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CBSE Class 10 Maths Standard 2023 Question Paper 30/5/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/5/3 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3Set 30/6/1Set 30/6/2Set 30/6/3

The distance between the points and is :

  1. (A)6 units
  2. (B)4 units
  3. (C)2 units
  4. (D)3 units
Show answer & solution
Answer: (D) 3 units
  1. Both points have y-coordinate 5, so PQ units.
Also asked in: 2023 Standard 30/5/1
Q21 markMCQCircles

In the given figure, AB = BC = 10 cm. If AC = 7 cm, then the length of BP is :

Diagram for CBSE 2023 Class 10 Maths question 2
  1. (A)3.5 cm
  2. (B)7 cm
  3. (C)6.5 cm
  4. (D)5 cm
Show answer & solution
Answer: (C) 6.5 cm
  1. Let the tangent lengths be AP = AR = x, CQ = CR, BP = BQ.
  2. BP = BQ and AB = BC give AP = CQ, so AR = CR = = 3.5 cm.
  3. AP = AR = 3.5 cm.
  4. BP = AB – AP = 10 – 3.5 = 6.5 cm.
Q31 markMCQSurface Areas and VolumesNot in current syllabus

Water in a river which is 3 m deep and 40 m wide is flowing at the rate of 2 km/h. How much water will fall into the sea in 2 minutes ?

  1. (A)800 m
  2. (B)4000 m
  3. (C)8000 m
  4. (D)2000 m
Show answer & solution
Answer: (C) 8000 m
  1. Speed = 2 km/h = 2000 m in 60 minutes.
  2. Length of water flowing in 2 minutes m.
  3. Volume m.
Q41 markMCQStatistics

If the mean and the mode of a distribution are 15 and 18 respectively, then the median of the distribution is :

  1. (A)17
  2. (B)15
  3. (C)16
  4. (D)18
Show answer & solution
Answer: (C) 16
  1. Empirical relation: 3 Median = Mode + 2 Mean.
  2. 3 Median = 18 + 2(15) = 48, so Median = 16.

The term from the end of the A.P. : 10, 7, 4, ......., is :

  1. (A)25
  2. (B)16
  3. (C)
  4. (D)0
Show answer & solution
Answer: (C)
  1. Reverse the A.P.: with first term and d = 3.
  2. term .
Also asked in: 2023 Standard 30/5/1
Q61 markMCQProbability

One card is drawn at random from a well shuffled pack of 52 playing cards. The probability that the drawn card is a queen, is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. A pack has 4 queens out of 52 cards.
  2. P(queen) .
Q71 markMCQCircles

PQ is tangent to a circle centered at O. If the radius of the circle is 5 cm, then the length of the tangent PQ is :

Diagram for CBSE 2023 Class 10 Maths question 7
  1. (A) cm
  2. (B) cm
  3. (C)10 cm
  4. (D) cm
Show answer & solution
Answer: (A) cm
  1. OQ PQ (radius tangent), so is right-angled at Q, with (from the figure).
  2. , so cm.
Q81 markMCQProbability

Which of the following numbers cannot be the probability of happening of an event ?

  1. (A)0
  2. (B)
  3. (C)0.07
  4. (D)
Show answer & solution
Answer: (B)
  1. Probability lies between 0 and 1.
  2. , so it cannot be a probability.

If , then the value of is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)3
Show answer & solution
Answer: (D) 3
  1. .
  2. So .

A quadratic equation whose roots are and is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Sum of roots .
  2. Product of roots .
  3. Equation: .
Q111 markMCQStatistics

If every term of the statistical data consisting of n terms is decreased by 2, then the mean of the data :

  1. (A)decreases by 2
  2. (B)remains unchanged
  3. (C)decreases by 2n
  4. (D)decreases by 1
Show answer & solution
Answer: (A) decreases by 2
  1. New sum = old sum – 2n.
  2. New mean = old mean – 2.
Q121 markMCQPolynomials

The number of polynomials having zeroes and 5 is :

  1. (A)only one
  2. (B)infinite
  3. (C)exactly two
  4. (D)at most two
Show answer & solution
Answer: (B) infinite
  1. Any polynomial with has zeroes and 5.
  2. Higher-degree polynomials such as also have these zeroes.
  3. Since k can be any non-zero real number, there are infinitely many such polynomials.
Also asked in: 2023 Standard 30/5/1

The solution of the pair of equations and is :

  1. (A)x = b, y = a
  2. (B)x = , y = b
  3. (C)x = a, y = b
  4. (D)x = a, y =
Show answer & solution
Answer: (C) x = a, y = b
  1. Multiply the first equation by b: .
  2. Add to the second: , so x = a (taking ).
  3. Then y = (a + b) – a = b.
  4. Check: .

The common difference of the A.P. whose term is given by , is :

  1. (A)7
  2. (B)3
  3. (C)3n
  4. (D)1
Show answer & solution
Answer: (B) 3
  1. , .
  2. .
Also asked in: 2023 Standard 30/5/1
Q151 markMCQTriangles

In the given figure, DE BC. The value of x is :

Diagram for CBSE 2023 Class 10 Maths question 15
  1. (A)6
  2. (B)12.5
  3. (C)8
  4. (D)10
Show answer & solution
Answer: (D) 10
  1. Since DE BC, (AA).
  2. AB = AD + DB = 2 + 3 = 5 cm.
  3. , so .
  4. x = 10.
Q161 markMCQTriangles

In and , . Which of the following makes the two triangles similar ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. For SAS similarity, the included angles of the proportional sides must be equal.
  2. Angle included between AB and BC is ; angle included between DE and FD is .
  3. So makes the triangles similar.

is equal to :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. , so .
  2. .
Also asked in: 2023 Standard 30/5/1
Q181 markMCQCircles

In the given figure, AB is a tangent to the circle centered at O. If OA = 6 cm and , then the radius of the circle is :

Diagram for CBSE 2023 Class 10 Maths question 18
  1. (A)3 cm
  2. (B) cm
  3. (C)2 cm
  4. (D) cm
Show answer & solution
Answer: (A) 3 cm
  1. OB AB (radius tangent), so is right-angled at B.
  2. , so OB cm.
Q191 markAssertion–ReasonReal Numbers

Assertion (A) : The number cannot end with the digit 0, where n is a natural number.
Reason (R): Prime factorisation of 5 has only two factors, 1 and 5.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. To end in 0 a number must have both 2 and 5 as prime factors.
  2. has only the prime 5 in its factorisation, so it never ends in 0. A is true.
  3. The prime factorisation of 5 is just 5; 1 is not a prime factor. So R, as stated, is false (and it does not explain A anyway).
Q201 markAssertion–ReasonCoordinate Geometry

Assertion (A) : If the points A(4, 3) and B(x, 5) lie on a circle with centre O(2, 3), then the value of x is 2.
Reason (R) : Centre of a circle is the mid-point of each chord of the circle.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (C) Assertion (A) is true, but Reason (R) is false.
  1. OA = .
  2. OB = OA: , so , x = 2. A is true.
  3. The centre is the mid-point only of a diameter, not of every chord. R is false.
Q212 marksVery Short AnswerReal Numbers

Find the greatest 3-digit number which is divisible by 18, 24 and 36.

Show answer & solution
Answer: 936
  1. , , .
  2. LCM ; a number divisible by all three is a multiple of 72.
  3. .
  4. Greatest 3-digit multiple of 72 .
Q222 marksVery Short AnswerIntroduction to Trigonometry

If and , then prove that .

Show answer & solution
Answer: Proved.
  1. .
  2. .
  3. Adding: .
  4. Hence proved.
OR
Q22 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS .
  2. , so LHS (taking A acute).
  3. .
  4. LHS = RHS.
Q232 marksVery Short AnswerCoordinate Geometry

Find the ratio in which y-axis divides the line segment joining the points and .

Show answer & solution
Answer: 5 : 1 (point of division )
  1. Let the y-axis divide the segment in the ratio k : 1. The point has x-coordinate 0.
  2. , so k = 5.
  3. Ratio = 5 : 1.
  4. y-coordinate .
Also asked in: 2023 Standard 30/5/1
Q242 marksVery Short AnswerCircles

Prove that the tangents drawn at the ends of a diameter of a circle are parallel.

Show answer & solution
Answer: Proved.
  1. Let AB be a diameter of a circle with centre O, and let PQ and RS be the tangents at A and B.
  2. The tangent at any point is perpendicular to the radius through that point, so OA PQ and OB RS.
  3. So and (P and S on opposite sides of AB).
  4. These are alternate angles made by the transversal AB with PQ and RS, and they are equal.
  5. Hence PQ RS.
Q252 marksVery Short AnswerCoordinate Geometry

The line segment joining the points and is divided by the point P such that AP : AB = 2 : 5. Find the coordinates of P.

Show answer & solution
Answer: P(4, )
  1. AP : AB = 2 : 5, so AP : PB = 2 : 3.
  2. .
  3. .
  4. P is (4, ).
OR
Q25 (OR) (OR)2 marksVery Short AnswerCoordinate Geometry

Point P(x, y) is equidistant from points A(5, 1) and B(1, 5). Prove that x = y.

Show answer & solution
Answer: Proved.
  1. PA = PB, so .
  2. .
  3. .
  4. , so .
  5. Hence x = y.
Q263 marksShort AnswerTriangles

In the given figure, CD is the perpendicular bisector of AB. EF is perpendicular to CD. AE intersects CD at G. Prove that .

Diagram for CBSE 2023 Class 10 Maths question 26
Show answer & solution
Answer: Proved.
  1. EF CD and BD CD, so EF BD and EF AD.
  2. In and : common, , so (AA). Hence ... (1)
  3. In and : (vertically opposite), , so (AA). Hence ... (2)
  4. D is the mid-point of AB, so AD = BD.
  5. From (1) and (2), .
OR
Q26 (OR) (OR)3 marksShort AnswerTriangles

In the given figure, ABCD is a parallelogram. BE bisects CD at M and intersects AC at L. Prove that EL = 2BL.

Diagram for CBSE 2023 Class 10 Maths question 26 (OR)
Show answer & solution
Answer: Proved.
  1. E lies on AD produced. In and : DM = CM (M is the mid-point of CD), (vertically opposite), (alternate angles, ED BC).
  2. So (ASA), giving ED = BC.
  3. BC = AD (opposite sides of parallelogram), so AE = AD + DE = 2BC.
  4. In and : (vertically opposite), (alternate angles, AE BC). So (AA).
  5. .
  6. Hence EL = 2BL.

A fraction becomes when 1 is subtracted from the numerator. It becomes when 8 is added to the denominator. Find the fraction.

Show answer & solution
Answer:
  1. Let the fraction be .
  2. gives ... (1)
  3. gives ... (2)
  4. (2) – (1): x = 5; then y = 3(5) – 3 = 12.
  5. The fraction is .
Q283 marksShort AnswerIntroduction to Trigonometry

Prove that :

Show answer & solution
Answer: Proved.
  1. LHS .
  2. , so LHS .
  3. .
  4. LHS = RHS.
Q293 marksShort AnswerStatistics

Find the mean of the following frequency distribution :
Classes: 25–30, 30–35, 35–40, 40–45, 45–50, 50–55, 55–60
Frequency: 14, 22, 16, 6, 5, 3, 4

Show answer & solution
Answer: Mean ≈ 36.86
  1. Class marks : 27.5, 32.5, 37.5, 42.5, 47.5, 52.5, 57.5; .
  2. Take a = 42.5, h = 5, : .
  3. : ; .
  4. Mean (approx.).
Also asked in: 2023 Standard 30/5/1
Q303 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Assume is rational: , where a, b are co-prime integers, .
  2. Then , so 3 divides , hence 3 divides a (3 is prime).
  3. Let a = 3c. Then , so , and 3 divides b.
  4. So 3 divides both a and b, contradicting that they are co-prime.
  5. Hence is irrational.
OR
Q30 (OR) (OR)3 marksShort AnswerReal Numbers

The traffic lights at three different road crossings change after every 48 seconds, 72 seconds and 108 seconds respectively. If they change simultaneously at 7 a.m., at what time will they change together next ?

Show answer & solution
Answer: At 7:07:12 a.m.
  1. , , .
  2. LCM seconds = 7 minutes 12 seconds.
  3. They change together next at 7 hours 7 minutes 12 seconds a.m.
Q313 marksShort AnswerArithmetic Progressions

Find the common difference of an A.P. whose first term is 8, the last term is 65 and the sum of all its terms is 730.

Show answer & solution
Answer: d = 3
  1. : , so .
  2. : , so .
Q325 marksLong AnswerQuadratic Equations

A train travels at a certain average speed for a distance of 54 km and then travels a distance of 63 km at an average speed of 6 km/h more than the first speed. If it takes 3 hours to complete the journey, what was its first average speed ?

Show answer & solution
Answer: 36 km/h
  1. Let the first speed be x km/h.
  2. .
  3. , so .
  4. , i.e. .
  5. ; speed is positive, so x = 36.
  6. First average speed = 36 km/h.
OR
Q32 (OR) (OR)5 marksLong AnswerQuadratic Equations

Two pipes together can fill a tank in hours. The pipe with larger diameter takes 2 hours less than the pipe with smaller diameter to fill the tank separately. Find the time in which each pipe can fill the tank separately.

Show answer & solution
Answer: Smaller pipe: 5 hours; larger pipe: 3 hours
  1. Let the smaller pipe take x hours; the larger takes (x – 2) hours.
  2. .
  3. , so , i.e. .
  4. , so x = 5 or .
  5. makes x – 2 negative, so x = 5.
  6. Smaller pipe 5 hours, larger pipe 3 hours.
Q335 marksLong AnswerAreas Related to Circles

A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope. Find the area of that part of the field in which the horse can graze. Also, find the increase in grazing area if length of rope is increased to 10 m. (Use )

Show answer & solution
Answer: 19.625 m; increase = 58.875 m
  1. The horse grazes a quadrant (angle ) of radius equal to the rope.
  2. With 5 m rope: area m.
  3. With 10 m rope: area m.
  4. Increase = 78.5 – 19.625 = 58.875 m.
Q345 marksLong AnswerCircles

A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC are of lengths 10 cm and 8 cm respectively. Find the lengths of the sides AB and AC, if it is given that area cm.

Diagram for CBSE 2023 Class 10 Maths question 34
Show answer & solution
Answer: AB = 14.5 cm, AC = 12.5 cm
  1. Tangents from an external point are equal. Let the tangent length from A be x.
  2. Then AB = x + 10, AC = x + 8, BC = 18 cm.
  3. Area = area OBC + area OCA + area OAB .
  4. , so , x = 4.5.
  5. AB = 14.5 cm, AC = 12.5 cm.
  6. Check: s = 22.5, area cm.
OR
Q34 (OR) (OR)5 marksLong AnswerCircles

Two circles with centres O and O′ of radii 6 cm and 8 cm, respectively intersect at two points P and Q such that OP and O′P are tangents to the two circles. Find the length of the common chord PQ.

Diagram for CBSE 2023 Class 10 Maths question 34 (OR)
Show answer & solution
Answer: PQ = 9.6 cm
  1. O′P is tangent to the circle with centre O at P, so OP O′P; .
  2. cm.
  3. The common chord PQ is perpendicular to OO′ and bisected by it at A.
  4. Area of : , so cm.
  5. PQ = 2PA = 9.6 cm.

Two pillars are standing on either side of a 80 m wide road. Height of one pillar is 20 m more than the height of the other pillar. From a point on the road between the pillars, the angle of elevation of the higher pillar is , whereas that of the other pillar is . Find the position of the point between the pillars and the height of each pillar. (Use )

Show answer & solution
Answer: The point is m from the higher pillar (51.35 m from the other); heights ≈ 49.6 m and 29.6 m
  1. Let the shorter pillar have height h m, so the higher one is (h + 20) m. Let the point be x m from the foot of the higher pillar, so (80 – x) m from the other.
  2. Higher pillar: , so .
  3. Other pillar: , so .
  4. gives , so , .
  5. x = 20 + 5(1.73) = 28.65 m; distance from the other pillar = 80 – 28.65 = 51.35 m.
  6. Higher pillar m.
  7. Other pillar = 49.6 – 20 = 29.6 m.
Q364 marksCase StudyPolynomials

In a pool at an aquarium, a dolphin jumps out of the water travelling at 20 cm per second. Its height above water level after t seconds is given by .
Based on the above, answer the following questions :
(i) Find zeroes of polynomial . (1)
(ii) Which of the following types of graph represents p(t) ? (1)
(iii) What would be the value of h at ? Interpret the result. (2)
OR (iii) How much distance has the dolphin covered before hitting the water level again ? (2)

Diagram for CBSE 2023 Class 10 Maths question 36
Show answer & solution
Answer: (i) 0 and (ii) Graph (a) (iii) h = cm: the dolphin is 6 cm below the water level at s; OR: 25 cm
  1. (i) gives t = 0 or .
  2. (ii) The leading coefficient is negative, so the graph is a downward parabola cutting the time axis at 0 and : graph (a).
  3. (iii) cm.
  4. Negative height means the dolphin has re-entered the water (at s) and is 6 cm below the water level.
  5. OR: The dolphin is out of the water from t = 0 to s.
  6. Distance covered at 20 cm per second cm.
Q374 marksCase StudySurface Areas and Volumes

A golf ball is spherical with about 300 – 500 dimples that help increase its velocity while in play. Golf balls are traditionally white but available in colours also. In the given figure, a golf ball has diameter 4.2 cm and the surface has 315 dimples (hemi-spherical) of radius 2 mm.
Based on the above, answer the following questions :
(i) Find the surface area of one such dimple. (1)
(ii) Find the volume of the material dug out to make one dimple. (1)
(iii) Find the total surface area exposed to the surroundings. (2)
OR (iii) Find the volume of the golf ball. (2)

Diagram for CBSE 2023 Class 10 Maths question 37
Show answer & solution
Answer: (i) 0.2514 cm (≈ 25.14 mm) (ii) 0.01676 cm (≈ 16.76 mm) (iii) 95.04 cm; OR: 33.528 cm
  1. Dimple radius r = 2 mm = 0.2 cm; ball radius R = 2.1 cm.
  2. (i) Curved surface of a hemispherical dimple cm (approx.).
  3. (ii) Volume dug out cm (approx.).
  4. (iii) Surface of sphere cm.
  5. Each dimple removes a circle and adds , a net gain of .
  6. Total exposed area cm.
  7. OR: Volume of sphere cm.
  8. Volume removed by dimples cm.
  9. Volume of golf ball = 38.808 – 5.28 = 33.528 cm.
Q384 marksCase StudyProbability

A middle school decided to run the following spinner game as a fund-raiser on Christmas Carnival.
Making Purple : Spin each spinner once. Blue and red make purple. So, if one spinner shows Red (R) and another Blue (B), then you ‘win’. One such outcome is written as ‘RB’.
Based on the above, answer the following questions :
(i) List all possible outcomes of the game. (1)
(ii) Find the probability of ‘Making Purple’. (1)
(iii) For each win, a participant gets ₹ 10, but if he/she loses, he/she has to pay ₹ 5 to the school. If 99 participants played, calculate how much fund could the school have collected. (2)
OR (iii) If the same amount of ₹ 5 has been decided for winning or losing the game, then how much fund had been collected by school ? (Number of participants = 99) (2)

Diagram for CBSE 2023 Class 10 Maths question 38
Show answer & solution
Answer: (i) RR, RB, RG, GR, GB, GG, YR, YB, YG (ii) (iii) ₹ 330; OR: ₹ 385
  1. Spinner I: R, G, Y (equal parts). Spinner II: R, B, G (equal parts).
  2. (i) Outcomes: RR, RB, RG, GR, GB, GG, YR, YB, YG (9 equally likely).
  3. (ii) Only RB makes purple, so P(purple) .
  4. (iii) Out of 99 participants, expected winners , losers = 88.
  5. Fund = 88 × 5 – 11 × 10 = 440 – 110 = ₹ 330.
  6. OR: Fund = 88 × 5 – 11 × 5 = 440 – 55 = ₹ 385.
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