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CBSE Class 10 Maths Basic 2024 Question Paper 430/2/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/2/2 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/3/1Set 430/3/2Set 430/3/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3

The difference of the areas of a minor sector of angle and its corresponding major sector of a circle of radius 21 cm, is

  1. (A)231 cm
  2. (B)462 cm
  3. (C)346.5 cm
  4. (D)693 cm
Show answer & solution
Answer: (B) 462 cm
  1. Minor sector ; major sector
  2. Difference
  3. cm
Q21 markMCQStatistics

The annual rainfall record of a city for 66 days is given in the following table :
Rainfall (in cm) : 0–10, 10–20, 20–30, 30–40, 40–50, 50–60
Number of days : 22, 10, 8, 15, 5, 6
The difference of upper limits of modal and median classes is :

  1. (A)10
  2. (B)15
  3. (C)20
  4. (D)30
Show answer & solution
Answer: (C) 20
  1. Highest frequency is 22, so modal class is 0–10 (upper limit 10).
  2. Cumulative frequencies: 22, 32, 40, 55, 60, 66; .
  3. 33 first lies in cf 40, so median class is 20–30 (upper limit 30).
  4. Difference
Q31 markMCQCircles

In the given figure, tangents PA and PB from a point P to a circle with centre O are inclined to each other at an angle of . is equal to

Diagram for CBSE 2024 Class 10 Maths question 3
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. and , so in quadrilateral OAPB, .
  2. OA = OB (radii), so is isosceles.

is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. and
Also asked in: 2024 Basic 430/2/1

If , then is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. (taking the acute angle)
Q61 markMCQPolynomials

The zeroes of the polynomial , are :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Zeroes: and 2

A pole m high casts a shadow 21 m long on the ground, then the sun’s elevation is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
Q81 markMCQReal Numbers

The HCF of smallest 2 – digit number and the smallest composite number is :

  1. (A)2
  2. (B)20
  3. (C)40
  4. (D)4
Show answer & solution
Answer: (A) 2
  1. Smallest 2-digit number = 10 and smallest composite number = 4.
  2. , .
  3. HCF = 2.
Also asked in: 2024 Basic 430/2/1

The total surface area of a solid hemisphere of radius 7 cm is :

  1. (A) cm
  2. (B) cm
  3. (C) cm
  4. (D) cm
Show answer & solution
Answer: (B) cm
  1. TSA of solid hemisphere
  2. cm
Also asked in: 2024 Basic 430/2/1

If , then value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
Also asked in: 2024 Basic 430/2/1

The graph of a pair of linear equations and in two variables and y represents parallel lines, if

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Lines are parallel when the pair is inconsistent.
  2. This happens when .
Q121 markMCQCircles

A line intersecting a circle in two distinct points is called a

  1. (A)secant
  2. (B)chord
  3. (C)diameter
  4. (D)tangent
Show answer & solution
Answer: (A) secant
  1. A line meeting a circle at two distinct points is a secant.
  2. (A chord is only the segment; a tangent meets the circle at one point.)

The value of ‘k’ for which the pair of linear equations and has infinitely many solutions, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. For infinitely many solutions, .
  2. So .
Also asked in: 2024 Basic 430/2/1
Q141 markMCQPolynomials

A quadratic polynomial, the sum of whose zeroes is and their product is 6, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Required polynomial
Q151 markMCQProbability

If P(A) denotes the probability of an event A, then

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Probability of any event lies between 0 and 1, both inclusive.
  2. So .

Which of the following quadratic equations has as a root ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Put :
  2. (A) ; (B) ; (C) ; (D)
  3. Only (A) gives 0.

The distance of the point (3, 4) from the origin is

  1. (A)25
  2. (B)5
  3. (C)7
  4. (D)1
Show answer & solution
Answer: (B) 5
  1. Distance

If the first term of an AP is and common difference , then the seventh term is

  1. (A)
  2. (B)9
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
Q191 markAssertion–ReasonCoordinate Geometry

Assertion (A) : The point (0, 4) lies on y – axis.
Reason (R) : The -coordinate of a point, lying on y – axis, is zero.

  1. (A)Both Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are correct but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A).
  1. Every point on the y-axis has -coordinate 0, so R is true.
  2. The point (0, 4) has -coordinate 0, so it lies on the y-axis; A is true.
  3. R explains A. Answer: (A)
Q201 markAssertion–ReasonTriangles

Assertion (A) : A line drawn parallel to any one side of a triangle intersects the other two sides in the same ratio.
Reason (R) : Parallel lines cannot be drawn to any side of a triangle.

  1. (A)Both Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are correct but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. By the Basic Proportionality Theorem, a line parallel to one side of a triangle meeting the other two sides in distinct points divides them in the same ratio. So A is true.
  2. A line parallel to any side of a triangle can always be drawn, so R is false.
  3. Answer: (C)
Q212 marksVery Short AnswerTriangles

In the given figure, . Prove that .

Diagram for CBSE 2024 Class 10 Maths question 21
Show answer & solution
Answer: Proved.
  1. Given , so .
  2. (vertically opposite angles).
  3. In and , two sides are proportional and the included angles are equal.
  4. Hence (SAS similarity).
OR
Q21 (OR) (OR)2 marksVery Short AnswerTriangles

In the given figure, and . Prove that is isosceles.

Diagram for CBSE 2024 Class 10 Maths question 21 (OR)
Show answer & solution
Answer: Proved.
  1. In , , so (sides opposite equal angles).
  2. Given and , so .
  3. .
  4. Hence is isosceles.
Q222 marksVery Short AnswerProbability

A lot consists of 165 ball pens of which 30 are defective and the others are good. Rakshita will buy a pen if it is good. The shopkeeper draws one pen at random and gives it to Rakshita. What is the probability that she will buy it ?

Show answer & solution
Answer:
  1. Total pens = 165; good pens
  2. P(she buys) = P(good)
Q232 marksVery Short AnswerCircles

Prove that the tangents drawn at the ends of a diameter of a circle are parallel to each other.

Show answer & solution
Answer: Proved.
  1. Let AB be a diameter of a circle with centre O, and let tangents PQ at A and RS at B be drawn.
  2. A tangent is perpendicular to the radius at the point of contact, so and .
  3. Hence and .
  4. These are alternate angles made by transversal AB with PQ and RS, and they are equal.
  5. So .
Q242 marksVery Short AnswerReal Numbers

Find the HCF of 84 and 144 by prime factorisation method.

Show answer & solution
Answer: HCF = 12
  1. HCF = product of smallest powers of common primes
Also asked in: 2024 Basic 430/2/1

The sum of two natural numbers is 70 and their difference is 10. Find the natural numbers.

Show answer & solution
Answer: 40 and 30
  1. Let the numbers be and ().
  2. and
  3. Adding: , so
  4. The numbers are 40 and 30.
OR
Q25 (OR) (OR)2 marksVery Short AnswerPair of Linear Equations in Two Variables

Solve for and y :

Show answer & solution
Answer: ,
  1. Subtract the first equation from the second:
  2. , so
  3. Then , so
Q263 marksShort AnswerAreas Related to Circles

To warn ships for underwater rocks, a light house spreads a red coloured light over a sector of angle to a distance of 16.5 km. Find the area of the sea over which the ships are warned. (Use )

Show answer & solution
Answer: 189.97 km
  1. Area of sector
  2. km
Q273 marksShort AnswerPolynomials

Zeroes of the quadratic polynomial are ‘’ and ‘’. Construct a quadratic polynomial whose zeroes are and .

Show answer & solution
Answer: (or any non-zero multiple)
  1. and
  2. Sum of new zeroes
  3. Product
  4. Polynomial , i.e. (or , )
OR
Q27 (OR) (OR)3 marksShort AnswerPolynomials

Find the zeroes of the polynomial and verify the relationship between the zeroes and the coefficients.

Show answer & solution
Answer: Zeroes: ; relationship verified.
  1. , so zeroes are and .
  2. Sum and .
  3. Product and .
  4. Both relations hold.
Q283 marksShort AnswerIntroduction to Trigonometry

Prove that

Show answer & solution
Answer: Proved.
  1. Let , so .
  2. LHS
  3. So LHS RHS.
Q293 marksShort AnswerProbability

Two dice are tossed simultaneously. Find the probability of getting
(a) an even number on both the dice.
(b) the sum of two numbers more than 9.

Show answer & solution
Answer: (a) (b)
  1. Total outcomes .
  2. (a) Each die shows 2, 4 or 6: outcomes. P
  3. (b) Sum 10: (4,6), (5,5), (6,4); sum 11: (5,6), (6,5); sum 12: (6,6). That is 6 outcomes.
  4. P
Also asked in: 2024 Basic 430/2/1
Q303 marksShort AnswerAreas Related to Circles

A car has two wipers which do not overlap. Each wiper has a blade of length 21 cm sweeping through an angle of . Find the area cleaned at each sweep of the blades.

Show answer & solution
Answer: 924 cm
  1. Each blade sweeps a sector of radius 21 cm and angle .
  2. Area of one sector cm
  3. The wipers do not overlap, so total area cm
Q313 marksShort AnswerCircles

In two concentric circles, a chord of length 24 cm of larger circle touches the smaller circle, whose radius is 5 cm. Find the radius of the larger circle.

Show answer & solution
Answer: 13 cm
  1. Let the chord AB touch the smaller circle at P. Then and OP = 5 cm.
  2. The perpendicular from the centre bisects the chord, so AP = 12 cm.
  3. In right ,
  4. OA = 13 cm, so the radius of the larger circle is 13 cm.
OR
Q31 (OR) (OR)3 marksShort AnswerCircles

Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line segment joining the points of contact at the centre.

Show answer & solution
Answer: Proved.
  1. Let PA and PB be tangents from external point P to a circle with centre O, touching it at A and B.
  2. Radius is perpendicular to tangent, so and .
  3. In quadrilateral OAPB, .
  4. , so the two angles are supplementary.
Q325 marksLong AnswerTriangles

In the given figure, altitudes CE and AD of intersect each other at the point P.
Show that
(i)
(ii)
(iii)

Diagram for CBSE 2024 Class 10 Maths question 32
Show answer & solution
Answer: Proved.
  1. (i) In and : and (vertically opposite). So (AA).
  2. (ii) In and : and (common angle B). So (AA).
  3. (iii) In and : and (common angle A). So (AA).
OR
Q32 (OR) (OR)5 marksLong AnswerTriangles

AD and PM are medians of triangles ABC and PQR, respectively, where . Prove that .

Show answer & solution
Answer: Proved.
  1. Since : and .
  2. D and M are midpoints, so BC = 2BD and QR = 2QM.
  3. Hence .
  4. In and : and , so (SAS).
  5. Therefore .
Q335 marksLong AnswerSurface Areas and Volumes

A textile industry runs in a shed. This shed is in the shape of a cuboid surmounted by a half cylinder. If the base of the industry is of dimensions 14 m 20 m and the height of the cuboidal portion is 7 m, find the volume of air that the industry can hold. Further, suppose the machinery in the industry occupies a total space of 400 m. Then, how much space is left in the industry ?

Diagram for CBSE 2024 Class 10 Maths question 33
Show answer & solution
Answer: Volume of air = 3500 m; space left = 3100 m
  1. Volume of cuboid m
  2. Half cylinder: radius m, length m. Volume m
  3. Volume of air m
  4. Space left m
OR
Q33 (OR) (OR)5 marksLong AnswerSurface Areas and Volumes

From a solid cylinder of height 8 cm and radius 6 cm, a conical cavity of the same height and same radius is carved out. Find the total surface area of the remaining solid. (Take )

Show answer & solution
Answer: 602.88 cm
  1. Slant height of cone cm
  2. TSA = curved surface of cylinder + top circular face + curved surface of cone
  3. cm

From the top of a 7 m high building, the angle of elevation of the top of a cable tower is and the angle of depression of its foot is . Determine the height of the tower. (Use )

Show answer & solution
Answer: m
  1. Let the building be AB = 7 m and the tower CD; let the horizontal distance be .
  2. Angle of depression of the foot is : , so m.
  3. Angle of elevation of the top is : height of tower above the building's top m.
  4. Height of tower m
Q355 marksLong AnswerQuadratic Equations

A cottage industry produces a certain number of pottery articles in a day. It was observed that on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was ₹ 90, find the number of articles produced and the cost of each article.

Show answer & solution
Answer: 6 articles; ₹ 15 each
  1. Let the number of articles be . Cost of each .
  2. ( is rejected)
  3. Cost of each article
Q364 marksCase StudyStatistics

Heart Rate : The heart rate is one of the ‘vital signs’ of health in the human body. It measures the number of times per minute that the heart contracts or beats. While a normal heart rate does not guarantee that a person is free of health problems, it is a useful benchmark for identifying a range of health issues.
Thirty women were examined by doctors of AIIMS and the number of heart beats per minute were recorded and summarized as follows :
Number of heart beats per minute : 65–68, 68–71, 71–74, 74–77, 77–80, 80–83, 83–86
Number of Women : 2, 4, 3, 8, 7, 4, 2
Based on the above information, answer the following questions :
(i) How many women are having heart beat in the range 68 – 77 ? (1)
(ii) What is the median class of heart beats per minute for these women ? (1)
(iii) Find the modal value of heart beats per minute for these women. (2)
OR (iii) Find the median value of heart beats per minute for these women. (2)

Show answer & solution
Answer: (i) 15 (ii) 74–77 (iii) Mode = 76.5; OR (iii) Median = 76.25
  1. (i) Classes 68–71, 71–74, 74–77: women
  2. (ii) Cumulative frequencies: 2, 6, 9, 17, 24, 28, 30; , which first lies in cf 17, so median class is 74–77
  3. (iii) Modal class 74–77: , , , ,
  4. Mode
  5. OR (iii) Median
Q374 marksCase StudyCoordinate Geometry

The top of a table is hexagonal in shape.
On the basis of the information given above, answer the following questions :
(i) Write the coordinates of A and B. (1)
(ii) Write the coordinates of the mid-point of line segment joining C and D. (1)
(iii) Find the distance between M and Q. (2)
OR (iii) Find the coordinates of the point which divides the line segment joining M and N in the ratio 1:3 internally. (2)

Diagram for CBSE 2024 Class 10 Maths question 37
Show answer & solution
Answer: (i) A(1, 9), B(5, 13) (ii) (11, 11) (iii) units; OR (iii) (6, 11)
  1. From the graph: A(1, 9), B(5, 13), C(9, 13), D(13, 9), M(5, 11), N(9, 11), Q(9, 3).
  2. (i) A(1, 9) and B(5, 13)
  3. (ii) Mid-point of CD
  4. (iii) units
  5. OR (iii) Point
Q384 marksCase StudyArithmetic Progressions

Saving money is a good habit and it should be inculcated in children right from the beginning. Rehan’s mother brought a piggy bank for Rehan and puts one ₹ 5 coin of her savings in the piggy bank on the first day. She increases his savings by one ₹ 5 coin daily.
Based on the above information, answer the following questions :
(i) How many coins were added to the piggy bank on 8th day ? (1)
(ii) How much money will be there in the piggy bank after 8 days ? (1)
(iii) If the piggy bank can hold one hundred twenty ₹ 5 coins in all, find the number of days she can contribute to put ₹ 5 coins into it. (2)
OR (iii) Find the total money saved, when the piggy bank is full. (2)

Show answer & solution
Answer: (i) 8 coins (ii) ₹ 180 (iii) 15 days; OR (iii) ₹ 600
  1. Coins added each day: 1, 2, 3, ... form an AP with , .
  2. (i) coins
  3. (ii) Coins after 8 days ; money
  4. (iii) days
  5. OR (iii) Full piggy bank holds 120 coins, so money
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