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CBSE Class 10 Maths Basic 2025 Question Paper 430/5/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/5/3 (2025), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/1Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/3/1Set 430/3/2Set 430/3/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3Set 430/6/1Set 430/6/2Set 430/6/3
Q11 markMCQCircles

PQ is tangent to the circle centred at O. If OQ = 3 cm, PQ = 5 cm, then OP is equal to

Diagram for CBSE 2025 Class 10 Maths question 1
  1. (A)5 cm
  2. (B)4 cm
  3. (C) cm
  4. (D) cm
Show answer & solution
Answer: (D) cm
  1. (radius tangent).
  2. , so OP cm.
Also asked in: 2025 Basic 430/5/1
Q21 markMCQStatistics

Which of the following depends on all observations of a given data ?

  1. (A)Median
  2. (B)Mean
  3. (C)Range
  4. (D)Mode
Show answer & solution
Answer: (B) Mean
  1. Mean = (sum of all observations) / (number of observations), so every observation affects it.
  2. Median, mode and range depend only on particular observations.
Q31 markMCQPolynomials

A quadratic polynomial having only zero (–2) is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. A quadratic with as its only zero must be .
  2. gives only.

If sin A = cos A, then is equal to

  1. (A)1
  2. (B)–1
  3. (C)0
  4. (D)not defined
Show answer & solution
Answer: (C) 0
  1. gives .
  2. .
Q51 markMCQProbability

A black card is lost from a deck of 52 playing cards. Rest of the cards are shuffled and one card is drawn at random from the available cards. The probability that drawn card is 'king of hearts', is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. 51 cards remain.
  2. The king of hearts is a red card, so it is still in the deck.
  3. P(king of hearts) .

The point (, 0) divides the line segment joining the points (–4, 5) and (0, –10) in the ratio

  1. (A)1 : 3
  2. (B)2 : 1
  3. (C)1 : 1
  4. (D)1 : 2
Show answer & solution
Answer: (D) 1 : 2
  1. Let the ratio be .
  2. y-coordinate: , so and .
  3. Ratio .
Q71 markMCQCircles

In the given figure, AB is diameter of the circle with centre O. CD is tangent to the circle so that . The value of is

Diagram for CBSE 2025 Class 10 Maths question 7
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. OC is a radius and CD a tangent at C, so .
  2. .
  3. OA = OC, so .
  4. (angle in a semicircle).
  5. In : .
Q81 markMCQPolynomials

Observe the given graph of polynomial p(). The number of zeroes of p() is

Diagram for CBSE 2025 Class 10 Maths question 8
  1. (A)0
  2. (B)1
  3. (C)3
  4. (D)2
Show answer & solution
Answer: (D) 2
  1. The number of zeroes equals the number of points where the graph meets the -axis.
  2. The curve cuts the -axis at two points, so p() has 2 zeroes.
Q91 markMCQProbability

Two dice are rolled together. The probability that only one die shows number 4, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Total outcomes .
  2. First die 4, second not 4: 5 outcomes; second die 4, first not 4: 5 outcomes.
  3. Favourable , so probability .

If the distance between the points (3, 0) and (2, y) is , then the value(s) of y is :

  1. (A)2, –2
  2. (B)2, 0
  3. (C)2, 1
  4. (D)–2, 0
Show answer & solution
Answer: (A) 2, –2
  1. .
  2. , so and or .
Q111 markMCQCircles

PQ and PR are tangents to a circle with centre O such that OQ = QP. The value of is equal to

Diagram for CBSE 2025 Class 10 Maths question 11
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. (radius tangent).
  2. OQ = QP, so is an isosceles right triangle.
  3. .

The roots of the equation are

  1. (A)rational and distinct
  2. (B)irrational and distinct
  3. (C)real and equal
  4. (D)not real
Show answer & solution
Answer: (B) irrational and distinct
  1. , so .
  2. The two roots are different and irrational.

term of the A.P. : –12, –19, –26, .... is

  1. (A)–75
  2. (B)–65
  3. (C)51
  4. (D)–82
Show answer & solution
Answer: (A) –75
  1. , .
  2. .
Also asked in: 2025 Basic 430/5/1
Q141 markMCQProbability

If E is an event such that P(E) = 0.1, then P() is equal to

  1. (A)0.9
  2. (B)
  3. (C)0.99
  4. (D)–1
Show answer & solution
Answer: (A) 0.9
  1. P() P(E) .
Also asked in: 2025 Basic 430/5/1

The largest possible cone is just fitted inside a hollow cube of edge 25 cm. The radius of the base of the cone is

  1. (A)5 cm
  2. (B)12.5 cm
  3. (C)25 cm
  4. (D)10 cm
Show answer & solution
Answer: (B) 12.5 cm
  1. The base of the largest cone fits exactly on a face of the cube, so its diameter equals the edge, 25 cm.
  2. Radius cm.

An arc of length '' subtends an angle of at the centre of a circle of radius 8.4 cm. The value of is

  1. (A)22 cm
  2. (B)2.2 cm
  3. (C)9.24 cm
  4. (D)4.2 cm
Show answer & solution
Answer: (B) 2.2 cm
  1. .
  2. cm.

The value of k for which the roots of the quadratic equation are real and equal, is

  1. (A)0
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A) 0
  1. For real and equal roots, .
  2. .
  3. So or .
  4. Of the options only fits (the equation becomes with equal roots 0, 0).
Also asked in: 2025 Basic 430/5/1
Q181 markMCQReal Numbers

is

  1. (A)an integer
  2. (B)a rational number
  3. (C)an irrational number
  4. (D)equal to 1
Show answer & solution
Answer: (C) an irrational number
  1. .
  2. is irrational, so is irrational.
Q191 markAssertion–ReasonIntroduction to Trigonometry

Assertion (A) : In a right angle triangle ABC, . Therefore the value of cos (A + C) is equal to 0.
Reason (R) : and .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  1. and , so .
  2. , so A is true.
  3. R is true and is exactly the reason used.
Q201 markAssertion–ReasonSurface Areas and Volumes

Assertion (A) : When a hemisphere of same radius (r) is carved out from one side of a solid wooden cylinder, the total surface area of remaining solid is increased by .
Reason (R) : Curved surface area of hemisphere is .

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. Carving out removes one circular face of area and adds the hemisphere's curved surface .
  2. Net increase , not , so A is false.
  3. CSA of a hemisphere , so R is true.
Q212 marksVery Short AnswerProbability

A bag contains 40 marbles out of which some are white and others are black. If the probability of drawing a black marble is , then find the number of white marbles.

Show answer & solution
Answer: 16
  1. Number of black marbles .
  2. Number of white marbles .
OR
Q21 (OR) (OR)2 marksVery Short AnswerProbability

In a pre-primary class, a teacher put cards numbered 20 to 59 in a bowl. A student picked up a card at random and read the number. Find the probability that the number read was (i) a prime number (ii) a perfect square.

Show answer & solution
Answer: (i) (ii)
  1. Total cards .
  2. (i) Primes: 23, 29, 31, 37, 41, 43, 47, 53, 59, i.e. 9 cards. P .
  3. (ii) Perfect squares: 25, 36, 49, i.e. 3 cards. P .
Q222 marksVery Short AnswerCoordinate Geometry

Find the coordinates of the points of trisection of line segment joining the points (–4, 1) and (6, 5).

Show answer & solution
Answer: and
  1. Let A(–4, 1), B(6, 5). The points of trisection divide AB in the ratios 1 : 2 and 2 : 1.
  2. For 1 : 2: .
  3. For 2 : 1: .
Also asked in: 2025 Basic 430/5/1
Q232 marksVery Short AnswerCoordinate Geometry

Using distance formula, show that the points (–1, 3), (6, 2) and (3, –1) are vertices of a right-angled triangle.

Show answer & solution
Answer: Proved (right angle at (3, –1)).
  1. Let A(–1, 3), B(6, 2), C(3, –1).
  2. .
  3. .
  4. .
  5. , so by the converse of Pythagoras theorem, is right-angled at C.
Q242 marksVery Short AnswerReal Numbers

Check whether , n being a natural number, ends with the digit zero.

Show answer & solution
Answer: Yes, always ends with the digit zero.
  1. .
  2. A number ends with 0 if its prime factorisation contains both 2 and 5.
  3. For every natural number n, both 2 and 5 occur, so ends with zero.
Also asked in: 2025 Basic 430/5/1
Q252 marksVery Short AnswerIntroduction to Trigonometry

If sec A = , then find the value of cosec A and tan A.

Show answer & solution
Answer: cosec A , tan A
  1. ; take hypotenuse , adjacent side .
  2. Opposite side .
  3. and .
OR
Q25 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Verify that sin (A + B) = sin A cos B + cos A sin B for A = and B = .

Show answer & solution
Answer: Verified (both sides equal 1).
  1. LHS .
  2. RHS .
  3. LHS = RHS, hence verified.
Q263 marksShort AnswerIntroduction to Trigonometry

Prove that : .

Show answer & solution
Answer: Proved.
  1. LHS .
  2. .
  3. .
  4. .
  5. LHS = RHS.
Q273 marksShort AnswerReal Numbers

The traffic lights at three different road crossings change after every 45 seconds, 75 seconds and 60 seconds respectively. If they change together at 5.00 a.m., then at what time they will change together next ?

Show answer & solution
Answer: 5:15 a.m. (after 900 seconds = 15 minutes)
  1. , , .
  2. LCM seconds minutes.
  3. They will change together next at 5:15 a.m.
Also asked in: 2025 Basic 430/5/1
Q283 marksShort AnswerPolynomials

If , are zeroes of the polynomial , then form a quadratic polynomial in whose zeroes are and .

Show answer & solution
Answer: , or
  1. , .
  2. Sum of new zeroes .
  3. Product of new zeroes .
  4. Required polynomial , or (any non-zero multiple).
OR
Q28 (OR) (OR)3 marksShort AnswerPolynomials

Find zeroes of the polynomial and verify the relationship between zeroes and its coefficients.

Show answer & solution
Answer: Zeroes and ; relationship verified.
  1. .
  2. Zeroes: and .
  3. Sum and .
  4. Product and .
  5. Both relations hold.
Q293 marksShort AnswerTriangles

It is given that . Prove that .

Diagram for CBSE 2025 Class 10 Maths question 29
Show answer & solution
Answer: Proved.
  1. Since , corresponding parts are equal: AD = AE and AC = AB.
  2. So .
  3. In and , (common angle).
  4. Hence (SAS similarity criterion).
Q303 marksShort AnswerQuadratic Equations

The sum of the squares of two consecutive odd numbers is 514. Find the numbers.

Show answer & solution
Answer: 15 and 17 (or –17 and –15)
  1. Let the numbers be and .
  2. , so , i.e. .
  3. , so or .
  4. The numbers are 15 and 17 (or –17 and –15).
Q313 marksShort AnswerSurface Areas and Volumes

A spherical glass vessel has a cylindrical neck 7 cm long and 8 cm in diameter. The radius of spherical part is 10 cm. Find the volume of the vessel.

Show answer & solution
Answer: cm cm
  1. Volume of sphere .
  2. Volume of neck (cylinder, r = 4 cm, h = 7 cm) .
  3. Total cm.
OR
Q31 (OR) (OR)3 marksShort AnswerSurface Areas and Volumes

From each end of a solid cylinder of height 20 cm and base radius 7 cm, a cone of base radius 2.1 cm and height 5 cm is scooped out. Find the volume of the remaining solid.

Show answer & solution
Answer: 3033.8 cm
  1. Volume of cylinder cm.
  2. Volume of one cone cm.
  3. Two cones cm.
  4. Remaining volume cm.
Q325 marksLong AnswerStatistics

Find 'mean' and 'mode' of the following data :
Class: 10-25, 25-40, 40-55, 55-70, 70-85, 85-100
Number of Students: 12, 10, 15, 13, 8, 12

Show answer & solution
Answer: Mean ; Mode
  1. Class marks: 17.5, 32.5, 47.5, 62.5, 77.5, 92.5; take , , : –2, –1, 0, 1, 2, 3.
  2. : –24, –10, 0, 13, 16, 36; , .
  3. Mean (approx.).
  4. Modal class 40-55: , , , , .
  5. Mode (approx.).
OR
Q32 (OR) (OR)5 marksLong AnswerStatistics

The following table shows the ages of patients admitted in a hospital during a year :
Age (in years): 5-15, 15-25, 25-35, 35-45, 45-55, 55-65
Number of Patients: 7, 10, 21, 22, 15, 5
Find 'mode' and 'median' of the above data.

Show answer & solution
Answer: Mode = 36.25 years; Median years
  1. Modal class 35-45: , , , , .
  2. Mode .
  3. Cumulative frequencies: 7, 17, 38, 60, 75, 80; , .
  4. Median class 35-45: , , , .
  5. Median (approx.).

A statue 3 m tall, stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is and from the same point the angle of elevation of the top of the pedestal is . Find the height of the pedestal and its distance from the point of observation on ground. (Use = 1.73)

Show answer & solution
Answer: Height of pedestal = 1.5 m; distance = m = 2.595 m
  1. Let the height of the pedestal be m and its distance from the point of observation be m.
  2. , so .
  3. , so .
  4. , so m.
  5. m.

Solve the following pair of equations using graphical method :
and

Show answer & solution
Answer: ,
  1. For , i.e. : points (–1, 0), (3, 3), (7, 6).
  2. For , i.e. : points (–2, 1), (3, 3), (8, 5).
  3. Plot both lines on the same axes.
  4. The lines intersect at (3, 3).
  5. Hence the solution is , .
Q355 marksLong AnswerTriangles

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.

Show answer & solution
Answer: Proved.
  1. Given: In , DE BC with D on AB and E on AC. To prove: .
  2. Construction: join BE and CD; draw EM AB and DN AC.
  3. ar(ADE) and ar(BDE) , so .
  4. ar(ADE) and ar(DEC) , so .
  5. and are on the same base DE and between the same parallels DE and BC, so ar(BDE) = ar(DEC).
  6. Hence .
OR
Q35 (OR) (OR)5 marksLong AnswerTriangles

It is given that sides AB and AC and median AD of are respectively proportional to sides PQ and PR and median PM of another . Show that .

Show answer & solution
Answer: Proved.
  1. Given .
  2. Produce AD to E with DE = AD and PM to N with MN = PM; join CE and RN.
  3. (BD = DC, AD = DE, vertically opposite angles), so CE = AB and .
  4. Similarly RN = PQ and .
  5. Now .
  6. So (SSS), giving and .
  7. Then .
  8. Adding: .
  9. With , (SAS).
Q364 marksCase StudyAreas Related to Circles

A farmer has put up a decorative windmill in his farm in which there are eight blades of equal width and equally placed in a circular arrangement. A circular wire goes through them.
The diagram shows two blades OAB and OPQ in a quarter circle with centre O. , OA = 28 cm, OC = 21 cm.
O is the centre of both the circles.
(i) Determine the measure of . (1)
(ii) Find length of arc CD. (1)
(iii) (a) Find the area of region CABD. (2)
OR
(iii) (b) Find perimeter of region CABD. (2)

Diagram for CBSE 2025 Class 10 Maths question 36
Show answer & solution
Answer: (i) (ii) 11 cm (iii) (a) cm cm OR (b) cm cm
  1. (i) The quarter circle AOR is ; the two blades take . The blades are equally placed, so the remaining is shared equally by and : (check: 8 blades of and 8 equal gaps of make ).
  2. (ii) Arc CD cm.
  3. (iii) (a) Area CABD = sector OAB – sector OCD cm.
  4. (iii) (b) Arc AB cm; CA = BD = 28 – 21 = 7 cm.
  5. Perimeter cm.
Q374 marksCase StudyArithmetic Progressions

A tent house owner provides furniture on rent. He stacks chairs in his shop to save space.
In the diagram, the height of seat of chair from ground is represented by , , , .... The height of first seat is 44 cm from ground level and gap between every two seats is 10 cm.
(i) Write the values of , , , and in this order only. (1)
(ii) Show that the above values form an A.P. Write its first term and common difference. (1)
(iii) (a) If chairs can be stacked up to the maximum height of 160 cm, then find the maximum number of chairs in a stack. (2)
OR
(iii) (b) Is it possible to stack 15 chairs if maximum height of the stack can not be more than 180 cm ? Justify your answer. (2)

Diagram for CBSE 2025 Class 10 Maths question 37
Show answer & solution
Answer: (i) 44, 54, 64, 74, 84 (cm) (ii) Yes, the common difference is constant (10 cm); first term = 44, common difference = 10 (iii) (a) 12 chairs OR (b) No, cm > 180 cm
  1. (i) , , , , (in cm).
  2. (ii) Each term exceeds the previous one by 10, a constant, so they form an A.P. with , .
  3. (iii) (a) gives , so .
  4. Maximum number of chairs (seat height 154 cm; the 13th would be at 164 cm).
  5. (iii) (b) cm, which is more than 180 cm.
  6. So 15 chairs cannot be stacked.
Q384 marksCase StudyCircles

In a Fine Arts class, students were asked to design triangular tiles in geometric pattern.
Neelima made a circular design inside an equilateral triangle ABC. The radius of the circle is 4 cm. Observe the diagram and answer the following questions :
(i) Determine the length OB. (1)
(ii) Is DE CA ? Give reason for your answer. (1)
(iii) (a) Write all angles of quadrilateral OEBD and show that it is a cyclic quadrilateral. (2)
OR
(iii) (b) Find the perimeter of . (Use ) (2)

Diagram for CBSE 2025 Class 10 Maths question 38
Show answer & solution
Answer: (i) OB = 8 cm (ii) Yes, D and E are mid-points of BC and AB (iii) (a) , , , ; cyclic since OR (b) cm = 41.52 cm
  1. The circle touches BC at D and AB at E, so OD BC, OE AB and OD = OE = 4 cm.
  2. (i) In right , : , so OB cm.
  3. (ii) Tangents from a point are equal: BD = BE, CD = CF, AE = AF (F the point of contact on CA). As AB = BC = CA, each tangent length is half a side, so D and E are mid-points of BC and BA.
  4. By the mid-point theorem, DE CA. Yes.
  5. (iii) (a) , , (angle of equilateral triangle), .
  6. (also ): opposite angles are supplementary, so OEBD is cyclic.
  7. (iii) (b) , so BD cm and BC cm.
  8. Perimeter cm.
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