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CBSE Class 12 Maths 2024 Question Paper 65/3/1 with Solutions

All 45 questions from the CBSE Class 12 Mathematics board paper, Set 65/3/1 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 65/1/1Set 65/1/2Set 65/1/3Set 65/2/1Set 65/2/2Set 65/2/3Set 65/3/1Set 65/3/2Set 65/3/3Set 65/4/1Set 65/4/2Set 65/4/3Set 65/5/1Set 65/5/2Set 65/5/3
Q11 markMCQMatrices

If A = is an identity matrix, then which of the following is true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. In an identity matrix every diagonal element is 1 and every off-diagonal element is 0.
  2. So when and when , which is option (D).
Also asked in: 2024 65/3/2, 2024 65/3/3

Let denote the set of all non-negative real numbers. Then the function defined as is :

  1. (A)one-one but not onto
  2. (B)onto but not one-one
  3. (C)both one-one and onto
  4. (D)neither one-one nor onto
Show answer & solution
Answer: (A) one-one but not onto
  1. One-one: if with , then .
  2. Not onto: for , , so values in (e.g. 0) have no pre-image.
  3. Hence f is one-one but not onto.
Q31 markMCQDeterminants

Let A = be a square matrix such that adj A = A. Then, (a + b + c + d) is equal to :

  1. (A)2a
  2. (B)2b
  3. (C)2c
  4. (D)0
Show answer & solution
Answer: (A) 2a
  1. adj A = .
  2. adj A = A gives , , , so , , .
  3. a + b + c + d = a + 0 + 0 + a = 2a.
Also asked in: 2024 65/3/2, 2024 65/3/3

A function is :

  1. (A)discontinuous at x = 1 only
  2. (B)discontinuous at x = 0 only
  3. (C)discontinuous at x = 0, 1
  4. (D)continuous everywhere
Show answer & solution
Answer: (D) continuous everywhere
  1. For : .
  2. For : .
  3. Both pieces are continuous and at both give 1, so f is continuous everywhere.
  4. (Also, f is a composition of continuous functions.)
Also asked in: 2024 65/3/2, 2024 65/3/3

If the sides of a square are decreasing at the rate of 1.5 cm/s, the rate of decrease of its perimeter is :

  1. (A)1.5 cm/s
  2. (B)6 cm/s
  3. (C)3 cm/s
  4. (D)2.25 cm/s
Show answer & solution
Answer: (B) 6 cm/s
  1. Perimeter , where x is the side.
  2. cm/s.
  3. So the perimeter decreases at 6 cm/s.
Q61 markMCQIntegrals

, if :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. This is 0 when , i.e. when f is an odd function.
Also asked in: 2024 65/3/3

is an example of a :

  1. (A)variable separable differential equation.
  2. (B)homogeneous differential equation.
  3. (C)first order linear differential equation.
  4. (D)differential equation whose degree is not defined.
Show answer & solution
Answer: (C) first order linear differential equation.
  1. Divide by : .
  2. This has the form with P, Q functions of x only.
  3. So it is a first order linear differential equation.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q81 markMCQVector Algebra

If and , then and are :

  1. (A)collinear vectors which are not parallel
  2. (B)parallel vectors
  3. (C)perpendicular vectors
  4. (D)unit vectors
Show answer & solution
Answer: (C) perpendicular vectors
  1. .
  2. Both vectors are non-zero, so they are perpendicular.
Also asked in: 2024 65/3/2, 2024 65/3/3

If , and are the angles which a line makes with positive directions of x, y and z axes respectively, then which of the following is not true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , so (A) is true.
  2. , so (B) is true.
  3. , so (C) is true.
  4. The sum of the direction cosines need not be 1 (e.g. for the x-axis direction it is 1, but for it is ). So (D) is not true.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q101 markMCQLinear Programming

The restrictions imposed on decision variables involved in an objective function of a linear programming problem are called :

  1. (A)feasible solutions
  2. (B)constraints
  3. (C)optimal solutions
  4. (D)infeasible solutions
Show answer & solution
Answer: (B) constraints
  1. The linear inequalities that restrict the decision variables of an LPP are called its constraints.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q111 markMCQProbability

Let E and F be two events such that P(E) = 0.1, P(F) = 0.3, = 0.4, then P(F|E) is :

  1. (A)0.6
  2. (B)0.4
  3. (C)0.5
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. .
  2. .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q121 markMCQMatrices

If A and B are two skew symmetric matrices, then (AB + BA) is :

  1. (A)a skew symmetric matrix
  2. (B)a symmetric matrix
  3. (C)a null matrix
  4. (D)an identity matrix
Show answer & solution
Answer: (B) a symmetric matrix
  1. , .
  2. .
  3. So AB + BA is symmetric.
Also asked in: 2024 65/3/3
Q131 markMCQDeterminants

If , then the value of k is :

  1. (A)2
  2. (B)– 2
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Expand along the third row: determinant .
  2. gives ; gives .
  3. So (corresponding to ).
Also asked in: 2024 65/3/2

The derivative of w.r.t. is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Let , . , .
  2. .
Q151 markMCQVector Algebra

If and , then :

  1. (A)[– 6, 4]
  2. (B)[0, 4]
  3. (C)[4, 6]
  4. (D)[0, 6]
Show answer & solution
Answer: (D) [0, 6]
  1. .
  2. For , takes all values in [0, 3].
  3. So .
Also asked in: 2024 65/3/2, 2024 65/3/3

If a line makes an angle of with the positive directions of both x-axis and z-axis, then the angle which it makes with the positive direction of y-axis is :

  1. (A)0
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. .
  2. , so .
  3. .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q171 markMCQLinear Programming

Of the following, which group of constraints represents the feasible region given below ?

Diagram for CBSE 2024 Class 12 Maths question 17
  1. (A), ,
  2. (B), ,
  3. (C), ,
  4. (D), ,
Show answer & solution
Answer: (C) , ,
  1. The shaded region lies on the far side of x + 2y = 76 from O (O does not satisfy it), so .
  2. It lies on the same side of 2x + y = 104 as O, so .
  3. It is in the first quadrant, so . Hence option (C).
Also asked in: 2024 65/3/2, 2024 65/3/3
Q181 markMCQMatrices

If A = , then is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. For a diagonal matrix with non-zero diagonal entries, the inverse is the diagonal matrix of reciprocals.
  2. Check: .
  3. So is option (A).
Also asked in: 2024 65/3/2, 2024 65/3/3
Q191 markAssertion–ReasonMatrices

Assertion (A) : Every scalar matrix is a diagonal matrix.
Reason (R) : In a diagonal matrix, all the diagonal elements are 0.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. A scalar matrix has all off-diagonal elements 0 (and equal diagonal elements), so it is diagonal. A is true.
  2. In a diagonal matrix the non-diagonal elements are 0; the diagonal elements need not be 0. R is false.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q201 markAssertion–ReasonVector Algebra

Assertion (A) : Projection of on is same as projection of on .
Reason (R) : Angle between and is same as angle between and numerically.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Projection of on is ; projection of on is .
  2. These are equal only if (or ), so A is false in general.
  3. is symmetric in , , so R is true.
Also asked in: 2024 65/3/2
Q212 marksVery Short AnswerInverse Trigonometric Functions

Evaluate :

Show answer & solution
Answer:
  1. Let , so and .
  2. Let , so and .
  3. Sum .
Q222 marksVery Short AnswerContinuity and Differentiability

If , prove that

Show answer & solution
Answer: Proved.
  1. Taking log: , so .
  2. .
  3. Hence proved.
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q22 (OR) (OR)2 marksVery Short AnswerContinuity and Differentiability

Check the differentiability of at x = 1.

Show answer & solution
Answer: Not differentiable at x = 1 (LHD = 2, RHD = –1).
  1. f(1) = 3 - 1 = 2.
  2. LHD .
  3. RHD .
  4. LHD RHD, so f is not differentiable at x = 1.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q232 marksVery Short AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. .
  2. .
  3. .
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q23 (OR) (OR)2 marksVery Short AnswerIntegrals

Given and F(1) = 0, find F(x).

Show answer & solution
Answer:
  1. .
  2. .
  3. , so .
  4. .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q242 marksVery Short AnswerVector Algebra

Find the position vector of point C which divides the line segment joining points A and B having position vectors and respectively in the ratio 4 : 1 externally. Further, find .

Show answer & solution
Answer: ;
  1. .
  2. , .
  3. , .
  4. .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q252 marksVery Short AnswerVector Algebra

Let and be two non-zero vectors.
Prove that .
State the condition under which equality holds, i.e., .

Show answer & solution
Answer: Proved. Equality holds when .
  1. , where is the angle between them.
  2. Since , .
  3. Equality holds when , i.e. : the vectors are perpendicular.
Q263 marksShort AnswerContinuity and Differentiability

If , prove that , where p is a constant.

Show answer & solution
Answer: Proved.
  1. .
  2. Differentiate w.r.t. y: .
  3. So .
  4. Hence .
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q26 (OR) (OR)3 marksShort AnswerContinuity and Differentiability

Find the value of a and b so that function f defined as :

is a continuous function.

Show answer & solution
Answer: a = 1, b = –1
  1. For : , so . LHL .
  2. For : , so . RHL .
  3. f(2) = a + b.
  4. Continuity at 2: gives ; gives .
  5. So a = 1, b = –1 (f is clearly continuous at other points).
Also asked in: 2024 65/3/2, 2024 65/3/3
Q273 marksShort AnswerApplication of Derivatives

Find the intervals in which the function is strictly increasing or strictly decreasing.

Show answer & solution
Answer: Strictly increasing in (0, e); strictly decreasing in .
  1. Domain: .
  2. .
  3. at , i.e. .
  4. For , , so : strictly increasing on (0, e).
  5. For , : strictly decreasing on .
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q27 (OR) (OR)3 marksShort AnswerApplication of Derivatives

Find the absolute maximum and absolute minimum values of the function f given by , on the interval [1, 2].

Show answer & solution
Answer: Absolute maximum (at x = 1); absolute minimum 2 (at x = 2).
  1. gives , (in [1, 2]).
  2. Evaluate at critical point and end points: , .
  3. Absolute maximum at x = 1; absolute minimum = 2 at x = 2.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q283 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. Put : .
  2. : , . : , .
  3. Integrand .
  4. Integral .
  5. .
Q293 marksShort AnswerIntegrals

Find :

Show answer & solution
Answer:
  1. .
  2. Integral .
  3. This is of the form with .
  4. Answer: .
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q29 (OR) (OR)3 marksShort AnswerIntegrals

Evaluate :

Show answer & solution
Answer:
  1. .
  2. .
  3. At : . At 0: .
  4. .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q303 marksShort AnswerLinear Programming

Solve the following linear programming problem graphically :
Maximise z = 4x + 3y,
subject to the constraints



.

Show answer & solution
Answer: Maximum z = 2600 at x = 200, y = 600.
  1. Draw x + y = 800, 2x + y = 1000 and x = 400; the feasible region is bounded, in the first quadrant, on the origin side of all three lines.
  2. Corner points: O(0, 0), (400, 0), (400, 200) [x = 400 on 2x + y = 1000], (200, 600) [x + y = 800 and 2x + y = 1000], (0, 800).
  3. z = 4x + 3y: 0, 1600, 2200, 2600, 2400.
  4. Maximum z = 2600 at (200, 600).
Q313 marksShort AnswerProbability

The chances of P, Q and R getting selected as CEO of a company are in the ratio 4 : 1 : 2 respectively. The probabilities for the company to increase its profits from the previous year under the new CEO, P, Q or R are 0.3, 0.8 and 0.5 respectively. If the company increased the profits from the previous year, find the probability that it is due to the appointment of R as CEO.

Show answer & solution
Answer:
  1. , , for P, Q, R selected. Let A: profits increase.
  2. , , .
  3. .
  4. By Bayes' theorem, .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q325 marksLong AnswerRelations and Functions

A relation R on set A = {– 4, – 3, – 2, – 1, 0, 1, 2, 3, 4} be defined as R = {(x, y) : x + y is an integer divisible by 2}. Show that R is an equivalence relation. Also, write the equivalence class [2].

Show answer & solution
Answer: R is an equivalence relation; [2] = {– 4, – 2, 0, 2, 4}.
  1. Reflexive: for , is divisible by 2, so .
  2. Symmetric: if , is divisible by 2, so is too; .
  3. Transitive: if , then , , so ; .
  4. Hence R is an equivalence relation.
  5. [2] = {x ∈ A : x + 2 is even} = set of even elements = {– 4, – 2, 0, 2, 4}.
Q335 marksLong AnswerApplication of Derivatives

It is given that function attains local maximum value at x = 1. Find the value of ‘a’, hence obtain all other points where the given function f(x) attains local maximum or local minimum values.

Show answer & solution
Answer: a = 120; local minimum at x = – 6 and at x = 5 (no other local maximum).
  1. . gives , so a = 120.
  2. .
  3. Critical points: x = 1, – 6, 5. .
  4. : local maximum at x = 1 (as given).
  5. : local minimum at x = – 6, value f(– 6) = – 1647.
  6. : local minimum at x = 5, value f(5) = – 316.
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q33 (OR) (OR)5 marksLong AnswerApplication of Derivatives

The perimeter of a rectangular metallic sheet is 300 cm. It is rolled along one of its sides to form a cylinder. Find the dimensions of the rectangular sheet so that volume of cylinder so formed is maximum.

Show answer & solution
Answer: 100 cm × 50 cm (the 100 cm side forms the circumference of the base).
  1. Let the sides be x and y with , so . Roll so that side x becomes the base circumference and y the height.
  2. , so . .
  3. gives x = 100 (x ≠ 0).
  4. at x = 100, so V is maximum.
  5. Dimensions: 100 cm and 50 cm.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q345 marksLong AnswerApplication of Integrals

Using integration, find the area of the region enclosed between the circle and the lines x = – 2 and x = 2.

Show answer & solution
Answer: sq units
  1. The region is the part of the disc between x = – 2 and x = 2; it is symmetric about both axes.
  2. Area .
  3. .
  4. Area sq units.
Q355 marksLong AnswerThree Dimensional Geometry

Find the equation of the line passing through the point of intersection of the lines and and perpendicular to these given lines.

Show answer & solution
Answer:
  1. General points: and .
  2. Equating: ; gives ; z: ✓. Intersection point (1, 3, 5).
  3. Required direction .
  4. Line: .
Also asked in: 2024 65/3/2, 2024 65/3/3
OR
Q35 (OR) (OR)5 marksLong AnswerThree Dimensional Geometry

Two vertices of the parallelogram ABCD are given as A(–1, 2, 1) and B(1, –2, 5). If the equation of the line passing through C and D is , then find the distance between sides AB and CD. Hence, find the area of parallelogram ABCD.

Show answer & solution
Answer: Distance units; area sq units.
  1. , parallel to (direction of CD). , .
  2. Distance between AB and CD = distance of A from line CD. Take P(4, –7, 8) on CD: .
  3. , magnitude .
  4. Distance units.
  5. Area sq units.
Also asked in: 2024 65/3/2, 2024 65/3/3
Q364 marksCase StudyProbabilityNot in current syllabus

Self-study helps students to build confidence in learning. It boosts the self-esteem of the learners. Recent surveys suggested that close to 50% learners were self-taught using internet resources and upskilled themselves.
A student may spend 1 hour to 6 hours in a day in upskilling self. The probability distribution of the number of hours spent by a student is given below :

where x denotes the number of hours.
Based on the above information, answer the following questions :
(i) Express the probability distribution given above in the form of a probability distribution table. (1)
(ii) Find the value of k. (1)
(iii) (a) Find the mean number of hours spent by the student. (2)
OR (iii) (b) Find P(1 < X < 6). (2)

Show answer & solution
Answer: (i) X: 1, 2, 3, 4, 5, 6; P(X): k, 4k, 9k, 8k, 10k, 12k (ii) (iii) (a) hours OR (iii) (b)
  1. (i) X: 1, 2, 3, 4, 5, 6 with P(X): k, 4k, 9k, 8k, 10k, 12k.
  2. (ii) Sum of probabilities: k + 4k + 9k + 8k + 10k + 12k = 44k = 1, so .
  3. (iii) (a) Mean hours.
  4. (iii) (b) P(1 < X < 6) = P(2) + P(3) + P(4) + P(5) = 4k + 9k + 8k + 10k = 31k .
Also asked in: 2024 65/3/2, 2024 65/3/3
Q374 marksCase StudyDifferential Equations

A bacteria sample of certain number of bacteria is observed to grow exponentially in a given amount of time. Using exponential growth model, the rate of growth of this sample of bacteria is calculated.
The differential equation representing the growth of bacteria is given as :
, where P is the population of bacteria at any time ‘t’.
Based on the above information, answer the following questions :
(i) Obtain the general solution of the given differential equation and express it as an exponential function of ‘t’. (2)
(ii) If population of bacteria is 1000 at t = 0, and 2000 at t = 1, find the value of k. (2)

Diagram for CBSE 2024 Class 12 Maths question 37
Show answer & solution
Answer: (i) (ii)
  1. (i) Separate variables: .
  2. Integrate: , so (C = ).
  3. (ii) t = 0, P = 1000 gives C = 1000, so .
  4. t = 1, P = 2000: , , (= ).
Also asked in: 2024 65/3/2, 2024 65/3/3
Q384 marksCase StudyDeterminants

A scholarship is a sum of money provided to a student to help him or her pay for education. Some students are granted scholarships based on their academic achievements, while others are rewarded based on their financial needs.
Every year a school offers scholarships to girl children and meritorious achievers based on certain criteria. In the session 2022 – 23, the school offered monthly scholarship of ₹ 3,000 each to some girl students and ₹ 4,000 each to meritorious achievers in academics as well as sports.
In all, 50 students were given the scholarships and monthly expenditure incurred by the school on scholarships was ₹ 1,80,000.
Based on the above information, answer the following questions :
(i) Express the given information algebraically using matrices. (1)
(ii) Check whether the system of matrix equations so obtained is consistent or not. (1)
(iii) (a) Find the number of scholarships of each kind given by the school, using matrices. (2)
OR (iii) (b) Had the amount of scholarship given to each girl child and meritorious student been interchanged, what would be the monthly expenditure incurred by the school ? (2)

Show answer & solution
Answer: (i) (ii) Consistent, since |A| = 1000 ≠ 0 (iii) (a) 20 girl students and 30 meritorious achievers OR (iii) (b) ₹ 1,70,000
  1. (i) Let x girls get ₹ 3,000 and y meritorious achievers get ₹ 4,000. Then x + y = 50 and 3000x + 4000y = 180000, i.e. AX = B with , , .
  2. (ii) |A| = 4000 – 3000 = 1000 ≠ 0, so A is invertible and the system is consistent (unique solution).
  3. (iii) (a) .
  4. : 20 girl students, 30 meritorious achievers.
  5. (iii) (b) Interchanged: 20 × 4000 + 30 × 3000 = 80000 + 90000 = ₹ 1,70,000.
Also asked in: 2024 65/3/2, 2024 65/3/3
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