [5] = {– 10, – 5, 0, 5, 10}.
Reflexive: x – x = 0 is divisible by 5, so (x,x)∈R for all x∈A.
Symmetric: if 5 divides x – y, then 5 divides y – x = –(x – y); so (y,x)∈R.
Transitive: if x – y = 5m and y – z = 5n, then x – z = 5(m + n); so (x,z)∈R.
Hence R is an equivalence relation.
[5] = {y ∈ A : y – 5 is divisible by 5} = {– 10, – 5, 0, 5, 10}.
A bacteria sample of certain number of bacteria is observed to grow exponentially in a given amount of time. Using exponential growth model, the rate of growth of this sample of bacteria is calculated. The differential equation representing the growth of bacteria is given as : dtdP=kP, where P is the population of bacteria at any time ‘t’. Based on the above information, answer the following questions : (i) Obtain the general solution of the given differential equation and express it as an exponential function of ‘t’. (2) (ii) If population of bacteria is 1000 at t = 0, and 2000 at t = 1, find the value of k. (2)
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Answer: (i) P=Cekt (ii) k=log2
(i) Separate variables: PdP=kdt.
Integrate: log∣P∣=kt+c1, so P=Cekt (C = ec1).
(ii) t = 0, P = 1000 gives C = 1000, so P=1000ekt.
t = 1, P = 2000: 2000=1000ek, ek=2, k=log2 (= loge2).
A scholarship is a sum of money provided to a student to help him or her pay for education. Some students are granted scholarships based on their academic achievements, while others are rewarded based on their financial needs. Every year a school offers scholarships to girl children and meritorious achievers based on certain criteria. In the session 2022 – 23, the school offered monthly scholarship of ₹ 3,000 each to some girl students and ₹ 4,000 each to meritorious achievers in academics as well as sports. In all, 50 students were given the scholarships and monthly expenditure incurred by the school on scholarships was ₹ 1,80,000. Based on the above information, answer the following questions : (i) Express the given information algebraically using matrices. (1) (ii) Check whether the system of matrix equations so obtained is consistent or not. (1) (iii) (a) Find the number of scholarships of each kind given by the school, using matrices. (2) OR (iii) (b) Had the amount of scholarship given to each girl child and meritorious student been interchanged, what would be the monthly expenditure incurred by the school ? (2)
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Answer: (i) [1300014000][xy]=[50180000] (ii) Consistent, since |A| = 1000 ≠ 0 (iii) (a) 20 girl students and 30 meritorious achievers OR (iii) (b) ₹ 1,70,000
(i) Let x girls get ₹ 3,000 and y meritorious achievers get ₹ 4,000. Then x + y = 50 and 3000x + 4000y = 180000, i.e. AX = B with A=[1300014000], X=[xy], B=[50180000].
(ii) |A| = 4000 – 3000 = 1000 ≠ 0, so A is invertible and the system is consistent (unique solution).
Q384 marksCase StudyProbabilityNot in current syllabus
Self-study helps students to build confidence in learning. It boosts the self-esteem of the learners. Recent surveys suggested that close to 50% learners were self-taught using internet resources and upskilled themselves. A student may spend 1 hour to 6 hours in a day in upskilling self. The probability distribution of the number of hours spent by a student is given below : P(X=x)=⎩⎨⎧kx2,2kx,0,for x=1,2,3for x=4,5,6otherwise where x denotes the number of hours. Based on the above information, answer the following questions : (i) Express the probability distribution given above in the form of a probability distribution table. (1) (ii) Find the value of k. (1) (iii) (a) Find the mean number of hours spent by the student. (2) OR (iii) (b) Find P(1 < X < 6). (2)