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CBSE Class 10 Maths Standard 2023 Question Paper 30/5/2 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/5/2 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3Set 30/6/1Set 30/6/2Set 30/6/3

is equal to :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. .
  2. .
Q21 markMCQTriangles

In and , . Which of the following makes the two triangles similar ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. For SAS similarity, the included angles of the proportional sides must be equal.
  2. Angle included between AB and BC is ; angle included between DE and FD is .
  3. So makes the triangles similar.

The term from the end of the A.P. : 20, 13, 6, , ....., is :

  1. (A)57
  2. (B)
  3. (C)64
  4. (D)
Show answer & solution
Answer: (D)
  1. Reverse the A.P.: with first term and d = 7.
  2. term .
Q41 markMCQProbability

Two dice are rolled together. What is the probability of getting a sum greater than 10 ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Total outcomes = 36.
  2. Sum greater than 10: (5, 6), (6, 5), (6, 6), i.e. 3 outcomes.
  3. P .
Q51 markMCQCircles

In the given figure, AB = BC = 10 cm. If AC = 7 cm, then the length of BP is :

Diagram for CBSE 2023 Class 10 Maths question 5
  1. (A)3.5 cm
  2. (B)7 cm
  3. (C)6.5 cm
  4. (D)5 cm
Show answer & solution
Answer: (C) 6.5 cm
  1. Let the tangent lengths be AP = AR = x, CQ = CR, BP = BQ.
  2. BP = BQ and AB = BC give AP = CQ, so AR = CR = = 3.5 cm.
  3. AP = AR = 3.5 cm.
  4. BP = AB – AP = 10 – 3.5 = 6.5 cm.
Q61 markMCQSurface Areas and VolumesNot in current syllabus

Water in a river which is 3 m deep and 40 m wide is flowing at the rate of 2 km/h. How much water will fall into the sea in 2 minutes ?

  1. (A)800 m
  2. (B)4000 m
  3. (C)8000 m
  4. (D)2000 m
Show answer & solution
Answer: (C) 8000 m
  1. Speed = 2 km/h = 2000 m in 60 minutes.
  2. Length of water flowing in 2 minutes m.
  3. Volume m.
Q71 markMCQStatistics

If the mean and the median of a data are 12 and 15 respectively, then its mode is :

  1. (A)13.5
  2. (B)21
  3. (C)6
  4. (D)14
Show answer & solution
Answer: (B) 21
  1. Empirical relation: Mode = 3 Median – 2 Mean.
  2. Mode = 3(15) – 2(12) = 45 – 24 = 21.
Also asked in: 2023 Standard 30/5/1
Q81 markMCQCircles

In the given figure, AB is a tangent to the circle centered at O. If OA = 6 cm and , then the radius of the circle is :

Diagram for CBSE 2023 Class 10 Maths question 8
  1. (A)3 cm
  2. (B) cm
  3. (C)2 cm
  4. (D) cm
Show answer & solution
Answer: (A) 3 cm
  1. OB AB (radius tangent), so is right-angled at B.
  2. , so OB cm.
Q91 markMCQCircles

In the given figure, AC and AB are tangents to a circle centered at O. If , then is equal to :

Diagram for CBSE 2023 Class 10 Maths question 9
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. A, O, D are collinear, so .
  2. (radius tangent), so .
  3. AO bisects , so .
Also asked in: 2023 Standard 30/5/1
Q101 markMCQProbability

Which of the following numbers cannot be the probability of happening of an event ?

  1. (A)0
  2. (B)
  3. (C)0.07
  4. (D)
Show answer & solution
Answer: (B)
  1. Probability lies between 0 and 1.
  2. , so it cannot be a probability.
Q111 markMCQStatistics

If every term of the statistical data consisting of n terms is decreased by 2, then the mean of the data :

  1. (A)decreases by 2
  2. (B)remains unchanged
  3. (C)decreases by 2n
  4. (D)decreases by 1
Show answer & solution
Answer: (A) decreases by 2
  1. New sum = old sum – 2n.
  2. New mean = old mean – 2.
Q121 markMCQTriangles

In the given figure, DE BC. The value of x is :

Diagram for CBSE 2023 Class 10 Maths question 12
  1. (A)6
  2. (B)12.5
  3. (C)8
  4. (D)10
Show answer & solution
Answer: (D) 10
  1. Since DE BC, (AA).
  2. AB = AD + DB = 2 + 3 = 5 cm.
  3. , so .
  4. x = 10.

A quadratic equation whose roots are and is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Sum of roots .
  2. Product of roots .
  3. Equation: , i.e. .
Also asked in: 2023 Standard 30/5/1

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Divide numerator and denominator by :
  2. .
Also asked in: 2023 Standard 30/5/1

If end points of a diameter of a circle are and , then the radius of the circle is :

  1. (A) units
  2. (B) units
  3. (C) units
  4. (D) units
Show answer & solution
Answer: (B) units
  1. Diameter units.
  2. Radius units.
Q161 markMCQPolynomials

The number of polynomials having zeroes and 2 is :

  1. (A)exactly 2
  2. (B)only 1
  3. (C)at most 2
  4. (D)infinite
Show answer & solution
Answer: (D) infinite
  1. Any polynomial with has zeroes and 2.
  2. Higher-degree polynomials with these factors also work.
  3. So there are infinitely many such polynomials.

The pair of equations and represent parallel lines, where a, b are integers, if :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. For parallel lines, .
  2. .
  3. gives (and for integers always holds).
Also asked in: 2023 Standard 30/5/1

The common difference of the A.P. whose term is given by is :

  1. (A)
  2. (B)7
  3. (C)5
  4. (D)
Show answer & solution
Answer: (C) 5
  1. , .
  2. .
Q191 markAssertion–ReasonReal Numbers

Assertion (A) : The number cannot end with the digit 0, where n is a natural number.
Reason (R): Prime factorisation of 5 has only two factors, 1 and 5.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. To end in 0 a number must have both 2 and 5 as prime factors.
  2. has only the prime 5 in its factorisation, so it never ends in 0. A is true.
  3. The prime factorisation of 5 is just 5; 1 is not a prime factor. So R, as stated, is false (and it does not explain A anyway).
Q201 markAssertion–ReasonCoordinate Geometry

Assertion (A) : If the points A(4, 3) and B(x, 5) lie on a circle with centre O(2, 3), then the value of x is 2.
Reason (R) : Centre of a circle is the mid-point of each chord of the circle.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. OA = .
  2. OB = OA: , so , x = 2. A is true.
  3. The centre is the mid-point only of a diameter, not of every chord. R is false.
Q212 marksVery Short AnswerReal Numbers

Using prime factorisation, find HCF and LCM of 96 and 120.

Show answer & solution
Answer: HCF = 24, LCM = 480
  1. .
  2. .
  3. HCF .
  4. LCM .
Also asked in: 2023 Standard 30/5/1
Q222 marksVery Short AnswerCoordinate Geometry

Find the ratio in which line divides the line segment joining the points and .

Show answer & solution
Answer: 9 : 5
  1. Let the line divide the segment in the ratio k : 1.
  2. Point of division .
  3. It lies on : , so , .
  4. Ratio = 9 : 5 (point of division ).
Q232 marksVery Short AnswerIntroduction to Trigonometry

If and , then prove that .

Show answer & solution
Answer: Proved.
  1. .
  2. .
  3. Adding: .
  4. Hence proved.
OR
Q23 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS .
  2. , so LHS (taking A acute).
  3. .
  4. LHS = RHS.
Q242 marksVery Short AnswerCoordinate Geometry

The line segment joining the points and is divided by the point P such that AP : AB = 2 : 5. Find the coordinates of P.

Show answer & solution
Answer: P(4, )
  1. AP : AB = 2 : 5, so AP : PB = 2 : 3.
  2. .
  3. .
  4. P is (4, ).
OR
Q24 (OR) (OR)2 marksVery Short AnswerCoordinate Geometry

Point P(x, y) is equidistant from points A(5, 1) and B(1, 5). Prove that x = y.

Show answer & solution
Answer: Proved.
  1. PA = PB, so .
  2. .
  3. .
  4. , so .
  5. Hence x = y.
Q252 marksVery Short AnswerCircles

In the given figure, PQ is a chord of the circle centered at O. PT is a tangent to the circle at P. If , then find .

Diagram for CBSE 2023 Class 10 Maths question 25
Show answer & solution
Answer:
  1. OP PT, so .
  2. OP = OQ, so and .
  3. Reflex .
  4. R lies on the minor arc PQ, so .
Q263 marksShort AnswerStatistics

Find the mean of the following distribution :
Classes: 0–15, 15–30, 30–45, 45–60, 60–75, 75–90
Frequency: 17, 20, 18, 21, 15, 9

Show answer & solution
Answer: Mean = 41.1
  1. Class marks : 7.5, 22.5, 37.5, 52.5, 67.5, 82.5; .
  2. : 127.5, 450, 675, 1102.5, 1012.5, 742.5; .
  3. Mean .

A 2-digit number is seven times the sum of its digits. The number formed by reversing the digits is 18 less than the given number. Find the given number.

Show answer & solution
Answer: 42
  1. Let the tens digit be x and the units digit be y; the number is 10x + y.
  2. gives , i.e. .
  3. gives .
  4. So , y = 2, x = 4.
  5. The number is 42.
Q283 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. Let , so .
  2. LHS .
  3. , so LHS .
  4. .
  5. So LHS = RHS.
Q293 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Assume is rational: , where a, b are co-prime integers, .
  2. Then , so 3 divides , hence 3 divides a (3 is prime).
  3. Let a = 3c. Then , so , and 3 divides b.
  4. So 3 divides both a and b, contradicting that they are co-prime.
  5. Hence is irrational.
OR
Q29 (OR) (OR)3 marksShort AnswerReal Numbers

The traffic lights at three different road crossings change after every 48 seconds, 72 seconds and 108 seconds respectively. If they change simultaneously at 7 a.m., at what time will they change together next ?

Show answer & solution
Answer: At 7:07:12 a.m.
  1. , , .
  2. LCM seconds = 7 minutes 12 seconds.
  3. They change together next at 7 hours 7 minutes 12 seconds a.m.
Q303 marksShort AnswerArithmetic Progressions

In an A.P., the sum of the first n terms is given by . Find its term.

Show answer & solution
Answer:
  1. .
  2. ; .
  3. .
Q313 marksShort AnswerTriangles

In the given figure, CD is the perpendicular bisector of AB. EF is perpendicular to CD. AE intersects CD at G. Prove that .

Diagram for CBSE 2023 Class 10 Maths question 31
Show answer & solution
Answer: Proved.
  1. EF CD and BD CD, so EF BD and EF AD.
  2. In and : common, , so (AA). Hence ... (1)
  3. In and : (vertically opposite), , so (AA). Hence ... (2)
  4. D is the mid-point of AB, so AD = BD.
  5. From (1) and (2), .
OR
Q31 (OR) (OR)3 marksShort AnswerTriangles

In the given figure, ABCD is a parallelogram. BE bisects CD at M and intersects AC at L. Prove that EL = 2BL.

Diagram for CBSE 2023 Class 10 Maths question 31 (OR)
Show answer & solution
Answer: Proved.
  1. E lies on AD produced. In and : DM = CM (M is the mid-point of CD), (vertically opposite), (alternate angles, ED BC).
  2. So (ASA), giving ED = BC.
  3. BC = AD (opposite sides of parallelogram), so AE = AD + DE = 2BC.
  4. In and : (vertically opposite), (alternate angles, AE BC). So (AA).
  5. .
  6. Hence EL = 2BL.
Q325 marksLong AnswerCircles

A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC are of lengths 10 cm and 8 cm respectively. Find the lengths of the sides AB and AC, if it is given that area cm.

Diagram for CBSE 2023 Class 10 Maths question 32
Show answer & solution
Answer: AB = 14.5 cm, AC = 12.5 cm
  1. Tangents from an external point are equal. Let the tangent length from A be x.
  2. Then AB = x + 10, AC = x + 8, BC = 18 cm.
  3. Area = area OBC + area OCA + area OAB .
  4. , so , x = 4.5.
  5. AB = 14.5 cm, AC = 12.5 cm.
  6. Check: s = 22.5, area cm.
OR
Q32 (OR) (OR)5 marksLong AnswerCircles

Two circles with centres O and O′ of radii 6 cm and 8 cm, respectively intersect at two points P and Q such that OP and O′P are tangents to the two circles. Find the length of the common chord PQ.

Diagram for CBSE 2023 Class 10 Maths question 32 (OR)
Show answer & solution
Answer: PQ = 9.6 cm
  1. O′P is tangent to the circle with centre O at P, so OP O′P; .
  2. cm.
  3. The common chord PQ is perpendicular to OO′ and bisected by it at A.
  4. Area of : , so cm.
  5. PQ = 2PA = 9.6 cm.
Q335 marksLong AnswerAreas Related to Circles

A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope. Find the area of that part of the field in which the horse can graze. Also, find the increase in grazing area if length of rope is increased to 10 m. (Use )

Show answer & solution
Answer: 19.625 m; increase = 58.875 m
  1. The horse grazes a quadrant (angle ) of radius equal to the rope.
  2. With 5 m rope: area m.
  3. With 10 m rope: area m.
  4. Increase = 78.5 – 19.625 = 58.875 m.

The angle of elevation of the top of a vertical tower from a point P on the ground is . From another point Q, 10 m vertically above the first point P, its angle of elevation is . Find :
(a) The height of the tower.
(b) The distance of the point P from the foot of the tower.
(c) The distance of the point P from the top of the tower.

Show answer & solution
Answer: (a) 15 m (b) m ≈ 8.66 m (c) m ≈ 17.32 m
  1. Let the tower AB have height h (B the foot) and PB = x.
  2. From P: , so .
  3. From Q (10 m above P): , so .
  4. gives , so m.
  5. (a) m.
  6. (b) PB m.
  7. (c) PA m.
Q355 marksLong AnswerQuadratic Equations

A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/h more than the first speed. If it takes 3 hours to complete the journey, what was its first average speed ?

Show answer & solution
Answer: 36 km/h
  1. Let the first speed be x km/h.
  2. .
  3. , so .
  4. , i.e. .
  5. ; speed is positive, so x = 36.
  6. First average speed = 36 km/h.
OR
Q35 (OR) (OR)5 marksLong AnswerQuadratic Equations

Two pipes together can fill a tank in hours. The pipe with larger diameter takes 2 hours less than the pipe with smaller diameter to fill the tank separately. Find the time in which each pipe can fill the tank separately.

Show answer & solution
Answer: Smaller pipe: 5 hours; larger pipe: 3 hours
  1. Let the smaller pipe take x hours; the larger takes (x – 2) hours.
  2. .
  3. , so , i.e. .
  4. , so x = 5 or .
  5. makes x – 2 negative, so x = 5.
  6. Smaller pipe 5 hours, larger pipe 3 hours.
Q364 marksCase StudyProbability

A middle school decided to run the following spinner game as a fund-raiser on Christmas Carnival.
Making Purple : Spin each spinner once. Blue and red make purple. So, if one spinner shows Red (R) and another Blue (B), then you ‘win’. One such outcome is written as ‘RB’.
Based on the above, answer the following questions :
(i) List all possible outcomes of the game. (1)
(ii) Find the probability of ‘Making Purple’. (1)
(iii) For each win, a participant gets ₹ 10, but if he/she loses, he/she has to pay ₹ 5 to the school. If 99 participants played, calculate how much fund could the school have collected. (2)
OR (iii) If the same amount of ₹ 5 has been decided for winning or losing the game, then how much fund had been collected by school ? (Number of participants = 99) (2)

Diagram for CBSE 2023 Class 10 Maths question 36
Show answer & solution
Answer: (i) RR, RB, RG, GR, GB, GG, YR, YB, YG (ii) (iii) ₹ 330; OR: ₹ 385
  1. Spinner I: R, G, Y (equal parts). Spinner II: R, B, G (equal parts).
  2. (i) Outcomes: RR, RB, RG, GR, GB, GG, YR, YB, YG (9 equally likely).
  3. (ii) Only RB makes purple, so P(purple) .
  4. (iii) Out of 99 participants, expected winners , losers = 88.
  5. Fund = 88 × 5 – 11 × 10 = 440 – 110 = ₹ 330.
  6. OR: Fund = 88 × 5 – 11 × 5 = 440 – 55 = ₹ 385.
Q374 marksCase StudySurface Areas and Volumes

A golf ball is spherical with about 300 – 500 dimples that help increase its velocity while in play. Golf balls are traditionally white but available in colours also. In the given figure, a golf ball has diameter 4.2 cm and the surface has 315 dimples (hemi-spherical) of radius 2 mm.
Based on the above, answer the following questions :
(i) Find the surface area of one such dimple. (1)
(ii) Find the volume of the material dug out to make one dimple. (1)
(iii) Find the total surface area exposed to the surroundings. (2)
OR (iii) Find the volume of the golf ball. (2)

Diagram for CBSE 2023 Class 10 Maths question 37
Show answer & solution
Answer: (i) 0.2514 cm (≈ 25.14 mm) (ii) 0.01676 cm (≈ 16.76 mm) (iii) 95.04 cm; OR: 33.528 cm
  1. Dimple radius r = 2 mm = 0.2 cm; ball radius R = 2.1 cm.
  2. (i) Curved surface of a hemispherical dimple cm (approx.).
  3. (ii) Volume dug out cm (approx.).
  4. (iii) Surface of sphere cm.
  5. Each dimple removes a circle and adds , a net gain of .
  6. Total exposed area cm.
  7. OR: Volume of sphere cm.
  8. Volume removed by dimples cm.
  9. Volume of golf ball = 38.808 – 5.28 = 33.528 cm.
Q384 marksCase StudyPolynomials

In a pool at an aquarium, a dolphin jumps out of the water travelling at 20 cm per second. Its height above water level after t seconds is given by .
Based on the above, answer the following questions :
(i) Find zeroes of polynomial . (1)
(ii) Which of the following types of graph represents p(t) ? (1)
(iii) What would be the value of h at ? Interpret the result. (2)
OR (iii) How much distance has the dolphin covered before hitting the water level again ? (2)

Diagram for CBSE 2023 Class 10 Maths question 38
Show answer & solution
Answer: (i) 0 and (ii) Graph (a) (iii) h = cm: the dolphin is 6 cm below the water level at s; OR: 25 cm
  1. (i) gives t = 0 or .
  2. (ii) The leading coefficient is negative, so the graph is a downward parabola cutting the time axis at 0 and : graph (a).
  3. (iii) cm.
  4. Negative height means the dolphin has re-entered the water (at s) and is 6 cm below the water level.
  5. OR: The dolphin is out of the water from t = 0 to s.
  6. Distance covered at 20 cm per second cm.
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