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CBSE Class 10 Maths Basic 2025 Question Paper 430/6/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/6/2 (2025), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/1Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/3/1Set 430/3/2Set 430/3/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3Set 430/6/1Set 430/6/2Set 430/6/3
Q11 markMCQCircles

In two concentric circles centred at O, a chord AB of the larger circle touches the smaller circle at C. If OA = 3.5 cm, OC = 2.1 cm, then AB is equal to

Diagram for CBSE 2025 Class 10 Maths question 1
  1. (A)5.6 cm
  2. (B)2.8 cm
  3. (C)3.5 cm
  4. (D)4.2 cm
Show answer & solution
Answer: (A) 5.6 cm
  1. OC AB (radius tangent), and the perpendicular from the centre bisects the chord, so AB = 2AC.
  2. AC cm.
  3. AB = 2 2.8 = 5.6 cm.
Q21 markMCQProbability

Three coins are tossed together. The probability that exactly one coin shows head, is

  1. (A)
  2. (B)
  3. (C)1
  4. (D)
Show answer & solution
Answer: (D)
  1. Total outcomes = 8.
  2. Exactly one head: HTT, THT, TTH, i.e. 3 outcomes.
  3. Probability .
Also asked in: 2025 Basic 430/6/1

The volume of air in a hollow cylinder is 450 cm. A cone of same height and radius as that of cylinder is kept inside it. The volume of empty space in the cylinder is

Diagram for CBSE 2025 Class 10 Maths question 3
  1. (A)225 cm
  2. (B)150 cm
  3. (C)250 cm
  4. (D)300 cm
Show answer & solution
Answer: (D) 300 cm
  1. Volume of cylinder cm.
  2. Volume of cone cm.
  3. Empty space cm.

In , . If , then cos C is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Since , AC is the hypotenuse and AB is opposite to C.
  2. , so .
  3. .
Also asked in: 2025 Basic 430/6/1

term of the A.P. , ....... is

  1. (A)23
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , .
  2. .
Q61 markMCQProbability

If probability of happening of an event is 57%, then probability of non-happening of the event is

  1. (A)0.43
  2. (B)0.57
  3. (C)53%
  4. (D)
Show answer & solution
Answer: (A) 0.43
  1. P(E) = 57% = 0.57.
  2. P(not E) = 1 0.57 = 0.43.
Q71 markMCQPolynomials

A quadratic polynomial having zeroes 0 and 2, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. A quadratic with zeroes 0 and is , .
  2. is of this form (k = 4).
  3. Check others: has zeroes 0, 2; has no real zeroes; has zeroes 0, .

OAB is sector of a circle with centre O and radius 7 cm. If length of arc cm, then is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Arc length .
  2. .
  3. .
Q91 markMCQStatistics

To calculate mean of a grouped data, Rahul used assumed mean method. He used d = , where A is assumed mean. Then is equal to

  1. (A)A +
  2. (B)A + h
  3. (C)h (A + )
  4. (D)A h
Show answer & solution
Answer: (A) A +
  1. In the assumed mean method with , .
  2. No class size factor h appears because d is not divided by h.

If the sum of first n terms of an A.P. is given by , then the first term of the A.P. is

  1. (A)2
  2. (B)
  3. (C)4
  4. (D)
Show answer & solution
Answer: (A) 2
  1. First term .

ABCD is a rectangle with its vertices at (2, ), (8, 4), (4, 8) and (, 2) taken in order. Length of its diagonal is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Diagonal AC joins (2, ) and (4, 8).
  2. AC .
Q121 markMCQCircles

In the given figure, PA is tangent to a circle with centre O. If and OA = 2.5 cm, then OP is equal to

Diagram for CBSE 2025 Class 10 Maths question 12
  1. (A)2.5 cm
  2. (B)5 cm
  3. (C) cm
  4. (D)2 cm
Show answer & solution
Answer: (B) 5 cm
  1. OA PA, so is right-angled at A.
  2. , so and OP = 5 cm.
Q131 markMCQProbability

Two dice are rolled together. The probability of getting an outcome (a, b) such that b = 2a, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Total outcomes = 36.
  2. b = 2a: (1, 2), (2, 4), (3, 6), i.e. 3 outcomes.
  3. Probability .

Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is

Diagram for CBSE 2025 Class 10 Maths question 14
  1. (A)8 cm
  2. (B) cm
  3. (C) cm
  4. (D)12 cm
Show answer & solution
Answer: (B) cm
  1. Height of one cone cm.
  2. The solid is two cones joined at their vertices, so its height cm.

If , then is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. .
  2. .
Q161 markMCQTriangles

In , DE BC. If AE = cm, EC = 4 cm, AD = cm and DB = 3 cm, then value of is

Diagram for CBSE 2025 Class 10 Maths question 16
  1. (A)1
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. By BPT, , so .
  2. , so and .

The value of k for which the system of equations and is inconsistent, is

  1. (A)
  2. (B)
  3. (C)6
  4. (D)
Show answer & solution
Answer: (A)
  1. Inconsistent when .
  2. gives , and .

The line intersects – axis at

  1. (A)(0, )
  2. (B)(0, 3)
  3. (C)(, 0)
  4. (D)(3, 0)
Show answer & solution
Answer: (D) (3, 0)
  1. On the -axis, .
  2. , so . The point is (3, 0).
Also asked in: 2025 Basic 430/6/1
Q191 markAssertion–ReasonTriangles

Assertion (A) : such that , . Hence .
Reason (R) : Sum of all angles of a triangle is .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not correct explanation for Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  1. R is true (angle sum property).
  2. In , by R.
  3. Corresponding angles of similar triangles are equal, so . A is true.
  4. R is used to find the angle, so R explains A.
Q201 markAssertion–ReasonReal Numbers

Assertion (A) : is a rational number, where a and b are positive integers.
Reason (R) : Product of two irrationals is always rational.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not correct explanation for Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. , an integer, so it is rational. A is true.
  2. R is false: e.g. is irrational.
Q212 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

Show answer & solution
Answer:
  1. , , .
  2. Denominator .
  3. Value .
OR
Q21 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Verify that , for .

Show answer & solution
Answer: Verified: both sides equal .
  1. LHS .
  2. RHS .
  3. LHS = RHS, hence verified.
Q222 marksVery Short AnswerProbability

A box contains 120 discs, which are numbered from 1 to 120. If one disc is drawn at random from the box, find the probability that
(i) it bears a 2– digit number
(ii) the number is a perfect square.

Show answer & solution
Answer: (i) (ii)
  1. Total outcomes = 120.
  2. (i) 2-digit numbers are 10 to 99, i.e. 90 numbers. P = .
  3. (ii) Perfect squares up to 120: 1, 4, 9, ..., 100, i.e. 10 numbers (). P .
Q232 marksVery Short AnswerReal Numbers

Using prime factorisation, find the HCF of 144, 180 and 192.

Show answer & solution
Answer: HCF = 12
  1. HCF = product of the smallest powers of common primes .
Q242 marksVery Short AnswerQuadratic Equations

Solve the equation , using quadratic formula.

Show answer & solution
Answer: ,
  1. , , .
  2. .
  3. .
Also asked in: 2025 Basic 430/6/1
OR
Q24 (OR) (OR)2 marksVery Short AnswerQuadratic Equations

Find the nature of roots of the equation .

Show answer & solution
Answer: Real and equal roots
  1. , , .
  2. .
  3. Since D = 0, the roots are real and equal.
Also asked in: 2025 Basic 430/6/1
Q252 marksVery Short AnswerTriangles

In the given figure, AB DE and BD EF. Prove that DC = CF AC.

Diagram for CBSE 2025 Class 10 Maths question 25
Show answer & solution
Answer: Proved.
  1. In , DE AB, so by BPT ... (1)
  2. In , FE DB, so by BPT ... (2)
  3. From (1) and (2), .
  4. Hence DC = CF AC.
Q263 marksShort AnswerReal Numbers

Three friends plan to go for a morning walk. They step off together and their steps measures 48 cm, 52 cm and 56 cm respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps ten times ?

Show answer & solution
Answer: LCM = 4368 cm; covering it ten times, each should walk 43680 cm = 436.8 m.
  1. , , .
  2. LCM cm, the least distance each can cover in complete steps.
  3. To do this ten times, distance cm m.
Q273 marksShort AnswerIntroduction to Trigonometry

Prove that

Show answer & solution
Answer: Proved.
  1. LHS .
  2. .
  3. = RHS.
Also asked in: 2025 Standard 30/2/1
Q283 marksShort AnswerAreas Related to Circles

AB and CD are diameters of a circle with centre O and radius 7 cm. If , then find the area and perimeter of the shaded region.

Diagram for CBSE 2025 Class 10 Maths question 28
Show answer & solution
Answer: Area cm (about 25.67 cm); perimeter cm (about 35.33 cm)
  1. The shaded region is two sectors BOD and AOC, each of angle (, vertically opposite).
  2. Area cm.
  3. Each arc cm.
  4. Perimeter = 4 radii + 2 arcs cm.
Q293 marksShort AnswerArithmetic Progressions

Find the A.P. whose third term is 16 and seventh term exceeds the fifth term by 12. Also, find the sum of first 29 terms of the A.P.

Show answer & solution
Answer: A.P.: 4, 10, 16, 22, ...;
  1. , so .
  2. , so .
  3. A.P.: 4, 10, 16, 22, ...
  4. .
OR
Q29 (OR) (OR)3 marksShort AnswerArithmetic Progressions

Find the sum of first 20 terms of an A.P. whose term is given by . Can 52 be a term of this A.P. ?

Show answer & solution
Answer: ; No, 52 is not a term.
  1. , .
  2. .
  3. If , then , which is not a natural number.
  4. So 52 is not a term of the A.P.
Q303 marksShort AnswerPolynomials

If , are zeroes of the polynomial , then form a quadratic polynomial in whose zeroes are and .

Show answer & solution
Answer: (or any non-zero multiple )
  1. , .
  2. Sum of new zeroes .
  3. Product of new zeroes .
  4. Required polynomial .
Also asked in: 2025 Basic 430/6/1
OR
Q30 (OR) (OR)3 marksShort AnswerPolynomials

Find the zeroes of the polynomial and verify the relationship between zeroes and its coefficients.

Show answer & solution
Answer: Zeroes: and ; relationship verified.
  1. .
  2. Zeroes: , .
  3. Sum and .
  4. Product and .
  5. Hence the relationship is verified.
Also asked in: 2025 Basic 430/6/1
Q313 marksShort AnswerQuadratic Equations

The sum of a number and its reciprocal is . Find the number.

Show answer & solution
Answer: or
  1. Let the number be . Then .
  2. , so .
  3. .
  4. or .

Two poles of equal heights are standing opposite each other on either side of the road which is 85 m wide. From a point between them on the road, the angles of elevation of the top of the poles are and respectively. Find the height of the poles and the distances of the point from the poles. (Use )

Show answer & solution
Answer: Height m; distances 21.25 m and 63.75 m
  1. Let the height be m and the point be m from the first pole (elevation ), so m from the other.
  2. , so .
  3. , so .
  4. gives , m.
  5. m.
  6. Distances from the poles: 21.25 m and 85 21.25 = 63.75 m.

Solve the following pair of linear equations by graphical method :
and

Show answer & solution
Answer: , (the lines intersect at (4, 1))
  1. For : points (0, 9), (3, 3), (4, 1).
  2. For : points (2, 0), (0, ), (4, 1).
  3. Plot both lines on the same axes.
  4. The lines intersect at (4, 1).
  5. Check: and . So , .
OR
Q33 (OR) (OR)5 marksLong AnswerPair of Linear Equations in Two Variables

Nidhi received simple interest of ₹ 1,200 when invested ₹ at 6% p.a. and ₹ y at 5% p.a. for 1 year. Had she invested ₹ at 3% p.a. and ₹ y at 8% p.a. for that year, she would have received simple interest of ₹ 1,260. Find the values of and y.

Show answer & solution
Answer: = ₹ 10,000, y = ₹ 12,000
  1. , so ... (1)
  2. , so ... (2)
  3. (2) 2: ... (3)
  4. (3) (1): , so .
  5. From (1): , so .
Q345 marksLong AnswerStatistics

Find ‘mean’ and ‘mode’ of the following data :
Class: 0 – 15, 15 – 30, 30 – 45, 45 – 60, 60 – 75, 75 – 90
Frequency: 11, 8, 15, 7, 10, 9

Show answer & solution
Answer: Mean = 43.5; Mode = 37
  1. Class marks: 7.5, 22.5, 37.5, 52.5, 67.5, 82.5; .
  2. .
  3. Mean .
  4. Modal class 30 – 45 (highest frequency 15): , , , , .
  5. Mode .
Q355 marksLong AnswerCircles

The given figure shows a circle with centre O and radius 4 cm circumscribed by . BC touches the circle at D such that BD = 6 cm, DC = 10 cm. Find the length of AE.

Diagram for CBSE 2025 Class 10 Maths question 35
Show answer & solution
Answer: AE cm (about 5.82 cm)
  1. Tangents from an external point are equal: BF = BD = 6, CE = CD = 10, AE = AF = (say).
  2. Sides: BC = 16, CA = , AB = ; semi-perimeter .
  3. Area perimeter .
  4. By Heron: Area .
  5. So , i.e. .
  6. , so cm.
OR
Q35 (OR) (OR)5 marksLong AnswerCircles

PA and PB are tangents drawn to a circle with centre O.
If and OA = 10 cm, then
(i) Find . (1)
(ii) Find the perimeter of . (3)
(iii) Find the length of chord AB. (1)

Diagram for CBSE 2025 Class 10 Maths question 35 (OR)
Show answer & solution
Answer: (i) (ii) cm (about 47.3 cm) (iii) AB cm
  1. (i) , so . OP bisects , so .
  2. (ii) In right : , so OP = 20 cm; , so AP cm.
  3. Perimeter cm.
  4. (iii) is isosceles with OA = OB = 10 and . The perpendicular from O to AB bisects AB and .
  5. Half of AB , so AB cm.
Q364 marksCase StudySurface Areas and Volumes

A hemispherical bowl is packed in a cuboidal box. The bowl just fits in the box. Inner radius of the bowl is 10 cm. Outer radius of the bowl is 10.5 cm.
Based on the above, answer the following questions :
(i) Find the dimensions of the cuboidal box. (1)
(ii) Find the total outer surface area of the box. (1)
(iii) (a) Find the difference between the capacity of the bowl and the volume of the box. (use ) (2)
OR
(iii) (b) The inner surface of the bowl and the thickness is to be painted. Find the area to be painted. (2)

Diagram for CBSE 2025 Class 10 Maths question 36
Show answer & solution
Answer: (i) 21 cm 21 cm 10.5 cm (ii) 1764 cm (iii) (a) about 2537.17 cm OR (b) about 660.79 cm
  1. (i) The bowl just fits, so length = breadth = outer diameter = 21 cm and height = outer radius = 10.5 cm.
  2. (ii) TSA cm.
  3. (iii) (a) Capacity of bowl cm.
  4. Volume of box cm.
  5. Difference cm.
  6. (iii) (b) Inner curved surface cm.
  7. Rim (thickness) cm.
  8. Area to be painted cm.
Q374 marksCase StudyTriangles

A triangular window of a building is shown above. Its diagram represents a with and AB = AC. Points P and R trisect AB and PQ RS AC.
Based on the above, answer the following questions :
(i) Show that . (1)
(ii) Prove that PQ AC. (1)
(iii) (a) If AB = 3 m, find length BQ and BS. Verify that BQ BS. (2)
OR
(iii) (b) Prove that BR + RS BC. (2)

Diagram for CBSE 2025 Class 10 Maths question 37
Show answer & solution
Answer: (i) Proved (AA similarity) (ii) Proved (iii) (a) BQ m, BS m, so BQ BS OR (b) Proved
  1. (i) In and : is common and (corresponding angles, PQ AC). So (AA).
  2. (ii) From (i), . P and R trisect AB with P nearer B, so BP AB. Hence PQ AC.
  3. (iii) (a) AC = AB = 3 m, so BC m. From the similarity, BQ BC m.
  4. Similarly with BR AB, so BS BC m. Thus BQ BS.
  5. (iii) (b) with ratio , so BR AB and RS AC.
  6. BR + RS (AB + AC) BC (Pythagoras in , right-angled at A).
Q384 marksCase StudyCoordinate Geometry

Gurveer and Arushi built a robot that can paint a path as it moves on a graph paper. Some co-ordinate of points are marked on it. It starts from (0, 0), moves to the points listed in order (in straight lines) and ends at (0, 0).
Arushi entered the points P(8, 6), Q(12, 2) and S( 6, 6) in order. The path drawn by robot is shown in the figure.
Based on the above, answer the following questions :
(i) Determine the distance OP. (1)
(ii) QS is represented by equation . Find the co-ordinates of the point where it intersects y – axis. (1)
(iii) (a) Point R(4.8, y) divides the line segment OP in a certain ratio, find the ratio. Hence, find the value of y. (2)
OR
(iii) (b) Using distance formula, show that . (2)

Diagram for CBSE 2025 Class 10 Maths question 38
Show answer & solution
Answer: (i) 10 units (ii) (iii) (a) 3 : 2, y = 3.6 OR (b) Shown: PQ , OS
  1. (i) OP units.
  2. (ii) On the y-axis : , . Point .
  3. (iii) (a) Let R divide OP in the ratio . Then , so , . Ratio .
  4. y .
  5. (iii) (b) PQ ; OS .
  6. .
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