CBSE Class 10 Maths Standard 2025 Question Paper 30/6/2 with Solutions
All 43 questions from the CBSE Class 10 Mathematics Standard board paper, Set 30/6/2 (2025),
with answers and step-by-step solutions. Total 80 marks. Tap “Show answer & solution” under any question.
For a circle with centre O and radius 5 cm, which of the following statements is true ? P : Distance between every pair of parallel tangents is 5 cm. Q : Distance between every pair of parallel tangents is 10 cm. R : Distance between every pair of parallel tangents must be between 5 cm and 10 cm. S : There does not exist a point outside the circle from where length of tangent is 5 cm.
(A)P
(B)Q
(C)R
(D)S
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Answer: (B) Q
Parallel tangents touch the circle at the two ends of a diameter.
So the distance between them equals the diameter =2×5=10 cm. Q is true; P and R are false.
S is false: a point at distance 52 cm from O has tangent length 50−25=5 cm.
A peacock sitting on the top of a tree of height 10 m observes a snake moving on the ground. If the snake is 103 m away from the base of the tree, then angle of depression of the snake from the eye of the peacock is
(A)30∘
(B)45∘
(C)60∘
(D)90∘
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Answer: (A) 30∘
Angle of depression = angle of elevation of the peacock from the snake =θ.
If a cone of greatest possible volume is hollowed out from a solid wooden cylinder, then the ratio of the volume of remaining wood to the volume of cone hollowed out is
(A)1 : 1
(B)1 : 3
(C)2 : 1
(D)3 : 1
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Answer: (C) 2 : 1
The largest cone has the same radius r and height h as the cylinder.
Assertion (A) : For two prime numbers x and y (x<y), HCF(x,y)=x and LCM(x,y)=y. Reason (R) : HCF(x,y)≤ LCM(x,y), where x, y are any two natural numbers.
(A)Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
(B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C)Assertion (A) is true, but Reason (R) is false.
(D)Assertion (A) is false, but Reason (R) is true.
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Answer: (D) Assertion (A) is false, but Reason (R) is true.
For two distinct primes x and y: HCF =1 and LCM =xy (e.g. 2 and 3: HCF =1=2, LCM =6=3). So A is false.
HCF divides both numbers and LCM is a multiple of both, so HCF ≤ LCM always. R is true.
In an experiment of throwing a die, Assertion (A) : Event E1 : getting a number less than 3 and Event E2 : getting a number greater than 3 are complementary events. Reason (R) : If two events E and F are complementary events, then P(E)+P(F)=1.
(A)Both Assertion (A) and Reason (R) are true and Reason (R) is correct explanation of Assertion (A).
(B)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C)Assertion (A) is true, but Reason (R) is false.
(D)Assertion (A) is false, but Reason (R) is true.
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Answer: (D) Assertion (A) is false, but Reason (R) is true.
E1={1,2}, E2={4,5,6}. Together they miss the outcome 3.
P(E1)+P(E2)=62+63=65=1, so they are not complementary. A is false.
R is the definition-property of complementary events, so R is true.
A bag contains cards which are numbered from 5 to 100 such that each card bears a different number. A card is drawn at random. Find the probability that number on the card is (i) a perfect square (ii) a 2-digit number
In a pair of supplementary angles, the greater angle exceeds the smaller by 50∘. Express the given situation as a system of linear equations in two variables and hence obtain the measure of each angle.
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Answer:x+y=180, x−y=50; angles are 115∘ and 65∘
Let the greater angle be x∘ and the smaller be y∘.
Let p, q and r be three distinct prime numbers. Check whether p⋅q⋅r+q is a composite number or not. Further, give an example for 3 distinct primes p, q, r such that (i) p⋅q⋅r+1 is a composite number. (ii) p⋅q⋅r+1 is a prime number.
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Answer: Composite, since pqr+q=q(pr+1). (i) e.g. 3⋅5⋅7+1=106=2×53 (ii) e.g. 2⋅3⋅5+1=31
p⋅q⋅r+q=q(pr+1)
Both factors q≥2 and pr+1≥7 exceed 1, so the number has a factor other than 1 and itself: it is composite.
If the points A(6,1), B(p,2), C(9,4) and D(7,q) are the vertices of a parallelogram ABCD, then find the values of p and q. Hence, check whether ABCD is a rectangle or not.
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Answer:p=8, q=3; ABCD is not a rectangle
Diagonals of a parallelogram bisect each other: midpoint of AC = midpoint of BD.
Midpoint of AC =(215,25); midpoint of BD =(2p+7,22+q)
p+7=15⇒p=8; 2+q=5⇒q=3
AC=32+32=32; BD=(7−8)2+(3−2)2=2
Diagonals are not equal, so ABCD is not a rectangle.
Following data shows the number of family members living in different bungalows of a locality : Number of Members: 0 – 2, 2 – 4, 4 – 6, 6 – 8, 8 – 10, Total Number of Bungalows: 10, p, 60, q, 5, 120 If the median number of members is found to be 5, find the values of p and q.
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Answer:p=20, q=25
10+p+60+q+5=120⇒p+q=45
2N=60; median 5 lies in class 4 – 6: l=4, f=60, h=2, cf=10+p
There is a circular park of diameter 65 m as shown in the following figure, where AB is a diameter. An entry gate is to be constructed at a point P on the boundary of the park such that distance of P from A is 35 m more than the distance of P from B. Find distance of point P from A and B respectively.
On the day of her examination, Riya sharpened her pencil from both ends as shown below : The diameter of the cylindrical and conical part of the pencil is 4.2 mm. If the height of each conical part is 2.8 mm and length of entire pencil is 105.6 mm, find the total surface area of the pencil.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid. (Use π=722,5=2.2)
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Answer: Volume =36076≈2025.33 cm3; surface area =1360.8 cm2
In order to organise, Annual Sports Day, a school prepared an eight lane running track with an integrated football field inside the track area as shown below : The length of innermost lane of the track is 400 m and each subsequent lane is 7.6 m longer than the preceding lane. Based on given information, answer the following questions, using concept of Arithmetic Progression. (i) What is the length of the 6th lane ? (1) (ii) How long is the 8th lane than that of 4th lane ? (1) (iii) (a) While practicing for a race, a student took one round each in first six lanes. Find the total distance covered by the student. (2) OR (iii) (b) A student took one round each in lane 4 to lane 8. Find the total distance covered by the student. (2)
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Answer: (i) 438 m (ii) 30.4 m (iii) (a) 2514 m OR (iii) (b) 2190 m
a=400, d=7.6
(i) a6=400+5×7.6=438 m
(ii) a8−a4=4d=4×7.6=30.4 m
(iii) (a) S6=26[2×400+5×7.6]=3×838=2514 m
(iii) (b) a4=422.8, a8=453.2; sum of 5 lanes =25(422.8+453.2)=25×876=2190 m
The Statue of Unity situated in Gujarat is the world's largest Statue which stands over a 58 m high base. As part of the project, a student constructed an inclinometer and wishes to find the height of Statue of Unity using it. He noted following observations from two places : Situation – I : The angle of elevation of the top of Statue from Place A which is 803 m away from the base of the Statue is found to be 60∘. Situation – II : The angle of elevation of the top of Statue from a Place B which is 40 m above the ground is found to be 30∘ and entire height of the Statue including the base is found to be 240 m. Based on given information, answer the following questions : (i) Represent the Situation – I with the help of a diagram. (1) (ii) Represent the Situation – II with the help of a diagram. (1) (iii) (a) Calculate the height of Statue excluding the base and also find the height including the base with the help of Situation – I. (2) OR (iii) (b) Find the horizontal distance of point B (Situation – II) from the Statue and the value of tanα, where α is the angle of elevation of top of base of the Statue from point B. (2)
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Answer: (i) Right triangle: vertical side = total height (statue + base), horizontal side 803 m from A, angle 60∘ at A (ii) B at 40 m above ground; horizontal line from B to statue; angle 30∘ to the top; height of top above B's level =240−40=200 m (iii) (a) 182 m excluding base, 240 m including base OR (iii) (b) 2003 m; tanα=10033
(i) Draw the statue with base as a vertical line PQ (Q at ground), A on the ground with AQ=803 m and ∠PAQ=60∘.
(ii) Draw B at height 40 m above the ground, a horizontal line from B meeting the statue's vertical line at M, and ∠PBM=30∘; PM=240−40=200 m.
(iii) (a) tan60∘=803PQ⇒PQ=803×3=240 m (including base)
Anurag purchased a farmhouse which is in the form of a semicircle of diameter 70 m. He divides it into three parts by taking a point P on the semicircle in such a way that ∠PAB=30∘ as shown in the following figure, where O is the centre of semicircle. In part I, he planted saplings of Mango tree, in part II, he grew tomatoes and in part III, he grew oranges. Based on given information, answer the following questions. (i) What is the measure of ∠POA ? (1) (ii) Find the length of wire needed to fence entire piece of land. (1) (iii) (a) Find the area of region in which saplings of Mango tree are planted. (2) OR (iii) (b) Find the length of wire needed to fence the region III. (2)
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Answer: (i) 120∘ (ii) 180 m (iii) (a) (31925−412253) m2≈111.24 m2 OR (iii) (b) (3220+353) m ≈133.96 m
(i) ∠POB=2∠PAB=60∘ (angle at centre), so ∠POA=180∘−60∘=120∘.
(ii) r=35 m. Fence = semicircular arc + diameter =722×35+70=110+70=180 m.
(iii) (a) Part I is the segment cut off by chord PB, with ∠POB=60∘.
Sector area =36060×722×352=31925≈641.67 m2
△POB is equilateral: area =43×352=412253≈530.43 m2
Area of part I ≈641.67−530.43=111.24 m2
(iii) (b) Region III is bounded by chord AP and arc AP, with ∠AOP=120∘.