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CBSE Class 10 Maths Standard 2024 Question Paper 30/1/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/1/2 (2024), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/3/1Set 30/3/2Set 30/3/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3

AD is a median of with vertices A, B and C. Length AD is equal to :

  1. (A) units
  2. (B) units
  3. (C) units
  4. (D)10 units
Show answer & solution
Answer: (A) units
  1. D is the mid-point of BC: .
  2. units.

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. .
  2. So .

If the distance between the points and is 15 units, then the values of are :

  1. (A)
  2. (B)
  3. (C)18, 5
  4. (D)
Show answer & solution
Answer: (B)
  1. Distance .
  2. So , giving or .

If , then value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. .
  2. .

In the given figure, graphs of two linear equations are shown. The pair of these linear equations is :

Diagram for CBSE 2024 Class 10 Maths question 5
  1. (A)consistent with unique solution.
  2. (B)consistent with infinitely many solutions.
  3. (C)inconsistent.
  4. (D)inconsistent but can be made consistent by extending these lines.
Show answer & solution
Answer: (A) consistent with unique solution.
  1. The two lines in the figure have different slopes, so they are not parallel.
  2. Non-parallel lines intersect in exactly one point (here, when extended to the left).
  3. Hence the pair is consistent with a unique solution.

The centre of a circle is at . If one end of a diameter is at , then the other end is at :

  1. (A)(0, 0)
  2. (B)(4, 0)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. The centre is the mid-point of the diameter. Let the other end be .
  2. gives ; gives .
  3. Other end .
Q71 markMCQProbability

Which of the following is not probability of an event ?

  1. (A)0.89
  2. (B)52%
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. A probability must lie between 0 and 1.
  2. 0.89, 52% = 0.52 and all lie between 0 and 1.
  3. , so it cannot be a probability.
Q81 markMCQPolynomials

The zeroes of a polynomial are twice the zeroes of the polynomial . The value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)10
Show answer & solution
Answer: (A)
  1. Sum of zeroes of is .
  2. Zeroes of are twice these, so their sum is .
  3. Sum of zeroes of is , so and .

The volume of the largest right circular cone that can be carved out from a solid cube of edge 2 cm is :

  1. (A) cu cm
  2. (B) cu cm
  3. (C) cu cm
  4. (D) cu cm
Show answer & solution
Answer: (D) cu cm
  1. The largest cone has base diameter = edge = 2 cm, so cm, and height cm.
  2. Volume cu cm.
Q101 markMCQStatistics

The middle most observation of every data arranged in order is called :

  1. (A)mode
  2. (B)median
  3. (C)mean
  4. (D)deviation
Show answer & solution
Answer: (B) median
  1. The median is the middle observation when the data are arranged in order.

If the roots of equation are real and equal, then which of the following relation is true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Real and equal roots means discriminant .
  2. So , i.e. .
Q121 markMCQProbability

If the probability of a player winning a game is 0.79, then the probability of his losing the same game is :

  1. (A)1.79
  2. (B)0.31
  3. (C)0.21%
  4. (D)0.21
Show answer & solution
Answer: (D) 0.21
  1. Winning and losing are complementary events.
  2. P(losing) .
Also asked in: 2024 Standard 30/1/1
Q131 markMCQPolynomials

If the sum and the product of zeroes of a quadratic polynomial are and 3 respectively, then a quadratic polynomial is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Required polynomial .
  2. .
Q141 markMCQStatistics

For some data with respective frequencies , the value of is equal to :

  1. (A)
  2. (B)1
  3. (C)
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. .
  2. Since , .
  3. So the value is 0.

A solid sphere is cut into two hemispheres. The ratio of the surface areas of sphere to that of two hemispheres taken together, is :

  1. (A)1 : 1
  2. (B)1 : 4
  3. (C)2 : 3
  4. (D)3 : 2
Show answer & solution
Answer: (C) 2 : 3
  1. Surface area of sphere .
  2. Each solid hemisphere has total surface area , so two together .
  3. Ratio .
Q161 markMCQReal Numbers

If two positive integers and can be expressed as and , where and are prime numbers, then LCM is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. and .
  2. LCM takes the highest power of each prime factor: .

th term of an A.P. is . The common difference is :

  1. (A)
  2. (B)4
  3. (C)7
  4. (D)1
Show answer & solution
Answer: (C) 7
  1. .
Q181 markMCQProbability

From the data 1, 4, 7, 9, 16, 21, 25, if all the even numbers are removed, then the probability of getting at random a prime number from the remaining is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Removing the even numbers 4 and 16 leaves 1, 7, 9, 21, 25 (5 numbers).
  2. Only 7 is prime.
  3. Required probability .
Q191 markAssertion–ReasonPolynomials

Assertion (A) : If the graph of a polynomial touches -axis at only one point, then the polynomial cannot be a quadratic polynomial.
Reason (R) : A polynomial of degree can have at most zeroes.

  1. (A)Both, Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  2. (B)Both, Assertion (A) and Reason (R) are true but Reason (R) is not correct explanation for Assertion (A).
  3. (C)Assertion (A) is true but Reason (R) is false.
  4. (D)Assertion (A) is false but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false but Reason (R) is true.
  1. A: The graph of touches the -axis only at the origin, and is quadratic. So A is false.
  2. R: A polynomial of degree has at most zeroes. R is true.
Q201 markAssertion–ReasonCircles

Assertion (A) : The tangents drawn at the end points of a diameter of a circle, are parallel.
Reason (R) : Diameter of a circle is the longest chord.

  1. (A)Both, Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  2. (B)Both, Assertion (A) and Reason (R) are true but Reason (R) is not correct explanation for Assertion (A).
  3. (C)Assertion (A) is true but Reason (R) is false.
  4. (D)Assertion (A) is false but Reason (R) is true.
Show answer & solution
Answer: (B) Both, Assertion (A) and Reason (R) are true but Reason (R) is not correct explanation for Assertion (A).
  1. A: Each tangent is perpendicular to the diameter at its end point, so both tangents are perpendicular to the same line and hence parallel. A is true.
  2. R: The diameter is the longest chord of a circle. R is true.
  3. A follows from the tangent being perpendicular to the radius, not from R. So R does not explain A.
Q212 marksVery Short AnswerTriangles

Diagonals AC and BD of a trapezium ABCD intersect at O, where AB DC. If , then show that AB = 2CD

Diagram for CBSE 2024 Class 10 Maths question 21
Show answer & solution
Answer: Proved.
  1. In and :
  2. and (alternate angles, AB DC).
  3. So (AA similarity).
  4. Hence , i.e. AB = 2CD.
Q222 marksVery Short AnswerReal Numbers

Prove that is an irrational number. It is given that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Assume is rational, say , where is rational.
  2. Then .
  3. The right side is rational (rational numbers are closed under subtraction and division by a non-zero rational), so would be rational.
  4. This contradicts the fact that is irrational.
  5. Hence is irrational.
OR
Q22 (OR) (OR)2 marksVery Short AnswerReal Numbers

Show that the number is a composite number.

Show answer & solution
Answer: It equals , which has factors other than 1 and itself, so it is composite.
  1. .
  2. So the number has the factors 11 and 88 besides 1 and itself.
  3. Hence it is a composite number.

Solve the following system of linear equations :
and

Show answer & solution
Answer: ,
  1. ... (1), ... (2)
  2. (1) : ; (2) : .
  3. Adding: , so .
  4. From (1): , so .
Q242 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

Show answer & solution
Answer: 4
OR
Q24 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

If and , verify that :

Show answer & solution
Answer: Verified (both sides equal 1).
  1. LHS .
  2. RHS .
  3. LHS = RHS, hence verified.
Q252 marksVery Short AnswerProbability

In a pack of 52 playing cards one card is lost. From the remaining cards, a card is drawn at random. Find the probability that the drawn card is queen of heart, if the lost card is a black card.

Show answer & solution
Answer:
  1. After a black card is lost, 51 cards remain.
  2. The queen of hearts is red, so it is still in the pack: 1 favourable outcome.
  3. Required probability .
Q263 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. Let , so .
  2. LHS
  3. = RHS.

In a chemistry lab, there is some quantity of 50% acid solution and some quantity of 25% acid solution. How much of each should be mixed to make 10 litres of 40% acid solution ?

Show answer & solution
Answer: 6 litres of 50% solution and 4 litres of 25% solution
  1. Let litres of 50% solution and litres of 25% solution be mixed.
  2. ... (1)
  3. Acid content: , i.e. ... (2)
  4. (2) (1): ; then .
  5. So 6 litres of 50% solution and 4 litres of 25% solution are needed.
Q283 marksShort AnswerCoordinate Geometry

Find the ratio in which the point divides the line segment joining the points and . Also, find the value of .

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Answer: Ratio ;
  1. Let the point divide the segment in the ratio .
  2. -coordinate: , so and .
  3. Ratio .
  4. .
OR
Q28 (OR) (OR)3 marksShort AnswerCoordinate Geometry

ABCD is a rectangle formed by the points A, B, C and D. P, Q, R and S are mid–points of sides AB, BC, CD and DA respectively. Show that diagonals of the quadrilateral PQRS bisect each other.

Show answer & solution
Answer: Mid-points of PR and QS are both , so the diagonals bisect each other.
  1. P (mid-point of AB) , Q (mid-point of BC) .
  2. R (mid-point of CD) , S (mid-point of DA) .
  3. Mid-point of PR .
  4. Mid-point of QS .
  5. The diagonals PR and QS have the same mid-point, so they bisect each other.
Q293 marksShort AnswerSurface Areas and Volumes

A wooden toy is made by scooping out a hemisphere of same radius as of cylinder, from each end of a wooden solid cylinder. If the height of the cylinder is 20 cm and its base is of radius 7 cm, find the total surface area of the toy.

Show answer & solution
Answer: 1496
  1. Total surface area = curved surface of cylinder + inner surfaces of the two hemispherical hollows.
  2. .
Q303 marksShort AnswerReal Numbers

In a teachers' workshop, the number of teachers teaching French, Hindi and English are 48, 80 and 144 respectively. Find the minimum number of rooms required if in each room the same number of teachers are seated and all of them are of the same subject.

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Answer: 17 rooms
  1. The number of teachers per room must divide 48, 80 and 144; for the fewest rooms it is their HCF.
  2. , , , so HCF .
  3. Number of rooms .
Q313 marksShort AnswerCircles

In the given figure, AB is a diameter of the circle with centre O. AQ, BP and PQ are tangents to the circle. Prove that .

Diagram for CBSE 2024 Class 10 Maths question 31
Show answer & solution
Answer: Proved.
  1. Let PQ touch the circle at C. Join OC.
  2. In and : OA = OC (radii), QA = QC (tangents from Q), OQ common. So (SSS) and .
  3. Similarly , so .
  4. AB is a diameter, so , i.e. .
  5. So , i.e. .
OR
Q31 (OR) (OR)3 marksShort AnswerCircles

A circle with centre O and radius 8 cm is inscribed in a quadrilateral ABCD in which P, Q, R, S are the points of contact as shown. If AD is perpendicular to DC, BC = 30 cm and BS = 24 cm, then find the length DC.

Diagram for CBSE 2024 Class 10 Maths question 31 (OR)
Show answer & solution
Answer: DC = 14 cm
  1. Tangents from an external point are equal: BR = BS = 24 cm.
  2. CR = BC BR = 30 24 = 6 cm, so CQ = CR = 6 cm.
  3. In quadrilateral OPDQ, and (radius tangent), and OP = OQ = 8 cm, so OPDQ is a square.
  4. So DQ = 8 cm.
  5. DC = DQ + QC = 8 + 6 = 14 cm.
Q325 marksLong AnswerTriangles

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.

Show answer & solution
Answer: Proved.
  1. Given: In , DE BC meets AB at D and AC at E.
  2. To prove: .
  3. Construction: Join BE and CD; draw EM AB and DN AC.
  4. .
  5. .
  6. and are on the same base DE and between the same parallels DE and BC, so ar(BDE) = ar(DEC).
  7. Hence .
OR
Q32 (OR) (OR)5 marksLong AnswerTriangles

In the given figure PA, QB and RC are each perpendicular to AC. If AP = , BQ = and CR = , then prove that

Diagram for CBSE 2024 Class 10 Maths question 32 (OR)
Show answer & solution
Answer: Proved.
  1. In and : is common and , so (AA).
  2. So , i.e. ... (1)
  3. In and : is common and , so (AA).
  4. So , i.e. ... (2)
  5. Adding (1) and (2): .
  6. Dividing by : .

From the top of a building 60 m high, the angles of depression of the top and bottom of the vertical lamp post are observed to be and respectively.
(i) Find the horizontal distance between the building and the lamp post.
(ii) Find the distance between the tops of the building and the lamp post.

Show answer & solution
Answer: (i) m m (ii) 40 m
  1. Let the building be AB = 60 m (top A) and the lamp post CD (top D, foot C), with BC = m.
  2. (i) Angle of depression of C is : , so m.
  3. (ii) Angle of depression of D is : the vertical drop from A to the level of D is m (so the lamp post is m high).
  4. Distance AD m (check: ).
Q345 marksLong AnswerArithmetic Progressions

The sum of first and eighth terms of an A.P. is 32 and their product is 60. Find the first term and common difference of the A.P. Hence, also find the sum of its first 20 terms.

Show answer & solution
Answer: , , ; or , ,
  1. Let the first term be and the eighth term .
  2. and , so and are roots of , i.e. .
  3. Case 1: , : , . .
  4. Case 2: , : , . .
OR
Q34 (OR) (OR)5 marksLong AnswerArithmetic Progressions

In an A.P. of 40 terms, the sum of first 9 terms is 153 and the sum of last 6 terms is 687. Determine the first term and common difference of A.P. Also, find the sum of all the terms of the A.P.

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Answer: First term = 5, common difference = 3, sum of all 40 terms = 2540
  1. , so ... (1)
  2. The last 6 terms are the 35th to 40th terms: sum , so ... (2)
  3. From (1), . Substituting: , so , , .
  4. .
Q355 marksLong AnswerSurface Areas and Volumes

A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area and the volume of the vessel.

Show answer & solution
Answer: Inner surface area = 572 ; volume
  1. Radius cm; height of cylinder cm.
  2. Inner surface area .
  3. Volume
  4. .
Q364 marksCase StudyStatistics

BINGO is game of chance. The host has 75 balls numbered 1 through 75. Each player has a BINGO card with some numbers written on it. The participant cancels the number on the card when called out a number written on the ball selected at random. Whosoever cancels all the numbers on his/her card, says BINGO and wins the game.
The table given below, shows the data of one such game where 48 balls were used before Tara said 'BINGO'.
Numbers announced: 0-15, 15-30, 30-45, 45-60, 60-75
Number of times: 8, 9, 10, 12, 9
Based on the above information, answer the following :
(i) Write the median class. (1)
(ii) When first ball was picked up, what was the probability of calling out an even number ? (1)
(iii) (a) Find median of the given data. (2)
OR (b) Find mode of the given data. (2)

Show answer & solution
Answer: (i) 30-45 (ii) (iii) (a) 40.5 OR (b) 51
  1. Cumulative frequencies: 8, 17, 27, 39, 48; , .
  2. (i) The cumulative frequency first exceeds 24 in the class 30-45, so the median class is 30-45.
  3. (ii) There are 37 even numbers from 1 to 75, so P(even) .
  4. (iii) (a) , , , . Median .
  5. OR (b) Modal class 45-60: , , , , .
  6. Mode .
Q374 marksCase StudyCircles

A backyard is in the shape of a triangle ABC with right angle at B. AB = 7 m and BC = 15 m. A circular pit was dug inside it such that it touches the walls AC, BC and AB at P, Q and R respectively such that AP = m.
Based on the above information, answer the following questions :
(i) Find the length of AR in terms of . (1)
(ii) Write the type of quadrilateral BQOR. (1)
(iii) (a) Find the length PC in terms of and hence find the value of . (2)
OR (b) Find and hence find the radius of circle. (2)

Diagram for CBSE 2024 Class 10 Maths question 37
Show answer & solution
Answer: (i) AR = m (ii) Square (iii) (a) PC = m, m OR (b) m, m
  1. (i) Tangents from A are equal: AR = AP = m.
  2. (ii) , (radius tangent) and OR = OQ = , so BQOR is a square.
  3. (iii) (a) BR = AB AR = , so BQ = BR = and CQ = . Hence PC = CQ = m.
  4. AC = AP + PC = , and AC .
  5. , so m.
  6. OR (b) As above, m.
  7. Since BQOR is a square, = BR = m.
Q384 marksCase StudyQuadratic Equations

A rectangular floor area can be completely tiled with 200 square tiles. If the side length of each tile is increased by 1 unit, it would take only 128 tiles to cover the floor.
(i) Assuming the original length of each side of a tile be units, make a quadratic equation from the above information. (1)
(ii) Write the corresponding quadratic equation in standard form. (1)
(iii) (a) Find the value of , the length of side of a tile by factorisation. (2)
OR (b) Solve the quadratic equation for , using quadratic formula. (2)

Show answer & solution
Answer: (i) (ii) (iii) (a) units OR (b) (rejecting )
  1. (i) Floor area is the same in both cases: .
  2. (ii) , so . Dividing by 8: .
  3. (iii) (a) .
  4. or ; length cannot be negative, so units.
  5. OR (b) , .
  6. , so or . Taking the positive value, units.
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