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CBSE Class 12 Maths 2024 Question Paper 65/3/3 with Solutions

All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/3/3 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 65/1/1Set 65/1/2Set 65/1/3Set 65/2/1Set 65/2/2Set 65/2/3Set 65/3/1Set 65/3/2Set 65/3/3Set 65/4/1Set 65/4/2Set 65/4/3Set 65/5/1Set 65/5/2Set 65/5/3
Q11 markMCQDeterminants

The value of is :

  1. (A)0
  2. (B)2
  3. (C)7
  4. (D)– 2
Show answer & solution
Answer: (A) 0
  1. Expand along the first row: .
  2. .
  3. (Indeed the first column is 4 times the second column.)

If , then is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. , so and .
  2. .
Q31 markMCQVector Algebra

If and , then :

  1. (A)[– 6, 4]
  2. (B)[0, 4]
  3. (C)[4, 6]
  4. (D)[0, 6]
Show answer & solution
Answer: (D) [0, 6]
  1. .
  2. For , takes all values in [0, 3].
  3. So .
Also asked in: 2024 65/3/1, 2024 65/3/2

If a line makes an angle of with the positive directions of both x-axis and z-axis, then the angle which it makes with the positive direction of y-axis is :

  1. (A)0
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. .
  2. , so .
  3. .
Also asked in: 2024 65/3/1, 2024 65/3/2

Of the following, which group of constraints represents the feasible region given below ?

Diagram for CBSE 2024 Class 12 Maths question 5
  1. (A), ,
  2. (B), ,
  3. (C), ,
  4. (D), ,
Show answer & solution
Answer: (C) , ,
  1. The shaded region lies on the far side of x + 2y = 76 from O (O does not satisfy it), so .
  2. It lies on the same side of 2x + y = 104 as O, so .
  3. It is in the first quadrant, so . Hence option (C).
Also asked in: 2024 65/3/1, 2024 65/3/2
Q61 markMCQMatrices

If A = , then is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. For a diagonal matrix with non-zero diagonal entries, the inverse is the diagonal matrix of reciprocals.
  2. Check: .
  3. So is option (A).
Also asked in: 2024 65/3/1, 2024 65/3/2
Q71 markMCQMatrices

If A = is an identity matrix, then which of the following is true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. In an identity matrix every diagonal element is 1 and every off-diagonal element is 0.
  2. So when and when , which is option (D).
Also asked in: 2024 65/3/1, 2024 65/3/2

Let Z denote the set of integers, then function defined as is :

  1. (A)both one-one and onto
  2. (B)one-one but not onto
  3. (C)onto but not one-one
  4. (D)neither one-one nor onto
Show answer & solution
Answer: (B) one-one but not onto
  1. One-one: gives , so .
  2. Not onto: for 1 in the co-domain, gives , which has no integer solution.
  3. So f is one-one but not onto.
Q91 markMCQDeterminants

Let A = be a square matrix such that adj A = A. Then, (a + b + c + d) is equal to :

  1. (A)2a
  2. (B)2b
  3. (C)2c
  4. (D)0
Show answer & solution
Answer: (A) 2a
  1. adj A = .
  2. adj A = A gives , , , so , , .
  3. a + b + c + d = a + 0 + 0 + a = 2a.
Also asked in: 2024 65/3/1, 2024 65/3/2

A function is :

  1. (A)discontinuous at x = 1 only
  2. (B)discontinuous at x = 0 only
  3. (C)discontinuous at x = 0, 1
  4. (D)continuous everywhere
Show answer & solution
Answer: (D) continuous everywhere
  1. For : .
  2. For : .
  3. Both pieces are continuous and at both give 1, so f is continuous everywhere.
  4. (Also, f is a composition of continuous functions.)
Also asked in: 2024 65/3/1, 2024 65/3/2

The rate of change of surface area of a sphere with respect to its radius ‘r’, when r = 4 cm, is :

  1. (A) cm/cm
  2. (B) cm/cm
  3. (C) cm/cm
  4. (D) cm/cm
Show answer & solution
Answer: (C) cm/cm
  1. , so .
  2. At r = 4: cm/cm.
Q121 markMCQIntegrals

, if :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. This is 0 when , i.e. when f is an odd function.
Also asked in: 2024 65/3/1

is an example of a :

  1. (A)variable separable differential equation.
  2. (B)homogeneous differential equation.
  3. (C)first order linear differential equation.
  4. (D)differential equation whose degree is not defined.
Show answer & solution
Answer: (C) first order linear differential equation.
  1. Divide by : .
  2. This has the form with P, Q functions of x only.
  3. So it is a first order linear differential equation.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q141 markMCQVector Algebra

If and , then and are :

  1. (A)collinear vectors which are not parallel
  2. (B)parallel vectors
  3. (C)perpendicular vectors
  4. (D)unit vectors
Show answer & solution
Answer: (C) perpendicular vectors
  1. .
  2. Both vectors are non-zero, so they are perpendicular.
Also asked in: 2024 65/3/1, 2024 65/3/2

If , and are the angles which a line makes with positive directions of x, y and z axes respectively, then which of the following is not true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , so (A) is true.
  2. , so (B) is true.
  3. , so (C) is true.
  4. The sum of the direction cosines need not be 1 (e.g. for the x-axis direction it is 1, but for it is ). So (D) is not true.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q161 markMCQLinear Programming

The restrictions imposed on decision variables involved in an objective function of a linear programming problem are called :

  1. (A)feasible solutions
  2. (B)constraints
  3. (C)optimal solutions
  4. (D)infeasible solutions
Show answer & solution
Answer: (B) constraints
  1. The linear inequalities that restrict the decision variables of an LPP are called its constraints.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q171 markMCQProbability

Let E and F be two events such that P(E) = 0.1, P(F) = 0.3, = 0.4, then P(F|E) is :

  1. (A)0.6
  2. (B)0.4
  3. (C)0.5
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. .
  2. .
Also asked in: 2024 65/3/1, 2024 65/3/2
Q181 markMCQMatrices

If A and B are two skew symmetric matrices, then (AB + BA) is :

  1. (A)a skew symmetric matrix
  2. (B)a symmetric matrix
  3. (C)a null matrix
  4. (D)an identity matrix
Show answer & solution
Answer: (B) a symmetric matrix
  1. , .
  2. .
  3. So AB + BA is symmetric.
Also asked in: 2024 65/3/1
Q191 markAssertion–ReasonVector Algebra

Assertion (A) : For any non-zero unit vector , .
Reason (R) : Angle between and is .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. for a unit vector, and the dot product is commutative. A is true.
  2. The angle between and is (cos θ = –1), not . R is false.
Q201 markAssertion–ReasonMatrices

Assertion (A) : Every scalar matrix is a diagonal matrix.
Reason (R) : In a diagonal matrix, all the diagonal elements are 0.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. A scalar matrix has all off-diagonal elements 0 (and equal diagonal elements), so it is diagonal. A is true.
  2. In a diagonal matrix the non-diagonal elements are 0; the diagonal elements need not be 0. R is false.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q212 marksVery Short AnswerVector Algebra

, and are three mutually perpendicular unit vectors. If is the angle between and , find the value of .

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Answer:
  1. .
  2. (cross terms vanish), so the magnitude is 7.
  3. .
Q222 marksVery Short AnswerInverse Trigonometric Functions

Evaluate :

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Answer:
  1. Let , so and .
  2. Let , so .
  3. Value .
Q232 marksVery Short AnswerContinuity and Differentiability

If , prove that

Show answer & solution
Answer: Proved.
  1. Taking log: , so .
  2. .
  3. Hence proved.
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q23 (OR) (OR)2 marksVery Short AnswerContinuity and Differentiability

Check the differentiability of at x = 1.

Show answer & solution
Answer: Not differentiable at x = 1 (LHD = 2, RHD = –1).
  1. f(1) = 3 - 1 = 2.
  2. LHD .
  3. RHD .
  4. LHD RHD, so f is not differentiable at x = 1.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q242 marksVery Short AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. .
  2. .
  3. .
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q24 (OR) (OR)2 marksVery Short AnswerIntegrals

Given and F(1) = 0, find F(x).

Show answer & solution
Answer:
  1. .
  2. .
  3. , so .
  4. .
Also asked in: 2024 65/3/1, 2024 65/3/2
Q252 marksVery Short AnswerVector Algebra

Find the position vector of point C which divides the line segment joining points A and B having position vectors and respectively in the ratio 4 : 1 externally. Further, find .

Show answer & solution
Answer: ;
  1. .
  2. , .
  3. , .
  4. .
Also asked in: 2024 65/3/1, 2024 65/3/2
Q263 marksShort AnswerLinear Programming

Solve the following linear programming problem graphically :
Maximize z = x + y
subject to constraints


.

Show answer & solution
Answer: Maximum z = 30 at , .
  1. Draw 2x + 5y = 100 (through (50, 0), (0, 20)) and 8x + 5y = 200 (through (25, 0), (0, 40)). The feasible region is bounded, in the first quadrant, on the origin side of both lines.
  2. The lines meet where : , .
  3. Corner points: (0, 0), (25, 0), , (0, 20).
  4. z = x + y: 0, 25, 30, 20.
  5. Maximum z = 30 at .
Q273 marksShort AnswerProbability

The chances of P, Q and R getting selected as CEO of a company are in the ratio 4 : 1 : 2 respectively. The probabilities for the company to increase its profits from the previous year under the new CEO, P, Q or R are 0.3, 0.8 and 0.5 respectively. If the company increased the profits from the previous year, find the probability that it is due to the appointment of R as CEO.

Show answer & solution
Answer:
  1. , , for P, Q, R selected. Let A: profits increase.
  2. , , .
  3. .
  4. By Bayes' theorem, .
Also asked in: 2024 65/3/1, 2024 65/3/2
Q283 marksShort AnswerContinuity and Differentiability

If , prove that , where p is a constant.

Show answer & solution
Answer: Proved.
  1. .
  2. Differentiate w.r.t. y: .
  3. So .
  4. Hence .
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q28 (OR) (OR)3 marksShort AnswerContinuity and Differentiability

Find the value of a and b so that function f defined as :

is a continuous function.

Show answer & solution
Answer: a = 1, b = –1
  1. For : , so . LHL .
  2. For : , so . RHL .
  3. f(2) = a + b.
  4. Continuity at 2: gives ; gives .
  5. So a = 1, b = –1 (f is clearly continuous at other points).
Also asked in: 2024 65/3/1, 2024 65/3/2
Q293 marksShort AnswerApplication of Derivatives

Find the intervals in which the function is strictly increasing or strictly decreasing.

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Answer: Strictly increasing in (0, e); strictly decreasing in .
  1. Domain: .
  2. .
  3. at , i.e. .
  4. For , , so : strictly increasing on (0, e).
  5. For , : strictly decreasing on .
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q29 (OR) (OR)3 marksShort AnswerApplication of Derivatives

Find the absolute maximum and absolute minimum values of the function f given by , on the interval [1, 2].

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Answer: Absolute maximum (at x = 1); absolute minimum 2 (at x = 2).
  1. gives , (in [1, 2]).
  2. Evaluate at critical point and end points: , .
  3. Absolute maximum at x = 1; absolute minimum = 2 at x = 2.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q303 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Put , : .
  2. .
  3. .
  4. .
Q313 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. .
  2. Integral .
  3. This is of the form with .
  4. Answer: .
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q31 (OR) (OR)3 marksShort AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. .
  2. .
  3. At : . At 0: .
  4. .
Also asked in: 2024 65/3/1, 2024 65/3/2
Q325 marksLong AnswerThree Dimensional Geometry

Find the equation of the line passing through the point of intersection of the lines and and perpendicular to these given lines.

Show answer & solution
Answer:
  1. General points: and .
  2. Equating: ; gives ; z: ✓. Intersection point (1, 3, 5).
  3. Required direction .
  4. Line: .
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q32 (OR) (OR)5 marksLong AnswerThree Dimensional Geometry

Two vertices of the parallelogram ABCD are given as A(–1, 2, 1) and B(1, –2, 5). If the equation of the line passing through C and D is , then find the distance between sides AB and CD. Hence, find the area of parallelogram ABCD.

Show answer & solution
Answer: Distance units; area sq units.
  1. , parallel to (direction of CD). , .
  2. Distance between AB and CD = distance of A from line CD. Take P(4, –7, 8) on CD: .
  3. , magnitude .
  4. Distance units.
  5. Area sq units.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q335 marksLong AnswerRelations and Functions

Let A = R – {3} and B = R – {a}. Find the value of ‘a’ such that the function defined by is onto. Also, check whether the given function is one-one or not.

Show answer & solution
Answer: a = 1; f is one-one.
  1. Let . Then , so , defined for every .
  2. Also would give , impossible, so this x always lies in A.
  3. Hence the range of f is R – {1}; f is onto B = R – {a} exactly when a = 1.
  4. One-one: gives , i.e. , so .
  5. So f is one-one.
Q345 marksLong AnswerApplication of Derivatives

It is given that function attains local maximum value at x = 1. Find the value of ‘a’, hence obtain all other points where the given function f(x) attains local maximum or local minimum values.

Show answer & solution
Answer: a = 120; local minimum at x = – 6 and at x = 5 (no other local maximum).
  1. . gives , so a = 120.
  2. .
  3. Critical points: x = 1, – 6, 5. .
  4. : local maximum at x = 1 (as given).
  5. : local minimum at x = – 6, value f(– 6) = – 1647.
  6. : local minimum at x = 5, value f(5) = – 316.
Also asked in: 2024 65/3/1, 2024 65/3/2
OR
Q34 (OR) (OR)5 marksLong AnswerApplication of Derivatives

The perimeter of a rectangular metallic sheet is 300 cm. It is rolled along one of its sides to form a cylinder. Find the dimensions of the rectangular sheet so that volume of cylinder so formed is maximum.

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Answer: 100 cm × 50 cm (the 100 cm side forms the circumference of the base).
  1. Let the sides be x and y with , so . Roll so that side x becomes the base circumference and y the height.
  2. , so . .
  3. gives x = 100 (x ≠ 0).
  4. at x = 100, so V is maximum.
  5. Dimensions: 100 cm and 50 cm.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q355 marksLong AnswerApplication of Integrals

Using integration, find the area of the region enclosed between the curve and the lines x = –1, x = 1 and the x-axis.

Show answer & solution
Answer: sq units
  1. The curve is the upper half of the circle ; the region is symmetric about the y-axis.
  2. Area .
  3. .
  4. sq units.
Q364 marksCase StudyDeterminants

A scholarship is a sum of money provided to a student to help him or her pay for education. Some students are granted scholarships based on their academic achievements, while others are rewarded based on their financial needs.
Every year a school offers scholarships to girl children and meritorious achievers based on certain criteria. In the session 2022 – 23, the school offered monthly scholarship of ₹ 3,000 each to some girl students and ₹ 4,000 each to meritorious achievers in academics as well as sports.
In all, 50 students were given the scholarships and monthly expenditure incurred by the school on scholarships was ₹ 1,80,000.
Based on the above information, answer the following questions :
(i) Express the given information algebraically using matrices. (1)
(ii) Check whether the system of matrix equations so obtained is consistent or not. (1)
(iii) (a) Find the number of scholarships of each kind given by the school, using matrices. (2)
OR (iii) (b) Had the amount of scholarship given to each girl child and meritorious student been interchanged, what would be the monthly expenditure incurred by the school ? (2)

Show answer & solution
Answer: (i) (ii) Consistent, since |A| = 1000 ≠ 0 (iii) (a) 20 girl students and 30 meritorious achievers OR (iii) (b) ₹ 1,70,000
  1. (i) Let x girls get ₹ 3,000 and y meritorious achievers get ₹ 4,000. Then x + y = 50 and 3000x + 4000y = 180000, i.e. AX = B with , , .
  2. (ii) |A| = 4000 – 3000 = 1000 ≠ 0, so A is invertible and the system is consistent (unique solution).
  3. (iii) (a) .
  4. : 20 girl students, 30 meritorious achievers.
  5. (iii) (b) Interchanged: 20 × 4000 + 30 × 3000 = 80000 + 90000 = ₹ 1,70,000.
Also asked in: 2024 65/3/1, 2024 65/3/2
Q374 marksCase StudyProbabilityNot in current syllabus

Self-study helps students to build confidence in learning. It boosts the self-esteem of the learners. Recent surveys suggested that close to 50% learners were self-taught using internet resources and upskilled themselves.
A student may spend 1 hour to 6 hours in a day in upskilling self. The probability distribution of the number of hours spent by a student is given below :

where x denotes the number of hours.
Based on the above information, answer the following questions :
(i) Express the probability distribution given above in the form of a probability distribution table. (1)
(ii) Find the value of k. (1)
(iii) (a) Find the mean number of hours spent by the student. (2)
OR (iii) (b) Find P(1 < X < 6). (2)

Show answer & solution
Answer: (i) X: 1, 2, 3, 4, 5, 6; P(X): k, 4k, 9k, 8k, 10k, 12k (ii) (iii) (a) hours OR (iii) (b)
  1. (i) X: 1, 2, 3, 4, 5, 6 with P(X): k, 4k, 9k, 8k, 10k, 12k.
  2. (ii) Sum of probabilities: k + 4k + 9k + 8k + 10k + 12k = 44k = 1, so .
  3. (iii) (a) Mean hours.
  4. (iii) (b) P(1 < X < 6) = P(2) + P(3) + P(4) + P(5) = 4k + 9k + 8k + 10k = 31k .
Also asked in: 2024 65/3/1, 2024 65/3/2
Q384 marksCase StudyDifferential Equations

A bacteria sample of certain number of bacteria is observed to grow exponentially in a given amount of time. Using exponential growth model, the rate of growth of this sample of bacteria is calculated.
The differential equation representing the growth of bacteria is given as :
, where P is the population of bacteria at any time ‘t’.
Based on the above information, answer the following questions :
(i) Obtain the general solution of the given differential equation and express it as an exponential function of ‘t’. (2)
(ii) If population of bacteria is 1000 at t = 0, and 2000 at t = 1, find the value of k. (2)

Diagram for CBSE 2024 Class 12 Maths question 38
Show answer & solution
Answer: (i) (ii)
  1. (i) Separate variables: .
  2. Integrate: , so (C = ).
  3. (ii) t = 0, P = 1000 gives C = 1000, so .
  4. t = 1, P = 2000: , , (= ).
Also asked in: 2024 65/3/1, 2024 65/3/2
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