MonoMath CBSE
CBSE Maths › Class 10 PYQs › 2025

CBSE Class 10 Maths Standard 2025 Question Paper 30/2/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/2/2 (2025), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/3/1Set 30/3/2Set 30/3/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3Set 30/6/1Set 30/6/2Set 30/6/3

The quadratic equation whose sum and product of roots are ‘’ and ‘’ respectively is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Equation:
  2. Multiply by a:

The term from the end (towards first term) of the AP is :

  1. (A)135
  2. (B)125
  3. (C)115
  4. (D)39
Show answer & solution
Answer: (C) 115
  1. Reading from the end, the AP is with first term 147 and
  2. term from the end

The perimeter of the triangle formed by the vertices , and is :

  1. (A)4 units
  2. (B)6 units
  3. (C) units
  4. (D) units
Show answer & solution
Answer: (D) units
  1. Sides: from to is 2; from to is 2
  2. From to :
  3. Perimeter units

The line represented by the equation is :

  1. (A)parallel to x-axis
  2. (B)parallel to y-axis
  3. (C)passing through the origin
  4. (D)passing through the point
Show answer & solution
Answer: (C) passing through the origin
  1. At , , so satisfies
  2. The line passes through the origin (it is neither horizontal nor vertical, and does not satisfy it)
Q51 markMCQPolynomials

If is a zero of the polynomial , then the value of k is :

  1. (A)3
  2. (B)9
  3. (C)6
  4. (D)
Show answer & solution
Answer: (B) 9
  1. , so
Also asked in: 2025 Standard 30/2/1
Q61 markMCQReal Numbers

The HCF of 40, 110 and 360 is :

  1. (A)40
  2. (B)110
  3. (C)360
  4. (D)10
Show answer & solution
Answer: (D) 10
  1. , ,
  2. HCF
Also asked in: 2025 Standard 30/2/1

If a large circular pizza is divided into 5 equal sectors, then the central angle of each sector will be :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Central angle
Also asked in: 2025 Standard 30/2/1
Q81 markMCQReal Numbers

The least number which is a perfect square and is divisible by each of 16, 20 and 50, is :

  1. (A)1200
  2. (B)100
  3. (C)3600
  4. (D)2400
Show answer & solution
Answer: (C) 3600
  1. , ,
  2. LCM , which is itself a perfect square ()
  3. So the true least such number is 400, which is not among the options.
  4. Checking the options: 1200 and 2400 are not perfect squares; 100 is not divisible by 16; and is divisible by 16, 20 and 50.
  5. So the intended option is 3600
Q91 markMCQTriangles

In the given figure, . If and cm, then the length of AQ is :

Diagram for CBSE 2025 Class 10 Maths question 9
  1. (A)2.8 cm
  2. (B)5.8 cm
  3. (C)3.8 cm
  4. (D)4.8 cm
Show answer & solution
Answer: (D) 4.8 cm
  1. By BPT,
  2. So
  3. cm

The coordinates of the end points of a diameter of a circle are and . The length of the radius of the circle is :

  1. (A)
  2. (B)
  3. (C)4
  4. (D)2
Show answer & solution
Answer: (D) 2
  1. Diameter
  2. Radius (a length cannot be negative)

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)0
  4. (D)1
Show answer & solution
Answer: (A)
  1. , so
Q121 markMCQReal Numbers

If , then is equal to :

  1. (A)6
  2. (B)
  3. (C)1
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. , , so
Q131 markMCQProbability

If all the red face cards are removed from the deck of 52 playing cards, then the probability of getting a black jack from the remaining cards is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Red face cards = 6 (J, Q, K of hearts and diamonds), so remaining cards
  2. Black jacks = 2 (spades and clubs)
  3. P(black jack)

The equation of a line parallel to the x-axis and at a distance of 3 units below x-axis is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. A line parallel to the x-axis has equation
  2. 3 units below the x-axis means , so
Also asked in: 2025 Standard 30/2/1
Q151 markMCQCircles

In the given figure, RS is the tangent to the circle at the point L and MN is the diameter. If , then is :

Diagram for CBSE 2025 Class 10 Maths question 15
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Join OL. (radii), so
  2. (radius is perpendicular to tangent), so
Q161 markMCQProbability

In a cricket match, a batsman hits the boundary 7 times out of the 42 balls he plays. The probability of his not hitting a boundary is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Balls without a boundary
  2. P(not a boundary)
Also asked in: 2025 Standard 30/2/1
Q171 markMCQTriangles

Which of the following statements is incorrect ?

  1. (A)Two congruent figures are always similar.
  2. (B)A square and a rhombus of the same area are always similar.
  3. (C)Two equilateral triangles are always similar.
  4. (D)Two similar triangles need not be congruent.
Show answer & solution
Answer: (B) A square and a rhombus of the same area are always similar.
  1. Congruent figures are always similar, all equilateral triangles are similar, and similar triangles need not be congruent: (A), (C), (D) are correct.
  2. A rhombus need not have right angles, so its angles need not equal those of a square; equal area does not make them similar.
  3. So (B) is incorrect

If , then the value of k is :

  1. (A)4
  2. (B)3
  3. (C)2
  4. (D)1
Show answer & solution
Answer: (A) 4
  1. , so

Assertion (A) : The pair of linear equations and will have infinitely many solutions if .
Reason (R) : If the pair of linear equations and has a unique solution, then .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  1. A: with , , so infinitely many solutions; A is true
  2. R: unique solution needs , i.e. ; R is true
  3. R is about a different pair and the unique-solution condition, so it does not explain A
Q201 markAssertion–ReasonArithmetic Progressions

Assertion (A) : Common difference of the AP : is 4.
Reason (R) : Common difference of the AP : is obtained by .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Common difference , not 4, so A is false
  2. is the correct definition, so R is true
Q212 marksVery Short AnswerPolynomials

Find a quadratic polynomial whose zeroes are 2 and .

Show answer & solution
Answer: (or any non-zero multiple )
  1. Sum of zeroes
  2. Product of zeroes
  3. Polynomial: , or multiplying by 5,
Q222 marksVery Short AnswerTriangles

In the given figure, D is a point on the side BC of such that . Show that .

Diagram for CBSE 2025 Class 10 Maths question 22
Show answer & solution
Answer: Proved.
  1. In and : (given) and (common)
  2. So (AA similarity)
  3. Corresponding sides are proportional:
  4. Hence
Also asked in: 2025 Standard 30/2/1
OR
Q22 (OR) (OR)2 marksVery Short AnswerTriangles

In the given figure, . Show that and .

Diagram for CBSE 2025 Class 10 Maths question 22 (OR)
Show answer & solution
Answer: Proved.
  1. Given , so
  2. In and : (vertically opposite angles)
  3. and
  4. So (SAS similarity)
  5. Corresponding angles are equal: and
Also asked in: 2025 Standard 30/2/1
Q232 marksVery Short AnswerAreas Related to Circles

In the given figure, the shape of the top of a table is that of a sector of a circle with centre O and . If cm, then find the perimeter of the top of the table.

Diagram for CBSE 2025 Class 10 Maths question 23
Show answer & solution
Answer: 282 cm
  1. The table top is the major sector, with angle
  2. Arc length cm
  3. Perimeter cm
OR
Q23 (OR) (OR)2 marksVery Short AnswerAreas Related to Circles

In the given figure, three sectors of a circle of radius 5 cm, making angles , and at the centre are shaded. Find the area of the shaded region. [Use ]

Diagram for CBSE 2025 Class 10 Maths question 23 (OR)
Show answer & solution
Answer: cm cm
  1. Total angle of shaded sectors
  2. Shaded area cm
  3. cm
Q242 marksVery Short AnswerCircles

At point A on the diameter AB of a circle of radius 10 cm, tangent XAY is drawn to the circle. Find the length of the chord CD parallel to XY at a distance of 16 cm from A.

Diagram for CBSE 2025 Class 10 Maths question 24
Show answer & solution
Answer: 16 cm
  1. and , so the diameter AB is perpendicular to CD; let it meet CD at P
  2. cm, so cm
  3. In right : cm
  4. The perpendicular from the centre bisects the chord, so cm
Q252 marksVery Short AnswerIntroduction to Trigonometry

If ; where A is an acute angle, then find the value of .

Show answer & solution
Answer:
  1. and A is acute, so
  2. ,
Q263 marksShort AnswerIntroduction to Trigonometry

If and , then prove that .

Show answer & solution
Answer: Proved.
  1. (taking acute)
  2. So
OR
Q26 (OR) (OR)3 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS
  2. = RHS
Q273 marksShort AnswerCoordinate Geometry

If is the mid-point of the line segment joining the points and and , then find the value of k.

Show answer & solution
Answer:
  1. ,
  2. gives , so
  3. , so
Q283 marksShort AnswerArithmetic Progressions

A sum of ₹ 2,000 is invested at 7% per annum simple interest. Calculate the interests at the end of , and year. Do these interests form an AP ? If so, find the interest at the end of the year.

Show answer & solution
Answer: ₹ 140, ₹ 280, ₹ 420; yes, they form an AP; interest at the end of the 27th year = ₹ 3,780
  1. Interest for one year
  2. Interest at end of years 1, 2, 3: ₹ 140, ₹ 280, ₹ 420
  3. Differences are equal (140), so they form an AP with ,
  4. , i.e. ₹ 3,780
Also asked in: 2025 Standard 30/2/1
Q293 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Suppose is rational. Then , where a and b are coprime integers and .
  2. Squaring: , so 3 divides , hence 3 divides a (3 is prime).
  3. Let . Then , so ; hence 3 divides and so 3 divides b.
  4. So 3 is a common factor of a and b, contradicting that they are coprime.
  5. Hence is irrational.
Q303 marksShort AnswerAreas Related to Circles

The length of the hour hand of a clock is 10 cm. Find the area of the minor sector swept by the hour hand of the clock between 5 a.m. to 8 a.m. Also, find the area of the major sector.

Show answer & solution
Answer: Minor sector cm; major sector cm
  1. The hour hand turns per hour; from 5 a.m. to 8 a.m. is 3 hours, so angle
  2. Minor sector cm
  3. Area of circle cm
  4. Major sector cm
Q313 marksShort AnswerCircles

Prove that the parallelogram circumscribing a circle is a rhombus.

Show answer & solution
Answer: Proved.
  1. Let parallelogram ABCD circumscribe a circle, touching AB, BC, CD, DA at P, Q, R, S respectively.
  2. Tangents from an external point are equal: , , ,
  3. Adding: , i.e.
  4. In a parallelogram and , so , i.e.
  5. So , hence ABCD is a rhombus.
OR
Q31 (OR) (OR)3 marksShort AnswerCircles

Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.

Show answer & solution
Answer: Proved.
  1. Let PA and PB be tangents from an external point P to a circle with centre O, touching it at A and B.
  2. The radius is perpendicular to the tangent at the point of contact, so
  3. In quadrilateral OAPB,
  4. , so the angle between the tangents is supplementary to .
Q325 marksLong AnswerQuadratic Equations

The sum of the areas of two squares is 52 cm and difference of their perimeters is 8 cm. Find the lengths of the sides of the two squares.

Show answer & solution
Answer: 6 cm and 4 cm
  1. Let the sides be x cm and y cm with
  2. , so
  3. , i.e.
  4. , so (side cannot be negative)
  5. : sides are 6 cm and 4 cm
Also asked in: 2025 Standard 30/2/1
OR
Q32 (OR) (OR)5 marksLong AnswerQuadratic Equations

The time taken by a person to travel an upward distance of 150 km was hours more than the time taken in the downward return journey. If he returned at a speed of 10 km/h more than the speed while going up, find the speeds in each direction.

Show answer & solution
Answer: Upward speed 20 km/h; downward speed 30 km/h
  1. Let the upward speed be x km/h; downward speed km/h
  2. , so
  3. , so (speed cannot be negative)
  4. Upward 20 km/h, downward 30 km/h
Also asked in: 2025 Standard 30/2/1
Q335 marksLong AnswerTriangles

Prove that a line drawn parallel to one side of a triangle to intersect the other two sides in distinct points divides the other two sides in the same ratio. Hence, in the figure given below, prove that where and .

Diagram for CBSE 2025 Class 10 Maths question 33
Show answer & solution
Answer: Proved.
  1. Theorem (BPT): In , let with S on PQ and T on PR. To prove .
  2. Join QT and RS. Draw and .
  3. and , so
  4. Similarly
  5. and are on the same base ST and between the same parallels ST and QR, so
  6. Hence .
  7. Application: In , , so by BPT
  8. In , , so by BPT
  9. Hence
Q345 marksLong AnswerStatistics

Find the mean and median for the following data :
Classes: 5 – 15, 15 – 25, 25 – 35, 35 – 45, 45 – 55, 55 – 65, 65 – 75
Frequency: 2, 3, 5, 7, 4, 2, 2

Show answer & solution
Answer: Mean ; Median
  1. Class marks : 10, 20, 30, 40, 50, 60, 70
  2. : 20, 60, 150, 280, 200, 120, 140
  3. ,
  4. Mean
  5. Cumulative frequencies: 2, 5, 10, 17, 21, 23, 25;
  6. Median class is 35 – 45: , , ,
  7. Median

The angle of elevation of an airborne helicopter from a point A on the ground is . After a flight of 15 seconds, the angle of elevation of the helicopter changes to . If the helicopter is flying at a constant height of 2000 m, find the speed of the helicopter. (Take )

Show answer & solution
Answer: 97.6 m/s
  1. Initial horizontal distance from A: , so m
  2. Later: , so m
  3. Distance flown m
  4. Speed m/s
OR
Q35 (OR) (OR)5 marksLong AnswerSome Applications of Trigonometry

A girl 1.5 m tall is standing at some distance from a 30 m high tower. The angle of elevation from her eye to the top of the tower increases from to as she walks towards the tower. Find the distance she walked towards the tower.

Show answer & solution
Answer: m m
  1. Height of tower above her eye level m
  2. Initial distance: , so m
  3. Final distance: , so m
  4. Distance walked m
Q364 marksCase StudyProbability

Rahul is a lucky charm for his cricket team. He has a jar of cards with numbers from 10 to 74. Before each match, he draws a card from the jar. If the card bears an even number, the team wins. If the number is even and divisible by 5, they win by a big margin. If the number is an odd number less than 30, they win by a small margin. And if the number is a prime number between 50 and 74, they lose.
Answer the following questions if Rahul draws a card today :
(i) What is the probability that Rahul draws a card with an even number ? (1)
(ii) What is the probability that Rahul draws a card with an odd number less than 30 ? (1)
(iii) (a) What is the probability that Rahul draws a card with a prime number between 50 and 74 ? (2)
OR (iii) (b) What is the probability that Rahul draws a card with an even number divisible by 5 ? (2)

Show answer & solution
Answer: (i) (ii) (iii) (a) ; OR (b)
  1. Total cards: 10 to 74, i.e.
  2. (i) Even numbers 10, 12, ..., 74: ; P
  3. (ii) Odd numbers less than 30: 11, 13, ..., 29, i.e. 10 numbers; P
  4. (iii) (a) Primes between 50 and 74: 53, 59, 61, 67, 71, 73, i.e. 6; P
  5. (iii) (b) Even numbers divisible by 5 are multiples of 10: 10, 20, ..., 70, i.e. 7; P
Q374 marksCase StudySurface Areas and Volumes

A skilled carpenter decided to craft a special rolling pin for the local baker. He carefully joined three cylindrical pieces of wood – two small ones on the ends and one larger in the centre to create a perfect tool. The baker loved the rolling pin, as it rolled out the smoothest dough for breads and pastries.
The length of the bigger cylindrical part is 12 cm and diameter is 7 cm and the length of each smaller cylindrical part is 5 cm and diameter is 2.1 cm.
Based on the above information, answer the following questions :
(i) Find the volume of the bigger cylindrical part. (1)
(ii) Find the curved surface area of the bigger cylindrical part. (1)
(iii) (a) Find the ratio of the volume of the bigger cylindrical part to the total volume of the two smaller (identical) cylindrical parts. (2)
OR (iii) (b) Find the sum of the curved surface areas of the two identical smaller cylindrical parts. (2)

Diagram for CBSE 2025 Class 10 Maths question 37
Show answer & solution
Answer: (i) 462 cm (ii) 264 cm (iii) (a) ; OR (b) 66 cm
  1. (i) Bigger part: cm, cm; cm
  2. (ii) CSA cm
  3. (iii) (a) Each smaller part: cm, cm; cm
  4. Two smaller parts: cm
  5. Ratio
  6. (iii) (b) CSA of one smaller part cm
  7. Sum for two parts cm

A school is organizing a grand cultural event to show the talent of its students. To accommodate the guests, the school plans to rent chairs and tables from a local supplier. It finds that rent for each chair is ₹ 50 and for each table is ₹ 200. The school spends ₹ 30,000 for renting the chairs and tables. Also, the total number of items (chairs and tables) rented are 300.
If the school rents ‘’ chairs and ‘’ tables, answer the following questions :
(i) Write down the pair of linear equations representing the given information. (1)
(ii) (a) Find the number of chairs and number of tables rented by the school. (2)
OR (ii) (b) If the school wants to spend a maximum of ₹ 27,000 on 300 items (tables and chairs), then find the number of chairs and tables it can rent. (2)
(iii) What is maximum number of tables that can be rented in ₹ 30,000 if no chairs are rented ? (1)

Show answer & solution
Answer: (i) and (ii) (a) 200 chairs and 100 tables; OR (b) 220 chairs and 80 tables (iii) 150 tables
  1. (i) Number of items: ; cost: , i.e.
  2. (ii) (a) Subtract: , so , ;
  3. 200 chairs and 100 tables
  4. (ii) (b) and , i.e.
  5. , so , : 220 chairs and 80 tables
  6. (iii) Tables only: , so tables
← 2025 Standard 30/2/1 2025 Standard 30/2/3 →
Practise smarter: chapter-wise revision, formula sheets and step-by-step NCERT solutions on MonoMath CBSE →