Some Applications of Trigonometry: CBSE Class 10 Previous Year Questions
151 different questions from Some Applications of Trigonometry (NCERT Chapter 9) asked in CBSE Class 10 Maths board exams 2022–2026.
Pick a mark group to practise, each with answers and step-by-step solutions.
From a point on the ground, which is 60 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is found to be 45∘. The height (in metres) of the tower is :
A wire is attached from a point A on the ground to the top of a pole BC, making an angle of elevation as 60∘. If AB = 53 m, then length of the wire is
Radio towers are used for transmitting a range of communication services including radio and television. The tower will either act as an antenna itself or support one or more antennas on its structure. On a similar concept, a radio station tower was built in two sections 'A' and 'B'. Tower is supported by wires from a point 'O' (as shown in figure). Distance between the base of the tower and point 'O' is 6 m. From point 'O', the angle of elevation of the top of the section 'B' is 30∘ and the angle of elevation of the top of section 'A' is 60∘. Based on the above information, answer the following questions : (i) Find the length of the wire from the point 'O' to the top of section 'B'. (1) (ii) Find the length of the wire from the point 'O' to the top of section 'A'. (1) (iii) (a) Find the distance AB. (2) OR (iii) (b) Find the area of △OPB. (2)
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Answer: (i) 43 m (ii) 12 m (iii) (a) 43 m OR (b) 63 m2
P is the base of the tower, OP=6 m, ∠BOP=30∘, ∠AOP=60∘, ∠OPA=90∘.
(i) cos30∘=OBOP, so OB=3/26=312=43 m.
(ii) cos60∘=OAOP, so OA=1/26=12 m.
(iii) (a) AP=6tan60∘=63 m and BP=6tan30∘=36=23 m.
AB=63−23=43 m.
(iii) (b) Area of △OPB=21×OP×BP=21×6×23=63 m2.
Tejas is standing at the top of a building and observes a car at an angle of depression of 30∘ as it approaches the base of the building at a uniform speed. 6 seconds later, the angle of depression increases to 60∘, and at that moment, the car is 25 m away from the building. Based on the information given above, answer the following questions : (i) What is the height of the building ? (1) (ii) What is the distance between the two positions of the car ? (1) (iii) (a) What would be the total time taken by the car to reach the foot of the building from the starting point ? (2) OR (iii) (b) What is the distance of the observer from the car when it makes an angle of 60∘ ? (2)
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Answer: (i) 253 m (ii) 50 m (iii) (a) 9 seconds OR (b) 50 m
In the figure, AB is the building, C and D are the two positions of the car, CB = 25 m.
(i) In △ABC, tan60∘=CBAB, so AB=253 m.
(ii) In △ABD, tan30∘=DBAB, so DB=253×3=75 m. DC = 75 - 25 = 50 m.
(iii)(a) Speed =650=325 m/s. Time for the remaining 25 m =25÷325=3 s.
Elevated water storage tanks are built to store and supply water to nearby colonies. In the diagram given above, AB is an elevated water tank and CD is a nearby multistorey building. The building is 54 metres away from the water tank. From a window (W) of the building, the angle of elevation of top of the tank is 45∘ and angle of depression of its foot is 30∘. (i) Write a relation between d (the height of window) and y. (1) (ii) Determine the value of h. (1) (iii) (a) Determine height of the water tank. (2) OR (iii) (b) Find the value of x and height of the window above ground level. (2)
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Answer: (i) y = 2d (ii) h = 54 m (iii) (a) 54+183 m ≈ 85.18 m OR (iii) (b) x=542 m, window height =183 m ≈ 31.18 m
Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are 60∘ and 30∘ respectively. Find the height of the poles and the distance of the point from the poles.
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Answer: Height =203 m (≈34.64 m); the point is 20 m from one pole and 60 m from the other.
Let each pole have height h m and let the point be x m from the pole whose top is seen at 60°; it is (80 − x) m from the other pole.
A kite is flying at a height of 60 m above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as 30∘. From the bottom of the same building, the angle of elevation of kite is 45∘. Find the length of the string and height of roof from the ground. (Use 3=1.73)
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Answer: Length of string = 69.2 m; height of roof = 25.4 m
Let the building be AB (B at the ground, A at the roof) of height h, the kite at K, 60 m above the ground, and d the horizontal distance of the kite from the building.