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CBSE Class 10 Maths Standard 2025 Question Paper 30/2/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/2/3 (2025), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/3/1Set 30/3/2Set 30/3/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3Set 30/6/1Set 30/6/2Set 30/6/3
Q11 markMCQProbability

If for any event E, , then the value of is :

  1. (A)0
  2. (B)
  3. (C)2
  4. (D)1
Show answer & solution
Answer: (B)
  1. For any event, , so

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)0
  4. (D)1
Show answer & solution
Answer: (D) 1
  1. with gives

If an arc of a circle of diameter 10 cm subtends an angle of at the centre of the circle, then the length of the arc is :

  1. (A) cm
  2. (B) cm
  3. (C) cm
  4. (D) cm
Show answer & solution
Answer: (B) cm
  1. Radius cm
  2. Arc length cm
Q41 markMCQReal Numbers

If , where ‘’ and ‘’ are positive integers, then the value of is :

  1. (A)72
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. , so ,
  2. , so
  3. (The trivial pair , gives , which is not an option.)
Q51 markMCQPolynomials

If one zero of the polynomial is reciprocal of the other, then the value of ‘’ is :

  1. (A)
  2. (B)1
  3. (C)
  4. (D)2
Show answer & solution
Answer: (D) 2
  1. If the zeroes are and , their product is 1
  2. Product of zeroes
  3. , i.e. , so

The equation of a line parallel to y-axis and at a distance of 5 units to the right of y-axis is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
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Answer: (A)
  1. A line parallel to the y-axis has equation
  2. 5 units to the right of the y-axis means , so
Q71 markMCQReal Numbers

The sum of the exponents of prime factors in the prime factorisation of 4004 is :

  1. (A)5
  2. (B)4
  3. (C)3
  4. (D)2
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Answer: (A) 5
  1. Sum of exponents
Also asked in: 2025 Standard 30/2/1
Q81 markMCQProbability

The probability of drawing an even prime number out of numbers from 1 to 30 is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)0
Show answer & solution
Answer: (A)
  1. Total outcomes = 30
  2. The only even prime is 2, so favourable outcomes = 1
  3. P(even prime)
Also asked in: 2025 Standard 30/2/1
Q91 markMCQTriangles

In the given figure, . If and cm, then the length of AQ is :

Diagram for CBSE 2025 Class 10 Maths question 9
  1. (A)2.8 cm
  2. (B)5.8 cm
  3. (C)3.8 cm
  4. (D)4.8 cm
Show answer & solution
Answer: (D) 4.8 cm
  1. By BPT,
  2. So
  3. cm

The line represented by the equation is :

  1. (A)parallel to x-axis
  2. (B)parallel to y-axis
  3. (C)passing through the origin
  4. (D)passing through the point
Show answer & solution
Answer: (C) passing through the origin
  1. At , , so satisfies
  2. The line passes through the origin (it is neither horizontal nor vertical, and does not satisfy it)

The points , and are the vertices of a triangle which is a/an :

  1. (A)right-angled triangle
  2. (B)isosceles triangle
  3. (C)equilateral triangle
  4. (D)scalene triangle
Show answer & solution
Answer: (B) isosceles triangle
  1. Let , ,
  2. , ,
  3. , and , , so it is not right-angled
  4. The triangle is isosceles
Also asked in: 2025 Standard 30/2/1

The term of the AP
is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. ,
Also asked in: 2025 Standard 30/2/1
Q131 markMCQCircles

In the given figure, RS is the tangent to the circle at the point L and MN is the diameter. If , then is :

Diagram for CBSE 2025 Class 10 Maths question 13
  1. (A)
  2. (B)
  3. (C)
  4. (D)
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Answer: (B)
  1. Join OL. (radii), so
  2. (radius is perpendicular to tangent), so

The coordinates of the end points of a diameter of a circle are and . The length of the radius of the circle is :

  1. (A)
  2. (B)
  3. (C)4
  4. (D)2
Show answer & solution
Answer: (D) 2
  1. Diameter
  2. Radius (a length cannot be negative)
Q151 markMCQTriangles

Which of the following statements is incorrect ?

  1. (A)Two congruent figures are always similar.
  2. (B)A square and a rhombus of the same area are always similar.
  3. (C)Two equilateral triangles are always similar.
  4. (D)Two similar triangles need not be congruent.
Show answer & solution
Answer: (B) A square and a rhombus of the same area are always similar.
  1. Congruent figures are always similar, all equilateral triangles are similar, and similar triangles need not be congruent: (A), (C), (D) are correct.
  2. A rhombus need not have right angles, so its angles need not equal those of a square; equal area does not make them similar.
  3. So (B) is incorrect
Q161 markMCQReal Numbers

The least number which is a perfect square and is divisible by each of 16, 20 and 50, is :

  1. (A)1200
  2. (B)100
  3. (C)3600
  4. (D)2400
Show answer & solution
Answer: (C) 3600
  1. , ,
  2. LCM , which is itself a perfect square ()
  3. So the true least such number is 400, which is not among the options.
  4. Checking the options: 1200 and 2400 are not perfect squares; 100 is not divisible by 16; and is divisible by 16, 20 and 50.
  5. So the intended option is 3600

If , then the value of k is :

  1. (A)4
  2. (B)3
  3. (C)2
  4. (D)1
Show answer & solution
Answer: (A) 4
  1. , so

The quadratic equation whose roots are 7 and is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Sum of roots , product
  2. Equation:
  3. Multiply by 7:
Also asked in: 2025 Standard 30/2/1
Q191 markAssertion–ReasonArithmetic Progressions

Assertion (A) : Common difference of the AP : is 4.
Reason (R) : Common difference of the AP : is obtained by .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Common difference , not 4, so A is false
  2. is the correct definition, so R is true

Assertion (A) : The pair of linear equations and will have infinitely many solutions if .
Reason (R) : If the pair of linear equations and has a unique solution, then .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  1. A: with , , so infinitely many solutions; A is true
  2. R: unique solution needs , i.e. ; R is true
  3. R is about a different pair and the unique-solution condition, so it does not explain A
Q212 marksVery Short AnswerAreas Related to Circles

In the given figure, the shape of the top of a table is that of a sector of a circle with centre O and . If cm, then find the perimeter of the top of the table.

Diagram for CBSE 2025 Class 10 Maths question 21
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Answer: 282 cm
  1. The table top is the major sector, with angle
  2. Arc length cm
  3. Perimeter cm
OR
Q21 (OR) (OR)2 marksVery Short AnswerAreas Related to Circles

In the given figure, three sectors of a circle of radius 5 cm, making angles , and at the centre are shaded. Find the area of the shaded region. [Use ]

Diagram for CBSE 2025 Class 10 Maths question 21 (OR)
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Answer: cm cm
  1. Total angle of shaded sectors
  2. Shaded area cm
  3. cm
Q222 marksVery Short AnswerCircles

At point A on the diameter AB of a circle of radius 10 cm, tangent XAY is drawn to the circle. Find the length of the chord CD parallel to XY at a distance of 16 cm from A.

Diagram for CBSE 2025 Class 10 Maths question 22
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Answer: 16 cm
  1. and , so the diameter AB is perpendicular to CD; let it meet CD at P
  2. cm, so cm
  3. In right : cm
  4. The perpendicular from the centre bisects the chord, so cm
Q232 marksVery Short AnswerPolynomials

If p and q are zeroes of the polynomial , then find the value of .

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Answer:
  1. ,
Also asked in: 2025 Standard 30/2/1
Q242 marksVery Short AnswerIntroduction to Trigonometry

If ; where A is an acute angle, then find the value of .

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Answer:
  1. and A is acute, so
  2. ,
Q252 marksVery Short AnswerTriangles

In the given figure, and . Prove that is an isosceles triangle.

Diagram for CBSE 2025 Class 10 Maths question 25
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Answer: Proved.
  1. Since , by the converse of the Basic Proportionality Theorem,
  2. So (corresponding angles)
  3. Given , hence
  4. Sides opposite equal angles are equal:
  5. So is isosceles
OR
Q25 (OR) (OR)2 marksVery Short AnswerTriangles

In the given figure, . Prove that .

Diagram for CBSE 2025 Class 10 Maths question 25 (OR)
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Answer: Proved.
  1. , so by CPCT and
  2. Hence
  3. In and : (common)
  4. and
  5. So (SAS similarity)
Q263 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS (taking acute)
  2. RHS
  3. So LHS = RHS
Also asked in: 2024 Standard 30/4/3
OR
Q26 (OR) (OR)3 marksShort AnswerIntroduction to Trigonometry

If , prove that or .

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Answer: Proved.
  1. , so
  2. If :
  3. If :
  4. Hence or
Q273 marksShort AnswerArithmetic Progressions

Find the sum of all 3-digit natural numbers which are divisible by 11.

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Answer: 44550
  1. 3-digit multiples of 11: 110, 121, ..., 990, an AP with ,
  2. , so ,
Q283 marksShort AnswerAreas Related to Circles

The length of the hour hand of a clock is 10 cm. Find the area of the minor sector swept by the hour hand of the clock between 5 a.m. to 8 a.m. Also, find the area of the major sector.

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Answer: Minor sector cm; major sector cm
  1. The hour hand turns per hour; from 5 a.m. to 8 a.m. is 3 hours, so angle
  2. Minor sector cm
  3. Area of circle cm
  4. Major sector cm
Q293 marksShort AnswerCircles

Prove that the parallelogram circumscribing a circle is a rhombus.

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Answer: Proved.
  1. Let parallelogram ABCD circumscribe a circle, touching AB, BC, CD, DA at P, Q, R, S respectively.
  2. Tangents from an external point are equal: , , ,
  3. Adding: , i.e.
  4. In a parallelogram and , so , i.e.
  5. So , hence ABCD is a rhombus.
OR
Q29 (OR) (OR)3 marksShort AnswerCircles

Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.

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Answer: Proved.
  1. Let PA and PB be tangents from an external point P to a circle with centre O, touching it at A and B.
  2. The radius is perpendicular to the tangent at the point of contact, so
  3. In quadrilateral OAPB,
  4. , so the angle between the tangents is supplementary to .
Q303 marksShort AnswerCoordinate Geometry

If the mid-point of the line segment joining the points and is and , then find the value of k.

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Answer:
  1. ,
  2. , so
Also asked in: 2025 Standard 30/2/1
Q313 marksShort AnswerReal Numbers

Prove that is an irrational number.

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Answer: Proved.
  1. Suppose is rational. Then , where a and b are coprime integers and .
  2. Squaring: , so 3 divides , hence 3 divides a (3 is prime).
  3. Let . Then , so ; hence 3 divides and so 3 divides b.
  4. So 3 is a common factor of a and b, contradicting that they are coprime.
  5. Hence is irrational.
Q325 marksLong AnswerTriangles

Prove that a line drawn parallel to one side of a triangle to intersect the other two sides in distinct points divides the other two sides in the same ratio. Hence, in the figure given below, prove that where and .

Diagram for CBSE 2025 Class 10 Maths question 32
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Answer: Proved.
  1. Theorem (BPT): In , let with S on PQ and T on PR. To prove .
  2. Join QT and RS. Draw and .
  3. and , so
  4. Similarly
  5. and are on the same base ST and between the same parallels ST and QR, so
  6. Hence .
  7. Application: In , , so by BPT
  8. In , , so by BPT
  9. Hence

Two ships are sailing in the sea on either side of a lighthouse. The angles of depression to the two ships as observed from the top of the lighthouse are and , respectively. If the distance between the ships is m, then find the height of the lighthouse.

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Answer: 100 m
  1. Let the height be h m; the ships are at distances x and y from the foot on opposite sides
  2. , so
  3. , so
  4. Equating with : m
Also asked in: 2025 Standard 30/2/1
OR
Q33 (OR) (OR)5 marksLong AnswerSome Applications of Trigonometry

The angles of depression of the top and the bottom of an 8 m tall building from the top of another multistoried building are and , respectively. Find the height of the multistoried building and the distance between the two buildings.

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Answer: Height m m; distance m m
  1. Let the multistoried building have height H m and let the distance between the buildings be d m
  2. Bottom of 8 m building: , so
  3. Top of 8 m building: , so
  4. , so
  5. m
Also asked in: 2025 Standard 30/2/1
Q345 marksLong AnswerStatistics

Find the Mean and Mode of the following data :
Class: 4 – 8, 8 – 12, 12 – 16, 16 – 20, 20 – 24, 24 – 28, 28 – 32, 32 – 36
Frequency: 2, 12, 15, 25, 18, 12, 13, 3

Show answer & solution
Answer: Mean ; Mode
  1. Class marks : 6, 10, 14, 18, 22, 26, 30, 34
  2. : 12, 120, 210, 450, 396, 312, 390, 102
  3. ,
  4. Mean
  5. Modal class is 16 – 20 (highest frequency 25): , , , ,
  6. Mode
Q355 marksLong AnswerQuadratic Equations

The numerator of a fraction is 3 less than its denominator. If 2 is added to both numerator and denominator, then the sum of the new fraction and the original fraction is . Find the original fraction.

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Answer:
  1. Let the numerator be x; denominator
  2. , so or (rejected: negative and not an integer)
  3. Original fraction (check: )
OR
Q35 (OR) (OR)5 marksLong AnswerQuadratic Equations

A train travelling at a uniform speed for 360 km would have taken 48 minutes less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train.

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Answer: 45 km/h
  1. Let the original speed be x km/h
  2. , so
  3. , i.e.
  4. (speed cannot be negative): original speed 45 km/h
Q364 marksCase StudySurface Areas and Volumes

A skilled carpenter decided to craft a special rolling pin for the local baker. He carefully joined three cylindrical pieces of wood – two small ones on the ends and one larger in the centre to create a perfect tool. The baker loved the rolling pin, as it rolled out the smoothest dough for breads and pastries.
The length of the bigger cylindrical part is 12 cm and diameter is 7 cm and the length of each smaller cylindrical part is 5 cm and diameter is 2.1 cm.
Based on the above information, answer the following questions :
(i) Find the volume of the bigger cylindrical part. (1)
(ii) Find the curved surface area of the bigger cylindrical part. (1)
(iii) (a) Find the ratio of the volume of the bigger cylindrical part to the total volume of the two smaller (identical) cylindrical parts. (2)
OR (iii) (b) Find the sum of the curved surface areas of the two identical smaller cylindrical parts. (2)

Diagram for CBSE 2025 Class 10 Maths question 36
Show answer & solution
Answer: (i) 462 cm (ii) 264 cm (iii) (a) ; OR (b) 66 cm
  1. (i) Bigger part: cm, cm; cm
  2. (ii) CSA cm
  3. (iii) (a) Each smaller part: cm, cm; cm
  4. Two smaller parts: cm
  5. Ratio
  6. (iii) (b) CSA of one smaller part cm
  7. Sum for two parts cm

A school is organizing a grand cultural event to show the talent of its students. To accommodate the guests, the school plans to rent chairs and tables from a local supplier. It finds that rent for each chair is ₹ 50 and for each table is ₹ 200. The school spends ₹ 30,000 for renting the chairs and tables. Also, the total number of items (chairs and tables) rented are 300.
If the school rents ‘’ chairs and ‘’ tables, answer the following questions :
(i) Write down the pair of linear equations representing the given information. (1)
(ii) (a) Find the number of chairs and number of tables rented by the school. (2)
OR (ii) (b) If the school wants to spend a maximum of ₹ 27,000 on 300 items (tables and chairs), then find the number of chairs and tables it can rent. (2)
(iii) What is maximum number of tables that can be rented in ₹ 30,000 if no chairs are rented ? (1)

Show answer & solution
Answer: (i) and (ii) (a) 200 chairs and 100 tables; OR (b) 220 chairs and 80 tables (iii) 150 tables
  1. (i) Number of items: ; cost: , i.e.
  2. (ii) (a) Subtract: , so , ;
  3. 200 chairs and 100 tables
  4. (ii) (b) and , i.e.
  5. , so , : 220 chairs and 80 tables
  6. (iii) Tables only: , so tables
Q384 marksCase StudyProbability

Rahul is a lucky charm for his cricket team. He has a jar of cards with numbers from 10 to 74. Before each match, he draws a card from the jar. If the card bears an even number, the team wins. If the number is even and divisible by 5, they win by a big margin. If the number is an odd number less than 30, they win by a small margin. And if the number is a prime number between 50 and 74, they lose.
Answer the following questions if Rahul draws a card today :
(i) What is the probability that Rahul draws a card with an even number ? (1)
(ii) What is the probability that Rahul draws a card with an odd number less than 30 ? (1)
(iii) (a) What is the probability that Rahul draws a card with a prime number between 50 and 74 ? (2)
OR (iii) (b) What is the probability that Rahul draws a card with an even number divisible by 5 ? (2)

Show answer & solution
Answer: (i) (ii) (iii) (a) ; OR (b)
  1. Total cards: 10 to 74, i.e.
  2. (i) Even numbers 10, 12, ..., 74: ; P
  3. (ii) Odd numbers less than 30: 11, 13, ..., 29, i.e. 10 numbers; P
  4. (iii) (a) Primes between 50 and 74: 53, 59, 61, 67, 71, 73, i.e. 6; P
  5. (iii) (b) Even numbers divisible by 5 are multiples of 10: 10, 20, ..., 70, i.e. 7; P
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