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CBSE Class 10 Maths Standard 2026 Question Paper 30/4/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/4/3 (2026), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/3/1Set 30/3/2Set 30/3/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3

The distance between the points and is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. , so
Also asked in: 2026 Standard 30/4/1

An ice-cream cone of radius r and height h is completely filled by two spherical scoopes of ice-cream. If radius of each spherical scoop is , then h : 2r equals

  1. (A)1 : 8
  2. (B)1 : 2
  3. (C)1 : 1
  4. (D)2 : 1
Show answer & solution
Answer: (B) 1 : 2
  1. Volume of cone = volume of two scoops:
  2. So .
  3. h : 2r = r : 2r = 1 : 2

The value of k for which the system of linear equations and has infinitely many solutions, is (does)

  1. (A)
  2. (B)3
  3. (C)4
  4. (D)Not exist
Show answer & solution
Answer: (D) Not exist
  1. Infinitely many solutions need .
  2. but .
  3. Since , no value of k works (k = 3 makes the lines parallel).
  4. Such k does not exist.

A circle is divided into 16 identical sectors. If radius of the circle is 7 cm, area of each sector is

  1. (A) cm
  2. (B)77 cm
  3. (C)154 cm
  4. (D) cm
Show answer & solution
Answer: (D) cm
  1. Area of circle cm
  2. Area of each sector cm
Also asked in: 2026 Standard 30/4/1
Q51 markMCQStatistics

Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

  1. (A)34
  2. (B)43
  3. (C)38.5
  4. (D)41.5
Show answer & solution
Answer: (A) 34
  1. Mode = 3 Median 2 Mean

Three tennis balls are just packed in a cylindrical jar. If radius of each ball is r, volume of air inside the jar is

Diagram for CBSE 2026 Class 10 Maths question 6
  1. (A)
  2. (B)
  3. (C)
  4. (D)
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Answer: (A)
  1. The jar has radius r and height 6r.
  2. Volume of jar
  3. Volume of 3 balls
  4. Volume of air
Q71 markMCQPolynomials

Observe the graph of polynomial . The zeroes of the polynomial are

Diagram for CBSE 2026 Class 10 Maths question 7
  1. (A), 0, 2.5
  2. (B), 2.5
  3. (C)0, 4
  4. (D), 0
Show answer & solution
Answer: (B) , 2.5
  1. Zeroes are the x-coordinates of the points where the graph meets the x-axis.
  2. The graph touches the x-axis at and cuts it at (2.5, 0).
  3. (0, 4) is the y-intercept, not a zero. Zeroes: , 2.5.
Q81 markMCQCircles

From an external point P, a tangent PT has been drawn to a circle with centre at O and radius 3 cm, intersecting its concentric circle at A and B. If AB = 8 cm and OA = AP, the length PQ equals.

Diagram for CBSE 2026 Class 10 Maths question 8
  1. (A)8 cm
  2. (B)10 cm
  3. (C)9 cm
  4. (D)12 cm
Show answer & solution
Answer: (C) 9 cm
  1. PT touches the inner circle at Q, so and OQ = 3 cm.
  2. The perpendicular from the centre bisects the chord AB of the outer circle: AQ = 4 cm.
  3. cm, so AP = OA = 5 cm.
  4. PQ = PA + AQ = 5 + 4 = 9 cm

is same as

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
Q101 markMCQCircles

PQ is tangent to a circle with centre O. If , then is

Diagram for CBSE 2026 Class 10 Maths question 10
  1. (A)
  2. (B)
  3. (C)
  4. (D)
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Answer: (C)
  1. SP is a diameter and R lies on the circle, so .
  2. (tangent radius).
  3. In :

In the given figure, a circle is centred at (1, 2). The diameter of the circle is

Diagram for CBSE 2026 Class 10 Maths question 11
  1. (A)4
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. The circle passes through the origin O(0, 0).
  2. Radius
  3. Diameter
Q121 markMCQTriangles

In the given figure, . If and AC = 6 cm, then length AE is

Diagram for CBSE 2026 Class 10 Maths question 12
  1. (A)1.5 cm
  2. (B)1 cm
  3. (C)2 cm
  4. (D)3 cm
Show answer & solution
Answer: (A) 1.5 cm
  1. By BPT, .
  2. So cm.
Also asked in: 2026 Standard 30/4/1
Q131 markMCQTriangles

It is given that . Which of the following is not true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
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Answer: (C)
  1. gives the correspondence , , .
  2. So , not .
  3. (A), (B) and (D) follow from .
  4. Hence (C) is not true.

If the quadratic equation has real and equal roots, then the value of k is

  1. (A)3
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A) 3
  1. For equal roots, .
  2. Both 3 and are valid; option (A) 3 (option (B) is also correct).
Also asked in: 2026 Standard 30/4/1

equals to :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)

If sum of first ten terms of an A.P. is zero with a as the first term and d, the common difference, which of the following relation is true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
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Answer: (C)
Q171 markMCQProbability

Two dice are rolled together. The probability that sum of the numbers obtained is atmost 12, is

  1. (A)1
  2. (B)0
  3. (C)
  4. (D)
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Answer: (A) 1
  1. The largest possible sum with two dice is 6 + 6 = 12.
  2. So every one of the 36 outcomes has sum at most 12: a sure event.
  3. Probability = 1

Arc PQ subtends an angle at the centre of the circle with radius 6.3 cm. If cm, then the value of is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Arc length
Q191 markAssertion–ReasonProbability

Assertion (A) : If probability of happening of an event is 0.2p, , then p can't be more than 5.
Reason (R) : for an event E.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (B) Both A and R are true, but R is not the correct explanation of A.
  1. Since , . So A is true.
  2. is true for any event E, so R is true.
  3. But A follows from , not from R. So R does not explain A.
Q201 markAssertion–ReasonReal Numbers

Assertion (A) : is an irrational number.
Reason (R) : Sum of the any two irrational numbers is always irrational.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) A is true, but R is false.
  1. If (rational), then , giving , rational: a contradiction. So A is true.
  2. R is false: e.g. is rational.
Q212 marksVery Short AnswerIntroduction to Trigonometry

Prove that : .

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Answer: Proved.
  1. LHS = RHS
OR
Q21 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

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Answer:
  1. , ,
  2. Numerator
  3. Denominator
  4. Value
Q222 marksVery Short AnswerPolynomials

and are the zeroes of the polynomial . Find the value of .

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Answer:
  1. ,
Also asked in: 2026 Standard 30/4/1
Q232 marksVery Short AnswerTriangles

In the given figure, DEFG is a square. is right angle triangle with . Prove that .

Diagram for CBSE 2026 Class 10 Maths question 23
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Answer: Proved.
  1. In and : (DEFG is a square, so ).
  2. , so (corresponding angles).
  3. Hence (AA).
  4. So , i.e. .
Q242 marksVery Short AnswerQuadratic Equations

Verify that roots of the quadratic equation are equal when .

Show answer & solution
Answer: Proved.
  1. Given , so .
  2. Then and .
  3. Since , the roots are equal.
Q252 marksVery Short AnswerReal Numbers

Prove that is an irrational number given that is irrational number.

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Answer: Proved.
  1. Suppose , where r is rational.
  2. Then , which is rational.
  3. This contradicts that is irrational.
  4. Hence is irrational.
OR
Q25 (OR) (OR)2 marksVery Short AnswerReal Numbers

If the HCF of 210 and 55 is expressed as , then find the value of m.

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Answer:
  1. , , so HCF = 5.
Q263 marksShort AnswerSurface Areas and Volumes

To protect plants from heat, a shed of iron rods covered with green cloth is made. The lower part of the shed is a cuboid mounted by semi-cylinder as shown in the figure. Find the area of the cloth required to make this shed, if dimensions of the cuboid are 14 m 25 m 16 m

Diagram for CBSE 2026 Class 10 Maths question 26
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Answer: 1952 m
  1. Cloth covers the four walls of the cuboid, the curved surface of the semi-cylinder and its two semicircular ends (not the floor).
  2. Radius of semi-cylinder m, length m.
  3. Four walls m
  4. Curved surface of semi-cylinder m
  5. Two semicircular ends m
  6. Total cloth m
OR
Q26 (OR) (OR)3 marksShort AnswerSurface Areas and Volumes

The internal and external radii of a hollow hemisphere are cm and 10 cm respectively. A cone of height cm and radius cm is surmounted on the hemisphere as shown in the figure. Find the total surface area of the object in terms of . (Use )

Diagram for CBSE 2026 Class 10 Maths question 26 (OR)
Show answer & solution
Answer: cm
  1. Outer curved surface of hemisphere
  2. Ring at the rim
  3. Slant height of cone cm
  4. Curved surface of cone
  5. The cone closes the hollow, so the inner surface is not exposed.
  6. Total surface area cm
Q273 marksShort AnswerProbability

A bag contains 30 balls out of which ‘m’ number of balls are blue in colour.
(i) Find the probability that a ball drawn at random from the bag is not blue.
(ii) If 6 more blue balls are added in the bag, then the probability of drawing a blue ball will be times the probability of drawing a blue ball in the first case. Find the value of m.

Show answer & solution
Answer: (i) (ii)
  1. (i) P(not blue)
  2. (ii) Now there are 36 balls, blue.
Q283 marksShort AnswerReal Numbers

Find the greatest number which divides 764 and 1198, leaving remainders 8 and 10 respectively.

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Answer: 108
  1. The number divides 764 8 = 756 and 1198 10 = 1188 exactly.
  2. ,
  3. HCF
  4. Required number = 108 (it exceeds both remainders).

In a class test, Veer scored 6 more than twice as many marks as Kevin scored. If one of them had scored 4 more marks, their total score would have been 40. Find the marks obtained by Veer and Kevin.

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Answer: Veer: 26 marks, Kevin: 10 marks
  1. Let Veer score x marks and Kevin score y marks.
  2. ... (1)
  3. If one of them scored 4 more, total = 40: ... (2)
  4. Substituting (1) in (2):
  5. Veer scored 26 and Kevin scored 10.
OR
Q29 (OR) (OR)3 marksShort AnswerPair of Linear Equations in Two Variables

Solve the linear equations and graphically.

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Answer: ,
  1. For : points (4, 2), (3, 5), (5, ).
  2. For : points (0, 2), (2, 2), (4, 2); a line parallel to the x-axis.
  3. Plot both lines on the same axes.
  4. They intersect at (4, 2).
  5. Solution: , .
Q303 marksShort AnswerAreas Related to Circles

Chord AB subtends an angle of at the centre O of the circle with radius cm. Find the perimeter of shaded segment ACB. (Use )

Diagram for CBSE 2026 Class 10 Maths question 30
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Answer: 39.85 cm
  1. Arc ACB cm
  2. Draw ; ,
  3. cm
  4. Perimeter cm
Q313 marksShort AnswerIntroduction to Trigonometry

If , show that .

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Answer: Proved.
  1. , so
  2. Numerator
  3. Denominator
  4. Ratio

A kite is flying at a height of 60 m above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as . From the bottom of the same building, the angle of elevation of kite is . Find the length of the string and height of roof from the ground. (Use )

Show answer & solution
Answer: Length of string = 69.2 m; height of roof = 25.4 m
  1. Let the building be AB (B at the ground, A at the roof) of height h, the kite at K, 60 m above the ground, and d the horizontal distance of the kite from the building.
  2. From B: m
  3. From A:
  4. m
  5. String m
Q335 marksLong AnswerQuadratic Equations

A person on tour has ₹ 5,400 for his expenses. If he extends his tour by 5 days, he has to cut down his daily expenses by ₹ 180. Find the original duration of the tour and daily expense.

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Answer: 10 days; ₹ 540 per day
  1. Let the original duration be x days. Daily expense .
  2. (x cannot be negative)
  3. Daily expense
OR
Q33 (OR) (OR)5 marksLong AnswerQuadratic Equations

The total cost of certain piece of cloth was ₹ 2,100. During special sale time, the shopkeeper offered 2 m extra cloth for free thus reducing the price of cloth per metre by ₹ 120. What was the original per metre price of cloth and its length ?

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Answer: Length 5 m; original price ₹ 420 per metre
  1. Let the original length be x m. Original price per metre .
  2. Price per metre
Q345 marksLong AnswerStatistics

Find mean and mode of the following frequency distribution :

Class :10 – 3030 – 5050 – 7070 – 9090 – 110110 – 130130 – 150
Frequency :68121014119
Show answer & solution
Answer: Mean = ; Mode =
  1. Class marks: 20, 40, 60, 80, 100, 120, 140;
  2. Mean
  3. Modal class 90 – 110: l = 90, , , , h = 20
  4. Mode
OR
Q34 (OR) (OR)5 marksLong AnswerStatistics

If the median of the distribution given below is 28.5, find the values of and y.

Class :0 – 1010 – 2020 – 3030 – 4040 – 5050 – 60Total
Frequency :52015y560
Show answer & solution
Answer: , y = 7
  1. Median 28.5 lies in 20 – 30: l = 20, f = 20, h = 10, cf , N/2 = 30
  2. y = 15 8 = 7
Q355 marksLong AnswerCircles

In the given figure, TP and TQ are tangents to a circle with centre M, touching another circle with centre N at A and B respectively. It is given that MQ = 13 cm, NB = 8 cm, BQ = 35 cm and TP = 80 cm.
(i) Name the quadrilateral MQBN. (1)
(ii) Is MN parallel to PA ? Justify your answer. (1)
(iii) Find length TB. (1)
(iv) Find length MN. (2)

Diagram for CBSE 2026 Class 10 Maths question 35
Show answer & solution
Answer: (i) Trapezium (ii) No (iii) TB = 45 cm (iv) MN = cm
  1. (i) and , so ; MQBN is a trapezium (right trapezium).
  2. (ii) and , so . If also , MPAN would be a parallelogram and MP = NA; but MP = 13 cm NA = 8 cm. So MN is not parallel to PA.
  3. (iii) Tangents from T: TQ = TP = 80 cm, so TB = TQ BQ = 80 35 = 45 cm.
  4. (iv) Draw . Then LQ = NB = 8, ML = 13 8 = 5 cm and NL = BQ = 35 cm.
  5. cm
Q364 marksCase StudyArithmetic Progressions

‘Kolam’ is a decorative art which is made with rice flour in South Indian States. It is drawn on grid pattern of dots. One such art work is shown below.
Observe the given figure carefully. There are 4 dots in first square, 8 dots in second square, 12 dots in third square and so on.
Based on the above, answer the following questions :
(i) Show that number of dots given above form an A.P. Write the first term and common difference. (1)
(ii) Write term of the A.P. formed. (1)
(iii) (a) The pattern is expanded on a large ground. If total 220 dots are used, then find the number of squares formed. (2)
OR (b) Is it possible to complete n number of squares using 100 dots ? If yes, then find the value of n.

Show answer & solution
Answer: (i) 4, 8, 12, ... is an A.P. with a = 4, d = 4 (ii) (iii) (a) 10 squares OR (b) No
  1. (i) 8 4 = 12 8 = 4, a constant difference, so 4, 8, 12, ... is an A.P. with a = 4, d = 4.
  2. (ii)
  3. (iii)(a)
  4. squares
  5. (iii)(b)
  6. is not a perfect square, so n is not a natural number. Not possible.
Q374 marksCase StudyCoordinate Geometry

Observe the map of Jaipur city placed on a Cartesian plane. Taking Rambagh Palace as origin, the location of some places are given below :
Point A : Rajasthan High Court
Point B : Birla Mandir
Point C : Heera Bagh
Point D : Amar Jawan Jyoti
Based on the above, answer the following questions :
(i) Advocate Rehana stays at Heera Bagh. How much distance she has to cover daily to go to the court and coming back home ? (1)
(ii) There is a crossing on X-axis which divides AD in a certain ratio. Find the ratio. (1)
(iii) (a) Is Birla Mandir equidistant from Heera Bagh and Amar Jawan Jyoti ? Justify your answer. (2)
OR (b) Using section formula, show that points A, O and B are not collinear.

Show answer & solution
Answer: (i) units (ii) 1 : 1 (iii) (a) No (BC = 7, BD = ) OR (b) Shown: O does not lie on AB
  1. (i) ; to and fro: units.
  2. (ii) Let the point on the x-axis divide AD in ratio k : 1. y-coordinate: . Ratio 1 : 1.
  3. (iii)(a) , . As , B is not equidistant from C and D.
  4. (iii)(b) If O(0, 0) lies on AB, let it divide AB in ratio k : 1. x: .
  5. Then y . No single ratio works, so A, O and B are not collinear.
Q384 marksCase StudyTriangles

Carom board is a very popular game. The board is a square of side length 65 cm. It has circular pockets in each corner.
Ansh strikes a disc, kept at position P with a striker. The disc, hits the boundary of the board at R and goes straight to pocket at corner C. It is given that PS = 9 cm, PQ = 35 cm, BR = , and .
Based on the above information, answer the following questions :
(i) Using law of reflection i.e. , prove that . (1)
(ii) Prove that given that PQ is perpendicular to AB. (1)
(iii) (a) Find the value of using similarity of triangles. (2)
OR (b) If , then find the value of .

Diagram for CBSE 2026 Class 10 Maths question 38
Show answer & solution
Answer: (i) Proved. (ii) Proved. (iii) (a) cm OR (b) cm
  1. (i) RT is perpendicular to AB at R, so and . As , .
  2. (ii) In and : and (part (i)). So (AA).
  3. (iii)(a) AQ = PS = 9 cm, so .
  4. cm
  5. (iii)(b) For similar triangles the area ratio equals the square of the ratio of corresponding sides, so , i.e. , giving cm.
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