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CBSE Class 10 Maths Standard 2023 Question Paper 30/1/3 with Solutions

All 44 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/1/3 (2023), with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.

Set 30/1/1Set 30/1/2Set 30/1/3Set 30/2/1Set 30/2/2Set 30/2/3Set 30/4/1Set 30/4/2Set 30/4/3Set 30/5/1Set 30/5/2Set 30/5/3Set 30/6/1Set 30/6/2Set 30/6/3

Curved surface area of a cylinder of height 5 cm is 94.2 cm. Radius of the cylinder is (Take )

  1. (A)2 cm
  2. (B)3 cm
  3. (C)2.9 cm
  4. (D)6 cm
Show answer & solution
Answer: (B) 3 cm
  1. CSA .
  2. , so cm.
Q21 markMCQStatistics

The distribution below gives the marks obtained by 80 students on a test :
Marks: Less than 10, Less than 20, Less than 30, Less than 40, Less than 50, Less than 60
Number of Students: 3, 12, 27, 57, 75, 80
The modal class of this distribution is :

  1. (A)10 – 20
  2. (B)20 – 30
  3. (C)30 – 40
  4. (D)50 – 60
Show answer & solution
Answer: (C) 30 – 40
  1. Convert the cumulative frequencies to class frequencies:
  2. 0–10: 3, 10–20: 9, 20–30: 15, 30–40: 30, 40–50: 18, 50–60: 5.
  3. The highest frequency is 30, for the class 30–40.
  4. Modal class = 30 – 40

The area of metal sheet required to make a closed hollow cylinder of height 2.4 m and base radius 0.7 m, is

  1. (A)10.56 m
  2. (B)13.52 m
  3. (C)13.64 m
  4. (D)14.08 m
Show answer & solution
Answer: (C) 13.64 m
  1. Area of sheet = total surface area of a closed cylinder .
  2. m

The distance between the points and is

  1. (A) units
  2. (B) units
  3. (C) units
  4. (D)0
Show answer & solution
Answer: (A) units
  1. Distance
  2. units
Also asked in: 2023 Standard 30/1/1
Q51 markMCQPolynomials

If , are zeroes of a polynomial then is equal to

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. , .

The least positive value of k, for which the quadratic equation has rational roots, is

  1. (A)
  2. (B)2
  3. (C)
  4. (D)
Show answer & solution
Answer: (B) 2
  1. Roots are rational when the discriminant is a perfect square.
  2. .
  3. k = 1 gives D = 33, not a perfect square.
  4. k = 2 gives , a perfect square (roots 1 and –2).
  5. Least positive value of k is 2.

is equal to

  1. (A)–1
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A) –1
  1. , , .
  2. Value
Also asked in: 2023 Standard 30/1/1
Q81 markMCQPolynomials

The graph of y = is given in the adjoining figure. Zeroes of the polynomial are

Diagram for CBSE 2023 Class 10 Maths question 8
  1. (A)–5, 7
  2. (B)
  3. (C)–5, 0, 7
  4. (D)–5, , 7
Show answer & solution
Answer: (C) –5, 0, 7
  1. Zeroes are the x-coordinates of the points where the graph cuts the x-axis.
  2. The graph cuts the x-axis at (–5, 0), (0, 0) and (7, 0).
  3. Zeroes: –5, 0, 7. (The points and are only feet of the turning points.)

The value of k for which the pair of equations and has infinitely many solutions,

  1. (A)is k = 3
  2. (B)does not exist
  3. (C)is k = –3
  4. (D)is k = 4
Show answer & solution
Answer: (B) does not exist
  1. Write the equations as and .
  2. For infinitely many solutions: .
  3. But and are not equal.
  4. So no value of k works.

If , and are in A.P., then the value of p is

  1. (A)–2
  2. (B)4
  3. (C)0
  4. (D)2
Show answer & solution
Answer: (C) 0
  1. For three terms in A.P., .
Also asked in: 2023 Standard 30/1/1

In what ratio, does x-axis divide the line segment joining the points A(3, 6) and B(–12, –3) ?

  1. (A)1 : 2
  2. (B)1 : 4
  3. (C)4 : 1
  4. (D)2 : 1
Show answer & solution
Answer: (D) 2 : 1
  1. Let the x-axis divide AB in the ratio k : 1.
  2. y-coordinate of the point .
  3. , so .
  4. Ratio = 2 : 1
Q121 markMCQProbability

Probability of happening of an event is denoted by p and probability of non-happening of the event is denoted by q. Relation between p and q is

  1. (A)p + q = 1
  2. (B)p = 1, q = 1
  3. (C)p = q – 1
  4. (D)p + q + 1 = 0
Show answer & solution
Answer: (A) p + q = 1
  1. P(E) + P(not E) = 1.
  2. So p + q = 1.
Q131 markMCQProbability

A girl calculates that the probability of her winning the first prize in a lottery is 0.08. If 6000 tickets are sold, how many tickets has she bought ?

  1. (A)40
  2. (B)240
  3. (C)480
  4. (D)750
Show answer & solution
Answer: (C) 480
  1. P(winning) = number of her tickets ÷ total tickets.
  2. Number of her tickets
Q141 markMCQCircles

In the given figure, PQ is tangent to the circle centred at O. If , then the measure of will be

Diagram for CBSE 2023 Class 10 Maths question 14
  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. OA = OB (radii), so .
  2. The radius OB is perpendicular to the tangent PQ, so .

If , then the value of is

  1. (A)
  2. (B)
  3. (C)3
  4. (D)does not exist
Show answer & solution
Answer: (C) 3
  1. .
  2. Divide numerator and denominator by : .
Q161 markMCQProbability

In a survey, it is found that every fifth person has a vehicle. The probability of a person NOT having a vehicle, is

  1. (A)
  2. (B)5%
  3. (C)
  4. (D)95%
Show answer & solution
Answer: (C)
  1. P(having a vehicle) .
  2. P(not having a vehicle)
Q171 markMCQStatistics

If the value of each observation of a statistical data is increased by 3, then the mean of the data

  1. (A)remains unchanged
  2. (B)increases by 3
  3. (C)increases by 6
  4. (D)increases by 3n
Show answer & solution
Answer: (B) increases by 3
  1. New mean .
  2. So the mean increases by 3.
Q181 markMCQPolynomials

Which of the following is a quadratic polynomial having zeroes and ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (D)
  1. Sum of zeroes = 0, product .
  2. Polynomial: , i.e. a multiple of .
  3. has zeroes .
Also asked in: 2023 Standard 30/1/1
Q191 markAssertion–ReasonReal Numbers

Assertion (A) : The perimeter of is a rational number.
Reason (R) : The sum of the squares of two rational numbers is always rational.

Diagram for CBSE 2023 Class 10 Maths question 19
  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true but Reason (R) is false.
  4. (D)Assertion (A) is false but Reason (R) is true.
Show answer & solution
Answer: (D) A is false but R is true.
  1. , so cm.
  2. Perimeter cm, which is irrational. A is false.
  3. If a, b are rational, is rational. R is true.
Q201 markAssertion–ReasonCoordinate Geometry

Assertion (A) : Point P(0, 2) is the point of intersection of y-axis with the line .
Reason (R) : The distance of point P(0, 2) from x-axis is 2 units.

  1. (A)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true but Reason (R) is false.
  4. (D)Assertion (A) is false but Reason (R) is true.
Show answer & solution
Answer: (B) Both A and R are true but R is not the correct explanation of A.
  1. On the y-axis x = 0, so , y = 2. The line meets the y-axis at (0, 2). A is true.
  2. Distance of (0, 2) from the x-axis = |y| = 2 units. R is true.
  3. R does not explain why (0, 2) lies on the line, so R is not the correct explanation of A.
Q212 marksVery Short AnswerIntroduction to Trigonometry

If , then prove that .

Show answer & solution
Answer: Proved.
  1. .
  2. .
OR
Q21 (OR) (OR)2 marksVery Short AnswerIntroduction to Trigonometry

If , then show that .

Show answer & solution
Answer: Proved.
  1. , so .
  2. , so .
Q222 marksVery Short AnswerReal Numbers

Find the greatest number which divides 85 and 72 leaving remainders 1 and 2 respectively.

Show answer & solution
Answer: 14
  1. The number divides 85 – 1 = 84 and 72 – 2 = 70 exactly.
  2. , .
  3. HCF(84, 70) .
  4. Required number = 14.
Also asked in: 2023 Standard 30/1/1
Q232 marksVery Short AnswerProbability

A bag contains 4 red, 3 blue and 2 yellow balls. One ball is drawn at random from the bag. Find the probability that drawn ball is (i) red (ii) yellow.

Show answer & solution
Answer: (i) (ii)
  1. Total balls = 4 + 3 + 2 = 9.
  2. (i) P(red)
  3. (ii) P(yellow)
Q242 marksVery Short AnswerTriangles

In the given figure, ABCD is a parallelogram. AE divides the line segment BD in the ratio 1 : 2. If BE = 1.5 cm, then find the length of BC.

Diagram for CBSE 2023 Class 10 Maths question 24
Show answer & solution
Answer: BC = 3 cm
  1. AE meets BD at O with BO : OD = 1 : 2.
  2. (E lies on BC), so in and : (vertically opposite) and (alternate angles).
  3. (AA), so .
  4. cm, and BC = AD = 3 cm.

Solve the pair of equations and graphically.

Show answer & solution
Answer: x = 3, y = –4, i.e. the lines meet at (3, –4).
  1. is a line parallel to the y-axis through (3, 0).
  2. is a line parallel to the x-axis through (0, –4).
  3. Draw both lines; they intersect at (3, –4).
  4. Solution: , .
Also asked in: 2023 Standard 30/1/1
OR
Q25 (OR) (OR)2 marksVery Short AnswerPair of Linear Equations in Two Variables

Using graphical method, find whether following system of linear equations is consistent or not :
and

Show answer & solution
Answer: Consistent; the lines meet at (0, –7).
  1. is the y-axis.
  2. is a line parallel to the x-axis through (0, –7).
  3. The two lines intersect at exactly one point (0, –7).
  4. So the system has a unique solution and is consistent.
Also asked in: 2023 Standard 30/1/1
Q263 marksShort AnswerCircles

Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that .

Diagram for CBSE 2023 Class 10 Maths question 26
Show answer & solution
Answer: Proved.
  1. Let .
  2. TP = TQ (tangents from an external point), so .
  3. OP TP, so .
  4. .
  5. Hence .
OR
Q26 (OR) (OR)3 marksShort AnswerCircles

In the given figure, a circle is inscribed in a quadrilateral ABCD in which . If AD = 17 cm, AB = 20 cm and DS = 3 cm, then find the radius of the circle.

Diagram for CBSE 2023 Class 10 Maths question 26 (OR)
Show answer & solution
Answer: 6 cm
  1. Tangents from an external point are equal: DR = DS = 3 cm.
  2. AR = AD – DR = 17 – 3 = 14 cm, so AQ = AR = 14 cm.
  3. BQ = AB – AQ = 20 – 14 = 6 cm.
  4. In OQBP, and BQ = BP, so OQBP is a square.
  5. r = OQ = BQ = 6 cm.
Q273 marksShort AnswerIntroduction to Trigonometry

Prove that : .

Show answer & solution
Answer: Proved.
  1. .
  2. .
  3. LHS = RHS.
Q283 marksShort AnswerSurface Areas and Volumes

A room is in the form of cylinder surmounted by a hemi-spherical dome. The base radius of hemisphere is one-half the height of cylindrical part. Find total height of the room if it contains m of air.

Show answer & solution
Answer: 6 m
  1. Let the radius be r; height of cylinder h = 2r.
  2. Volume .
  3. , so , , r = 2 m.
  4. Total height = h + r = 4 + 2 = 6 m.
OR
Q28 (OR) (OR)3 marksShort AnswerSurface Areas and Volumes

An empty cone is of radius 3 cm and height 12 cm. Ice-cream is filled in it so that lower part of the cone which is of the volume of the cone is unfilled but hemisphere is formed on the top. Find volume of the ice-cream. (Take )

Diagram for CBSE 2023 Class 10 Maths question 28 (OR)
Show answer & solution
Answer: 150.72 cm
  1. Volume of cone cm.
  2. Filled part of cone cm.
  3. Volume of hemisphere cm.
  4. Volume of ice-cream = 94.2 + 56.52 = 150.72 cm.
Q293 marksShort AnswerCoordinate Geometry

If (–5, 3) and (5, 3) are two vertices of an equilateral triangle, then find co-ordinates of the third vertex, given that origin lies inside the triangle. (Take )

Show answer & solution
Answer: (0, –5.5)
  1. Let A(–5, 3), B(5, 3); AB = 10.
  2. The third vertex C is equidistant from A and B, so it lies on x = 0: C(0, y).
  3. , so , .
  4. Origin is inside the triangle, so C is below AB: .
  5. Third vertex = (0, –5.5)
Also asked in: 2023 Standard 30/1/1
Q303 marksShort AnswerReal Numbers

Prove that is an irrational number.

Show answer & solution
Answer: Proved.
  1. Suppose is rational. Then with integers a, b, , having no common factor other than 1.
  2. Squaring, , so 5 divides , hence 5 divides a (5 is prime).
  3. Let . Then , so ; 5 divides , hence 5 divides b.
  4. So 5 is a common factor of a and b, a contradiction.
  5. Hence is irrational.

Jaya scored 40 marks in a test getting 3 marks for each correct answer and losing 1 mark for each incorrect answer. Had 4 marks being awarded for each correct answer and 2 marks were deducted for each incorrect answer then Jaya again would have scored 40 marks. How many questions were there in the Test ?

Show answer & solution
Answer: 40 questions
  1. Let x be the number of correct answers and y the number of incorrect answers.
  2. ... (1)
  3. , i.e. ... (2)
  4. Subtract (2) from (1): x = 20; then y = 3(20) – 40 = 20.
  5. Total questions = x + y = 40.
Q325 marksLong AnswerAreas Related to Circles

A chord of a circle of radius 14 cm subtends an angle of at the centre. Find the area of the corresponding minor segment of the circle. Also find the area of the major segment of the circle.

Show answer & solution
Answer: Minor segment cm ≈ 17.89 cm; major segment cm ≈ 598.11 cm
  1. Area of sector cm ≈ 102.67 cm.
  2. The triangle formed is equilateral (two radii with between them): area cm ≈ 84.87 cm.
  3. Minor segment ≈ 17.89 cm.
  4. Area of circle cm.
  5. Major segment ≈ 598.11 cm.
Q335 marksLong AnswerArithmetic Progressions

The ratio of the 11 term to 17 term of an A.P. is 3 : 4. Find the ratio of 5 term to 21 term of the same A.P. Also, find the ratio of the sum of first 5 terms to that of first 21 terms.

Show answer & solution
Answer: 3 : 7 and 25 : 189
  1. , so , .
  2. .
  3. .
  4. .
  5. .
OR
Q33 (OR) (OR)5 marksLong AnswerArithmetic Progressions

250 logs are stacked in the following manner :
22 logs in the bottom row, 21 in the next row, 20 in the row next to it and so on (as shown by an example). In how many rows, are the 250 logs placed and how many logs are there in the top row ?

Show answer & solution
Answer: 20 rows; 3 logs in the top row
  1. Rows form an A.P.: a = 22, d = –1.
  2. , so .
  3. , , n = 20 or 25.
  4. For n = 25 the last row would have 22 – 24 = –2 logs, not possible. So n = 20.
  5. Top row logs.
Q345 marksLong AnswerTriangles

Sides AB and AC and median AM of a are proportional to sides DE and DF and Median DN of another . Show that .

Show answer & solution
Answer: Proved.
  1. Given . Produce AM to P with MP = AM, and DN to Q with NQ = DN; join CP and FQ.
  2. In and : BM = CM, AM = PM, , so they are congruent (SAS) and CP = AB. Similarly FQ = DE.
  3. So (as AP = 2AM, DQ = 2DN). Hence (SSS) and .
  4. In the same way (using BP = AC, EQ = DF) , so .
  5. Adding, .
  6. In and : and , so (SAS).
OR
Q34 (OR) (OR)5 marksLong AnswerTriangles

ABCD is a parallelogram, P is a point on side BC and DP when produced meets AB produced at L. Prove that
(i)
(ii)
(iii) If LP : PD = 2 : 3 then find BP : BC.

Diagram for CBSE 2023 Class 10 Maths question 34 (OR)
Show answer & solution
Answer: (i) Proved. (ii) Proved. (iii) BP : BC = 2 : 5
  1. (i) In and : (vertically opposite) and (alternate angles, ). So (AA), giving .
  2. (ii) In and : (alternate angles, ) and (opposite angles of a parallelogram). So (AA), giving .
  3. (iii) From : .
  4. So BP = 2k, PC = 3k, BC = 5k, and BP : BC = 2 : 5.

An aeroplane when flying at a height of 3000 m from the ground passes vertically above another aeroplane at an instant when the angles of elevation of the two planes from the same point on the ground are and respectively. Find the vertical distance between the aeroplanes at that instant. Also, find the distance of first plane from the point of observation. (Take )

Show answer & solution
Answer: Vertical distance m = 1270 m; distance of first plane m = 3460 m
  1. Let O be the observation point, C the point on the ground below the planes, A the first plane (AC = 3000 m) and B the second plane.
  2. , so m.
  3. , so m.
  4. Vertical distance AB = 3000 – 1730 = 1270 m.
  5. m.
Q364 marksCase StudyStatistics

India meteorological department observes seasonal and annual rainfall every year in different sub-divisions of our country.
It helps them to compare and analyse the results. The table given below shows sub-division wise seasonal (monsoon) rainfall (mm) in 2018 :
Rainfall (mm): 200-400, 400-600, 600-800, 800-1000, 1000-1200, 1200-1400, 1400-1600, 1600-1800
Number of Sub-divisions: 2, 4, 7, 4, 2, 3, 1, 1
Based on the above information, answer the following questions :
(I) Write the modal class. (1)
(II) Find the median of the given data. (2)
OR
Find the mean rainfall in this season.
(III) If sub-division having at least 1000 mm rainfall during monsoon season, is considered good rainfall sub-division, then how many sub-divisions had good rainfall ? (1)

Show answer & solution
Answer: (I) 600-800 (II) Median ≈ 771.43 mm; OR: Mean = 850 mm (III) 7
  1. (I) Highest frequency is 7, for 600–800. Modal class = 600–800.
  2. (II) N = 24, . Cumulative frequencies: 2, 6, 13, 17, 19, 22, 23, 24. Median class 600–800.
  3. Median mm (approx.).
  4. OR: Class marks 300, 500, 700, 900, 1100, 1300, 1500, 1700. .
  5. Mean mm.
  6. (III) Sub-divisions with at least 1000 mm = 2 + 3 + 1 + 1 = 7.
Q374 marksCase StudyCircles

The discus throw is an event in which an athlete attempts to throw a discus. The athlete spins anti-clockwise around one and a half times through a circle, then releases the throw. When released, the discus travels along tangent to the circular spin orbit.
In the given figure, AB is one such tangent to a circle of radius 75 cm. Point O is centre of the circle and . PQ is parallel to OA.
Based on above information :
(a) find the length of AB. (1)
(b) find the length of OB. (1)
(c) find the length of AP. (2)
OR
find the length of PQ.

Diagram for CBSE 2023 Class 10 Maths question 37
Show answer & solution
Answer: (a) cm (b) 150 cm (c) cm; OR: PQ = 37.5 cm
  1. (a) OA AB. , so cm (≈ 129.9 cm).
  2. (b) , so OB = 150 cm.
  3. (c) Q lies on the circle, so OQ = 75 cm and QB = 150 – 75 = 75 cm; Q is the mid-point of OB.
  4. , so by the mid-point theorem (converse) P is the mid-point of AB.
  5. cm (≈ 64.95 cm).
  6. OR: cm.
Q384 marksCase StudyQuadratic Equations

While designing the school year book, a teacher asked the student that the length and width of a particular photo is increased by x units each to double the area of the photo. The original photo is 18 cm long and 12 cm wide.
Based on the above information, answer the following questions :
(I) Write an algebraic equation depicting the above information. (1)
(II) Write the corresponding quadratic equation in standard form. (1)
(III) What should be the new dimensions of the enlarged photo ? (2)
OR
Can any rational value of x make the new area equal to 220 cm ?

Diagram for CBSE 2023 Class 10 Maths question 38
Show answer & solution
Answer: (I) (II) (III) 24 cm × 18 cm; OR: No, since has discriminant 916, not a perfect square, so x is irrational.
  1. (I) Original area = 18 × 12 = 216 cm. New area = .
  2. (II) , i.e. .
  3. (III) ; x > 0, so x = 6. New dimensions: 18 + 6 = 24 cm by 12 + 6 = 18 cm.
  4. OR: gives .
  5. , which is not a perfect square, so x is irrational. No rational x gives area 220 cm.
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