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Statistics: 1 mark Questions (CBSE Class 10)

69 different 1 mark questions on Statistics from CBSE Class 10 Maths board exams 2022–2026, newest first.

1 mark (69)2 marks (15)3 marks (27)4 marks (14)5 marks (73)

While calculating mean of a grouped frequency distribution using step deviation method it was found that = 62, a = 47.5, h = 5. The value of is :

  1. (A)3
  2. (B)14.5
  3. (C)2.9
  4. (D)3.1
Show answer & solution
Answer: (C) 2.9
  1. .
  2. .
  3. .
Q201 markAssertion–ReasonStatisticsCBSE 2026 · Basic 430/5/1

Assertion (A) : Median of a data is the value of , where N represents sum of all frequencies.
Reason (R) : Median divides the whole distribution in two equal parts.

  1. (A)Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  2. (B)Both, Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (D) Assertion (A) is false, but Reason (R) is true.
  1. only tells us the position used to locate the median (median class); the median is the value of the observation there, not itself. A is false.
  2. The median is the middle value, which divides the distribution into two equal parts. R is true.

If the mean and mode of a data are 12 and 21 respectively, then its median is :

  1. (A)6
  2. (B)13.5
  3. (C)15
  4. (D)14
Show answer & solution
Answer: (C) 15
  1. Empirical relation: .
  2. .
  3. Median .

The mean and median of a frequency distribution are 43 and 43.4 respectively. The mode of the distribution is :

  1. (A)43.4
  2. (B)42.4
  3. (C)44.2
  4. (D)49.3
Show answer & solution
Answer: (C) 44.2
  1. Mode = 3 Median - 2 Mean

The median and mode of a distribution are 25.2 and 26.1 respectively. The mean of the distribution is :

  1. (A)24.75
  2. (B)24.25
  3. (C)24.3
  4. (D)25.5
Show answer & solution
Answer: (A) 24.75
  1. Empirical relation: Mode Median Mean
  2. Mean Mean
  3. Mean

Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

  1. (A)34
  2. (B)43
  3. (C)38.5
  4. (D)41.5
Show answer & solution
Answer: (A) 34
  1. Mode = 3 Median 2 Mean

While calculating mean of a grouped frequency distribution, step deviation method was used . It was found that , h = 5 and a = 62.5. The value of is

  1. (A)0.5
  2. (B)1.5
  3. (C)0.3
  4. (D)7.5
Show answer & solution
Answer: (C) 0.3
  1. , so

The class mark of the median class of the following data is :
Class Interval: 10 – 25, 25 – 40, 40 – 55, 55 – 70, 70 – 85, 85 – 100
Frequency: 2, 3, 7, 6, 6, 6

  1. (A)40
  2. (B)55
  3. (C)47.5
  4. (D)62.5
Show answer & solution
Answer: (D) 62.5
  1. , so .
  2. Cumulative frequencies: 2, 5, 12, 18, 24, 30.
  3. 15 lies in the class 55 – 70, which is the median class.
  4. Class mark .

The following distribution shows the number of runs scored by some batsmen in test matches :
Runs Scored: 3000 – 4000, 4000 – 5000, 5000 – 6000, 6000 – 7000
Number of Batsmen: 5, 10, 9, 8
The lower limit of the modal class is :

  1. (A)3000
  2. (B)4000
  3. (C)5000
  4. (D)6000
Show answer & solution
Answer: (B) 4000
  1. The highest frequency is 10, for the class 4000 – 5000.
  2. So the modal class is 4000 – 5000 and its lower limit is 4000.

In the formula of mode given by mode ,
denotes the :

  1. (A)frequency of the modal class
  2. (B)frequency of class preceding modal class
  3. (C)frequency of class succeeding modal class
  4. (D)cumulative frequency of modal class
Show answer & solution
Answer: (A) frequency of the modal class
  1. In the mode formula, is the frequency of the modal class, of the class preceding it and of the class succeeding it.

For a distribution, if mean = median = a, then its mode is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C) a
  1. Using the empirical relation, mode = 3 median – 2 mean.
  2. Mode .

The following table shows the marks scored by 23 students of a class.
Marks: 0 – 10, 10 – 20, 20 – 30, 30 – 40, 40 – 50
Number of Students: 5, 3, 4, 8, 3
The lower limit of the modal class is :

  1. (A)10
  2. (B)20
  3. (C)30
  4. (D)40
Show answer & solution
Answer: (C) 30
  1. The highest frequency is 8, for the class 30 – 40.
  2. Modal class = 30 – 40, so its lower limit is 30.

For a distribution, if mean = 15 and mode = 12, then its median is :

  1. (A)12
  2. (B)13
  3. (C)14
  4. (D)15
Show answer & solution
Answer: (C) 14
  1. Empirical relation: .
  2. , so Median .
Q191 markAssertion–ReasonStatisticsCBSE 2025 · Basic 430/4/1

Assertion (A) : Median marks of students in a class test is 16. It means half of the class got marks less than 16.
Reason (R) : Median divides the distribution in two equal parts.

  1. (A)Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. (B)Both, Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
  3. (C)Assertion (A) is true, but Reason (R) is false.
  4. (D)Assertion (A) is false, but Reason (R) is true.
Show answer & solution
Answer: (A) Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  1. The median is the middle value of the arranged data, so it divides the distribution into two equal parts: R is true.
  2. Hence median 16 means half the students scored below 16 (and half above): A is true.
  3. R explains A.

Which of the following depends on all observations of a given data ?

  1. (A)Median
  2. (B)Mean
  3. (C)Range
  4. (D)Mode
Show answer & solution
Answer: (B) Mean
  1. Mean = (sum of all observations) / (number of observations), so every observation affects it.
  2. Median, mode and range depend only on particular observations.

To calculate mean of a grouped data, Rahul used assumed mean method. He used d = , where A is assumed mean. Then is equal to

  1. (A)A +
  2. (B)A + h
  3. (C)h (A + )
  4. (D)A h
Show answer & solution
Answer: (A) A +
  1. In the assumed mean method with , .
  2. No class size factor h appears because d is not divided by h.

Mode and Mean of a data are and , respectively. Then the median of the data is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. Empirical relation: .
  2. , so .
Also asked in: 2025 Standard 30/1/2

What is the mode of a data if median and mean of the same data are and , respectively ?

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (A)
  1. Empirical relation: .
  2. .

If the mean of is 7, then the value of is :

  1. (A)9
  2. (B)6
  3. (C)5
  4. (D)3
Show answer & solution
Answer: (D) 3
  1. Sum ; there are 7 observations.
  2. , so .
  3. .
Also asked in: 2025 Standard 30/3/2

The mean of seven observations is 17. If the mean of the first four observations is 15 and that of the last four observations is 18, then the fourth observation is :

  1. (A)14
  2. (B)13
  3. (C)12
  4. (D)10
Show answer & solution
Answer: (B) 13
  1. Sum of all seven .
  2. Sum of first four ; sum of last four .
  3. The fourth observation is counted in both: .
  4. .

The cumulative frequency for calculating median is obtained by adding the frequencies of all the :

  1. (A)classes up to the median class
  2. (B)classes following the median class
  3. (C)classes preceding the median class
  4. (D)all classes
Show answer & solution
Answer: (C) classes preceding the median class
  1. In the median formula, is the cumulative frequency of the class preceding the median class, i.e. the sum of frequencies of all classes before the median class.

If mean and median of given set of observations are 10 and 11 respectively, then the value of mode is :

  1. (A)10.5
  2. (B)8
  3. (C)13
  4. (D)21
Show answer & solution
Answer: (C) 13
  1. Mode Median Mean

If mean and mode of given set of observations are 10 and 13 respectively, then the value of median is :

  1. (A)19
  2. (B)4
  3. (C)11
  4. (D)43
Show answer & solution
Answer: (C) 11
  1. Mode Median Mean
  2. Median Median Median

If mode and median of given set of observations are 13 and 11 respectively, then the value of mean is :

  1. (A)17
  2. (B)7
  3. (C)10
  4. (D)28
Show answer & solution
Answer: (C) 10
  1. Mode Median Mean
  2. Mean Mean Mean

If median + mean = mode; is the empirical relationship between mean, median and mode, then the value of is

  1. (A)6
  2. (B)3
  3. (C)2
  4. (D)1
Show answer & solution
Answer: (C) 2
  1. Empirical relation: Mode Median Mean, i.e. Median Mean Mode.

Following data shows the marks obtained by 100 students in a class test :
Marks obtained: 20, 29, 28, 33, 42, 38, 43, 25
Number of students: 6, 28, 24, 15, 2, 4, 1, 20
The median will be the average of which two observations ?

  1. (A)29 and 33
  2. (B)25 and 28
  3. (C)28 and 29
  4. (D)33 and 38
Show answer & solution
Answer: (C) 28 and 29
  1. Arrange marks in ascending order with cumulative frequencies:
  2. 20 (6), 25 (26), 28 (50), 29 (78), 33 (93), 38 (97), 42 (99), 43 (100)
  3. (even), so median = average of 50th and 51st observations.
  4. 50th observation = 28, 51st observation = 29.

If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are

  1. (A)12 and 13
  2. (B)13 and 12
  3. (C)10 and 15
  4. (D)15 and 10
Show answer & solution
Answer: (B) 13 and 12
  1. Empirical relation: Mode Median Mean
  2. Let mean , median . Then
  3. , median

If the maximum number of students has obtained 52 marks out of 80, then

  1. (A)52 is the mean of the data.
  2. (B)52 is the median of the data.
  3. (C)52 is the mode of the data.
  4. (D)52 is the range of the data.
Show answer & solution
Answer: (C) 52 is the mode of the data.
  1. The observation that occurs most often (highest frequency) is the mode, so 52 is the mode.

The mean and median of a statistical data are 21 and 23 respectively. The mode of the data is :

  1. (A)27
  2. (B)22
  3. (C)17
  4. (D)23
Show answer & solution
Answer: (A) 27
  1. Mode Median Mean.
  2. Mode .
Also asked in: 2024 Basic 430/1/3

If a certain variable divides a statistical data arranged in order into two equal parts, then the value of is called the :

  1. (A)mean
  2. (B)median
  3. (C)mode
  4. (D)range
Show answer & solution
Answer: (B) median
  1. The value that divides ordered data into two equal halves is the median.
Also asked in: 2024 Basic 430/1/3

The annual rainfall record of a city for 66 days is given in the following table :
Rainfall (in cm) : 0–10, 10–20, 20–30, 30–40, 40–50, 50–60
Number of days : 22, 10, 8, 15, 5, 6
The difference of upper limits of modal and median classes is :

  1. (A)10
  2. (B)15
  3. (C)20
  4. (D)30
Show answer & solution
Answer: (C) 20
  1. Highest frequency is 22, so modal class is 0–10 (upper limit 10).
  2. Cumulative frequencies: 22, 32, 40, 55, 60, 66; .
  3. 33 first lies in cf 40, so median class is 20–30 (upper limit 30).
  4. Difference

If the mean and median of a data are 10 and 11 respectively, then mode of the data is :

  1. (A)12
  2. (B)8
  3. (C)20
  4. (D)13
Show answer & solution
Answer: (D) 13
  1. Using the empirical relation, Mode Median Mean.
  2. Mode .

If for a distribution, , and the mean of the distribution is 8.1, then the value of p is :

  1. (A)3
  2. (B)6
  3. (C)4
  4. (D)5
Show answer & solution
Answer: (B) 6
  1. Mean , so .
  2. , so and .

The following distribution gives the daily income of 50 workers of a factory :
Income (in ₹): 400–424, 425–449, 450–474, 475–499, 500–524
Number of workers: 12, 14, 8, 6, 10
The lower limit of the modal class is :

  1. (A)425
  2. (B)449
  3. (C)
  4. (D)
Show answer & solution
Answer: (C)
  1. The highest frequency is 14, so the modal class is 425–449.
  2. The classes are not continuous (gap of 1), so subtract 0.5 from each lower limit and add 0.5 to each upper limit.
  3. The modal class becomes 424.5–449.5, so its lower limit is 424.5.

The median group in the following frequency distribution is :
Class: 0–10, 10–20, 20–30, 30–40, 40–50, 50–60
Frequency: 5, 8, 20, 15, 7, 5

  1. (A)10–20
  2. (B)20–30
  3. (C)30–40
  4. (D)40–50
Show answer & solution
Answer: (B) 20–30
  1. , so .
  2. Cumulative frequencies: 5, 13, 33, 48, 55, 60.
  3. The first cumulative frequency greater than 30 is 33, so the median class is 20–30.
Also asked in: 2024 Basic 430/4/2

The mode and mean of a data are 7 and 8 respectively. Then, the median of the data is :

  1. (A)
  2. (B)
  3. (C)
  4. (D)33
Show answer & solution
Answer: (A)
  1. Empirical relation: .
  2. , so Median .

If the mean and mode of a frequency distribution are 28 and 16 respectively, then its median is :

  1. (A)22
  2. (B)23.5
  3. (C)24
  4. (D)24.5
Show answer & solution
Answer: (C) 24
  1. Empirical relation: Mode = 3 Median 2 Mean.
  2. , so .
  3. Median = 24.

If the difference of mode and median of a data is 24, then the difference of median and mean of the same data is :

  1. (A)8
  2. (B)12
  3. (C)24
  4. (D)34
Show answer & solution
Answer: (B) 12
  1. Empirical relation: Mode = 3 Median 2 Mean.
  2. So Mode Median = 2 (Median Mean).
  3. (Median Mean), so Median Mean .

In a frequency distribution, the mid-value of a class is 10 and the width of the class is 6. The lower limit of the class is :

  1. (A)6
  2. (B)7
  3. (C)8
  4. (D)12
Show answer & solution
Answer: (B) 7
  1. Lower limit = mid-value .
  2. .

For some data with respective frequencies , the value of is equal to :

  1. (A)
  2. (B)1
  3. (C)
  4. (D)0
Show answer & solution
Answer: (D) 0
  1. .
  2. Since , .
  3. So the value is 0.

The middle most observation of every data arranged in order is called :

  1. (A)mode
  2. (B)median
  3. (C)mean
  4. (D)deviation
Show answer & solution
Answer: (B) median
  1. The median is the middle observation when the data are arranged in order.

If value of each observation in a data is increased by 2, then median of the new data

  1. (A)increases by 2
  2. (B)increases by 2n
  3. (C)remains same
  4. (D)decreases by 2
Show answer & solution
Answer: (A) increases by 2
  1. Adding 2 to every observation keeps their order the same.
  2. The middle value also increases by 2, so the median increases by 2.

After an examination, a teacher wants to know the marks obtained by maximum number of the students in her class. She requires to calculate _____ of marks.

  1. (A)median
  2. (B)mode
  3. (C)mean
  4. (D)range
Show answer & solution
Answer: (B) mode
  1. The value that occurs most often (obtained by the maximum number of students) is the mode.

The mean of five observations is 15. If the mean of first three observations is 14 and that of the last three observations is 17, then the third observation is

  1. (A)20
  2. (B)19
  3. (C)18
  4. (D)17
Show answer & solution
Answer: (C) 18
  1. Sum of all five = .
  2. Sum of first three = ; sum of last three = .
  3. The third observation is counted in both: 42 + 51 = 75 + third observation.
  4. Third observation = 93 - 75 = 18.

If the mean of five observations , , , and is 11, then the value of is :

  1. (A)4
  2. (B)7
  3. (C)11
  4. (D)6
Show answer & solution
Answer: (B) 7
  1. Sum = , so mean = .
  2. .

The mean of five numbers is 15. If we include one more number, the mean of six numbers becomes 17. The included number is :

  1. (A)27
  2. (B)37
  3. (C)17
  4. (D)25
Show answer & solution
Answer: (A) 27
  1. Sum of five numbers = .
  2. Sum of six numbers = .
  3. Included number = 102 - 75 = 27.

If the difference of mode and median of a data is 24, then the difference of its median and mean is :

  1. (A)12
  2. (B)24
  3. (C)8
  4. (D)36
Show answer & solution
Answer: (A) 12
  1. Empirical relation: Mode = 3 Median 2 Mean.
  2. So Mode Median = 2(Median Mean).
  3. (Median Mean), so Median Mean = 12.
Also asked in: 2024 Standard 30/4/3

If the mean of 6, 7, p, 8, q, 14 is 9, then

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Mean = .
  2. .
  3. .

For the data 2, 9, , , 5, 10, 5; if the mean is 7, then the value of is :

  1. (A)9
  2. (B)6
  3. (C)5
  4. (D)3
Show answer & solution
Answer: (D) 3
  1. There are 7 observations with sum .
  2. .

If the mean and mode of a data are 24 and 12 respectively, then its median is :

  1. (A)25
  2. (B)18
  3. (C)20
  4. (D)22
Show answer & solution
Answer: (C) 20
  1. Empirical relation: Mode Median Mean.
  2. .

If the mean of the first natural numbers is , then the value of is :

  1. (A)5
  2. (B)4
  3. (C)9
  4. (D)10
Show answer & solution
Answer: (C) 9
  1. Mean of the first natural numbers .
  2. .

Median and Mode of a distribution are 25 and 21 respectively. Mean of the data using empirical relationship is :

  1. (A)27
  2. (B)29
  3. (C)18
  4. (D)
Show answer & solution
Answer: (a) 27
  1. Empirical relation: 3 Median = Mode + 2 Mean
  2. 2 Mean = 54, so Mean = 27

The mode of the numbers 2, 3, 3, 4, 5, 4, 4, 5, 3, 4, 2, 6, 7 is :

  1. (A)2
  2. (B)3
  3. (C)4
  4. (D)5
Show answer & solution
Answer: (C) 4
  1. Frequencies: 2 occurs 2 times, 3 occurs 3 times, 4 occurs 4 times, 5 occurs 2 times, 6 and 7 once each.
  2. 4 occurs most often, so the mode is 4.

The median class for the data given below is :
Class: 20 – 40, 40 – 60, 60 – 80, 80 – 100, 100 – 120
Frequency: 10, 12, 14, 13, 17

  1. (A)80 – 100
  2. (B)20 – 40
  3. (C)40 – 60
  4. (D)60 – 80
Show answer & solution
Answer: (D) 60 – 80
  1. , so .
  2. Cumulative frequencies: 10, 22, 36, 49, 66.
  3. The first cumulative frequency greater than 33 is 36, so the median class is 60 – 80.

Mean and median of some data are 32 and 30 respectively. Using empirical relation, mode of the data is :

  1. (A)36
  2. (B)26
  3. (C)30
  4. (D)20
Show answer & solution
Answer: (B) 26
  1. Mode = 3 Median − 2 Mean.
  2. Mode = 3 × 30 − 2 × 32 = 90 − 64 = 26.

The time, in seconds, taken by 150 athletes to run a 100 m hurdle race are tabulated below :
Time (sec.): 13-14, 14-15, 15-16, 16-17, 17-18, 18-19
Number of Athletes: 2, 4, 5, 71, 48, 20
The number of athletes who completed the race in less than 17 seconds is

  1. (A)11
  2. (B)71
  3. (C)82
  4. (D)68
Show answer & solution
Answer: (C) 82
  1. Athletes taking less than 17 s are those in the classes 13-14, 14-15, 15-16 and 16-17.
  2. Number .
Also asked in: 2023 Basic 430/6/2

The median of first seven prime numbers is

  1. (A)5
  2. (B)7
  3. (C)11
  4. (D)13
Show answer & solution
Answer: (B) 7
  1. First seven primes: 2, 3, 5, 7, 11, 13, 17.
  2. The middle (4th) value is 7.

If the mean of 6, 7, , 8, y, 14 is 9, then

  1. (A)
  2. (B)
  3. (C)
  4. (D)
Show answer & solution
Answer: (B)
  1. Mean .
  2. , so .

The mean of first ten natural numbers is

  1. (A)5.5
  2. (B)55
  3. (C)45
  4. (D)4.5
Show answer & solution
Answer: (A) 5.5
  1. Sum of 1 to 10 .
  2. Mean .

The Empirical relation between the three measures of central tendency is

  1. (A)Mode = 3 Mean – 2 Median
  2. (B)Mode = 2 Median – 3 Mean
  3. (C)Mode = 2 Mean – 3 Median
  4. (D)Mode = 3 Median – 2 Mean
Show answer & solution
Answer: (D) Mode = 3 Median – 2 Mean
  1. The empirical relation is 3 Median = Mode + 2 Mean.
  2. So Mode = 3 Median – 2 Mean.

The median of first 10 natural numbers is

  1. (A)5
  2. (B)6
  3. (C)5.5
  4. (D)6.5
Show answer & solution
Answer: (C) 5.5
  1. Numbers 1 to 10: there are 10 values, so the median is the mean of the 5th and 6th values.
  2. Median .

The distribution below gives the marks obtained by 80 students on a test :
Marks: Less than 10, Less than 20, Less than 30, Less than 40, Less than 50, Less than 60
Number of Students: 3, 12, 27, 57, 75, 80
The modal class of this distribution is :

  1. (A)10 – 20
  2. (B)20 – 30
  3. (C)30 – 40
  4. (D)50 – 60
Show answer & solution
Answer: (C) 30 – 40
  1. Convert the cumulative frequencies to class frequencies:
  2. 0–10: 3, 10–20: 9, 20–30: 15, 30–40: 30, 40–50: 18, 50–60: 5.
  3. The highest frequency is 30, for the class 30–40.
  4. Modal class = 30 – 40

If the value of each observation of a statistical data is increased by 3, then the mean of the data

  1. (A)remains unchanged
  2. (B)increases by 3
  3. (C)increases by 6
  4. (D)increases by 3n
Show answer & solution
Answer: (B) increases by 3
  1. New mean .
  2. So the mean increases by 3.

The empirical relation between the mode, median and mean of a distribution is :

  1. (A)Mode = 3 Median – 2 Mean
  2. (B)Mode = 3 Mean – 2 Median
  3. (C)Mode = 2 Median – 3 Mean
  4. (D)Mode = 2 Mean – 3 Median
Show answer & solution
Answer: (A) Mode = 3 Median – 2 Mean
  1. The empirical relation is 3 Median = Mode + 2 Mean.
  2. So Mode = 3 Median – 2 Mean.

For the following distribution :
Class: 0-5, 5-10, 10-15, 15-20, 20-25
Frequency: 10, 15, 12, 20, 9
The sum of lower limits of median class and modal class is :

  1. (A)15
  2. (B)25
  3. (C)30
  4. (D)35
Show answer & solution
Answer: (B) 25
  1. N = 10 + 15 + 12 + 20 + 9 = 66,
  2. Cumulative frequencies: 10, 25, 37, 57, 66, so the median class is 10-15 (lower limit 10).
  3. Highest frequency is 20, so the modal class is 15-20 (lower limit 15).
  4. Sum = 10 + 15 = 25

For the following distribution :
Marks Below: 10, 20, 30, 40, 50, 60
Number of Students: 3, 12, 27, 57, 75, 80
The modal class is :

  1. (A)10-20
  2. (B)20-30
  3. (C)30-40
  4. (D)50-60
Show answer & solution
Answer: (C) 30-40
  1. Convert the 'less than' cumulative frequencies to class frequencies:
  2. 0-10: 3, 10-20: 9, 20-30: 15, 30-40: 30, 40-50: 18, 50-60: 5
  3. The highest frequency is 30, so the modal class is 30-40.

If the mean and the median of a data are 12 and 15 respectively, then its mode is :

  1. (A)13.5
  2. (B)21
  3. (C)6
  4. (D)14
Show answer & solution
Answer: (B) 21
  1. Empirical relation: Mode = 3 Median – 2 Mean.
  2. Mode = 3(15) – 2(12) = 45 – 24 = 21.
Also asked in: 2023 Standard 30/5/2

If every term of the statistical data consisting of n terms is decreased by 2, then the mean of the data :

  1. (A)decreases by 2
  2. (B)remains unchanged
  3. (C)decreases by 2n
  4. (D)decreases by 1
Show answer & solution
Answer: (A) decreases by 2
  1. New sum = old sum – 2n.
  2. New mean = old mean – 2.

If the mean and the mode of a distribution are 15 and 18 respectively, then the median of the distribution is :

  1. (A)17
  2. (B)15
  3. (C)16
  4. (D)18
Show answer & solution
Answer: (C) 16
  1. Empirical relation: 3 Median = Mode + 2 Mean.
  2. 3 Median = 18 + 2(15) = 48, so Median = 16.
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