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CBSE Class 10 Maths Basic 2023 Question Paper 430/6/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/6/3 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/1Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3Set 430/6/1Set 430/6/2Set 430/6/3
Q11 markMCQReal Numbers

The prime factorisation of the number 5488 is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. , so .
Q21 markMCQStatistics

The Empirical relation between the three measures of central tendency is

  1. (A)Mode = 3 Mean – 2 Median
  2. (B)Mode = 2 Median – 3 Mean
  3. (C)Mode = 2 Mean – 3 Median
  4. (D)Mode = 3 Median – 2 Mean
Show answer & solution
Answer: (D) Mode = 3 Median – 2 Mean
  1. The empirical relation is 3 Median = Mode + 2 Mean.
  2. So Mode = 3 Median – 2 Mean.

In the given figure, is a right triangle right angled at Q. If PQ = 4 cm and PR = 8 cm, then is

Diagram for CBSE 2023 Class 10 Maths question 3
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. .
  2. So .
Q41 markMCQStatistics

The median of first 10 natural numbers is

  1. (A)5
  2. (B)6
  3. (C)5.5
  4. (D)6.5
Show answer & solution
Answer: (C) 5.5
  1. Numbers 1 to 10: there are 10 values, so the median is the mean of the 5th and 6th values.
  2. Median .
Q51 markMCQPolynomials

The zeroes of the polynomial are

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. .
  2. Zeroes: and .
Q61 markMCQPolynomials

The graph of is shown in the figure for some polynomial . The number of zeroes of are

Diagram for CBSE 2023 Class 10 Maths question 6
  1. (A)4
  2. (B)3
  3. (C)2
  4. (D)1
Show answer & solution
Answer: (A) 4
  1. The zeroes are the x-coordinates of the points where the graph meets the x-axis.
  2. The graph crosses the x-axis at 4 points (one of them the origin), so has 4 zeroes.

The distance of the point (5, 0) from the origin is

  1. (A)0
  2. (B)5
  3. (C)
  4. (D)
Show answer & solution
Answer: (B) 5
  1. Distance .
Also asked in: 2023 Basic 430/6/1
Q81 markMCQStatistics

If the mean of 6, 7, , 8, y, 14 is 9, then

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Mean .
  2. , so .
Q91 markMCQReal Numbers

If n is a natural number, then cannot end with digit

  1. (A)0
  2. (B)2
  3. (C)4
  4. (D)6
Show answer & solution
Answer: (A) 0
  1. has only the prime factor 2.
  2. A number ending in 0 must have both 2 and 5 as prime factors, so cannot end with 0.
  3. (Its last digits cycle 8, 4, 2, 6.)

Area of a quadrant of a circle of radius 7 cm is

  1. (A)154 cm
  2. (B)77 cm
  3. (C) cm
  4. (D) cm
Show answer & solution
Answer: (C) cm
  1. Area of quadrant cm.
Q111 markMCQCircles

In the given figure, PQ and PR are tangents drawn from P to the circle with centre O such that . The measure of is.

Diagram for CBSE 2023 Class 10 Maths question 11
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. (radius tangent).
  2. In quadrilateral PQOR, .
Q121 markMCQProbability

One card is drawn at random from a well-shuffled deck of 52 playing cards. What is the probability of getting a black king ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. There are 2 black kings (spades and clubs) in 52 cards.
  2. P(black king) .

The value of k, if (6, k) lies on the line represented by , is

  1. (A)
  2. (B)12
  3. (C)
  4. (D)4
Show answer & solution
Answer: (D) 4
  1. Put , : .
  2. , so .
Also asked in: 2023 Basic 430/6/1

If (2, 4) is the mid-point of the line-segment joining (6, 3) and (a, 5), then the value of a is

  1. (A)2
  2. (B)4
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , so and .
  2. (Check: .)
Q151 markMCQProbability

An unbiased die is thrown. The probability of getting an odd prime number is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Outcomes: 1, 2, 3, 4, 5, 6. Odd primes: 3 and 5.
  2. P(odd prime) .

The value of ‘k’ for which the system of equations and have no solution, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. No solution when .
  2. gives ; and .
  3. So .

If are three consecutive terms of an A.P., then the value of is

  1. (A)
  2. (B)2
  3. (C)1
  4. (D)
Show answer & solution
Answer: (D)
  1. For consecutive terms of an A.P., .
  2. So .
Also asked in: 2023 Basic 430/6/1
Q181 markMCQReal Numbers

If HCF (72, 120) = 24, then LCM (72, 120) is

  1. (A)72
  2. (B)120
  3. (C)360
  4. (D)9640
Show answer & solution
Answer: (C) 360
  1. HCF LCM = product of the numbers.
  2. LCM .
Also asked in: 2023 Basic 430/6/1
Q191 markAssertion–ReasonIntroduction to Trigonometry

Assertion (A) : For , and are reciprocal of each other.
Reason (R) :

  1. (A)Both Assertion (A) and Reason (R) are true; and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. , so the two are reciprocals: A is true.
  2. But , not 1: R is false.
Q201 markAssertion–ReasonProbability

Assertion (A) : The probability that a leap year has 53 Sundays is .
Reason (R) : The probability that a non-leap year has 53 Sundays is .

  1. (A)Both Assertion (A) and Reason (R) are true; and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (B) Both A and R are true, but R is not the correct explanation of A.
  1. A leap year has 366 days = 52 weeks + 2 days. The 2 extra days can be (Sun, Mon), (Mon, Tue), ..., (Sat, Sun): 7 cases, 2 contain a Sunday. P , so A is true.
  2. A non-leap year has 365 days = 52 weeks + 1 day; the extra day is Sunday in 1 of 7 cases. P , so R is true.
  3. R is about a non-leap year, so it does not explain A.
Q212 marksVery Short AnswerProbability

A bag contains 30 discs numbered from 1 to 30. One disc is drawn at random from the bag. Find the probability that it bears a number
(a) divisible by 6.
(b) greater than 25.

Show answer & solution
Answer: (a) (b)
  1. Total outcomes = 30.
  2. (a) Multiples of 6: 6, 12, 18, 24, 30, i.e. 5 numbers. P .
  3. (b) Numbers greater than 25: 26, 27, 28, 29, 30, i.e. 5 numbers. P .
Q222 marksVery Short AnswerQuadratic Equations

Find the value of k for which the roots of the quadratic equation are real and equal.

Show answer & solution
Answer:
  1. For real and equal roots, .
  2. , so .
  3. .
OR
Q22 (OR) (OR)2 marksVery Short AnswerQuadratic Equations

If one root of the quadratic equation is seven times the other, then find the value of k.

Show answer & solution
Answer:
  1. Let the roots be and .
  2. Sum: , so .
  3. Product: , so .
  4. , so and .
Q232 marksVery Short AnswerIntroduction to Trigonometry

Evaluate : .

Show answer & solution
Answer: 12
  1. , , .
  2. Value .
Also asked in: 2023 Basic 430/6/1
Q242 marksVery Short AnswerCircles

From a point P, the length of the tangent to a circle is 24 cm and the distance of P from the centre of the circle is 25 cm. Find the radius of the circle.

Show answer & solution
Answer: 7 cm
  1. The radius is perpendicular to the tangent at the point of contact, so radius, tangent and OP form a right triangle with hypotenuse OP.
  2. cm.
Q252 marksVery Short AnswerPolynomials

Find a quadratic polynomial whose zeroes are 6 and .

Show answer & solution
Answer:
  1. Sum of zeroes ; product .
  2. Polynomial (or any non-zero multiple of it).
OR
Q25 (OR) (OR)2 marksVery Short AnswerPolynomials

Find the zeroes of the polynomial .

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Answer: 2 and
  1. .
  2. Zeroes: and .
Q263 marksShort AnswerReal Numbers

Prove that is an irrational number, given that is an irrational number.

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Answer: Proved.
  1. Suppose is rational, say where is rational.
  2. Then .
  3. The right side is rational, so would be rational.
  4. This contradicts the fact that is irrational. Hence is irrational.
Q273 marksShort AnswerQuadratic Equations

Solve for :

Show answer & solution
Answer: or
  1. , so .
  2. , so .
  3. .
  4. Both values are allowed (neither is 0 or 2), so or .
Q283 marksShort AnswerIntroduction to Trigonometry

Prove that

Show answer & solution
Answer: Proved.
  1. LHS
  2. Multiply numerator and denominator by : = RHS.
OR
Q28 (OR) (OR)3 marksShort AnswerIntroduction to Trigonometry

Prove that

Show answer & solution
Answer: Proved.
  1. LHS
  2. = RHS.
Q293 marksShort AnswerTriangles

E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that .

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Answer: Proved.
  1. In and :
  2. (opposite angles of parallelogram ABCD).
  3. AD BC, so AE BC and BE is a transversal; hence (alternate angles).
  4. By AA similarity, .
OR
Q29 (OR) (OR)3 marksShort AnswerTriangles

In the given figure, CM and RN are respectively the medians of and . If , then prove that .

Diagram for CBSE 2023 Class 10 Maths question 29 (OR)
Show answer & solution
Answer: Proved.
  1. Since : and .
  2. M and N are mid-points of AB and PQ, so and .
  3. Hence .
  4. In and : and .
  5. By SAS similarity, .
Q303 marksShort AnswerStatistics

A survey conducted on 20 households in a locality by a group of students resulted in the following frequency table for the number of family members in a household :
Family size: 1-3, 3-5, 5-7, 7-9, 9-11
Number of Families: 7, 8, 2, 2, 1
Find the median of this data.

Show answer & solution
Answer: 3.75
  1. Cumulative frequencies: 7, 15, 17, 19, 20. , .
  2. Median class = 3-5 (first cf ).
  3. , , , .
  4. Median .
Q313 marksShort AnswerCoordinate Geometry

Find the co-ordinates of the points of trisection of the line-segment joining the points (5, 3) and (4, 5).

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Answer: and
  1. Let A(5, 3), B(4, 5). The points of trisection divide AB in the ratios 1 : 2 and 2 : 1.
  2. 1 : 2:
  3. 2 : 1:
Also asked in: 2023 Basic 430/6/1
Q325 marksLong AnswerTriangles

Prove that a line drawn parallel to one side of a triangle to intersect the other two sides in distinct points, divides the two sides in the same ratio.

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Answer: Proved.
  1. Given: In , a line DE BC meets AB at D and AC at E. To prove: .
  2. Construction: Join BE and CD; draw EN AB and DM AC.
  3. ar(ADE) and ar(BDE) , so .
  4. Similarly ar(ADE) and ar(DEC) , so .
  5. Triangles BDE and DEC are on the same base DE and between the same parallels DE and BC, so ar(BDE) = ar(DEC).
  6. Therefore .
OR
Q32 (OR) (OR)5 marksLong AnswerTriangles

In the given figure, and . Prove that .

Diagram for CBSE 2023 Class 10 Maths question 32 (OR)
Show answer & solution
Answer: Proved.
  1. In , i.e. , so (sides opposite equal angles).
  2. Given , so .
  3. In and : and (common angle ).
  4. By SAS similarity, .

From a point on a bridge across a river, the angles of depression of the banks on opposite sides of the river are and respectively. If the bridge is at a height of 3 m from the banks, find the width of the river. (Use )

Show answer & solution
Answer: 8.19 m
  1. Let P be the point on the bridge, 3 m above the foot D on the line joining the banks A and B, with A and B on opposite sides of D.
  2. Angle of depression of A is : , so m.
  3. Angle of depression of B is : , so m.
  4. Width m.
OR
Q33 (OR) (OR)5 marksLong AnswerSome Applications of Trigonometry

From a point on the ground, the angle of elevation of the bottom and top of a transmission tower fixed at the top of a 20 m high building are and respectively. Find the height of the tower. (Use )

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Answer: 14.6 m
  1. Let P be the point on the ground at distance m from the foot of the building, building height 20 m and tower height m.
  2. Bottom of tower: , so m.
  3. Top of tower: , so .
  4. m.
Q345 marksLong AnswerArithmetic Progressions

The sum of the and term of an A.P. is 24 and the sum of the and term of the A.P. is 44. Find the A.P. Also, find the sum of first 25 terms of the A.P.

Show answer & solution
Answer: A.P.: ;
  1. : , so .
  2. : , so .
  3. Subtracting: , so and .
  4. A.P.:
  5. .
Q355 marksLong AnswerSurface Areas and Volumes

A wooden article was made by scooping out a hemisphere from each end of a solid cylinder (as shown in the figure).
If the height of the cylinder is 10 cm and its base is of radius 3.5 cm, find the total surface area of the article.

Diagram for CBSE 2023 Class 10 Maths question 35
Show answer & solution
Answer: 374 cm
  1. TSA = curved surface area of cylinder + 2 curved surface area of hemisphere.
  2. CSA of cylinder cm.
  3. Two hemispheres cm.
  4. TSA cm.
Also asked in: 2023 Standard 30/4/3
Q364 marksCase StudyCircles

People of a circular village Dharamkot want to construct a road nearest to it. The road cannot pass through the village. But the people want the road at a shortest distance from the centre of the village. Suppose the road starts from A which is outside the circular village (as shown in the figure) and touch the boundary of the circular village at B such that AB = 20 m. Also the distance of the point A from the centre O of the village is 25 m.
Based on the above information, answer the following questions :
(i) If B is the mid-point of AC, then find the distance AC. (1)
(ii) Find the shortest distance of the road from the centre of the village. (1)
(iii) Find the circumference of the village. (2)
OR (iii) Find the area of the village. (2)

Diagram for CBSE 2023 Class 10 Maths question 36
Show answer & solution
Answer: (i) 40 m (ii) 15 m (iii) m m OR (iii) m m
  1. (i) m.
  2. (ii) The road AC touches the circle at B, so OB AC and OB is the shortest distance. m.
  3. (iii) Radius = 15 m. Circumference m.
  4. OR (iii) Area m.
Q374 marksCase StudyAreas Related to Circles

For the inauguration of ‘Earth day’ week in a school, badges were given to volunteers. Organisers purchased these badges from an NGO, who made these badges in the form of a circle inscribed in a square of side 8 cm.
O is the centre of the circle and :
Based on the above information, answer the following questions :
(i) What is the area of square ABCD ? (1)
(ii) What is the length of diagonal AC of square ABCD ? (1)
(iii) Find the area of sector OPRQO. (2)
OR (iii) Find the area of remaining part of square ABCD when area of circle is excluded. (2)

Diagram for CBSE 2023 Class 10 Maths question 37
Show answer & solution
Answer: (i) 64 cm (ii) cm (iii) cm cm OR (iii) cm cm
  1. (i) Area cm.
  2. (ii) cm.
  3. (iii) Radius of circle cm, angle . Area of sector cm.
  4. OR (iii) Area of circle cm. Remaining area cm.

Lokesh, a production manager in Mumbai, hires a taxi everyday to go to his office. The taxi charges in Mumbai consists of a fixed charges together with the charges for the distance covered. His office is at a distance of 10 km from his home. For a distance of 10 km to his office, Lokesh paid ₹ 105. While coming back home, he took another route. He covered a distance of 15 km and the charges paid by him were ₹ 155.
Based on the above information, answer the following questions :
(i) What are the fixed charges ? (1)
(ii) What are the charges per km ? (1)
(iii) If fixed charges are ₹ 20 and charges per km are ₹ 10, then how much Lokesh have to pay for travelling a distance of 10 km ? (2)
OR (iii) Find the total amount paid by Lokesh for travelling 10 km from home to office and 25 km from office to home. [Fixed charges and charges per km are as in (i) & (ii). (2)

Show answer & solution
Answer: (i) ₹ 5 (ii) ₹ 10 (iii) ₹ 120 OR (iii) ₹ 360
  1. Let fixed charge = ₹ and charge per km = ₹ .
  2. and . Subtracting, , so and .
  3. (i) Fixed charges = ₹ 5.
  4. (ii) Charges per km = ₹ 10.
  5. (iii) ₹ 120.
  6. OR (iii) Home to office: ; office to home: . Total = ₹ 360.
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