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CBSE Class 10 Maths Standard 2023 Question Paper 30/6/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/6/3 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3Set 30/6/1Set 30/6/2Set 30/6/3

The distance between the points (0, 5) and (–3, 1) is :

  1. (A)8 units
  2. (B)5 units
  3. (C)3 units
  4. (D)25 units
Show answer & solution
Answer: (B) 5 units
  1. Distance units

If , then is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Take opposite side = x and adjacent side = y; hypotenuse .
Q31 markMCQPolynomials

The zeroes of the polynomial are :

  1. (A), – 4
  2. (B), 4
  3. (C), 4
  4. (D), – 4
Show answer & solution
Answer: (A) , – 4
  1. Zeroes: and .

The circumferences of two circles are in the ratio 4 : 5. What is the ratio of their radii ?

  1. (A)16 : 25
  2. (B)25 : 16
  3. (C)
  4. (D)4 : 5
Show answer & solution
Answer: (D) 4 : 5
  1. So .

If the sum of the first n terms of an A.P be and its common difference is 6, then its first term is

  1. (A)2
  2. (B)3
  3. (C)1
  4. (D)4
Show answer & solution
Answer: (D) 4
  1. First term .
  2. (Check: , so d = 6.)
Q61 markMCQPolynomials

If the zeroes of the quadratic polynomial are 2 and –3, then

  1. (A)a = –7, b = –1
  2. (B)a = 5, b = –1
  3. (C)a = 2, b = – 6
  4. (D)a = 0, b = – 6
Show answer & solution
Answer: (D) a = 0, b = – 6
  1. Sum of zeroes: , so .
  2. Product of zeroes: .
Q71 markMCQReal Numbers

If , then p is a/an

  1. (A)whole number
  2. (B)integer
  3. (C)rational number
  4. (D)irrational number
Show answer & solution
Answer: (C) rational number
  1. .
  2. , which is a rational number (not an integer).
Also asked in: 2023 Standard 30/6/1

If is an acute angle of a right angled triangle, then which of the following equation is not true ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. is true.
  2. is true.
  3. is an identity.
  4. , so , not 1. (D) is not true.
Also asked in: 2023 Standard 30/6/1

The point of intersection of the line represented by and the y-axis is given by

  1. (A)(0, –3)
  2. (B)(0, 3)
  3. (C)(2, 0)
  4. (D)(–2, 0)
Show answer & solution
Answer: (A) (0, –3)
  1. On the y-axis, .
  2. gives .
  3. The point is (0, –3).
Q101 markMCQCircles

In the given figure, PA and PB are tangents from external point P to a circle with centre C and Q is any point on the circle. Then the measure of is

Diagram for CBSE 2023 Class 10 Maths question 10
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. CA PA and CB PB, so in quadrilateral PACB, .
  2. The angle subtended by arc AB at a point Q on the remaining part of the circle is half the angle at the centre.
Q111 markMCQPolynomials

If and are the zeroes of the polynomial , then the value of is

  1. (A)2
  2. (B)1
  3. (C)–1
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. For , sum of zeroes .
  2. Here , , so .
  3. (The zeroes are 1 and –1.)
Also asked in: 2023 Standard 30/6/1
Q121 markMCQTriangles

If ; PQ = 6 cm, AB = 8 cm and the perimeter of is 36 cm, then the perimeter of is

  1. (A)20.25 cm
  2. (B)27 cm
  3. (C)48 cm
  4. (D)64 cm
Show answer & solution
Answer: (B) 27 cm
  1. Perimeters of similar triangles are in the ratio of corresponding sides.
  2. Perimeter of cm
Q131 markMCQTriangles

In the given figure, DEBC. If AD = 3 cm, AB = 7 cm and EC = 3 cm, then the length of AE is

Diagram for CBSE 2023 Class 10 Maths question 13
  1. (A)2 cm
  2. (B)2.25 cm
  3. (C)3.5 cm
  4. (D)4 cm
Show answer & solution
Answer: (B) 2.25 cm
  1. DB = AB – AD = 7 – 3 = 4 cm.
  2. By BPT, .
  3. , so AE = = 2.25 cm.

The volume of a right circular cone whose area of the base is 156 cm and the vertical height is 8 cm, is

  1. (A)2496 cm
  2. (B)1248 cm
  3. (C)1664 cm
  4. (D)416 cm
Show answer & solution
Answer: (D) 416 cm
  1. Volume = base area height
  2. cm
Q151 markMCQProbability

A card is drawn at random from a well shuffled deck of 52 playing cards. The probability of getting a face card is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. There are 12 face cards (J, Q, K of 4 suits).
  2. P =

If 'p' is a root of the quadratic equation , then the value of 'k' is

  1. (A)p
  2. (B)q
  3. (C)p + q
  4. (D)pq
Show answer & solution
Answer: (D) pq
  1. Put x = p: .
  2. , so k = pq.
Q171 markMCQProbability

Cards bearing numbers 3 to 20 are placed in a bag and mixed thoroughly. A card is taken out of the bag at random. What is the probability that the number on the card taken out is an even number ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Numbers 3 to 20: 18 cards.
  2. Even numbers: 4, 6, ..., 20, i.e. 9 cards.
  3. P =

The condition for the system of linear equations ; to have a unique solution is

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Unique solution when .
  2. This gives .
Q191 markAssertion–ReasonIntroduction to Trigonometry

Statement A (Assertion) : For , and are reciprocal of each other.
Statement R (Reason) :

  1. (A)Both Assertion (A) and Reason (R) are true; and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true; but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true but Reason (R) is false.
  4. (D)Assertion (A) is false but Reason (R) is true.
Show answer & solution
Answer: (A) Both A and R are true and R is the correct explanation of A.
  1. R is a standard identity, so R is true.
  2. .
  3. So the two expressions are reciprocals: A is true, and R explains A.
Q201 markAssertion–ReasonQuadratic Equations

Statement A (Assertion) : If is a root of a quadratic equation with rational co-efficients, then its other root is .
Statement R (Reason) : Surd roots of a quadratic equation with rational co-efficients occur in conjugate pairs.

  1. (A)Both Assertion (A) and Reason (R) are true; and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true; but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true but Reason (R) is false.
  4. (D)Assertion (A) is false but Reason (R) is true.
Show answer & solution
Answer: (A) Both A and R are true and R is the correct explanation of A.
  1. By the quadratic formula, roots with rational coefficients are , so irrational (surd) roots occur in conjugate pairs. R is true.
  2. Hence if is a root, is the other root. A is true and follows from R.
Q212 marksVery Short AnswerCoordinate Geometry

Find the ratio in which the y-axis divides the line segment joining the points (5, – 6) and (–1, – 4).

Show answer & solution
Answer: 5 : 1
  1. Let the y-axis divide the segment in the ratio k : 1 at (0, y).
  2. x-coordinate:
  3. , so k = 5.
  4. Ratio = 5 : 1
Q222 marksVery Short AnswerTriangles

In the given figure, ABC is a triangle in which DEBC. If AD = , DB = , AE = and EC = , then find the value of .

Diagram for CBSE 2023 Class 10 Maths question 22
Show answer & solution
Answer: x = 4
  1. By BPT, .
OR
Q22 (OR) (OR)2 marksVery Short AnswerTriangles

Diagonals AC and BD of trapezium ABCD with ABDC intersect each other at point O. Show that .

Diagram for CBSE 2023 Class 10 Maths question 22 (OR)
Show answer & solution
Answer: Proved.
  1. In and :
  2. (alternate angles, AB DC, AC transversal)
  3. (alternate angles, BD transversal)
  4. So (AA similarity).
  5. Hence (corresponding sides of similar triangles are proportional).
Q232 marksVery Short AnswerReal Numbers

Show that can not end with digit 0 for any natural number 'n'.

Show answer & solution
Answer: Proved.
  1. A number ending in 0 is divisible by 10, so its prime factorisation must contain both 2 and 5.
  2. .
  3. By the Fundamental Theorem of Arithmetic this factorisation is unique, and it has no factor 5.
  4. So cannot end with the digit 0 for any natural number n.
OR
Q23 (OR) (OR)2 marksVery Short AnswerReal Numbers

Find the LCM and HCF of 72 and 120

Show answer & solution
Answer: LCM = 360, HCF = 24
  1. LCM =
  2. HCF =
Also asked in: 2023 Standard 30/6/2
Q242 marksVery Short AnswerSome Applications of Trigonometry

Find the length of the shadow on the ground of a pole of height 18 m when angle of elevation of the sun is such that .

Show answer & solution
Answer: 21 m
  1. Let the shadow be s m. Then .
  2. m
Q252 marksVery Short AnswerCircles

In the given figure, PA is a tangent to the circle drawn from the external point P and PBC is the secant to the circle with BC as diameter. If , then find the measure of , where O is the centre of the circle.

Diagram for CBSE 2023 Class 10 Maths question 25
Show answer & solution
Answer:
  1. (linear pair).
  2. OA PA (radius is perpendicular to tangent), so .
  3. In :
Q263 marksShort AnswerIntroduction to Trigonometry

Prove that .

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Answer: Proved.
  1. LHS
  2. = RHS
Q273 marksShort AnswerQuadratic Equations

A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.

Show answer & solution
Answer: 8
  1. Let the number be x. Then .
  2. x = 8 (x = –20 is not a natural number).
OR
Q27 (OR) (OR)3 marksShort AnswerQuadratic Equations

If one root of the quadratic equation is thrice the other root, then find the value of k.

Show answer & solution
Answer: k = –27
  1. Let the roots be and .
  2. Sum: , so ; roots are –3 and –9.
  3. Product: , so .
  4. k = –27
Q283 marksShort AnswerCoordinate Geometry

Find the ratio in which the line segment joining the points A(6, 3) and B(–2, –5) is divided by -axis.

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Answer: 3 : 5
  1. Let the x-axis divide AB in the ratio k : 1 at P(x, 0).
  2. y-coordinate of P:
  3. , so .
  4. Ratio = 3 : 5 (the point is (3, 0)).
Q293 marksShort AnswerAreas Related to Circles

In a circle of radius 21 cm, an arc subtends an angle of at the centre. Find the area of the sector formed by the arc. Also, find the length of the arc.

Show answer & solution
Answer: Area of sector = 231 cm; length of arc = 22 cm
  1. Area of sector cm
  2. Length of arc cm
Also asked in: 2023 Standard 30/6/1
Q303 marksShort AnswerTriangles

In the given figure, E is a point on the side CB produced of an isosceles triangle ABC with AB = AC. If AD BC and EF AC, then prove that .

Diagram for CBSE 2023 Class 10 Maths question 30
Show answer & solution
Answer: Proved.
  1. AB = AC, so (angles opposite equal sides).
  2. In and :
  3. So (AA similarity).
Q313 marksShort AnswerReal Numbers

Find the HCF and LCM of 26, 65 and 117, using prime factorisation.

Show answer & solution
Answer: HCF = 13, LCM = 1170
  1. HCF = 13
  2. LCM =
OR
Q31 (OR) (OR)3 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Assume is rational, so where a, b are co-prime integers and .
  2. Squaring: , so 2 divides , hence 2 divides a.
  3. Let a = 2c. Then , so ; 2 divides , hence 2 divides b.
  4. So 2 is a common factor of a and b, contradicting that they are co-prime.
  5. Hence is irrational.
Q325 marksLong AnswerArithmetic Progressions

The sum of first seven terms of an A.P. is 182. If its 4 term and the 17 term are in the ratio 1 : 5, find the A.P.

Show answer & solution
Answer: 2, 10, 18, 26, ...
  1. , so .
  2. , so .
  3. Subtracting: , d = 8; then a = 26 – 24 = 2.
  4. The A.P. is 2, 10, 18, 26, ...
OR
Q32 (OR) (OR)5 marksLong AnswerArithmetic Progressions

The sum of first q terms of an A.P. is . If its p term is –60, find the value of p. Also, find the 11 term of this A.P.

Show answer & solution
Answer: p = 21; 11th term = 0
  1. ; , so and d = –6.
  2. , so p = 21.
Q335 marksLong AnswerCircles

Prove that a parallelogram circumscribing a circle is a rhombus.

Show answer & solution
Answer: Proved.
  1. Let parallelogram ABCD touch the circle at P, Q, R, S on AB, BC, CD, DA respectively.
  2. Tangents from an external point are equal: AP = AS, BP = BQ, CR = CQ, DR = DS.
  3. Adding: (AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ), i.e. AB + CD = AD + BC.
  4. In a parallelogram AB = CD and AD = BC, so 2AB = 2BC, i.e. AB = BC.
  5. So all sides are equal and ABCD is a rhombus.
OR
Q33 (OR) (OR)5 marksLong AnswerCircles

In the given figure, tangents PQ and PR are drawn to a circle such that . A chord RS is drawn parallel to the tangent PQ. Find the measure of .

Diagram for CBSE 2023 Class 10 Maths question 33 (OR)
Show answer & solution
Answer:
  1. PQ = PR (tangents from P), so .
  2. RS PQ, so (alternate angles).
  3. OQ PQ and RS PQ, so OQ RS; the perpendicular from the centre bisects the chord RS, so Q is equidistant from R and S, i.e. QR = QS.
  4. Hence .
Q345 marksLong AnswerStatistics

250 apples of a box were weighed and the distribution of masses of the apples is given in the following table :
Mass (in grams): 80 – 100, 100 – 120, 120 – 140, 140 – 160, 160 – 180
Number of apples: 20, 60, 70, , 60
(i) Find the value of and the mean mass of the apples. (3)
(ii) Find the modal mass of the apples (2)

Show answer & solution
Answer: (i) x = 40, mean mass = 134.8 g (ii) modal mass = 125 g
  1. (i) 20 + 60 + 70 + x + 60 = 250, so x = 40.
  2. Class marks: 90, 110, 130, 150, 170.
  3. Mean g
  4. (ii) Modal class is 120 – 140 (frequency 70); , , , , .
  5. Mode g
Q355 marksLong AnswerSurface Areas and Volumes

A solid is in the shape of a right-circular cone surmounted on a hemisphere, the radius of each of them being 7 cm and the height of the cone is equal to its diameter. Find the volume of the solid.

Show answer & solution
Answer: cm (about 1437.33 cm)
  1. r = 7 cm, height of cone h = 14 cm.
  2. Volume of cone cm
  3. Volume of hemisphere cm
  4. Total volume cm
Also asked in: 2023 Standard 30/6/1

Radio towers are used for transmitting a range of communication services including radio and television. The tower will either act as an antenna itself or support one or more antennas on its structure. On a similar concept, a radio station tower was built in two Sections A and B. Tower is supported by wires from a point O.
Distance between the base of the tower and point O is 36 cm. From point O, the angle of elevation of the top of the Section B is and the angle of elevation of the top of Section A is .
Based on the above information, answer the following questions :
(i) Find the length of the wire from the point O to the top of Section B. (1)
(ii) Find the distance AB. (2)
OR Find the area of .
(iii) Find the height of the Section A from the base of the tower. (1)

Diagram for CBSE 2023 Class 10 Maths question 36
Show answer & solution
Answer: (i) cm (ii) AB = cm; OR: cm (iii) 36 cm
  1. (i) In right , , so cm.
  2. (ii) cm and cm.
  3. AB = PA – PB = cm.
  4. OR: Area of cm.
  5. (iii) PA = = 36 cm.
Q374 marksCase StudyProbability

“Eight Ball” is a game played on a pool table with 15 balls numbered 1 to 15 and a “cue ball” that is solid and white. Of the 15 numbered balls, eight are solid (non-white) coloured and numbered 1 to 8 and seven are striped balls numbered 9 to 15.
The 15 numbered pool balls (no cue ball) are placed in a large bowl and mixed, then one ball is drawn out at random.
Based on the above information, answer the following questions :
(i) What is the probability that the drawn ball bears number 8 ?
(ii) What is the probability that the drawn ball bears an even number ?
OR What is the probability that the drawn ball bears a number, which is a multiple of 3 ?
(iii) What is the probability that the drawn ball is a solid coloured and bears an even number ?

Show answer & solution
Answer: (i) (ii) ; OR: (iii)
  1. Total outcomes = 15.
  2. (i) Only one ball bears 8: P = .
  3. (ii) Even numbers: 2, 4, 6, 8, 10, 12, 14, i.e. 7 balls: P = .
  4. OR: Multiples of 3: 3, 6, 9, 12, 15, i.e. 5 balls: P = .
  5. (iii) Solid coloured balls are 1 to 8; even ones: 2, 4, 6, 8, i.e. 4 balls: P = .

A coaching institute of Mathematics conducts classes in two batches I and II and fees for rich and poor children are different. In batch I, there are 20 poor and 5 rich children, whereas in batch II, there are 5 poor and 25 rich children. The total monthly collection of fees from batch I is ₹ 9000 and from batch II is ₹ 26,000. Assume that each poor child pays ₹ per month and each rich child pays ₹ y per month.
Based on the above information, answer the following questions :
(i) Represent the information given above in terms of and y. (1)
(ii) Find the monthly fee paid by a poor child. (2)
OR Find the difference in the monthly fee paid by a poor child and a rich child.
(iii) If there are 10 poor and 20 rich children in batch II, what is the total monthly collection of fees from batch II ? (1)

Show answer & solution
Answer: (i) , (ii) ₹ 200; OR: ₹ 800 (iii) ₹ 22,000
  1. (i) Batch I: , i.e. . Batch II: , i.e. .
  2. (ii) From , .
  3. , so , x = 200.
  4. Monthly fee of a poor child = ₹ 200 (and y = 1000).
  5. OR: Rich child pays ₹ 1000, so the difference = 1000 – 200 = ₹ 800.
  6. (iii)
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