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CBSE Class 12 Maths 2024 Question Paper 65/3/2 with Solutions

All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/3/2 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 65/1/1Set 65/1/2Set 65/1/3Set 65/2/1Set 65/2/2Set 65/2/3Set 65/3/1Set 65/3/2Set 65/3/3Set 65/4/1Set 65/4/2Set 65/4/3Set 65/5/1Set 65/5/2Set 65/5/3
Q11 markMCQDeterminants

If , then the value of k is :

  1. (A)2
  2. (B)– 2
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Expand along the third row: determinant .
  2. gives ; gives .
  3. So (corresponding to ).
Also asked in: 2024 65/3/1

The derivative of w.r.t. is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Let , . , .
  2. .
Q31 markMCQVector Algebra

If and , then :

  1. (A)[– 6, 4]
  2. (B)[0, 4]
  3. (C)[4, 6]
  4. (D)[0, 6]
Show answer & solution
Answer: (D) [0, 6]
  1. .
  2. For , takes all values in [0, 3].
  3. So .
Also asked in: 2024 65/3/1, 2024 65/3/3

If a line makes an angle of with the positive directions of both x-axis and z-axis, then the angle which it makes with the positive direction of y-axis is :

  1. (A)0
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. .
  2. , so .
  3. .
Also asked in: 2024 65/3/1, 2024 65/3/3

Of the following, which group of constraints represents the feasible region given below ?

Diagram for CBSE 2024 Class 12 Maths question 5
  1. (A), ,
  2. (B), ,
  3. (C), ,
  4. (D), ,
Show answer & solution
Answer: (C) , ,
  1. The shaded region lies on the far side of x + 2y = 76 from O (O does not satisfy it), so .
  2. It lies on the same side of 2x + y = 104 as O, so .
  3. It is in the first quadrant, so . Hence option (C).
Also asked in: 2024 65/3/1, 2024 65/3/3
Q61 markMCQMatrices

If A = , then is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. For a diagonal matrix with non-zero diagonal entries, the inverse is the diagonal matrix of reciprocals.
  2. Check: .
  3. So is option (A).
Also asked in: 2024 65/3/1, 2024 65/3/3
Q71 markMCQMatrices

For any square matrix A, (A – A′) is always

  1. (A)an identity matrix
  2. (B)a null matrix
  3. (C)a skew symmetric matrix
  4. (D)a symmetric matrix
Show answer & solution
Answer: (C) a skew symmetric matrix
  1. .
  2. So A – A′ is skew symmetric.

A function defined as is onto, if A is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. For real x, , so , and every is attained ().
  2. Range of f . f is onto when the co-domain A equals the range, i.e. .
Q91 markMCQDeterminants

Let A = be a square matrix such that adj A = A. Then, (a + b + c + d) is equal to :

  1. (A)2a
  2. (B)2b
  3. (C)2c
  4. (D)0
Show answer & solution
Answer: (A) 2a
  1. adj A = .
  2. adj A = A gives , , , so , , .
  3. a + b + c + d = a + 0 + 0 + a = 2a.
Also asked in: 2024 65/3/1, 2024 65/3/3

A function is :

  1. (A)discontinuous at x = 1 only
  2. (B)discontinuous at x = 0 only
  3. (C)discontinuous at x = 0, 1
  4. (D)continuous everywhere
Show answer & solution
Answer: (D) continuous everywhere
  1. For : .
  2. For : .
  3. Both pieces are continuous and at both give 1, so f is continuous everywhere.
  4. (Also, f is a composition of continuous functions.)
Also asked in: 2024 65/3/1, 2024 65/3/3

The point of inflexion of a function f(x) is the point where

  1. (A) and changes its sign from positive to negative from left to right of that point.
  2. (B) and changes its sign from negative to positive from left to right of that point.
  3. (C) and does not change its sign from left to right of that point.
  4. (D).
Show answer & solution
Answer: (C) and does not change its sign from left to right of that point.
  1. By the first derivative test, at a critical point c ():
  2. if changes from + to –, c is a point of local maximum; if from – to +, a point of local minimum;
  3. if does not change sign, c is neither, and is called a point of inflexion. So option (C).
Q121 markMCQIntegrals

If g(x) is a continuous function satisfying , then is equal to :

  1. (A)0
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Put in : it becomes .
  2. So , option (D).
  3. (A) and (C) are 0, and (B) is not equal to it in general, e.g. g(x) = x.

is an example of a :

  1. (A)variable separable differential equation.
  2. (B)homogeneous differential equation.
  3. (C)first order linear differential equation.
  4. (D)differential equation whose degree is not defined.
Show answer & solution
Answer: (C) first order linear differential equation.
  1. Divide by : .
  2. This has the form with P, Q functions of x only.
  3. So it is a first order linear differential equation.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q141 markMCQVector Algebra

If and , then and are :

  1. (A)collinear vectors which are not parallel
  2. (B)parallel vectors
  3. (C)perpendicular vectors
  4. (D)unit vectors
Show answer & solution
Answer: (C) perpendicular vectors
  1. .
  2. Both vectors are non-zero, so they are perpendicular.
Also asked in: 2024 65/3/1, 2024 65/3/3

If , and are the angles which a line makes with positive directions of x, y and z axes respectively, then which of the following is not true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , so (A) is true.
  2. , so (B) is true.
  3. , so (C) is true.
  4. The sum of the direction cosines need not be 1 (e.g. for the x-axis direction it is 1, but for it is ). So (D) is not true.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q161 markMCQLinear Programming

The restrictions imposed on decision variables involved in an objective function of a linear programming problem are called :

  1. (A)feasible solutions
  2. (B)constraints
  3. (C)optimal solutions
  4. (D)infeasible solutions
Show answer & solution
Answer: (B) constraints
  1. The linear inequalities that restrict the decision variables of an LPP are called its constraints.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q171 markMCQProbability

Let E and F be two events such that P(E) = 0.1, P(F) = 0.3, = 0.4, then P(F|E) is :

  1. (A)0.6
  2. (B)0.4
  3. (C)0.5
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. .
  2. .
Also asked in: 2024 65/3/1, 2024 65/3/3
Q181 markMCQMatrices

If A = is an identity matrix, then which of the following is true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. In an identity matrix every diagonal element is 1 and every off-diagonal element is 0.
  2. So when and when , which is option (D).
Also asked in: 2024 65/3/1, 2024 65/3/3
Q191 markAssertion–ReasonVector Algebra

Assertion (A) : Projection of on is same as projection of on .
Reason (R) : Angle between and is same as angle between and numerically.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Projection of on is ; projection of on is .
  2. These are equal only if (or ), so A is false in general.
  3. is symmetric in , , so R is true.
Also asked in: 2024 65/3/1
Q201 markAssertion–ReasonMatrices

Assertion (A) : Every scalar matrix is a diagonal matrix.
Reason (R) : In a diagonal matrix, all the diagonal elements are 0.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. A scalar matrix has all off-diagonal elements 0 (and equal diagonal elements), so it is diagonal. A is true.
  2. In a diagonal matrix the non-diagonal elements are 0; the diagonal elements need not be 0. R is false.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q212 marksVery Short AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. .
  2. .
  3. .
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q21 (OR) (OR)2 marksVery Short AnswerIntegrals

Given and F(1) = 0, find F(x).

Show answer & solution
Answer:
  1. .
  2. .
  3. , so .
  4. .
Also asked in: 2024 65/3/1, 2024 65/3/3
Q222 marksVery Short AnswerVector Algebra

Find the position vector of point C which divides the line segment joining points A and B having position vectors and respectively in the ratio 4 : 1 externally. Further, find .

Show answer & solution
Answer: ;
  1. .
  2. , .
  3. , .
  4. .
Also asked in: 2024 65/3/1, 2024 65/3/3
Q232 marksVery Short AnswerVector Algebra

If , and are three unit vectors such that , find the angle between vectors and .

Show answer & solution
Answer:
  1. , so .
  2. , i.e. , so .
  3. , so .
Q242 marksVery Short AnswerInverse Trigonometric Functions

Find the value of .

Show answer & solution
Answer:
  1. Let , so and .
  2. Let , so and .
  3. Value .
Q252 marksVery Short AnswerContinuity and Differentiability

If , prove that

Show answer & solution
Answer: Proved.
  1. Taking log: , so .
  2. .
  3. Hence proved.
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q25 (OR) (OR)2 marksVery Short AnswerContinuity and Differentiability

Check the differentiability of at x = 1.

Show answer & solution
Answer: Not differentiable at x = 1 (LHD = 2, RHD = –1).
  1. f(1) = 3 - 1 = 2.
  2. LHD .
  3. RHD .
  4. LHD RHD, so f is not differentiable at x = 1.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q263 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Put , : .
  2. .
  3. .
  4. .
Q273 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. .
  2. Integral .
  3. This is of the form with .
  4. Answer: .
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q27 (OR) (OR)3 marksShort AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. .
  2. .
  3. At : . At 0: .
  4. .
Also asked in: 2024 65/3/1, 2024 65/3/3
Q283 marksShort AnswerLinear Programming

Solve the following linear programming problem graphically :
Minimize z = 600x + 400y,
subject to the constraints



.

Show answer & solution
Answer: Minimum z = 3200 at x = 0, y = 8.
  1. Draw x + y = 8, x + 2y = 16 and 4x + y = 29. The feasible region is the triangle above x + y = 8 and below the other two lines.
  2. Corner points: (0, 8) [x + y = 8 and x + 2y = 16 meet on the y-axis], (7, 1) [x + y = 8 and 4x + y = 29], (6, 5) [x + 2y = 16 and 4x + y = 29].
  3. z = 600x + 400y: at (0, 8) z = 3200; at (7, 1) z = 4600; at (6, 5) z = 5600.
  4. The region is bounded, so minimum z = 3200 at (0, 8).
Q293 marksShort AnswerProbability

The chances of P, Q and R getting selected as CEO of a company are in the ratio 4 : 1 : 2 respectively. The probabilities for the company to increase its profits from the previous year under the new CEO, P, Q or R are 0.3, 0.8 and 0.5 respectively. If the company increased the profits from the previous year, find the probability that it is due to the appointment of R as CEO.

Show answer & solution
Answer:
  1. , , for P, Q, R selected. Let A: profits increase.
  2. , , .
  3. .
  4. By Bayes' theorem, .
Also asked in: 2024 65/3/1, 2024 65/3/3
Q303 marksShort AnswerContinuity and Differentiability

If , prove that , where p is a constant.

Show answer & solution
Answer: Proved.
  1. .
  2. Differentiate w.r.t. y: .
  3. So .
  4. Hence .
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q30 (OR) (OR)3 marksShort AnswerContinuity and Differentiability

Find the value of a and b so that function f defined as :

is a continuous function.

Show answer & solution
Answer: a = 1, b = –1
  1. For : , so . LHL .
  2. For : , so . RHL .
  3. f(2) = a + b.
  4. Continuity at 2: gives ; gives .
  5. So a = 1, b = –1 (f is clearly continuous at other points).
Also asked in: 2024 65/3/1, 2024 65/3/3
Q313 marksShort AnswerApplication of Derivatives

Find the intervals in which the function is strictly increasing or strictly decreasing.

Show answer & solution
Answer: Strictly increasing in (0, e); strictly decreasing in .
  1. Domain: .
  2. .
  3. at , i.e. .
  4. For , , so : strictly increasing on (0, e).
  5. For , : strictly decreasing on .
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q31 (OR) (OR)3 marksShort AnswerApplication of Derivatives

Find the absolute maximum and absolute minimum values of the function f given by , on the interval [1, 2].

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Answer: Absolute maximum (at x = 1); absolute minimum 2 (at x = 2).
  1. gives , (in [1, 2]).
  2. Evaluate at critical point and end points: , .
  3. Absolute maximum at x = 1; absolute minimum = 2 at x = 2.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q325 marksLong AnswerApplication of Derivatives

It is given that function attains local maximum value at x = 1. Find the value of ‘a’, hence obtain all other points where the given function f(x) attains local maximum or local minimum values.

Show answer & solution
Answer: a = 120; local minimum at x = – 6 and at x = 5 (no other local maximum).
  1. . gives , so a = 120.
  2. .
  3. Critical points: x = 1, – 6, 5. .
  4. : local maximum at x = 1 (as given).
  5. : local minimum at x = – 6, value f(– 6) = – 1647.
  6. : local minimum at x = 5, value f(5) = – 316.
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q32 (OR) (OR)5 marksLong AnswerApplication of Derivatives

The perimeter of a rectangular metallic sheet is 300 cm. It is rolled along one of its sides to form a cylinder. Find the dimensions of the rectangular sheet so that volume of cylinder so formed is maximum.

Show answer & solution
Answer: 100 cm × 50 cm (the 100 cm side forms the circumference of the base).
  1. Let the sides be x and y with , so . Roll so that side x becomes the base circumference and y the height.
  2. , so . .
  3. gives x = 100 (x ≠ 0).
  4. at x = 100, so V is maximum.
  5. Dimensions: 100 cm and 50 cm.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q335 marksLong AnswerApplication of Integrals

Find the area of the region bounded by the lines x – 2y = 4, x = –1, x = 6 and x-axis, using integration.

Show answer & solution
Answer: sq units
  1. The line is ; it meets the x-axis at x = 4 and is below the axis for x < 4.
  2. Area .
  3. .
  4. .
  5. Total area sq units.
Q345 marksLong AnswerThree Dimensional Geometry

Find the equation of the line passing through the point of intersection of the lines and and perpendicular to these given lines.

Show answer & solution
Answer:
  1. General points: and .
  2. Equating: ; gives ; z: ✓. Intersection point (1, 3, 5).
  3. Required direction .
  4. Line: .
Also asked in: 2024 65/3/1, 2024 65/3/3
OR
Q34 (OR) (OR)5 marksLong AnswerThree Dimensional Geometry

Two vertices of the parallelogram ABCD are given as A(–1, 2, 1) and B(1, –2, 5). If the equation of the line passing through C and D is , then find the distance between sides AB and CD. Hence, find the area of parallelogram ABCD.

Show answer & solution
Answer: Distance units; area sq units.
  1. , parallel to (direction of CD). , .
  2. Distance between AB and CD = distance of A from line CD. Take P(4, –7, 8) on CD: .
  3. , magnitude .
  4. Distance units.
  5. Area sq units.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q355 marksLong AnswerRelations and Functions

A relation R on set A = {x : – 10 ≤ x ≤ 10, x ∈ Z} is defined as R = {(x, y) : (x – y) is divisible by 5}. Show that R is an equivalence relation. Also, write the equivalence class [5].

Show answer & solution
Answer: R is an equivalence relation; [5] = {– 10, – 5, 0, 5, 10}.
  1. Reflexive: x – x = 0 is divisible by 5, so for all .
  2. Symmetric: if 5 divides x – y, then 5 divides y – x = –(x – y); so .
  3. Transitive: if x – y = 5m and y – z = 5n, then x – z = 5(m + n); so .
  4. Hence R is an equivalence relation.
  5. [5] = {y ∈ A : y – 5 is divisible by 5} = {– 10, – 5, 0, 5, 10}.
Q364 marksCase StudyDifferential Equations

A bacteria sample of certain number of bacteria is observed to grow exponentially in a given amount of time. Using exponential growth model, the rate of growth of this sample of bacteria is calculated.
The differential equation representing the growth of bacteria is given as :
, where P is the population of bacteria at any time ‘t’.
Based on the above information, answer the following questions :
(i) Obtain the general solution of the given differential equation and express it as an exponential function of ‘t’. (2)
(ii) If population of bacteria is 1000 at t = 0, and 2000 at t = 1, find the value of k. (2)

Diagram for CBSE 2024 Class 12 Maths question 36
Show answer & solution
Answer: (i) (ii)
  1. (i) Separate variables: .
  2. Integrate: , so (C = ).
  3. (ii) t = 0, P = 1000 gives C = 1000, so .
  4. t = 1, P = 2000: , , (= ).
Also asked in: 2024 65/3/1, 2024 65/3/3
Q374 marksCase StudyDeterminants

A scholarship is a sum of money provided to a student to help him or her pay for education. Some students are granted scholarships based on their academic achievements, while others are rewarded based on their financial needs.
Every year a school offers scholarships to girl children and meritorious achievers based on certain criteria. In the session 2022 – 23, the school offered monthly scholarship of ₹ 3,000 each to some girl students and ₹ 4,000 each to meritorious achievers in academics as well as sports.
In all, 50 students were given the scholarships and monthly expenditure incurred by the school on scholarships was ₹ 1,80,000.
Based on the above information, answer the following questions :
(i) Express the given information algebraically using matrices. (1)
(ii) Check whether the system of matrix equations so obtained is consistent or not. (1)
(iii) (a) Find the number of scholarships of each kind given by the school, using matrices. (2)
OR (iii) (b) Had the amount of scholarship given to each girl child and meritorious student been interchanged, what would be the monthly expenditure incurred by the school ? (2)

Show answer & solution
Answer: (i) (ii) Consistent, since |A| = 1000 ≠ 0 (iii) (a) 20 girl students and 30 meritorious achievers OR (iii) (b) ₹ 1,70,000
  1. (i) Let x girls get ₹ 3,000 and y meritorious achievers get ₹ 4,000. Then x + y = 50 and 3000x + 4000y = 180000, i.e. AX = B with , , .
  2. (ii) |A| = 4000 – 3000 = 1000 ≠ 0, so A is invertible and the system is consistent (unique solution).
  3. (iii) (a) .
  4. : 20 girl students, 30 meritorious achievers.
  5. (iii) (b) Interchanged: 20 × 4000 + 30 × 3000 = 80000 + 90000 = ₹ 1,70,000.
Also asked in: 2024 65/3/1, 2024 65/3/3
Q384 marksCase StudyProbabilityNot in current syllabus

Self-study helps students to build confidence in learning. It boosts the self-esteem of the learners. Recent surveys suggested that close to 50% learners were self-taught using internet resources and upskilled themselves.
A student may spend 1 hour to 6 hours in a day in upskilling self. The probability distribution of the number of hours spent by a student is given below :

where x denotes the number of hours.
Based on the above information, answer the following questions :
(i) Express the probability distribution given above in the form of a probability distribution table. (1)
(ii) Find the value of k. (1)
(iii) (a) Find the mean number of hours spent by the student. (2)
OR (iii) (b) Find P(1 < X < 6). (2)

Show answer & solution
Answer: (i) X: 1, 2, 3, 4, 5, 6; P(X): k, 4k, 9k, 8k, 10k, 12k (ii) (iii) (a) hours OR (iii) (b)
  1. (i) X: 1, 2, 3, 4, 5, 6 with P(X): k, 4k, 9k, 8k, 10k, 12k.
  2. (ii) Sum of probabilities: k + 4k + 9k + 8k + 10k + 12k = 44k = 1, so .
  3. (iii) (a) Mean hours.
  4. (iii) (b) P(1 < X < 6) = P(2) + P(3) + P(4) + P(5) = 4k + 9k + 8k + 10k = 31k .
Also asked in: 2024 65/3/1, 2024 65/3/3
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