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CBSE Class 10 Maths Standard 2026 Question Paper 30/2/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/2/3 (2026), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/3/1Set 30/3/2Set 30/3/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3

The distance of the point A(4a, 3a) from x-axis is :

  1. (A)3a
  2. (B)
  3. (C)4a
  4. (D)
Show answer & solution
Answer: (A) 3a
  1. The distance of a point from the x-axis is the absolute value of its y-coordinate.
  2. So the distance is 3a (taking a > 0).
Also asked in: 2026 Standard 30/2/1
Q21 markMCQReal Numbers

The natural number 1 is :

  1. (A)a prime number.
  2. (B)a composite number.
  3. (C)prime as well as composite.
  4. (D)neither prime nor composite.
Show answer & solution
Answer: (D) neither prime nor composite.
  1. A prime number has exactly two factors and a composite number has more than two factors.
  2. 1 has only one factor (itself), so it is neither prime nor composite.

Given , the value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. : adjacent = 3, opposite = 1, hypotenuse .
Q41 markMCQReal Numbers

For any natural number n, ends with the digit :

  1. (A)0
  2. (B)5
  3. (C)3
  4. (D)2
Show answer & solution
Answer: (B) 5
  1. , , , ...
  2. Every power of 5 ends with the digit 5.

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)1
Show answer & solution
Answer: (B)
  1. , so .
Q61 markMCQReal Numbers

The LCM of 960 and 240 is :

  1. (A)960
  2. (B)240
  3. (C)60
  4. (D)15
Show answer & solution
Answer: (A) 960
  1. Since , 240 is a factor of 960.
  2. So the smallest common multiple of 960 and 240 is 960 itself.
Also asked in: 2026 Standard 30/2/1

From a point on the ground, which is 60 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is found to be . The height (in metres) of the tower is :

  1. (A)
  2. (B)
  3. (C)60
  4. (D)30
Show answer & solution
Answer: (C) 60
  1. Let the height be h m.
Q81 markMCQPolynomials

How many zeroes does p(x) = (x - 2) (x + 3) have ?

  1. (A)Zero
  2. (B)One
  3. (C)Two
  4. (D)Three
Show answer & solution
Answer: (C) Two
  1. p(x) = 0 when x = 2 or x = -3.
  2. So p(x) has two zeroes.
Q91 markMCQCircles

In the given figure, PA and PB are tangents to a circle centred at O. If , then equals :

Diagram for CBSE 2026 Class 10 Maths question 9
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. (radius tangent), so .
  2. PA = PB, so .
Q101 markMCQPolynomials

If and are two zeroes of a polynomial and , then value of p is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. and .
Q111 markMCQCircles

In the given figure, PA and PB are tangents to a circle centred at O. If , then is equal to :

Diagram for CBSE 2026 Class 10 Maths question 11
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. In quadrilateral OAPB, .

If the pair of linear equations : and is consistent and dependent, then

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. A consistent and dependent pair represents coincident lines.
  2. For coincident lines, .
Also asked in: 2026 Standard 30/2/1

A hemispherical bowl is made of steel of thickness 1 cm. The outer radius of the bowl is 6 cm. The volume of steel used (in ) is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Outer radius R = 6 cm, inner radius r = 6 - 1 = 5 cm.
  2. Volume of steel

Which of the following sequence is not an A.P. ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. (A) : common difference , an A.P.
  2. (B) : common difference , an A.P.
  3. (C) : common difference , an A.P.
  4. (D) : differences 8, 16, 24 are not equal, so it is not an A.P.
Also asked in: 2026 Standard 30/2/1

The area of a semicircle of diameter 'd' is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Radius .
  2. Area of semicircle
Q161 markMCQTriangles

In the given figure is shown, in which DE BC. If AD = 5 cm, DB = 2.5 cm and DE = 8 cm, then the length of BC is :

Diagram for CBSE 2026 Class 10 Maths question 16
  1. (A)10 cm
  2. (B)6 cm
  3. (C)12 cm
  4. (D)7.5 cm
Show answer & solution
Answer: (C) 12 cm
  1. Since DE BC, .
  2. cm
Q171 markMCQStatistics

The mean and median of a frequency distribution are 43 and 43.4 respectively. The mode of the distribution is :

  1. (A)43.4
  2. (B)42.4
  3. (C)44.2
  4. (D)49.3
Show answer & solution
Answer: (C) 44.2
  1. Mode = 3 Median - 2 Mean
Q181 markMCQProbability

The probability for a randomly selected number out of 1, 2, 3, 4, ..., 25 to be a composite number is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Primes up to 25: 2, 3, 5, 7, 11, 13, 17, 19, 23 (9 numbers). The number 1 is neither prime nor composite.
  2. Composite numbers = 25 - 9 - 1 = 15.
  3. P(composite)
Q191 markAssertion–ReasonSurface Areas and Volumes

Assertion (A) : The surface area of the cuboid formed by joining two cubes of sides 4 cm each, end-to-end, is 160 .
Reason (R): The surface area of a cuboid of dimensions is .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. The cuboid formed is 8 cm × 4 cm × 4 cm.
  2. Surface area , so A is true.
  3. The surface area of a cuboid is , not , so R is false.
Q201 markAssertion–ReasonArithmetic Progressions

Assertion (A) : The mean of first 'n' natural numbers is .
Reason (R): The sum of first 'n' natural numbers is .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Sum of first n natural numbers , so R is true.
  2. Mean , not , so A is false.
Q212 marksVery Short AnswerCoordinate Geometry

If the distance between the points (4, p) and (1, 0) is 5, what is the value of p ?

Show answer & solution
Answer:
  1. By the distance formula, .
  2. , so or .
Q222 marksVery Short AnswerCircles

In the given figure, O is the centre of the circle. PQ and PR are tangents. Show that the quadrilateral PQOR is cyclic.

Diagram for CBSE 2026 Class 10 Maths question 22
Show answer & solution
Answer: Proved.
  1. A tangent is perpendicular to the radius at the point of contact, so and .
  2. , i.e. one pair of opposite angles of PQOR is supplementary.
  3. Sum of all angles is , so as well.
  4. Hence PQOR is a cyclic quadrilateral.
Q232 marksVery Short AnswerPolynomials

If , are the zeroes of the quadratic polynomial , then find the value of .

Show answer & solution
Answer:
  1. ,
Also asked in: 2026 Standard 30/2/1
Q242 marksVery Short AnswerTriangles

In the given figure, . If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find the length of AC.

Diagram for CBSE 2026 Class 10 Maths question 24
Show answer & solution
Answer: AC = 5 cm
  1. Since , .
  2. AC = 5 cm
OR
Q24 (OR) (OR)2 marksVery Short AnswerTriangles

In the given figure, XY QR, and PR = 6.3 cm. Find the length of YR.

Diagram for CBSE 2026 Class 10 Maths question 24 (OR)
Show answer & solution
Answer: YR = 2.7 cm
  1. Since XY QR, by BPT .
  2. cm
Q252 marksVery Short AnswerIntroduction to Trigonometry

If , find and .

Show answer & solution
Answer: ,
  1. Take a right triangle with opposite side 4k and adjacent side 3k.
  2. Hypotenuse
  3. ,
OR
Q25 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Express and in terms of .

Show answer & solution
Answer: ,
  1. , so (for acute A).
Q263 marksShort AnswerCircles

Prove that the lengths of tangents drawn from an external point to a circle are equal.

Show answer & solution
Answer: Proved.
  1. Let PQ and PR be tangents from an external point P to a circle with centre O, touching it at Q and R. Join OP, OQ and OR.
  2. (tangent radius).
  3. In right triangles OQP and ORP: OQ = OR (radii) and OP = OP (common).
  4. So (RHS).
  5. Hence PQ = PR (CPCT).
OR
Q26 (OR) (OR)3 marksShort AnswerCircles

Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that .

Show answer & solution
Answer: Proved.
  1. Let .
  2. TP = TQ (tangents from an external point), so is isosceles and .
  3. (radius tangent).
  4. Hence .
Q273 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Assume, to the contrary, that is rational. Then , where a, b are co-prime integers and .
  2. Squaring, , so 5 divides , hence 5 divides a.
  3. Let a = 5c. Then , i.e. , so 5 divides and hence 5 divides b.
  4. So 5 is a common factor of a and b, contradicting that they are co-prime.
  5. Hence is irrational.
Q283 marksShort AnswerAreas Related to Circles

Find the area of the sector of a circle of radius 42 cm and of central angle . Also, find the area of the corresponding major sector. [Use ]

Show answer & solution
Answer: Minor sector = 462 ; major sector = 5082
  1. Area of sector
  2. Area of circle
  3. Area of major sector
Also asked in: 2026 Standard 30/2/1
Q293 marksShort AnswerCoordinate Geometry

The three vertices of a rhombus PQRS are P(2, -3), Q(6, 5) and R(-2, 1). Find the coordinates of the fourth vertex S and coordinates of the point where both the diagonals PR and QS intersect.

Show answer & solution
Answer: S(-6, -7); diagonals intersect at (0, -1)
  1. Diagonals of a rhombus bisect each other.
  2. Mid-point of PR ; this is the point of intersection.
  3. Let S = (x, y). Mid-point of QS = (0, -1): , .
  4. x = -6, y = -7, so S = (-6, -7).
Q303 marksShort AnswerProbability

Two different dice are thrown together. Find the probability that the numbers obtained have :
(i) even sum,
(ii) even product.

Show answer & solution
Answer: (i) (ii)
  1. Total outcomes = 36.
  2. (i) Sum is even when both numbers are even (3 × 3 = 9) or both are odd (3 × 3 = 9): 18 outcomes. P
  3. (ii) Product is odd only when both numbers are odd: 9 outcomes. Even product: 36 - 9 = 27. P
Q313 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. and .
  2. LHS
  3. RHS
  4. Hence LHS = RHS.
OR
Q31 (OR) (OR)3 marksShort AnswerIntroduction to Trigonometry

If and , then prove that .

Show answer & solution
Answer: Proved.
  1. and .
  2. Hence proved.
Q325 marksLong AnswerTriangles

Prove that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio.

Show answer & solution
Answer: Proved.
  1. Given: In , DE BC meets AB at D and AC at E. To prove: .
  2. Construction: Join BE and CD; draw EN AB and DM AC.
  3. and , so .
  4. Similarly (using height DM).
  5. Triangles BDE and DEC are on the same base DE and between the same parallels DE and BC, so .
  6. Hence .
OR
Q32 (OR) (OR)5 marksLong AnswerTriangles

As shown in the given figure, a girl of height 90 cm is walking away from the base of a lamp post at a speed of 1.2 m/s. If the lamp is 3.6 m above the ground, find the length of her shadow after 4 seconds.

Diagram for CBSE 2026 Class 10 Maths question 32 (OR)
Show answer & solution
Answer: 1.6 m
  1. Distance walked in 4 s: BD = 1.2 × 4 = 4.8 m. Let shadow DE = x m. CD = 90 cm = 0.9 m, AB = 3.6 m.
  2. (AA: right angles at B and D, common ).
  3. , so
  4. , so and x = 1.6
  5. The shadow is 1.6 m long.
Q335 marksLong AnswerStatistics

An SBI health insurance agent found the following data for distribution of ages of 100 policy holders. The health insurance policies are given to persons of age 15 years and onwards, but less than 60 years.

Age (in yrs)Number of policy holders
15 - 202
20 - 254
25 - 3018
30 - 3521
35 - 4033
40 - 4511
45 - 503
50 - 556
55 - 602

Find the modal age and median age of the policy holders.

Show answer & solution
Answer: Modal age ≈ 36.76 years; median age ≈ 35.76 years
  1. Mode: modal class 35 - 40 (highest frequency 33); l = 35, , , , h = 5.
  2. Mode years
  3. Cumulative frequencies: 2, 6, 24, 45, 78, 89, 92, 98, 100; N = 100, .
  4. Median class 35 - 40; l = 35, cf = 45, f = 33, h = 5.
  5. Median years
Also asked in: 2026 Standard 30/2/1

Represent the following pair of linear equations graphically and hence comment on the condition of consistency of this pair :
x - 5y = 6; 2x - 10y = 12

Show answer & solution
Answer: The lines coincide; the pair is consistent (dependent) with infinitely many solutions.
  1. Points on : (6, 0), (1, -1), (-4, -2).
  2. Points on : (6, 0), (1, -1), (11, 1).
  3. Plotting, both equations give the same line (coincident lines).
  4. Also , , , all equal.
  5. So the pair is consistent and dependent, with infinitely many solutions.
Q355 marksLong AnswerQuadratic Equations

In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

Show answer & solution
Answer: Maths 13, Science 17 or Maths 12, Science 18
  1. Let Maths marks = x; Science marks = 30 - x.
  2. , so x = 12 or 13.
  3. Maths 12, Science 18; or Maths 13, Science 17.
OR
Q35 (OR) (OR)5 marksLong AnswerQuadratic Equations

The length of hypotenuse (in cm) of a right-angled triangle is 6 cm more than twice the length of its shortest side. If the length of its third side is 6 cm less than thrice the length of its shortest side, find the dimensions of the triangle.

Show answer & solution
Answer: 10 cm, 24 cm and 26 cm
  1. Let the shortest side be x cm; hypotenuse = (2x + 6) cm; third side = (3x - 6) cm.
  2. , so x = 10 (x ≠ 0).
  3. Sides: 10 cm, 24 cm and 26 cm.
Q364 marksCase StudySurface Areas and Volumes

On a Sunday your parents took you to a fair. You could see lot of toys displayed and you wanted them to buy a Rubik's cube and a strawberry ice-cream for you.
Based on the information given above, answer the following questions :
(i) Find the length of the diagonal of Rubik's cube if each edge measures 6 cm. (1)
(ii) Find the volume of Rubik's cube if the length of the edge is 7 cm. (1)
(iii) (a) What is the curved surface area of hemisphere (ice-cream) if the base radius is 7 cm ? (2)
OR
(iii) (b) If two cubes of edges 4 cm are joined end-to-end, then find the surface area of the resulting cuboid. (2)

Show answer & solution
Answer: (i) cm (ii) 343 (iii) (a) 308 OR (b) 160
  1. (i) Diagonal of a cube cm
  2. (ii) Volume
  3. (iii)(a) CSA of hemisphere
  4. (iii)(b) Resulting cuboid is 8 cm × 4 cm × 4 cm.
  5. Surface area
Q374 marksCase StudyArithmetic Progressions

Your elder brother wants to buy a car and plans to take a loan from a bank for his car. He repays his total loan of ₹ 1,18,000 by paying every month, starting with the first instalment of ₹ 1,000 and he increases the instalment by ₹ 100 every month.
Based on the information given above, answer the following questions :
(i) Find the amount paid by him in the instalment. (1)
(ii) If the total number of instalments is 40, what is the amount paid in the last instalment ? (1)
(iii) (a) What amount does he still have to pay after the instalment ? (2)
OR
(iii) (b) Find the ratio of the tenth instalment to the last instalment. (2)

Show answer & solution
Answer: (i) ₹ 3,900 (ii) ₹ 4,900 (iii) (a) ₹ 44,500 OR (b) 19 : 49
  1. Instalments form an A.P. with a = 1000, d = 100.
  2. (i) , i.e. ₹ 3,900
  3. (ii) , i.e. ₹ 4,900
  4. (iii)(a)
  5. Amount still to pay = 118000 - 73500 = ₹ 44,500
  6. (iii)(b) ; last instalment = 4900
  7. Ratio = 1900 : 4900 = 19 : 49

Tejas is standing at the top of a building and observes a car at an angle of depression of as it approaches the base of the building at a uniform speed. 6 seconds later, the angle of depression increases to , and at that moment, the car is 25 m away from the building.
Based on the information given above, answer the following questions :
(i) What is the height of the building ? (1)
(ii) What is the distance between the two positions of the car ? (1)
(iii) (a) What would be the total time taken by the car to reach the foot of the building from the starting point ? (2)
OR
(iii) (b) What is the distance of the observer from the car when it makes an angle of ? (2)

Diagram for CBSE 2026 Class 10 Maths question 38
Show answer & solution
Answer: (i) m (ii) 50 m (iii) (a) 9 seconds OR (b) 50 m
  1. In the figure, AB is the building, C and D are the two positions of the car, CB = 25 m.
  2. (i) In , , so m.
  3. (ii) In , , so m. DC = 75 - 25 = 50 m.
  4. (iii)(a) Speed m/s. Time for the remaining 25 m s.
  5. Total time = 6 + 3 = 9 seconds.
  6. (iii)(b) , so m.
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