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CBSE Class 10 Maths Standard 2024 Question Paper 30/3/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/3/2 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/3/1Set 30/3/2Set 30/3/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3
Q11 markMCQCircles

In the given figure, if PT is a tangent to a circle with centre O and , then the measure of is :

Diagram for CBSE 2024 Class 10 Maths question 1
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. OT is a radius and PT is a tangent at T, so .
  2. In : .
  3. T, O and the other end of the line through T and O lie on a straight line, so .
Q21 markMCQProbability

The probability of guessing the correct answer to a certain test question is . If the probability of not guessing the correct answer to this question is , then the value of is :

  1. (A)2
  2. (B)3
  3. (C)4
  4. (D)6
Show answer & solution
Answer: (A) 2
  1. P(correct) + P(not correct) = 1.
  2. .
  3. .
Also asked in: 2024 Standard 30/3/1

From a point on the ground, which is 30 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is found to be . The height (in metres) of the tower is :

  1. (A)
  2. (B)
  3. (C)60
  4. (D)30
Show answer & solution
Answer: (B)
  1. Let the height be m. Then .
  2. m.
Q41 markMCQCircles

In the given figure, O is the centre of the circle. MN is the chord and the tangent ML at point M makes an angle of with MN. The measure of is :

Diagram for CBSE 2024 Class 10 Maths question 4
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. (radius tangent), so .
  2. OM = ON, so .
  3. .

If a pair of linear equations in two variables is consistent, then the lines represented by the two equations are :

  1. (A)always intersecting
  2. (B)parallel
  3. (C)always coincident
  4. (D)intersecting or coincident
Show answer & solution
Answer: (D) intersecting or coincident
  1. A consistent pair has at least one solution.
  2. Intersecting lines give exactly one solution and coincident lines give infinitely many; parallel lines give none.
  3. So the lines are intersecting or coincident.

If the area of a sector of a circle is of the area of the circle, then the angle at the centre is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Area of sector = .
  2. .
Q71 markMCQProbability

If a digit is chosen at random from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9; then the probability that this digit is an odd prime number is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Total outcomes = 9.
  2. Odd primes among them: 3, 5, 7, i.e. 3 outcomes.
  3. P(odd prime) = .
Also asked in: 2024 Standard 30/3/1
Q81 markMCQTriangles

If the diagonals of a quadrilateral divide each other proportionally, then it is a :

  1. (A)parallelogram
  2. (B)rectangle
  3. (C)square
  4. (D)trapezium
Show answer & solution
Answer: (D) trapezium
  1. Let diagonals AC and BD of quadrilateral ABCD meet at O with .
  2. Draw OE DC through O meeting AD at E. By BPT in , .
  3. By the converse of BPT in , EO AB, so AB DC.
  4. Hence the quadrilateral is a trapezium.
Q91 markMCQReal Numbers

If , , and LCM (a, b, c) = 3780, then is equal to

  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)0
Show answer & solution
Answer: (C) 3
  1. .
  2. LCM (a, b, c) (taking the highest power of each prime, with ).
  3. Comparing the powers of 3: , so .
Also asked in: 2024 Standard 30/3/1
Q101 markMCQProbability

Two coins are tossed simultaneously. The probability of getting at most one tail is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)1
Show answer & solution
Answer: (C)
  1. Outcomes: HH, HT, TH, TT (4 outcomes).
  2. At most one tail: HH, HT, TH (3 outcomes).
  3. P = .
Q111 markMCQStatistics

If the mean of five observations , , , and is 11, then the value of is :

  1. (A)4
  2. (B)7
  3. (C)11
  4. (D)6
Show answer & solution
Answer: (B) 7
  1. Sum = , so mean = .
  2. .
Q121 markMCQPolynomials

The zeroes of the quadratic polynomial are :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. .
  2. Zeroes: and .
Also asked in: 2024 Standard 30/3/1
Q131 markMCQCircles

Maximum number of common tangents that can be drawn to two circles intersecting at two distinct points is :

  1. (A)4
  2. (B)3
  3. (C)2
  4. (D)1
Show answer & solution
Answer: (C) 2
  1. Two circles cutting each other at two points have only the two direct (outer) common tangents.
  2. No transverse common tangent is possible, since the circles overlap.
  3. So the maximum number is 2.
Q141 markMCQTriangles

In , DE BC (as shown in the figure). If AD = 2 cm, BD = 3 cm, BC = 7.5 cm, then the length of DE (in cm) is :

Diagram for CBSE 2024 Class 10 Maths question 14
  1. (A)2.5
  2. (B)3
  3. (C)5
  4. (D)6
Show answer & solution
Answer: (B) 3
  1. Since DE BC, (AA).
  2. .
  3. cm.

If and , then is :

  1. (A)
  2. (B)
  3. (C)1
  4. (D)not defined
Show answer & solution
Answer: (A)
  1. For acute angles, .
  2. .
  3. .
Also asked in: 2024 Standard 30/3/1
Q161 markMCQReal Numbers

Given HCF (2520, 6600) = 40, LCM (2520, 6600) = , then the value of k is :

  1. (A)1650
  2. (B)1600
  3. (C)165
  4. (D)1625
Show answer & solution
Answer: (A) 1650
  1. HCF LCM = product of the two numbers.
  2. .
  3. .

If the sum of first n terms of an A.P. is and its common difference is 6, then its first term is :

  1. (A)7
  2. (B)4
  3. (C)6
  4. (D)3
Show answer & solution
Answer: (A) 7
  1. First term = .
  2. (Check: , so and , as given.)
Q181 markMCQPolynomials

What should be subtracted from the polynomial , so that 15 is the zero of the resulting polynomial ?

  1. (A)30
  2. (B)14
  3. (C)15
  4. (D)16
Show answer & solution
Answer: (C) 15
  1. Let be subtracted: .
  2. 15 is a zero: .
  3. .
Q191 markAssertion–ReasonProbability

Assertion (A) : In a cricket match, a batsman hits a boundary 9 times out of 45 balls he plays. The probability that in a given ball, he does not hit the boundary is .
Reason (R) : P(E) + P(not E) = 1

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  1. P(boundary) = .
  2. P(no boundary) = , so A is true.
  3. R is true, and it is exactly the rule used to get A, so R explains A.
  4. Answer: (A).
Q201 markAssertion–ReasonCoordinate Geometry

Assertion (A) : The point which divides the line segment joining the points A (1, 2) and B(, 1) internally in the ratio 1 : 2 is
Reason (R) : The coordinates of the point which divides the line segment joining the points A (, ) and B(, ) in the ratio are

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Reason is the section formula, so R is true.
  2. Using it with : , .
  3. The point is , not , so A is false.
  4. Answer: (D).
Q212 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

Show answer & solution
Answer: 2
  1. , , .
  2. Numerator = ; denominator = .
  3. Value = .
Q222 marksVery Short AnswerCoordinate Geometry

Find a relation between and y such that the point P(, y) is equidistant from the points A(7, 1) and B(3, 5).

Show answer & solution
Answer:
  1. PA = PB, so .
  2. .
  3. .
  4. .
  5. So .
OR
Q22 (OR) (OR)2 marksVery Short AnswerCoordinate Geometry

Points A(, y) and B(5, 7) lie on a circle with centre O(2, ) such that AB is a diameter of the circle. Find the value of y. Also, find the radius of the circle.

Show answer & solution
Answer: ; radius = 5 units
  1. O is the mid-point of diameter AB.
  2. Mid-point of AB = .
  3. So .
  4. Then O = (2, 3) and A = (, ).
  5. Radius OA = units.
Q232 marksVery Short AnswerProbability

One card is drawn at random from a well shuffled deck of 52 cards. Find the probability that the card drawn
(i) is queen of hearts;
(ii) is not a jack.

Show answer & solution
Answer: (i) (ii)
  1. Total outcomes = 52.
  2. (i) There is 1 queen of hearts, so P = .
  3. (ii) There are 4 jacks, so 48 cards are not jacks. P = .

If and , find the value of .

Show answer & solution
Answer:
  1. Adding the equations: , so .
  2. Then .
  3. .
OR
Q24 (OR) (OR)2 marksVery Short AnswerPair of Linear Equations in Two Variables

Sum of two numbers is 105 and their difference is 45. Find the numbers.

Show answer & solution
Answer: 75 and 30
  1. Let the numbers be and with .
  2. and .
  3. Adding: , so ; then .
  4. The numbers are 75 and 30.
Q252 marksVery Short AnswerTriangles

In the given figure, , prove that

Diagram for CBSE 2024 Class 10 Maths question 25
Show answer & solution
Answer: Proved.
  1. In and :
  2. (given).
  3. (vertically opposite angles).
  4. So by SAS similarity, .

Solve the following system of linear equations graphically :

Show answer & solution
Answer: ,
  1. Line 1: ; points (0, 1), (1, 2), (2, 3).
  2. Line 2: ; points (0, 5), (5, 0), (2, 3).
  3. Plot both lines on the same axes.
  4. They intersect at (2, 3).
  5. So the solution is , .
Q273 marksShort AnswerIntroduction to Trigonometry

Prove that

Show answer & solution
Answer: Proved.
  1. LHS = .
  2. Numerator = .
  3. Denominator = .
  4. So LHS = = RHS.
Q283 marksShort AnswerCoordinate Geometry

In what ratio does the X-axis divides the line segment joining the points(2, ) and (5, 6) ? Also, find the coordinates of the point of intersection.

Show answer & solution
Answer: 1 : 2; point of intersection (3, 0)
  1. Let the x-axis divide the segment in the ratio at .
  2. -coordinate: , so the ratio is 1 : 2.
  3. .
  4. Point of intersection: (3, 0).
OR
Q28 (OR) (OR)3 marksShort AnswerCoordinate Geometry

Find the length of the median AD of having vertices A(0, ), B(2, 1) and C(0, 3).

Show answer & solution
Answer: AD = units
  1. D is the mid-point of BC: D = .
  2. AD = units.
Q293 marksShort AnswerCircles

Prove that the tangents drawn at the end points of a chord of a circle makes equal angles with the chord.

Show answer & solution
Answer: Proved.
  1. Let AB be a chord of a circle with centre O, and let the tangents at A and B meet at P.
  2. Tangents drawn from an external point are equal, so PA = PB.
  3. In , PA = PB, so (angles opposite equal sides).
  4. Hence the tangents make equal angles with the chord.
  5. (If AB is a diameter the tangents are parallel and each makes with AB, so the angles are again equal.)
Also asked in: 2024 Standard 30/3/1
Q303 marksShort AnswerPolynomials

Find the zeroes of the quadratic polynomial and verify the relationship between the zeroes and the coefficients of the polynomial.

Show answer & solution
Answer: Zeroes: and ; relationship verified.
  1. , so the zeroes are and .
  2. Here , , .
  3. Sum of zeroes = .
  4. Product of zeroes = .
  5. Hence the relationship is verified.
Q313 marksShort AnswerArithmetic Progressions

If the sum of first 7 terms of an A.P. is 49 and that of first 17 terms is 289, find the sum of its first 20 terms.

Show answer & solution
Answer:
  1. .
  2. .
  3. Subtracting: , so and .
  4. .
OR
Q31 (OR) (OR)3 marksShort AnswerArithmetic Progressions

The ratio of the term to its term of an A.P. is 1 : 3 and the sum of its first six terms is 42. Find the first term and the common difference of A.P.

Show answer & solution
Answer: First term , common difference
  1. .
  2. .
  3. With : , so and .
Q325 marksLong AnswerSurface Areas and Volumes

A solid iron pole consists of a solid cylinder of height 200 cm and base diameter 28 cm, which is surmounted by another cylinder of height 50 cm and radius 7 cm. Find the mass of the pole, given that 1 cm of iron has approximately 8 g mass.

Show answer & solution
Answer: 1047200 g = 1047.2 kg
  1. Lower cylinder: cm, cm; volume = cm.
  2. Upper cylinder: cm, cm; volume = cm.
  3. Total volume = 123200 + 7700 = 130900 cm.
  4. Mass = g = 1047.2 kg.
OR
Q32 (OR) (OR)5 marksLong AnswerSurface Areas and Volumes

A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is 14 mm and the diameter of the capsule is 4 mm, find its surface area. Also, find its volume.

Diagram for CBSE 2024 Class 10 Maths question 32 (OR)
Show answer & solution
Answer: Surface area = 176 mm; volume = mm
  1. Radius mm; length of the cylindrical part = mm.
  2. Surface area = .
  3. mm.
  4. Volume = .
  5. mm.
Q335 marksLong AnswerQuadratic Equations

In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed is reduced by 100 km/h and by doing so, the time of flight is increased by 30 minutes. Find the original duration of the flight.

Show answer & solution
Answer: hours (3 h 30 min)
  1. Let the original speed be km/h.
  2. .
  3. .
  4. (speed cannot be negative).
  5. Original duration = hours = 3 hours 30 minutes.
OR
Q33 (OR) (OR)5 marksLong AnswerQuadratic Equations

The denominator of a fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is , find the fraction.

Show answer & solution
Answer:
  1. Let the numerator be ; the denominator is .
  2. .
  3. .
  4. .
  5. (taking the natural-number value).
  6. Fraction = . Check: .
Q345 marksLong AnswerTriangles

Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting AC in L and AD produced in E. Prove that EL = 2BL.

Show answer & solution
Answer: Proved.
  1. In and : MC = MD (M is the mid-point of CD), (vertically opposite), (alternate angles, since BC AE).
  2. So (ASA), giving BC = DE.
  3. AD = BC (opposite sides of a parallelogram), so AE = AD + DE = 2BC.
  4. In and : (vertically opposite) and (alternate angles, AE BC).
  5. So (AA), and .
  6. Hence EL = 2BL.

The angle of elevation of a jet plane from a point A on the ground is . After a flight of 30 seconds, the angle of elevation changes to . If the jet plane is flying at a constant height of m, find the speed of the jet plane.

Show answer & solution
Answer: 240 m/s (= 864 km/h)
  1. Let the plane be at P then Q, with feet of perpendiculars B and C on the ground line through A; PB = QC = m.
  2. m.
  3. m.
  4. Distance flown PQ = BC = 10800 - 3600 = 7200 m.
  5. Speed = m/s = km/h.
Q364 marksCase StudyReal Numbers

Teaching Mathematics through activities is a powerful approach that enhances students’ understanding and engagement. Keeping this in mind, Ms. Mukta planned a prime number game for class 5 students. She announces the number 2 in her class and asked the first student to multiply it by a prime number and then pass it to second student. Second student also multiplied it by a prime number and passed it to third student. In this way by multiplying to a prime number, the last student got 173250.
Now, Mukta asked some questions as given below to the students :
(i) What is the least prime number used by students ? (1)
(ii) How many students are in the class ? (2)
OR What is the highest prime number used by students ? (2)
(iii) Which prime number has been used maximum times ? (1)

Show answer & solution
Answer: (i) 3 (ii) 7; OR 11 (iii) 5
  1. .
  2. The teacher's 2 accounts for the factor 2; the students multiplied by .
  3. (i) Least prime used by students = 3.
  4. (ii) Number of primes used = 2 + 3 + 1 + 1 = 7, so there are 7 students.
  5. OR: Highest prime used = 11.
  6. (iii) 5 is used the maximum number of times (three times).
Q374 marksCase StudyAreas Related to Circles

A stable owner has four horses. He usually tie these horses with 7 m long rope to pegs at each corner of a square shaped grass field of 20 m length, to graze in his farm. But tying with rope sometimes results in injuries to his horses, so he decided to build fence around the area so that each horse can graze.
Based on the above, answer the following questions :
(i) Find the area of the square shaped grass field. (1)
(ii) Find the area of the total field in which these horses can graze. (2)
OR If the length of the rope of each horse is increased from 7 m to 10 m, find the area grazed by one horse. (Use = 3.14) (2)
(iii) What is area of the field that is left ungrazed, if the length of the rope of each horse is 7 cm ? (1)

Diagram for CBSE 2024 Class 10 Maths question 37
Show answer & solution
Answer: (i) 400 m (ii) 154 m; OR 78.5 m (iii) 399.9846 m as printed (7 cm); 246 m if the rope is 7 m
  1. (i) Area of the square = m.
  2. (ii) Each horse grazes a quadrant of radius 7 m; four quadrants make one full circle: m.
  3. OR: Area grazed by one horse = m.
  4. (iii) With a 7 cm = 0.07 m rope, grazed area = m, so ungrazed area = m.
  5. If the rope is 7 m (as in the passage), ungrazed area = m.
Q384 marksCase StudyStatistics

Vocational training complements traditional education by providing practical skills and hands-on experience. While education equips individuals with a broad knowledge base, vocational training focuses on job-specific skills, enhancing employability thus making the student self-reliant. Keeping this in view, a teacher made the following table giving the frequency distribution of students/adults undergoing vocational training from the training institute.
Age (in years): 15-19, 20-24, 25-29, 30-34, 35-39, 40-44, 45-49, 50-54
Number of participants: 62, 132, 96, 37, 13, 11, 10, 4
From the above answer the following questions :
(i) What is the lower limit of the modal class of the above data ? (1)
(ii) Find the median class of the above data. (2)
OR Find the number of participants of age less than 50 years who undergo vocational training. (2)
(iii) Give the empirical relationship between mean, median and mode. (1)

Show answer & solution
Answer: (i) 19.5 (modal class 20-24, i.e. 19.5-24.5) (ii) 20-24 (19.5-24.5); OR 361 (iii) 3 Median = Mode + 2 Mean
  1. (i) Highest frequency is 132, so the modal class is 20-24. Making the classes continuous (subtract 0.5 / add 0.5), it is 19.5-24.5, with lower limit 19.5.
  2. (ii) N = 62 + 132 + 96 + 37 + 13 + 11 + 10 + 4 = 365, so N/2 = 182.5.
  3. Cumulative frequencies: 62, 194, 290, 327, 340, 351, 361, 365.
  4. The first cumulative frequency above 182.5 is 194, so the median class is 20-24 (19.5-24.5).
  5. OR: Participants below 50 years = 365 - 4 = 361.
  6. (iii) Empirical relationship: 3 Median = Mode + 2 Mean.
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