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CBSE Class 10 Maths Basic 2026 Question Paper 430/5/1 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Basic board paper, Set 430/5/1 (2026), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 430/4/1Set 430/4/2Set 430/4/3Set 430/5/1Set 430/5/2Set 430/5/3
Q11 markMCQReal Numbers

is

  1. (A)a prime number.
  2. (B)an odd number.
  3. (C)a composite number.
  4. (D)a multiple of 5.
Show answer & solution
Answer: (C) a composite number.
  1. , so the number is .
  2. , so it has a factor other than 1 and itself.
  3. It is even (not odd) and does not end in 0 or 5 (not a multiple of 5).
  4. Hence it is a composite number.
Also asked in: 2026 Basic 430/5/2

The roots of the quadratic equation are

  1. (A)real and equal
  2. (B)not real
  3. (C)real and negative of each other
  4. (D)rational numbers
Show answer & solution
Answer: (B) not real
  1. Here , , .
  2. .
  3. So the roots are not real.

The distance between the points and is

  1. (A)
  2. (B)14
  3. (C)
  4. (D)7
Show answer & solution
Answer: (A)
Also asked in: 2026 Basic 430/5/3

A cylinder of radius is surmounted on a hemisphere of same radius. If total height of the object is 13 cm, then its inner surface area is

Diagram for CBSE 2026 Class 10 Maths question 4
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Height of the cylindrical part .
  2. Inner surface area curved surface of cylinder curved surface of hemisphere .
Q51 markMCQTriangles

Which of the following statements is not always true ?

  1. (A)Two circles are similar.
  2. (B)Two isosceles right triangles are similar.
  3. (C)Two rectangles are similar.
  4. (D)Two equilateral triangles are similar.
Show answer & solution
Answer: (C) Two rectangles are similar.
  1. All circles, all isosceles right triangles (angles 45°, 45°, 90°) and all equilateral triangles have the same shape, so they are always similar.
  2. Two rectangles have equal angles, but their sides need not be in the same ratio (e.g. 1 × 2 and 1 × 3).
  3. So 'Two rectangles are similar' is not always true.

If value of is , then equals

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. , so
Also asked in: 2026 Basic 430/5/3
Q71 markMCQCircles

A chord QR subtends an angle of at the centre O of the circle. The measure of is

Diagram for CBSE 2026 Class 10 Maths question 7
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. In , , so .
  2. QP is a tangent at Q, so .
Also asked in: 2026 Basic 430/5/2
Q81 markMCQProbability

The probability of getting sum greater than 10, when two dice are rolled together, is

  1. (A)
  2. (B)
  3. (C)
  4. (D)1
Show answer & solution
Answer: (C)
  1. Total outcomes = 36.
  2. Sum greater than 10: (5, 6), (6, 5), (6, 6), i.e. 3 outcomes.
  3. Probability
Also asked in: 2026 Basic 430/5/2
Q91 markMCQPolynomials

The graph of a polynomial is shown here. The number of zeroes of the polynomial is

Diagram for CBSE 2026 Class 10 Maths question 9
  1. (A)5
  2. (B)1
  3. (C)0
  4. (D)4
Show answer & solution
Answer: (D) 4
  1. The number of zeroes equals the number of points where the graph meets the x-axis.
  2. The graph cuts the x-axis at 4 points, so p(x) has 4 zeroes.

term of the A.P. : is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. ,
Also asked in: 2026 Basic 430/5/2
Q111 markMCQTriangles

In the given figure, DE BC.
If AD : AB = 1 : 3 and AE = 2.5 cm, then AC equals

Diagram for CBSE 2026 Class 10 Maths question 11
  1. (A)7.5 cm
  2. (B)5 cm
  3. (C)10 cm
  4. (D)2.5 cm
Show answer & solution
Answer: (A) 7.5 cm
  1. Since DE BC, (BPT).
  2. , so AC = 7.5 cm.
Q121 markMCQPolynomials

The value of k for which sum of the zeroes of the polynomial is 2, is

  1. (A)2
  2. (B)
  3. (C)
  4. (D)6
Show answer & solution
Answer: (D) 6
  1. Sum of zeroes
  2. , so
Also asked in: 2026 Basic 430/5/3
Q131 markMCQProbability

A bag contains some red and some white balls. A ball is drawn at random from the bag. If the probability of getting a red ball is , then the probability of getting a white ball is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. The ball is either red or white.
  2. P(white)

If are in A.P., then the value of is

  1. (A)14
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. For an A.P., .
Also asked in: 2026 Basic 430/5/3
Q151 markMCQCircles

PQ is tangent to a circle at a point P on the circle. The number of tangents which can be drawn to the circle parallel to PQ, is

  1. (A)2
  2. (B)1
  3. (C)many
  4. (D)zero
Show answer & solution
Answer: (B) 1
  1. Tangents parallel to a given direction touch the circle at the two ends of a diameter.
  2. One of them is PQ itself (at P); the only other one is the tangent at the end of the diameter through P.
  3. So exactly 1 tangent can be drawn parallel to PQ.
Q161 markMCQProbability

A card is drawn from a well-shuffled deck of 52 playing cards. The probability of getting a queen of spade is

  1. (A)
  2. (B)
  3. (C)0
  4. (D)
Show answer & solution
Answer: (B)
  1. There is only one queen of spades in the deck.
  2. Probability

The length of a pendulum is 70 cm and it describes an arc of length 88 cm when swings. The angle subtended by the arc at the centre is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Arc length

The total surface area of a solid cone of radius 7 cm and slant height 25 cm, is

  1. (A)724 cm
  2. (B)704 cm
  3. (C)550 cm
  4. (D)616 cm
Show answer & solution
Answer: (B) 704 cm
  1. TSA
  2. cm
Q191 markAssertion–ReasonIntroduction to Trigonometry

Assertion (A) : For an acute angle , is always less than 1.
Reason (R) : In a right-angled triangle, hypotenuse is the longest side and .

  1. (A)Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both, Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both (A) and (R) are true and (R) is the correct explanation of (A).
  1. In a right-angled triangle the hypotenuse is the longest side, so Base < Hypotenuse. R is true.
  2. Hence for an acute angle , . A is true and follows from R.
Q201 markAssertion–ReasonStatistics

Assertion (A) : Median of a data is the value of , where N represents sum of all frequencies.
Reason (R) : Median divides the whole distribution in two equal parts.

  1. (A)Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both, Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. only tells us the position used to locate the median (median class); the median is the value of the observation there, not itself. A is false.
  2. The median is the middle value, which divides the distribution into two equal parts. R is true.
Q212 marksVery Short AnswerIntroduction to Trigonometry

If and , then find the value of .

Show answer & solution
Answer: (i.e. )
  1. gives ; gives .
Also asked in: 2026 Basic 430/5/3
OR
Q21 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Evaluate :

Show answer & solution
Answer:
  1. , ,
  2. Value
Also asked in: 2026 Basic 430/5/3
Q222 marksVery Short AnswerReal Numbers

Find the H.C.F. and L.C.M. of 1530 and 2040.

Show answer & solution
Answer: H.C.F. = 510, L.C.M. = 6120
  1. H.C.F.
  2. L.C.M.
Q232 marksVery Short AnswerCoordinate Geometry

If A(a, 0), B(1, 1) and C(0, b) form a triangle, right angled at B when joined, then establish a relation between a and b.

Show answer & solution
Answer:
  1. Right angle at B, so .
  2. , ,
  3. , so
Also asked in: 2026 Basic 430/5/2
Q242 marksVery Short AnswerProbability

Find the probability that a number selected at random from the numbers 30, 31, 32, 33, ....., 60 is (i) a prime number (ii) a multiple of 6.

Show answer & solution
Answer: (i) (ii)
  1. Total numbers from 30 to 60 = 31.
  2. (i) Primes: 31, 37, 41, 43, 47, 53, 59, i.e. 7. P = 7/31.
  3. (ii) Multiples of 6: 30, 36, 42, 48, 54, 60, i.e. 6. P = 6/31.
OR
Q24 (OR) (OR)2 marksVery Short AnswerProbability

Slips of letters of the word ‘BACKGROUND’ are put in a bowl and thoroughly mixed. One slip is picked up at random. Find the probability that picked up slip’s letter is (i) a vowel (ii) present in the word ‘BALL’.

Show answer & solution
Answer: (i) (ii)
  1. BACKGROUND has 10 letters: B, A, C, K, G, R, O, U, N, D.
  2. (i) Vowels: A, O, U, i.e. 3. P = 3/10.
  3. (ii) Letters also in 'BALL': B and A, i.e. 2 slips. P = 2/10 = 1/5.
Q252 marksVery Short AnswerTriangles

In the given figure, AB DC. If OB = 3OD and CD = 1.8 cm, then find the length AB.

Diagram for CBSE 2026 Class 10 Maths question 25
Show answer & solution
Answer: AB = 5.4 cm
  1. In and : and (alternate angles, AB DC).
  2. So (AA).
  3. AB cm
Q263 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Suppose is rational. Then , where a, b are co-prime integers and .
  2. Squaring, , so 2 divides and hence 2 divides a.
  3. Let . Then , i.e. , so 2 divides b.
  4. So 2 is a common factor of a and b, contradicting that they are co-prime.
  5. Hence is irrational.
Q273 marksShort AnswerCoordinate Geometry

Points P(6, 0), Q(2, 8) and R(−2, 4) are vertices of . It is given that MN QR such that . Using distance formula and ratio formula, show that .

Diagram for CBSE 2026 Class 10 Maths question 27
Show answer & solution
Answer: Proved: M(5, 2), N(4, 1), MN , QR , so .
  1. M divides PQ in 1 : 3:
  2. Since MN QR, by BPT .
  3. MN ; QR
Also asked in: 2026 Basic 430/5/2
Q283 marksShort AnswerArithmetic Progressions

In an A.P., it is given that a = 2, d = 8 and . Find the value of n.

Show answer & solution
Answer: n = 5
  1. n cannot be negative, so .
OR
Q28 (OR) (OR)3 marksShort AnswerArithmetic Progressions

How many 4-digit numbers are divisible by 7 ?

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Answer: 1286
  1. The smallest 4-digit multiple of 7 is 1001 and the largest is 9996.
  2. 1001, 1008, ..., 9996 is an A.P. with a = 1001, d = 7.
Q293 marksShort AnswerIntroduction to Trigonometry

Prove that .

Show answer & solution
Answer: Proved.
  1. LHS
  2. = RHS
Q303 marksShort AnswerPolynomials

If are zeroes of the polynomial , then form a quadratic polynomial whose zeroes are and .

Show answer & solution
Answer: (or any non-zero multiple of it)
  1. ,
  2. Sum
  3. Product
  4. Polynomial: ; taking ,
Also asked in: 2026 Basic 430/5/3
OR
Q30 (OR) (OR)3 marksShort AnswerPolynomials

Find the zeroes of the polynomial and verify the relationship between its zeroes and the coefficients.

Show answer & solution
Answer: Zeroes: and ; relationship verified.
  1. Zeroes: and
  2. Sum
  3. Product . Verified.
Also asked in: 2026 Basic 430/5/3
Q313 marksShort AnswerAreas Related to Circles

Chord AB of a circle subtends an angle of at the centre O of the circle. Find the length of arc AB, if radius of the circle is 21 cm.

Diagram for CBSE 2026 Class 10 Maths question 31
Show answer & solution
Answer: 44 cm
  1. Arc length
  2. cm
Q325 marksLong AnswerTriangles

In the given figure, is right angled triangle with . AD is perpendicular to BC.
Prove that :
(i)
(ii)
(iii) Find the area of when DB = 9 cm and DC = 16 cm.

Diagram for CBSE 2026 Class 10 Maths question 32
Show answer & solution
Answer: (i) Proved. (ii) Proved. (iii) 150 cm
  1. (i) In and : .
  2. (since ).
  3. So (AA).
  4. (ii) Corresponding sides are proportional: , so .
  5. (iii) , so DA = 12 cm; BC = 9 + 16 = 25 cm.
  6. Area of cm
OR
Q32 (OR) (OR)5 marksLong AnswerTriangles

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then prove that the other two sides are divided in the same ratio.

Show answer & solution
Answer: Proved.
  1. Given: In , DE BC with D on AB and E on AC. To prove: .
  2. Construction: join BE and CD; draw EN ⊥ AB and DM ⊥ AC.
  3. ar(ADE) and ar(BDE) , so .
  4. Similarly, .
  5. Triangles BDE and DEC are on the same base DE and between the same parallels DE and BC, so ar(BDE) = ar(DEC).
  6. Hence .

Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are and respectively. Find the height of the poles and the distance of the point from the poles.

Show answer & solution
Answer: Height m ( m); the point is 20 m from one pole and 60 m from the other.
  1. Let each pole have height h m and let the point be x m from the pole whose top is seen at 60°; it is (80 − x) m from the other pole.
  2. m; distances are 20 m and 60 m.
Q345 marksLong AnswerQuadratic Equations

ABCD is a rectangle of dimensions 80 cm 60 cm. Another rectangle PQRS is drawn inside ABCD leaving space of equal width cm along the edges of ABCD. If area PQRS is half of the area ABCD, then find the value of .

Show answer & solution
Answer:
  1. Dimensions of PQRS: cm and cm.
  2. , so or
  3. makes negative, so .
OR
Q34 (OR) (OR)5 marksLong AnswerQuadratic Equations

A train covers a distance of 90 km at a uniform speed. Had the speed been 15 km/h more, it would have taken 30 minutes less for the same journey. Find the original speed of the train.

Show answer & solution
Answer: 45 km/h
  1. Let the original speed be x km/h.
  2. Speed cannot be negative, so x = 45 km/h.
Q355 marksLong AnswerStatistics

Find mean and mode of the following data :

Class10-2020-3030-4040-5050-6060-7070-80
Frequency54101312106
Show answer & solution
Answer: Mean ; Mode = 47.5
  1. Class marks: 15, 25, 35, 45, 55, 65, 75; N = 60.
  2. Take a = 45, h = 10, : −3, −2, −1, 0, 1, 2, 3.
  3. : −15, −8, −10, 0, 12, 20, 18;
  4. Mean (approx.)
  5. Modal class 40-50: , , , ,
  6. Mode

Seema daily goes to a park to exercise on machines available there. When Seema spent 15 minutes on exercise bicycle and 30 minutes on double cross walker, she received a message of burning 435 calories on her fitness watch. When she spent 30 minutes on exercise bicycle and 40 minutes on double cross walker, she received a message of burning 690 calories.
To find the number of calories burned per minute on each machine, answer the following :
(i) Represent the above situation in terms of a pair of linear equations in two variables.
(ii) Show that the equations have unique solution.
(iii) (a) Solve both equations to find the values of the variables using elimination method.
OR (b) Solve both equations to find the values of the variables using substitution method.

Show answer & solution
Answer: (i) and , i.e. and , where x and y are calories burned per minute on the exercise bicycle and the double cross walker (ii) , so a unique solution (iii) , (by either method)
  1. (i) Let x and y be the calories burned per minute on the exercise bicycle and the double cross walker.
  2. ;
  3. (ii) For and : , ; these are unequal, so the pair has a unique solution.
  4. (iii)(a) Elimination: multiply by 2: . Subtract from : . Then , .
  5. (iii)(b) Substitution: ; , .
  6. So 11 calories per minute on the exercise bicycle and 9 calories per minute on the double cross walker.
Q374 marksCase StudySurface Areas and Volumes

There are many varieties of mushrooms available in the world. One such mushroom ‘Amanita muscaria’ has a upper part which is like red cap (hemispherical) and lower part is like white stem (cylinderical).
The hemispherical cap’s radius = 3 cm and cylindrical stem is 2 cm high with diameter 1.4 cm. Considering mushroom a solid object, answer the following questions :
(i) What is the total height of a mushroom ?
(ii) Find the volume of the stem.
(iii) (a) Determine the volume of 7 such mushrooms.
OR (b) Find the total surface area of 7 such mushrooms.

Diagram for CBSE 2026 Class 10 Maths question 37
Show answer & solution
Answer: (i) 5 cm (ii) 3.08 cm (iii) (a) 417.56 cm OR (b) 655.6 cm
  1. (i) Total height = radius of cap + height of stem = 3 + 2 = 5 cm.
  2. (ii) Stem radius = 0.7 cm. Volume cm
  3. (iii)(a) Volume of cap cm
  4. Volume of 7 mushrooms cm
  5. (iii)(b) Surface of one mushroom = curved surface of cap + flat underside of cap not covered by stem + curved surface of stem + base of stem
  6. cm
  7. For 7 mushrooms: cm
Q384 marksCase StudyCircles

In a circular museum hall of radius 14 m, some statues are displayed. Statues are kept inside the inner concentric circle of radius 7 m. One such statue lying in sector OAB, is fenced along line segments OA, AP, PB and BO where P is a point on outer circle.
Based on above information, answer the following questions :
(i) Find . (1)
(ii) Prove that . (1)
(iii) (a) Find the length of fencing required to protect the statue. (Take = 1.73) (2)
OR (b) Find area of quadrilateral OAPB. (Take = 1.73)

Diagram for CBSE 2026 Class 10 Maths question 38
Show answer & solution
Answer: (i) (ii) Proved (iii) (a) 38.22 m OR (b) 84.77 m
  1. (i) PA is a tangent to the inner circle, so . OA = 7 m, OP = 14 m.
  2. , so .
  3. (ii) In and : OA = OB (radii), PA = PB (tangents from an external point), OP is common. So (SSS).
  4. (iii)(a) m = PB
  5. Fencing m
  6. (iii)(b) Area of OAPB m
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