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CBSE Class 10 Maths Basic 2023 Question Paper 430/2/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/2/2 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/1Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3Set 430/6/1Set 430/6/2Set 430/6/3

The pair of linear equations and :

  1. (A)is inconsistent
  2. (B)is consistent with many solutions
  3. (C)is consistent with a unique solution
  4. (D)is consistent with two solutions
Show answer & solution
Answer: (c) is consistent with a unique solution
  1. and
  2. Since , the lines intersect at one point.
  3. The pair is consistent with a unique solution.
Q21 markMCQProbability

Which of the following numbers cannot be the probability of an event ?

  1. (A)0.5
  2. (B)5%
  3. (C)
  4. (D)
Show answer & solution
Answer: (c)
  1. A probability must lie between 0 and 1.
  2. 0.5, 5% = 0.05 and all lie in this range.
  3. , so it cannot be a probability.

The value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)9
Show answer & solution
Answer: (d) 9
Also asked in: 2023 Basic 430/2/1

The lines represented by the linear equations and intersect at P. The coordinates of the point P are :

Diagram for CBSE 2023 Class 10 Maths question 4
  1. (A)(4, 0)
  2. (B)(4, 4)
  3. (C)(0, 4)
  4. (D)
Show answer & solution
Answer: (b) (4, 4)
  1. At P, x = 4.
  2. Since P lies on y = x, y = 4.
  3. P = (4, 4)

If the quadratic equation has equal roots, then the value of b is :

  1. (A)0
  2. (B) only
  3. (C)3 only
  4. (D)
Show answer & solution
Answer: (d)
  1. For equal roots, .
  2. , so

A solid is of the form of a cone of radius ‘r’ surmounted on a hemisphere of the same radius. If the height of the cone is the same as the diameter of its base, then the volume of the solid is :

Diagram for CBSE 2023 Class 10 Maths question 6
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (b)
  1. Height of cone h = 2r.
  2. Volume of cone
  3. Volume of hemisphere
  4. Total
Q71 markMCQPolynomials

Graph of a polynomial p(x) is given in the figure. The number of zeroes of p(x) is :

Diagram for CBSE 2023 Class 10 Maths question 7
  1. (A)2
  2. (B)3
  3. (C)4
  4. (D)5
Show answer & solution
Answer: (a) 2
  1. The number of zeroes equals the number of points where the graph meets the x-axis.
  2. The graph cuts the x-axis at two points (the dip between the two humps stays above the axis).
  3. Number of zeroes = 2
Q81 markMCQStatistics

Median and Mode of a distribution are 25 and 21 respectively. Mean of the data using empirical relationship is :

  1. (A)27
  2. (B)29
  3. (C)18
  4. (D)
Show answer & solution
Answer: (a) 27
  1. Empirical relation: 3 Median = Mode + 2 Mean
  2. 2 Mean = 54, so Mean = 27

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (b)

In what ratio does x-axis divide the line segment joining the points and ?

  1. (A)2 : 3
  2. (B)2 : 1
  3. (C)3 : 4
  4. (D)1 : 2
Show answer & solution
Answer: (d) 1 : 2
  1. Let the x-axis divide AB in the ratio k : 1.
  2. y-coordinate of the point
  3. , so
  4. Ratio = 1 : 2
Also asked in: 2023 Basic 430/2/1

The sum of the first 21 terms of an A.P. : 16, 12, 8, 4, ..... is :

  1. (A)
  2. (B)
  3. (C)1176
  4. (D)
Show answer & solution
Answer: (b)
  1. a = 16, d = −4, n = 21

The area of a sector of angle (in degrees) of a circle with radius R is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (d)
  1. Area of a sector = area of the circle
Q131 markMCQReal Numbers

If the HCF of 72 and 234 is 18, then the LCM (72, 234) is :

  1. (A)936
  2. (B)836
  3. (C)324
  4. (D)234
Show answer & solution
Answer: (a) 936
  1. LCM

The curved surface area of a right circular cylinder of height 14 cm is 88 cm. The diameter of its circular base is :

  1. (A)2 cm
  2. (B)1 cm
  3. (C)4 cm
  4. (D)7 cm
Show answer & solution
Answer: (a) 2 cm
  1. CSA
  2. , so r = 1 cm
  3. Diameter = 2 cm
Also asked in: 2023 Basic 430/2/1
Q151 markMCQProbability

A card is drawn at random from a well-shuffled deck of 52 playing cards. The probability that it is a red king, is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (c)
  1. Red kings: king of hearts and king of diamonds, so 2 favourable outcomes.
  2. P(red king)

is equal to :

  1. (A)1
  2. (B)0
  3. (C)9
  4. (D)8
Show answer & solution
Answer: (d) 8
  1. So

The string of a kite in air is 50 m long and it makes an angle of with the horizontal. Assuming the string to be straight, the height of the kite from the ground is :

  1. (A) m
  2. (B) m
  3. (C) m
  4. (D) m
Show answer & solution
Answer: (d) m
  1. Height = string length
  2. m
Q181 markMCQCircles

From a point P, two tangents PQ and PR are drawn to a circle with centre at O. T is a point on the major arc QR of the circle. If , then equals :

Diagram for CBSE 2023 Class 10 Maths question 18
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (c)
  1. (radius tangent).
  2. In quadrilateral OQPR,
  3. Angle at the circumference is half the angle at the centre:
Q191 markAssertion–ReasonProbability

Assertion (A) : The probability of getting a prime number, when a die is thrown once, is .
Reason (R): On the faces of a die, prime numbers are 2, 3, 5.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (d) Assertion (A) is false, but Reason (R) is true.
  1. Prime numbers on a die are 2, 3, 5, so R is true.
  2. P(prime) , so A is false.
  3. Hence (d).
Q201 markAssertion–ReasonPolynomials

Assertion (A) : Polynomial has two real zeroes.
Reason (R) : Zeroes of the polynomial are 0 and a.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (c) Assertion (A) is true, but Reason (R) is false.
  1. , zeroes 0 and : two real zeroes, so A is true.
  2. , zeroes are 0 and , not 0 and a, so R is false.
  3. Hence (c).
Q212 marksVery Short AnswerCoordinate Geometry

Find the value(s) of ‘x’ so that PQ = QR, where the coordinates of P, Q and R are , and respectively.

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Answer: x = 5 or x =
  1. PQ = QR gives , so
  2. , so x = 5 or x =
OR
Q21 (OR) (OR)2 marksVery Short AnswerCoordinate Geometry

The vertices of a triangle are , and . Is the triangle equilateral, isosceles or scalene ?

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Answer: Scalene
  1. Let A(−2, 0), B(2, 3), C(1, −3).
  2. All three sides are different, so the triangle is scalene.
Q222 marksVery Short AnswerPolynomials

are the zeroes of the quadratic polynomial , such that . Find the value of k.

Show answer & solution
Answer: k = 12
  1. and
  2. , so 2k = 24 and k = 12
Q232 marksVery Short AnswerProbability

From a well-shuffled deck of 52 playing cards, all diamond cards are removed. Now, a card is drawn from the remaining pack at random. Find the probability that the selected card is a king.

Show answer & solution
Answer:
  1. Cards left after removing 13 diamonds = 52 − 13 = 39
  2. Kings left (king of diamonds removed) = 3
  3. P(king)
Also asked in: 2023 Basic 430/2/1
Q242 marksVery Short AnswerTriangles

In the given figure, and . Prove that .

Diagram for CBSE 2023 Class 10 Maths question 24
Show answer & solution
Answer: Proved.
  1. In , , so by BPT, ...(1)
  2. In , , so by BPT, ...(2)
  3. From (1) and (2),
  4. Hence .
Q252 marksVery Short AnswerReal Numbers

Find the HCF of the numbers 540 and 630, using prime factorization method.

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Answer: 90
  1. HCF = product of the smallest powers of common primes
OR
Q25 (OR) (OR)2 marksVery Short AnswerReal Numbers

Show that cannot end with the digit 0 for any natural number ‘n’.

Show answer & solution
Answer: Proved.
  1. A number ending with digit 0 is divisible by 10, so its prime factorisation must contain both 2 and 5.
  2. By the Fundamental Theorem of Arithmetic this factorisation is unique, and it has no factor 2.
  3. Hence cannot end with the digit 0 for any natural number n.
Q263 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. RHS
  2. = LHS
OR
Q26 (OR) (OR)3 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS
  2. = RHS
Q273 marksShort AnswerPolynomials

Find the zeroes of the polynomial and verify the relationship between its coefficients and zeroes.

Show answer & solution
Answer: Zeroes: and
  1. Zeroes: x = and x =
  2. Sum and ✓
  3. Product and ✓
Q283 marksShort AnswerCoordinate Geometry

Prove that the points , , and are the vertices of a parallelogram ABCD. Is it also a rectangle ?

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Answer: ABCD is a parallelogram; it is not a rectangle.
  1. Mid-point of AC
  2. Mid-point of BD
  3. The diagonals bisect each other, so ABCD is a parallelogram.
  4. ,
  5. The diagonals are not equal, so ABCD is not a rectangle.
Also asked in: 2023 Basic 430/2/1
Q293 marksShort AnswerAreas Related to Circles

In the given figure, two concentric circles with centre O are shown. Radii of the circles are 2 cm and 5 cm respectively. Find the area of the shaded region.

Diagram for CBSE 2023 Class 10 Maths question 29
Show answer & solution
Answer: 11 cm
  1. The shaded region lies between the outer sector OAC and the inner sector OED, both with central angle .
  2. Area of outer sector
  3. Area of inner sector
  4. Shaded area cm
Q303 marksShort AnswerReal Numbers

Prove that is an irrational number, given that is an irrational number.

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Answer: Proved.
  1. Suppose is rational, say , where p, q are integers and .
  2. Then , so
  3. The right side is rational since p, q are integers, so would be rational.
  4. This contradicts the given fact that is irrational.
  5. Hence is irrational.
Q313 marksShort AnswerCircles

A quadrilateral ABCD is drawn to circumscribe a circle, as shown in the figure. Prove that AB + CD = AD + BC.

Diagram for CBSE 2023 Class 10 Maths question 31
Show answer & solution
Answer: Proved.
  1. Let the circle touch AB, BC, CD and DA at P, Q, R and S respectively.
  2. Tangents drawn from an external point to a circle are equal:
  3. AP = AS, BP = BQ, CR = CQ, DR = DS
  4. Adding: (AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ)
  5. AB + CD = AD + BC
OR
Q31 (OR) (OR)3 marksShort AnswerCircles

Prove that the parallelogram circumscribing a circle is a rhombus.

Show answer & solution
Answer: Proved.
  1. Let parallelogram ABCD touch the circle at P, Q, R, S on AB, BC, CD, DA.
  2. Equal tangents from external points: AP = AS, BP = BQ, CR = CQ, DR = DS
  3. Adding: AB + CD = AD + BC
  4. In a parallelogram AB = CD and AD = BC, so 2AB = 2AD, i.e. AB = AD.
  5. Thus AB = BC = CD = DA, so ABCD is a rhombus.
Q325 marksLong AnswerTriangles

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.

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Answer: Proved.
  1. Given: In , a line DE BC meets AB at D and AC at E.
  2. To prove: .
  3. Construction: Join BE and CD; draw and .
  4. and , so .
  5. Similarly and , so .
  6. Triangles BDE and DEC are on the same base DE and between the same parallels DE and BC, so .
  7. Hence .
Q335 marksLong AnswerArithmetic Progressions

If the sum of the first 7 terms of an A.P. is and that of the first 17 terms is , then find the sum of its first ‘n’ terms.

Show answer & solution
Answer:
  1. , so ...(1)
  2. , so ...(2)
  3. (2) − (1): 5d = −10, d = −2; then a = −3 + 6 = 3
OR
Q33 (OR) (OR)5 marksLong AnswerArithmetic Progressions

A man repays a loan of ₹ 3,250 by paying ₹ 20 in the first month and then increases the payment by ₹ 15 every month. How long will it take to clear the loan ?

Show answer & solution
Answer: 20 months
  1. The monthly payments form an A.P. with a = 20, d = 15, and .
  2. , so
  3. n = 20 (n cannot be negative), so the loan is cleared in 20 months.
Q345 marksLong AnswerStatistics

Find the mean and the median of the following data :
Class: 85–90, 90–95, 95–100, 100–105, 105–110, 110–115
Frequency: 10, 12, 15, 14, 12, 7

Show answer & solution
Answer: Mean ≈ 99.43; Median = ≈ 99.33
  1. Class marks : 87.5, 92.5, 97.5, 102.5, 107.5, 112.5;
  2. : 875, 1110, 1462.5, 1435, 1290, 787.5;
  3. Mean
  4. Cumulative frequencies: 10, 22, 37, 51, 63, 70
  5. , so the median class is 95–100 with l = 95, cf = 22, f = 15, h = 5
  6. Median

From the top of a building 60 m high, the angles of depression of the top and bottom of a tower are observed to be and respectively. Find the height of the tower. Also, find the distance between the building and the tower. (Use )

Show answer & solution
Answer: Height of tower = 40 m; distance = m = 34.64 m
  1. Let AB be the building (AB = 60 m), CD the tower of height h and BD = x the distance between them.
  2. Angle of depression of the bottom D is : , so m
  3. Angle of depression of the top C is :
  4. , so h = 40 m
  5. Distance m
OR
Q35 (OR) (OR)5 marksLong AnswerSome Applications of Trigonometry

The angle of elevation of the top of a building from a point A on the ground is . On moving a distance of 30 m towards its base to the point B, the angle of elevation changes to . Find the height of the building and the distance of its base from point A. (Use )

Show answer & solution
Answer: Height = m = 40.98 m; distance from A = 70.98 m
  1. Let PQ = h be the building with foot Q, and BQ = y.
  2. From B: , so y = h
  3. From A:
  4. , so
  5. m
  6. Distance of base from A = h + 30 = 70.98 m
Q364 marksCase StudySurface Areas and Volumes

A wooden toy is shown in the picture. This is a cuboidal wooden block of dimensions 14 cm 17 cm 4 cm. On its top there are seven cylindrical hollows for bees to fit in. Each cylindrical hollow is of height 3 cm and radius 2 cm.
Based on the above, answer the following questions :
(i) Find the volume of wood carved out to make one cylindrical hollow. (1)
(ii) Find the lateral surface area of the cuboid to paint it with green colour. (1)
(iii) (a) Find the volume of wood in the remaining cuboid after carving out seven cylindrical hollows. (2)
OR (iii) (b) Find the surface area of the top surface of the cuboid to be painted yellow. (2)

Show answer & solution
Answer: (i) cm ≈ 37.71 cm (ii) 248 cm (iii) (a) 688 cm OR (iii) (b) 150 cm
  1. (i) Volume of one hollow cm
  2. (ii) Lateral surface area cm
  3. (iii) (a) Volume of cuboid cm
  4. Wood removed cm, so remaining wood cm
  5. (iii) (b) Area of top face cm
  6. Area of the 7 circular openings cm
  7. Area to be painted yellow cm
Q374 marksCase StudyCircles

Circles play an important part in our life. When a circular object is hung on the wall with a cord at nail N, the cords NA and NB work like tangents. Observe the figure, given that and OA = 5 cm.
Based on the above, answer the following questions :
(i) Find the distance AN. (1)
(ii) Find the measure of . (1)
(iii) (a) Find the total length of cords NA, NB and the chord AB. (2)
OR (iii) (b) If is , then name the type of quadrilateral OANB. Justify your answer. (2)

Diagram for CBSE 2023 Class 10 Maths question 37
Show answer & solution
Answer: (i) cm (ii) (iii) (a) cm ≈ 25.98 cm OR (iii) (b) Square
  1. (i) (radius tangent). In right , , so cm
  2. (ii) ; in quadrilateral OANB,
  3. (iii) (a) NA = NB = cm and , so is equilateral and AB = cm
  4. Total length = cm ≈ 25.98 cm
  5. (iii) (b) If , then , , so
  6. Also gives AN = OA, and NA = NB, OA = OB, so all four sides are equal (5 cm).
  7. All angles are right angles and all sides are equal, so OANB is a square.
Q384 marksCase StudyAreas Related to Circles

Flower beds look beautiful growing in gardens. One such circular park of radius ‘r’ m, has two segments with flowers. One segment which subtends an angle of at the centre is full of red roses, while the other segment with central angle is full of yellow coloured flowers. [See figure]
It is given that the combined area of the two segments (of flowers) is sq m.
Based on the above, answer the following questions :
(i) Write an equation representing the total area of the two segments in terms of ‘r’. (1)
(ii) Find the value of ‘r’. (1)
(iii) (a) Find the area of the segment with red roses. (2)
OR (iii) (b) Find the area of the segment with yellow flowers. (2)

Diagram for CBSE 2023 Class 10 Maths question 38
Show answer & solution
Answer: (i) (ii) r = 14 m (iii) (a) 154 m OR (iii) (b) m
  1. The given total works out only if the flower regions are taken as the regions with central angles and (sector areas), which is the intended reading.
  2. (i) , i.e.
  3. (ii) , so and r = 14 m
  4. (iii) (a) Red roses: m
  5. (iii) (b) Yellow flowers: m
  6. (If true segments are used, red = and yellow = , which gives r ≈ 26.1 m, not a neat value.)
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