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CBSE Class 10 Maths Basic 2025 Question Paper 430/2/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/2/2 (2025), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/1/1Set 430/1/2Set 430/1/3Set 430/2/1Set 430/2/2Set 430/2/3Set 430/3/1Set 430/3/2Set 430/3/3Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3Set 430/6/1Set 430/6/2Set 430/6/3

The mid-point of the line segment joining points (1, 3) and (1, ) lies :

  1. (A)at the origin
  2. (B)in the second quadrant
  3. (C)on x-axis
  4. (D)on y-axis
Show answer & solution
Answer: (C) on x-axis
  1. Mid-point .
  2. Its y-coordinate is 0, so it lies on the x-axis.
Q21 markMCQTriangles

In the given figure, if DE BC, AD = 1.5 cm, DB = 3 cm and EC = 2 cm, the length of AC is :

Diagram for CBSE 2025 Class 10 Maths question 2
  1. (A)1.5 cm
  2. (B)3 cm
  3. (C)3.5 cm
  4. (D)4.5 cm
Show answer & solution
Answer: (B) 3 cm
  1. Since DE BC, by BPT .
  2. cm.
  3. AC = AE + EC = 1 + 2 = 3 cm.
Q31 markMCQCircles

In two concentric circles, a tangent to the smaller circle will intersect the larger circle at :

  1. (A)zero point
  2. (B)one point
  3. (C)two points
  4. (D)three points
Show answer & solution
Answer: (C) two points
  1. A tangent to the smaller circle passes through a point inside the larger circle (the point of contact).
  2. A line through an interior point of a circle cuts the circle at two points.
  3. So it is a chord of the larger circle: two points.

The value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. , so .
  2. Value .

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B) 2
  1. Expand: .
  2. .

The length of the shadow of a tower when the sun’s altitude changes from to will :

  1. (A)become shorter
  2. (B)become longer
  3. (C)remain same
  4. (D)be doubled
Show answer & solution
Answer: (A) become shorter
  1. For a tower of height h, shadow .
  2. At : shadow ; at : shadow .
  3. So the shadow becomes shorter.

In the given figure, the shaded region represents :

Diagram for CBSE 2025 Class 10 Maths question 7
  1. (A)minor sector
  2. (B)major sector
  3. (C)minor segment
  4. (D)major segment
Show answer & solution
Answer: (C) minor segment
  1. The shaded region is bounded by a chord and the smaller arc cut off by it.
  2. The region between a chord and the minor arc is the minor segment.

The area of a quadrant of a circle of radius ‘2r’ is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Area of quadrant .

A cone of height ‘h’ and radius ‘r’ is surmounted on a solid cylinder of same dimensions. The total surface area of the entire solid will be :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Exposed surfaces: curved surface of cylinder , bottom base of cylinder and curved surface of cone with .
  2. The top of the cylinder and the base of the cone are joined and hidden.
  3. TSA .
Q101 markMCQStatistics

In the formula of mode given by mode ,
denotes the :

  1. (A)frequency of the modal class
  2. (B)frequency of class preceding modal class
  3. (C)frequency of class succeeding modal class
  4. (D)cumulative frequency of modal class
Show answer & solution
Answer: (A) frequency of the modal class
  1. In the mode formula, is the frequency of the modal class, of the class preceding it and of the class succeeding it.
Q111 markMCQStatistics

For a distribution, if mean = median = a, then its mode is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C) a
  1. Using the empirical relation, mode = 3 median – 2 mean.
  2. Mode .
Q121 markMCQProbability

The total number of outcomes in the experiment of simultaneous throw of three dice is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D) 216
  1. Each die has 6 outcomes.
  2. Total outcomes .
Q131 markMCQReal Numbers

The value of (HCF – LCM) for the two numbers 3 and 5 is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. 3 and 5 are both prime, so HCF = 1 and LCM = .
  2. HCF – LCM .
Q141 markMCQReal Numbers

The number , where is a natural number, cannot end with the digit :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C) 5
  1. A number ending in 5 is divisible by 5, so 5 would have to be a prime factor.
  2. The only prime factor of is 3, so cannot end with 5.
  3. (Its last digits cycle 3, 9, 7, 1.)

The number of solutions of the system of equations , is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)Infinite
Show answer & solution
Answer: (B) 1
  1. is a vertical line and is a horizontal line.
  2. They intersect at exactly one point (3, ), so there is one solution.

The value of ‘a’ for which the equation has real and equal roots is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. For real and equal roots, .
  2. .

Which of the following equations is a quadratic equation ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. (A) gives , which is linear.
  2. (B) gives , which is quadratic.
  3. (C) gives , which is cubic.
  4. (D) is not a polynomial equation.
  5. So (B) is the quadratic equation.

The distance of the point (2, 3) from the origin is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Distance .
Q191 markAssertion–ReasonTriangles

Assertion (A) : All congruent triangles are similar.
Reason (R) : In congruent triangles, the ratio of corresponding sides is 1 : 1.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  1. Congruent triangles have equal corresponding angles and corresponding sides in the ratio 1 : 1.
  2. So their corresponding sides are proportional, which makes them similar.
  3. Both A and R are true and R explains A.
Q201 markAssertion–ReasonReal Numbers

Assertion (A) : The prime numbers which divide 36 also divide 6.
Reason (R) : Any number which divides also divides p.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. , so the primes dividing 36 are 2 and 3, and both divide 6. A is true.
  2. R is false as stated: for example, 4 divides but 4 does not divide 2 (also divides but not p).
  3. The true result is: if a prime divides , then it divides a.
  4. So A is true and R is false.
Q212 marksVery Short AnswerCircles

A quadrilateral circumscribes the circle as shown in the given figure. If AB = 5 cm, BC = 7 cm and CD = 6 cm, then find the length of AD.

Diagram for CBSE 2025 Class 10 Maths question 21
Show answer & solution
Answer: AD = 4 cm
  1. Tangents drawn from an external point to a circle are equal.
  2. So for a quadrilateral circumscribing a circle, AB + CD = BC + AD.
  3. cm.
Q222 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

Show answer & solution
Answer:
  1. , , .
  2. Denominator .
  3. Value .
Q232 marksVery Short AnswerAreas Related to Circles

The area of a smaller circle is equal to the area of a sector of a larger circle with central angle . The radii of the smaller and larger circles are ‘r’ and ‘R’ respectively. Find r : R.

Show answer & solution
Answer:
  1. Area of sector .
  2. .
  3. , so .
OR
Q23 (OR) (OR)2 marksVery Short AnswerAreas Related to Circles

In the given figure, O is the centre of a circle of radius 7 cm. AB is a chord of the circle. Find the perimeter of the shaded region.

Diagram for CBSE 2025 Class 10 Maths question 23 (OR)
Show answer & solution
Answer: cm (about 14.33 cm)
  1. In , OA = OB = 7 cm and , so the base angles are also : the triangle is equilateral and AB = 7 cm.
  2. Length of arc AB cm.
  3. Perimeter of shaded segment = AB + arc AB cm cm.

Find the value of for which the following pair of linear equations has infinitely many solutions :

Show answer & solution
Answer:
  1. Write as and .
  2. For infinitely many solutions: .
  3. From : , so or .
  4. From : , so .
  5. Check : . So .
OR
Q24 (OR) (OR)2 marksVery Short AnswerPair of Linear Equations in Two Variables

Solve for and :

Show answer & solution
Answer: ,
  1. Adding: .
  2. Subtracting: .
  3. Adding these: ; then .
  4. Check: , .
Q252 marksVery Short AnswerTriangles

D is a point on side BC of such that . Prove that .

Show answer & solution
Answer: Proved.
  1. In and :
  2. (given) and (common angle C).
  3. So (AA similarity).
  4. Corresponding sides are proportional: .
  5. Hence .

Solve graphically the following pair of linear equations :
and
Also, write the coordinates of the points where the lines represented by these equations cut the y-axis.

Show answer & solution
Answer: Solution , ; the lines cut the y-axis at (0, ) and (0, ).
  1. : points (0, ), (1, 0), (2, 2).
  2. : points (0, ), (1, 0), (2, 4).
  3. Plot both lines; they intersect at (1, 0), so , .
  4. Put : the first line cuts the y-axis at (0, ) and the second at (0, ).
OR
Q26 (OR) (OR)3 marksShort AnswerPair of Linear Equations in Two Variables

An academy offering cricket coaching bought 10 bats and 5 balls for ₹ 32,500. Later, the academy bought 2 bats and 8 balls for ₹ 10,000. If there is no change in the cost of the bat and of the ball, find the cost of 1 bat and 1 ball.

Show answer & solution
Answer: Cost of 1 bat = ₹ 3,000; cost of 1 ball = ₹ 500
  1. Let a bat cost ₹ x and a ball ₹ y.
  2. ...(1)
  3. ...(2)
  4. From (1), . Substitute in (2): .
  5. .
  6. So a bat costs ₹ 3,000 and a ball costs ₹ 500.
Q273 marksShort AnswerCircles

In the given figure, TP and TQ are tangents at points P and Q of the circle respectively. If reflex , find the measure of each angle of quadrilateral POQT.

Diagram for CBSE 2025 Class 10 Maths question 27
Show answer & solution
Answer: , , ,
  1. .
  2. A tangent is perpendicular to the radius at the point of contact, so .
  3. Sum of angles of quadrilateral POQT is : .
Q283 marksShort AnswerIntroduction to Trigonometry

Prove the following trigonometric identity :

Show answer & solution
Answer: Proved.
  1. LHS .
  2. Numerator .
  3. LHS = RHS.
Q293 marksShort AnswerProbability

A game of chance consists of spinning a wheel which comes to rest at one of the numbers from 1 to 10 (as shown in the given figure) with equal probabilities.
What is the probability that the wheel stops at
(i) a prime number greater than 2 ?
(ii) an odd number less than 9 ?
(iii) a multiple of 4 ?

Diagram for CBSE 2025 Class 10 Maths question 29
Show answer & solution
Answer: (i) (ii) (iii)
  1. Total equally likely outcomes = 10.
  2. (i) Primes greater than 2: 3, 5, 7. P .
  3. (ii) Odd numbers less than 9: 1, 3, 5, 7. P .
  4. (iii) Multiples of 4: 4, 8. P .
Q303 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Assume is rational. Then , where a, b are coprime integers and .
  2. Squaring: , so 5 divides , and since 5 is prime, 5 divides a.
  3. Let . Then , so 5 divides and hence 5 divides b.
  4. So 5 is a common factor of a and b, contradicting that they are coprime.
  5. Hence is irrational.
OR
Q30 (OR) (OR)3 marksShort AnswerReal Numbers

State the “Fundamental Theorem of Arithmetic” and use it to find LCM of 36 and 54.

Show answer & solution
Answer: LCM = 108
  1. Fundamental Theorem of Arithmetic: every composite number can be expressed (factorised) as a product of primes, and this factorisation is unique, apart from the order in which the prime factors occur.
  2. and .
  3. LCM = product of the greatest power of each prime factor .
Q313 marksShort AnswerPolynomials

Find the zeroes of the polynomial and verify the relationship between zeroes of p(x) and its coefficients.

Show answer & solution
Answer: Zeroes: and
  1. .
  2. Zeroes: and .
  3. Sum and . Verified.
  4. Product and . Verified.
Q325 marksLong AnswerTriangles

State AA criterion of similarity of two triangles and use it to prove the following.
In the given figures of and , AD and PS are angle bisectors of and respectively.
If , prove that .

Diagram for CBSE 2025 Class 10 Maths question 32
Show answer & solution
Answer: Proved.
  1. AA criterion: if two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.
  2. Since : and .
  3. AD and PS bisect and , so .
  4. In and : and .
  5. Hence (AA similarity).
Q335 marksLong AnswerSurface Areas and Volumes

A hemispherical depression is scooped out from the top face of a wooden cubical block of side 14 cm. If the diameter of the hemisphere is equal to the side of the cube, find the total surface area of the remaining solid block. (Use )

Show answer & solution
Answer: 1330 cm
  1. Side of cube a = 14 cm; radius of hemisphere r = 7 cm.
  2. TSA = surface area of cube – area of circular top removed + inner curved surface of hemisphere.
  3. .
  4. cm and cm.
  5. TSA cm.
Q345 marksLong AnswerStatistics

The lengths of 40 leaves of a plant are measured, correct to the nearest millimetre and data obtained is represented in the following table :
Length in (mm): 100–120, 120–140, 140–160, 160–180, 180–200
Number of leaves: 8, 9, 12, 5, 6
Find the median length (in mm) of the leaves.

Show answer & solution
Answer: Median length = 145 mm
  1. Cumulative frequencies: 8, 17, 29, 34, 40. n = 40, .
  2. cf just greater than 20 is 29, so the median class is 140–160.
  3. , cf = 17, f = 12, h = 20.
  4. Median mm.
OR
Q34 (OR) (OR)5 marksLong AnswerStatistics

A class teacher has the following absentees record of 30 students of a class.
Number of days: 0–4, 4–8, 8–12, 12–16, 16–20, 20–24
Number of Absent students: 1, 8, , 6, 5,
If the mean number of days a student was absent is 12, find the values of and .

Show answer & solution
Answer: ,
  1. Total: .
  2. Class marks: 2, 6, 10, 14, 18, 22.
  3. .
  4. Mean .
  5. Put : , so .
Q355 marksLong AnswerQuadratic Equations

The sum of areas of two squares is 2650 cm. If the sum of their perimeters is 280 cm, find the sides of the two given squares.

Show answer & solution
Answer: 45 cm and 25 cm
  1. Let the sides be x cm and y cm.
  2. .
  3. .
  4. .
  5. or .
  6. If , (and vice versa). Check: .
  7. The sides are 45 cm and 25 cm.
OR
Q35 (OR) (OR)5 marksLong AnswerQuadratic Equations

Express the equation , as a quadratic equation in standard form. Hence, find the roots of the quadratic equation so obtained.

Show answer & solution
Answer: ; roots and
  1. .
  2. (standard form).
  3. Here , , ; .
  4. .
  5. Both roots are different from 0 and 2, so they are valid.
Q364 marksCase StudyArithmetic Progressions

A woman borrowed ₹ 10,00,000 from her friend and promised to return the borrowed money in monthly instalments beginning from the next month. After one month, she returned ₹ 10,000, the next month she returned ₹ 15,000, the third month she returned ₹ 20,000 and so on, thereby increasing the monthly instalment uniformly.
Based on the above information, answer the following questions :
(i) Find the amount of instalment paid in the tenth month. (1)
(ii) In which instalment did she pay ₹ 40,000 ? (1)
(iii) (a) If she returned ₹ 11,50,000 in all, how many instalments did she pay ? (2)
OR (b) By which instalment has she returned a total amount of ₹ 3,25,000 ? (2)

Show answer & solution
Answer: (i) ₹ 55,000 (ii) 7th instalment (iii) (a) 20 instalments OR (b) by the 10th instalment
  1. Instalments form an AP with , .
  2. (i) , i.e. ₹ 55,000.
  3. (ii) : the 7th instalment.
  4. (iii) (a) .
  5. , so instalments.
  6. OR (b) .
  7. , so : by the 10th instalment.
Q374 marksCase StudyCoordinate Geometry

A field is in the form of a rectangle. The coordinates of the rectangular field ABCD are A(10, 10), B(40, 10), C(40, 50) and D(, ). Anil and Anita, two friends decided to have a race. Anita started from point A and moved to point E along the diagonal AC, where E is the point of intersection of both the diagonals of ABCD. From point E, she moved to point B along the other diagonal DB and then moved back to point A along BA. While Anil started from point C and ran to point A via D along the boundary of the field.
Based on the above information, answer the following questions :
(i) Find the coordinates of point E. (1)
(ii) Find the distance between the points B and C. (1)
(iii) (a) Find the coordinates of point D and the distance BD. (2)
OR (b) Find the total distance travelled by Anita. (2)

Diagram for CBSE 2025 Class 10 Maths question 37
Show answer & solution
Answer: (i) E(25, 30) (ii) 40 units (iii) (a) D(10, 50), BD = 50 units OR (b) 80 units
  1. (i) E is the mid-point of AC: .
  2. (ii) BC units.
  3. (iii) (a) ABCD is a rectangle with AB horizontal and BC vertical, so D = (10, 50).
  4. BD units.
  5. OR (b) AC , so AE ; diagonals of a rectangle are equal and bisect each other, so EB ; BA .
  6. Total distance by Anita units.

Kite festival is a popular festival in India which takes place during Makar Sankranti. The festival is celebrated by people flying kites from their rooftops. Reena and Ravi are also flying kites to enjoy the festival. The height of Reena’s kite is 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground, and the inclination of the string with the ground is . Ravi is flying a kite from a 10 m high building. His kite is also flying 60 m above the ground and the length of the string used by Ravi is same as that of Reena’s. is the angle of elevation of Ravi’s kite from a point on the rooftop.
Based on the above information, answer the following questions :
(i) Find the length of string used by Reena. (1)
(ii) Find the value of . (1)
(iii) (a) If changes to , without changing the length of the string, what will be the height of Ravi’s kite above the ground ? (Use ) (2)
OR (b) What would have been the height of Ravi’s kite above the ground, if the string had an inclination of with the ground, assuming that the length of the string does not change ? (2)

Show answer & solution
Answer: (i) 120 m (ii) (iii) (a) 112 m OR (b) 70 m
  1. (i) For Reena: m.
  2. (ii) Ravi’s kite is m above the rooftop and his string is 120 m long, so .
  3. (iii) (a) With : height above rooftop m.
  4. Height above ground m.
  5. OR (b) With inclination : height above rooftop m.
  6. Height above ground m.
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