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CBSE Class 10 Maths Basic 2023 Question Paper 430/5/1 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/5/1 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/1Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3Set 430/6/1Set 430/6/2Set 430/6/3

The term of an A.P. is 17 and its term is 29. The common difference of this A.P. is :

  1. (A)3
  2. (B)2
  3. (C)5
  4. (D)
Show answer & solution
Answer: (B) 2
  1. and .
  2. Subtracting, , so .
Q21 markMCQCircles

In the given figure, O is the centre of a circle, PQ is a chord and the tangent PT at P makes an angle of with PQ. The measure of is :

Diagram for CBSE 2023 Class 10 Maths question 2
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. OP PT, so .
  2. OP = OQ (radii), so .
  3. .
Also asked in: 2023 Basic 430/5/2
Q31 markMCQProbability

One card is drawn at random from a well shuffled deck of 52 playing cards. What is the probability of getting ‘4 of hearts’ ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. There is only one 4 of hearts in a deck of 52 cards.
  2. P(4 of hearts) .

The distance between the points A(0, 6) and B( 6, 2) is :

  1. (A)6 units
  2. (B) units
  3. (C) units
  4. (D) units
Show answer & solution
Answer: (C) units
  1. AB .
  2. units.
Also asked in: 2023 Basic 430/5/3

The value(s) of k for which the roots of quadratic equation are real, is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. For real roots, .
  2. , so .
Q61 markMCQReal Numbers

LCM of and is :

  1. (A)40
  2. (B)560
  3. (C)1680
  4. (D)1120
Show answer & solution
Answer: (C) 1680
  1. LCM = product of the highest powers of all prime factors.
  2. LCM .
Also asked in: 2023 Basic 430/5/2
Q71 markMCQPolynomials

If one zero of the quadratic polynomial is 2, then the value of k is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Put : .
  2. , so .

If the lines represented by equations and are parallel, then the value of m is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Write the lines as and .
  2. For parallel lines, .
  3. , so .
Q91 markMCQTriangles

and their perimeters are 32 cm and 24 cm respectively. If AB = 10 cm, then DE equals :

  1. (A)8 cm
  2. (B)7.5 cm
  3. (C)15 cm
  4. (D) cm
Show answer & solution
Answer: (B) 7.5 cm
  1. In similar triangles, the ratio of perimeters equals the ratio of corresponding sides.
  2. , so DE cm.

The two roots of the equation are :

  1. (A)real and distinct
  2. (B)not real
  3. (C)real and equal
  4. (D)rational
Show answer & solution
Answer: (C) real and equal
  1. .
  2. So the roots are real and equal.

If , then is equal to :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. .

The sum of the first 100 even natural numbers is :

  1. (A)10100
  2. (B)2550
  3. (C)5050
  4. (D)10010
Show answer & solution
Answer: (A) 10100
  1. The numbers are 2, 4, ..., 200 with .
  2. .
Also asked in: 2023 Basic 430/5/2
Q131 markMCQTriangles

In the given figure, AD = 2 cm, DB = 3 cm, DE = 2.5 cm and DE BC. The value of x is :

Diagram for CBSE 2023 Class 10 Maths question 13
  1. (A)6 cm
  2. (B)3.75 cm
  3. (C)6.25 cm
  4. (D)7.5 cm
Show answer & solution
Answer: (C) 6.25 cm
  1. DE BC, so (AA).
  2. , i.e. .
  3. cm.
Also asked in: 2023 Basic 430/5/3
Q141 markMCQCircles

A circle is of radius 3 cm. The distance between two of its parallel tangents is :

  1. (A)12 cm
  2. (B)6 cm
  3. (C)3 cm
  4. (D)4.5 cm
Show answer & solution
Answer: (B) 6 cm
  1. Parallel tangents touch the circle at the ends of a diameter.
  2. Distance between them = diameter = 2 × 3 = 6 cm.
Q151 markMCQStatistics

The median class for the data given below is :
Class: 20 – 40, 40 – 60, 60 – 80, 80 – 100, 100 – 120
Frequency: 10, 12, 14, 13, 17

  1. (A)80 – 100
  2. (B)20 – 40
  3. (C)40 – 60
  4. (D)60 – 80
Show answer & solution
Answer: (D) 60 – 80
  1. , so .
  2. Cumulative frequencies: 10, 22, 36, 49, 66.
  3. The first cumulative frequency greater than 33 is 36, so the median class is 60 – 80.

If , then equals :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. So the expression .
Also asked in: 2023 Basic 430/5/3
Q171 markMCQTriangles

In two triangles and , it is given that . For these two triangles to be similar, which of the following should be true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)CA = QR
Show answer & solution
Answer: (C)
  1. By SAS similarity, the angles included between the proportional sides must be equal.
  2. The angle between AB and BC is ; the angle between PQ and PR is .
  3. So we need .
Q181 markMCQStatistics

Mean and median of some data are 32 and 30 respectively. Using empirical relation, mode of the data is :

  1. (A)36
  2. (B)26
  3. (C)30
  4. (D)20
Show answer & solution
Answer: (B) 26
  1. Mode = 3 Median − 2 Mean.
  2. Mode = 3 × 30 − 2 × 32 = 90 − 64 = 26.
Q191 markAssertion–ReasonProbability

Assertion (A) : When two coins are tossed together, the probability of getting no tail is .
Reason (R) : The probability P(E) of an event E satisfies P(E) .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (B) Both (A) and (R) are true, but (R) is not the correct explanation of (A).
  1. Outcomes: HH, HT, TH, TT. No tail means HH only.
  2. P(no tail) , so A is true.
  3. R is a true general fact, but it does not explain why the probability is .
Q201 markAssertion–ReasonSurface Areas and Volumes

Assertion (A) : The surface area of largest sphere that can be inscribed in a hollow cube of side ‘a’ cm is cm.
Reason (R) : The surface area of a sphere of radius ‘r’ is .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. The largest sphere has diameter a, so .
  2. Surface area cm, so A is true.
  3. is the volume of a sphere, not its surface area (), so R is false.
Q212 marksVery Short AnswerReal Numbers

Find LCM of 576 and 512 by prime factorization.

Show answer & solution
Answer: 4608
  1. .
  2. .
  3. LCM .
Q222 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

Show answer & solution
Answer:
  1. Numerator .
  2. Denominator .
  3. Value .
  4. Rationalising: .
OR
Q22 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

For A = and B = , verify that :
.

Show answer & solution
Answer: Verified: both sides equal 1.
  1. LHS .
  2. RHS .
  3. = LHS. Hence verified.
Q232 marksVery Short AnswerCircles

In the given figure, tangents AB and AC are drawn to a circle centred at O. If and OB = 5 cm, find lengths OA and AC.

Diagram for CBSE 2023 Class 10 Maths question 23
Show answer & solution
Answer: OA cm, AC cm
  1. OB AB (radius tangent), so is right-angled at B.
  2. , so OA cm.
  3. , so AB cm.
  4. Tangents from an external point are equal, so AC = AB cm.
Q242 marksVery Short AnswerCoordinate Geometry

Show that A(1, 2), B(5, 4), C(3, 8) and D(1, 6) are vertices of a parallelogram ABCD.

Show answer & solution
Answer: Proved.
  1. AB , CD .
  2. BC , DA .
  3. Both pairs of opposite sides are equal (AB = CD and BC = DA), so ABCD is a parallelogram.
  4. (Check: midpoint of AC = (2, 5) = midpoint of BD, so the diagonals bisect each other.)
OR
Q24 (OR) (OR)2 marksVery Short AnswerCoordinate Geometry

Show that the points A(3, 0), B(6, 4) and C(1, 3) are vertices of a right-angled triangle.

Show answer & solution
Answer: Proved.
  1. .
  2. .
  3. .
  4. , so by the converse of Pythagoras theorem the triangle is right-angled at A.
Q252 marksVery Short AnswerArithmetic Progressions

Find the sum of the first 15 terms of the A.P. : .

Show answer & solution
Answer:
  1. , .
  2. .
  3. .

Sabina went to a bank ATM to withdraw ₹ 2,000. She received ₹ 50 and ₹ 100 notes only. If Sabina got 25 notes in all, how many notes of ₹ 50 and ₹ 100 did she receive ?

Show answer & solution
Answer: 10 notes of ₹ 50 and 15 notes of ₹ 100
  1. Let the number of ₹ 50 notes be and ₹ 100 notes be .
  2. ... (1)
  3. , i.e. ... (2)
  4. (2) (1): ; then .
  5. She received 10 notes of ₹ 50 and 15 notes of ₹ 100.
OR
Q26 (OR) (OR)3 marksShort AnswerPair of Linear Equations in Two Variables

Five years ago, Amit was thrice as old as Baljeet. Ten years hence, Amit shall be twice as old as Baljeet. What are their present ages ?

Show answer & solution
Answer: Amit: 50 years, Baljeet: 20 years
  1. Let present ages of Amit and Baljeet be and years.
  2. , so ... (1)
  3. , so ... (2)
  4. From (1) and (2): , so and .
  5. Amit is 50 years and Baljeet is 20 years old.
Q273 marksShort AnswerReal Numbers

Prove that is an irrational number, given that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Suppose is rational, say where is rational.
  2. Then .
  3. Since is rational, is rational, so would be rational.
  4. This contradicts the fact that is irrational.
  5. Hence is irrational.
Q283 marksShort AnswerStatistics

Find mean of the following data :
Class: 0 – 15, 15 – 30, 30 – 45, 45 – 60, 60 – 75, 75 – 90
Frequency: 12, 15, 11, 20, 16, 6

Show answer & solution
Answer: Mean = 43.3125 (about 43.31)
  1. Class marks : 7.5, 22.5, 37.5, 52.5, 67.5, 82.5.
  2. Take , , : .
  3. : ; , .
  4. Mean .
Q293 marksShort AnswerCoordinate Geometry

Determine the ratio in which the point P(a, 2) divides the line segment joining the points A( 4, 3) and B(2, 4). Also, find the value of ‘a’.

Show answer & solution
Answer: 5 : 2,
  1. Let P divide AB in the ratio .
  2. y-coordinate: , so , .
  3. Ratio = 5 : 2.
  4. x-coordinate: .
OR
Q29 (OR) (OR)3 marksShort AnswerCoordinate Geometry

In the given figure, in points D and E are mid-points of sides BC and AC respectively. If given vertices are A(4, 2), B(2, 2) and C( 6, 7), then verify the result DE = AB.

Diagram for CBSE 2023 Class 10 Maths question 29 (OR)
Show answer & solution
Answer: Verified: DE = 1 unit, AB = 2 units.
  1. D = midpoint of BC .
  2. E = midpoint of AC .
  3. DE .
  4. AB .
  5. So DE AB. Verified.
Q303 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS .
  2. .
  3. RHS .
  4. LHS = RHS. Hence proved.
Q313 marksShort AnswerCircles

ABC is an isosceles triangle with AB = AC, circumscribed about a circle. Prove that BC is bisected at E.

Diagram for CBSE 2023 Class 10 Maths question 31
Show answer & solution
Answer: Proved.
  1. The sides AB, BC, CA touch the circle at D, E, F.
  2. Tangents from an external point are equal: AD = AF, BD = BE, CE = CF.
  3. AB = AC gives AD + DB = AF + FC.
  4. Since AD = AF, DB = FC, hence BE = CE.
  5. So E is the mid-point of BC, i.e. BC is bisected at E.

A person walking 48 m towards a tower in a horizontal line through its base observes that angle of elevation of the top of the tower changes from to . Find the height of the tower and distance of the person, now, from the tower. (Use = 1.732)

Show answer & solution
Answer: Height = 113.568 m (about 113.57 m); present distance = 65.568 m (about 65.57 m)
  1. Let the height be and the present distance be m; the earlier distance was m.
  2. , so .
  3. , so .
  4. , so m.
  5. m.
  6. Height of the tower ≈ 113.57 m; the person is now ≈ 65.57 m from the tower.
Q335 marksLong AnswerAreas Related to Circles

In the given figure, AB is a chord of a circle of radius 7 cm and centred at O. Find the area of the shaded region if . Also, find length of minor arc AB.

Diagram for CBSE 2023 Class 10 Maths question 33
Show answer & solution
Answer: Area of shaded region = 14 cm; minor arc AB = 11 cm
  1. Area of sector OAB cm.
  2. Area of cm.
  3. Shaded segment = 38.5 − 24.5 = 14 cm.
  4. Minor arc AB cm.
OR
Q33 (OR) (OR)5 marksLong AnswerAreas Related to Circles

AB and CD are arcs of two concentric circles of radii 3.5 cm and 10.5 cm respectively and centred at O. Find the area of the shaded region if . Also, find the length of arc CD.

Diagram for CBSE 2023 Class 10 Maths question 33 (OR)
Show answer & solution
Answer: Area of shaded region cm; arc CD = 11 cm
  1. Shaded area = sector OCD sector OAB .
  2. cm.
  3. Arc CD cm.
Q345 marksLong AnswerTriangles

If a line is drawn parallel to one side of a triangle to intersect the other two sides at distinct points, then prove that the other two sides are divided in the same ratio.

Show answer & solution
Answer: Proved.
  1. Given: In , DE BC meets AB at D and AC at E. To prove: .
  2. Construction: Join BE and CD; draw EM AB and DN AC.
  3. ar(ADE) and ar(BDE) , so .
  4. Similarly ar(ADE) and ar(DEC) , so .
  5. and are on the same base DE and between the same parallels DE and BC, so ar(BDE) = ar(DEC).
  6. Hence . Proved.
Q355 marksLong AnswerQuadratic Equations

The difference of two numbers is 5 and the difference of their reciprocals is . Find the numbers.

Show answer & solution
Answer: 10 and 5, or and
  1. Let the numbers be and (larger first).
  2. , so .
  3. , i.e. .
  4. gives numbers 10 and 5; gives numbers and .
  5. The numbers are 10 and 5 (or and ).
OR
Q35 (OR) (OR)5 marksLong AnswerQuadratic Equations

Find all the values of k for which the quadratic equation has equal roots. Also, find the roots.

Show answer & solution
Answer: (roots ) or (roots 2, 2)
  1. Equal roots: , so and .
  2. For : , i.e. , roots .
  3. For : , i.e. , roots 2, 2.
Q364 marksCase StudyPolynomials

Rainbow is an arch of colours that is visible in the sky after rain or when water droplets are present in the atmosphere. The colours of the rainbow are generally, red, orange, yellow, green, blue, indigo and violet. Each colour of the rainbow makes a parabola. We know that any quadratic polynomial represents a parabola on the graph paper.
Based on the above, answer the following questions :
(i) The graph of a rainbow is shown in the figure. Write the number of zeroes of the curve. (1)
(ii) If the graph of a rainbow does not intersect the x-axis but intersects y-axis at one point, then how many zeroes will it have ? (1)
(iii) (a) If a rainbow is represented by the quadratic polynomial , whose zeroes are 2 and 3, find the value of a and b. (2)
OR
(iii) (b) The polynomial represents a rainbow. If 4 is a zero of it, find the value of p. (2)

Diagram for CBSE 2023 Class 10 Maths question 36
Show answer & solution
Answer: (i) 2 (ii) 0 (iii) (a) , OR (b)
  1. (i) The curve cuts the x-axis at two points, so it has 2 zeroes.
  2. (ii) It does not meet the x-axis, so it has no (0) zeroes.
  3. (iii) (a) Sum of zeroes , so .
  4. Product of zeroes .
  5. (iii) (b) , so , , .
Q374 marksCase StudySurface Areas and Volumes

Singing bowls (hemispherical in shape) are commonly used in sound healing practices. Mallet (cylindrical in shape) is used to strike the bowl in a sequence to produce sound and vibration.
One such bowl is shown here whose dimensions are :
Hemispherical bowl has outer radius 6 cm and inner radius 5 cm.
Mallet has height of 10 cm and radius 2 cm.
Based on the above, answer the following questions :
(i) What is the volume of the material used in making the mallet ? (1)
(ii) The bowl is to be polished from inside. Find the inner surface area of the bowl. (1)
(iii) (a) Find the volume of metal used to make the bowl. (2)
OR
(iii) (b) Find total surface area of the mallet. (Use ) (2)

Show answer & solution
Answer: (i) cm (ii) cm (iii) (a) cm OR (b) 150.72 cm
  1. (i) Volume of mallet cm.
  2. (ii) Inner surface area cm.
  3. (iii) (a) Volume of metal cm.
  4. (iii) (b) TSA of mallet cm.
Q384 marksCase StudyProbability

Some students were asked to list their favourite colour. The measure of each colour is shown by the central angle of a pie chart given below :
Study the pie chart and answer the following questions :
(i) If a student is chosen at random, then find the probability of his/her favourite colour being white ? (1)
(ii) What is the probability of his/her favourite colour being blue or green ? (1)
(iii) (a) If 15 students liked the colour yellow, how many students participated in the survey ? (2)
OR
(iii) (b) What is the probability of the favourite colour being red or blue ? (2)

Diagram for CBSE 2023 Class 10 Maths question 38
Show answer & solution
Answer: (i) (ii) (iii) (a) 60 OR (b)
  1. (i) P(white) .
  2. (ii) P(blue or green) .
  3. (iii) (a) Yellow has , i.e. of the students. So total .
  4. (iii) (b) P(red or blue) .
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