Coordinate Geometry: 1 mark Questions (CBSE Class 10)
97 different 1 mark questions on Coordinate Geometry from CBSE Class 10 Maths board exams 2022–2026, newest first.
The distance between the points (– 4, 2) and (1, 0) is :
(A) 13 units(B) 3 units(C) 9 units(D) 29 units
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Distance = ( 1 + 4 ) 2 + ( 0 − 2 ) 2 . = 25 + 4 = 29 units.
The distance between the points (– 5, 1) and (2, 2) is :
(A) 2 5 units(B) 10 units(C) 5 2 units(D) 3 2 units
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Distance = ( 2 + 5 ) 2 + ( 2 − 1 ) 2 . = 49 + 1 = 50 = 5 2 units.
The distance between the points (– 1, 2 2 ) and (2, 2 ) is :
(A) 5 units(B) 11 units(C) 13 units(D) 7 units
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Distance = ( 2 + 1 ) 2 + ( 2 − 2 2 ) 2 . = 9 + 2 = 11 units.
The distance between the points ( − 2 , 5 ) and ( 5 , − 2 ) is
(A) 7 2 (B) 14(C) 2 7 (D) 7
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d = ( 5 − ( − 2 ) ) 2 + ( − 2 − 5 ) 2 = 49 + 49 = 98 = 7 2
The distance between the points ( − 4 , 5 ) and ( − 1 , 2 ) is
(A) 5(B) 3 2 (C) 6(D) 2 3
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d = ( − 1 + 4 ) 2 + ( 2 − 5 ) 2 = 9 + 9 = 18 = 3 2
The mid-point of the line segment joining the points ( 5 , − 4 ) and ( 6 , 4 ) lies on :
(A) x -axis(B) y -axis(C) origin(D) neither x -axis nor y -axis
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Answer: (A) x -axis
Mid-point = ( 2 5 + 6 , 2 − 4 + 4 ) = ( 2 11 , 0 ) . Its y -coordinate is 0, so it lies on the x -axis.
The distance of the point A(4a, 3a) from x-axis is :
(A) 3a(B) − 3 a (C) 4a(D) − 4 a
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Answer: (A) 3a
The distance of a point from the x-axis is the absolute value of its y-coordinate. So the distance is 3a (taking a > 0).
If the distance between the points (4, p) and (1, 0) is 5, then p is equal to :
(A) ± 4 (B) 4(C) − 4 (D) 0
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Answer: (A) ± 4
( 4 − 1 ) 2 + ( p − 0 ) 2 = 5 2 9 + p 2 = 25 p 2 = 16 , so p = ± 4
In the given figure, Δ ABC is an equilateral triangle. AD is a median of the triangle joining the points A( 0 , 2 5 3 ) , D(0, 0). Points B and C are (in same order) :
(A) (– 5, 0), (5, 0)(B) ( − 2 5 , 0 ) , ( 2 5 , 0 ) (C) (– 10, 0), (10, 0)(D) ( − 5 3 , 0 ) , ( 5 3 , 0 )
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Answer: (B) ( − 2 5 , 0 ) , ( 2 5 , 0 )
AD = 2 5 3 is the height of the equilateral triangle Height = 2 3 × side, so side = 5 D is the midpoint of BC on the x-axis, so BD = DC = 2 5 B( − 2 5 , 0 ) , C( 2 5 , 0 )
In the given figure, a circle is centred at (1, 2). The diameter of the circle is
(A) 4(B) 2 2 (C) 5 (D) 2 5
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The circle passes through the origin O(0, 0). Radius = ( 1 − 0 ) 2 + ( 2 − 0 ) 2 = 5 Diameter = 2 5
The distance between the points ( a cos θ + b sin θ , 0 ) and ( 0 , a sin θ − b cos θ ) is
(A) a 2 + b 2 (B) a 2 − b 2 (C) a 2 − b 2 (D) a 2 + b 2
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d 2 = ( a cos θ + b sin θ ) 2 + ( a sin θ − b cos θ ) 2 = a 2 ( cos 2 θ + sin 2 θ ) + b 2 ( sin 2 θ + cos 2 θ ) + 2 ab sin θ cos θ − 2 ab sin θ cos θ = a 2 + b 2 , so d = a 2 + b 2
A circle centred at ( − 1 , 2 ) passes through the point (0, 3). Radius of the circle is
(A) 2 2 (B) 2 (C) 26 (D) 1
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Radius = ( 0 + 1 ) 2 + ( 3 − 2 ) 2 = 2
The line segment joining the points P ( − 4 , − 2 ) and Q ( 10 , 4 ) is divided by y-axis in the ratio
(A) 2 : 5(B) 1 : 2(C) 2 : 1(D) 5 : 2
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Answer: (A) 2 : 5
Let the y-axis divide PQ in the ratio k : 1 . The point of division has x-coordinate k + 1 10 k − 4 , which is 0 on the y-axis. 10 k − 4 = 0 , so k = 5 2 .Ratio = 2 : 5
For a point ( 3 , − 5 ) , the value of (abscissa − ordinate) is :
(A) − 8 (B) − 2 (C) 2(D) 8
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Answer: (D) 8
Abscissa = 3, ordinate = − 5 . Abscissa − ordinate = 3 − ( − 5 ) = 8 .
The mid-point of a line segment divides the line segment in the ratio :
(A) 1 : 2(B) 2 : 1(C) 1 : 1(D) 2 1 : 2
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Answer: (C) 1 : 1
The mid-point is equidistant from both ends, so it divides the segment in the ratio 1 : 1.
The distance of a point P ( 3 , − 7 ) from y-axis is :
(A) 3(B) 7(C) − 7 (D) 58
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Answer: (A) 3
The distance of a point ( x , y ) from the y-axis is ∣ x ∣ , so the distance is ∣3∣ = 3 .
For a point X ( a , b ) where ( b > a > 0 ) , the value of its [distance from x-axis − distance from y-axis] is :
(A) a − b (B) b − a (C) a 2 − b 2 (D) b 2 − a 2
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Answer: (B) b − a
Distance of ( a , b ) from the x-axis = b ; from the y-axis = a (both positive). Required value = b − a .
The distance of the point (2, 3) from the origin is :
(A) 2 (B) 3 (C) 5 (D) 13
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Distance = 2 2 + 3 2 = 4 + 9 = 13 .
The mid-point of the line segment joining points (1, 3) and (1, − 3 ) lies :
(A) at the origin(B) in the second quadrant(C) on x-axis(D) on y-axis
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Answer: (C) on x-axis
Mid-point = ( 2 1 + 1 , 2 3 + ( − 3 ) ) = ( 1 , 0 ) . Its y-coordinate is 0, so it lies on the x-axis.
If point ( 1 , 2 ) is the mid-point of the line segment joining the points ( 3 , 5 ) and ( 2 a , b ) , then ( a , b ) =
(A) ( − 1 , − 1 ) (B) ( − 2 1 , − 2 1 ) (C) ( − 2 1 , − 1 ) (D) ( − 1 , − 2 1 )
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Answer: (C) ( − 2 1 , − 1 )
Mid-point: 2 3 + 2 a = 1 and 2 5 + b = 2 . 3 + 2 a = 2 ⇒ a = − 2 1 .5 + b = 4 ⇒ b = − 1 .
The distance of point ( − 3 , 4 ) from y-axis is :
(A) − 3 (B) 3(C) 4(D) 5
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Answer: (B) 3
Distance of a point ( x , y ) from the y-axis is ∣ x ∣ . ∣ − 3∣ = 3 .
If point ( 1 , 2 ) divides the line segment joining the points ( 3 , 5 ) and ( 2 p , q ) in the ratio 1 : 1 , then ( p , q ) is equal to :
(A) ( − 2 1 , − 1 ) (B) ( − 2 1 , − 2 1 ) (C) ( − 1 , − 1 ) (D) ( − 1 , − 2 1 )
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Answer: (A) ( − 2 1 , − 1 )
Ratio 1 : 1 means ( 1 , 2 ) is the mid-point. 2 3 + 2 p = 1 ⇒ 2 p = − 1 ⇒ p = − 2 1 .2 5 + q = 2 ⇒ q = − 1 .
If point ( a , 2 b ) is the mid-point of the line segment joining the points ( 3 , 5 ) and ( − 1 , − 1 ) , then ( a , b ) is equal to :
(A) ( 1 , 2 ) (B) ( 2 , 2 ) (C) ( 2 , 1 ) (D) ( 1 , 1 )
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Answer: (D) ( 1 , 1 )
Mid-point = ( 2 3 + ( − 1 ) , 2 5 + ( − 1 ) ) = ( 1 , 2 ) . So a = 1 and 2 b = 2 ⇒ b = 1 . ( a , b ) = ( 1 , 1 ) .
The distance between the points ( − 6 , 9 ) and ( 2 , 7 ) is :
(A) 2 17 (B) 4 17 (C) 2 5 (D) 2 15
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Distance = ( 2 + 6 ) 2 + ( 7 − 9 ) 2 = 64 + 4 = 68 . 68 = 2 17 .
The distance between the points ( 2 , − 7 ) and ( − 2 , − 1 ) is :
(A) 10(B) 2 13 (C) 8(D) 4 13
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Distance = ( − 2 − 2 ) 2 + ( − 1 + 7 ) 2 = 16 + 36 = 52 = 2 13 .
The distance between the points (2, 3) and (–2, –3) is
(A) 4 13 (B) 40 (C) 2 13 (D) 5
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Distance = ( 2 − ( − 2 ) ) 2 + ( 3 − ( − 3 ) ) 2 = 16 + 36 = 52 . 52 = 2 13 .
The point (x , 0) divides the line segment joining the points (–4, 5) and (0, –10) in the ratio
(A) 1 : 3(B) 2 : 1(C) 1 : 1(D) 1 : 2
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Answer: (D) 1 : 2
Let the ratio be k : 1 . y-coordinate: k + 1 k ( − 10 ) + 1 ( 5 ) = 0 , so − 10 k + 5 = 0 and k = 2 1 . Ratio = 2 1 : 1 = 1 : 2 .
If the distance between the points (3, 0) and (2, y) is 5 , then the value(s) of y is :
(A) 2, –2(B) 2, 0(C) 2, 1(D) –2, 0
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Answer: (A) 2, –2
( 3 − 2 ) 2 + ( 0 − y ) 2 = ( 5 ) 2 .1 + y 2 = 5 , so y 2 = 4 and y = 2 or − 2 .
ABCD is a rectangle with its vertices at (2, − 2 ), (8, 4), (4, 8) and (− 2 , 2) taken in order. Length of its diagonal is
(A) 4 2 (B) 6 2 (C) 4 26 (D) 2 26
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Diagonal AC joins (2, − 2 ) and (4, 8). AC = ( 4 − 2 ) 2 + ( 8 + 2 ) 2 = 4 + 100 = 104 = 2 26 .
The mid-point of the line segment joining the points P ( − 4 , 5 ) and Q ( 4 , 6 ) lies on :
(A) x-axis(B) y-axis(C) origin(D) neither x-axis nor y-axis
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Answer: (B) y-axis
Mid-point = ( 2 − 4 + 4 , 2 5 + 6 ) = ( 0 , 2 11 ) . Its x-coordinate is 0 , so it lies on the y-axis.
The end points of a diameter of circle are ( 2 , 4 ) and ( − 3 , − 1 ) . The length of its radius is :
(A) 2 5 2 units(B) 5 2 units(C) 3 2 units(D) ± 2 5 2 units
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Diameter = ( 2 + 3 ) 2 + ( 4 + 1 ) 2 = 25 + 25 = 5 2 units. Radius = 2 5 2 units (a length cannot be negative).
The coordinates of the end points of a diameter of a circle are ( 5 , − 2 ) and ( 5 , 2 ) . The length of the radius of the circle is :
(A) ± 2 (B) ± 4 (C) 4(D) 2
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Answer: (D) 2
Diameter = ( 5 − 5 ) 2 + ( 2 − ( − 2 ) ) 2 = 16 = 4 Radius = 2 4 = 2 (a length cannot be negative)
The points ( − 5 , 0 ) , ( 5 , 0 ) and ( 0 , 4 ) are the vertices of a triangle which is a/an :
(A) right-angled triangle(B) isosceles triangle(C) equilateral triangle(D) scalene triangle
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Answer: (B) isosceles triangle
Let A ( − 5 , 0 ) , B ( 5 , 0 ) , C ( 0 , 4 ) A B = 10 , A C = 25 + 16 = 41 , B C = 25 + 16 = 41 A C = B C = A B , and 41 + 41 = 100 , 41 + 100 = 41 , so it is not right-angledThe triangle is isosceles
The perimeter of the triangle formed by the vertices ( 0 , 0 ) , ( 2 , 0 ) and ( 0 , 2 ) is :
(A) 4 units(B) 6 units(C) 6 2 units(D) ( 4 + 2 2 ) units
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Answer: (D)
( 4 + 2 2 ) units
Sides: from ( 0 , 0 ) to ( 2 , 0 ) is 2; from ( 0 , 0 ) to ( 0 , 2 ) is 2 From ( 2 , 0 ) to ( 0 , 2 ) : 4 + 4 = 2 2 Perimeter = 2 + 2 + 2 2 = ( 4 + 2 2 ) units
The line represented by 4 x + 6 y = 1 , intersects x-axis and y-axis respectively at P and Q. The coordinates of the mid-point of line segment PQ are :
(A) ( 2 , 3 ) (B) ( 3 , 2 ) (C) ( 2 , 0 ) (D) ( 0 , 3 )
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Answer: (A) ( 2 , 3 )
On the x-axis y = 0 , so x = 4 : P ( 4 , 0 ) . On the y-axis x = 0 , so y = 6 : Q ( 0 , 6 ) . Mid-point = ( 2 4 + 0 , 2 0 + 6 ) = ( 2 , 3 ) .
Two of the vertices of △ P QR are P ( − 1 , 5 ) and Q ( 5 , 2 ) . The coordinates of a point which divides PQ in the ratio 2 : 1 are :
(A) ( 3 , − 3 ) (B) ( 5 , 5 ) (C) ( 3 , 3 ) (D) ( 5 , 1 )
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Answer: (C) ( 3 , 3 )
Using the section formula with m : n = 2 : 1 : x = 3 2 ( 5 ) + 1 ( − 1 ) = 3 9 = 3 .y = 3 2 ( 2 ) + 1 ( 5 ) = 3 9 = 3 .The point is ( 3 , 3 ) .
AOBC is a rectangle whose three vertices are A ( 0 , 2 ) , O ( 0 , 0 ) and B ( 4 , 0 ) . The square of the length of its diagonal is equal to :
(A) 36(B) 20(C) 16(D) 4
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Answer: (B) 20
Diagonal AB joins A ( 0 , 2 ) and B ( 4 , 0 ) . A B 2 = ( 4 − 0 ) 2 + ( 0 − 2 ) 2 = 16 + 4 = 20 .
If the mid-point of the line segment joining the points ( a , 4 ) and ( 2 , 2 b ) is ( 2 , 6 ) , then the value of ( a + b ) is given by :
(A) 6(B) 7(C) 8(D) 16
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Answer: (A) 6
2 a + 2 = 2 , so a = 2 .2 4 + 2 b = 6 , so b = 4 .a + b = 6 .
The distance of the point ( 4 , 0 ) from x-axis is :
(A) 4 units(B) 16 units(C) 0 units(D) 4 2 units
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Answer: (C) 0 units
The distance of a point ( x , y ) from the x-axis is ∣ y ∣ . For ( 4 , 0 ) it is 0 units; the point lies on the x-axis.
The distance of a point A from x -axis is 3 units. Which of the following cannot be coordinates of the point A ?
(A) ( 1 , 3 ) (B) ( − 3 , − 3 ) (C) ( − 3 , 3 ) (D) ( 3 , 1 )
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Answer: (D) ( 3 , 1 )
Distance of ( x , y ) from the x -axis is ∣ y ∣ , so ∣ y ∣ = 3 . ( 1 , 3 ) , ( − 3 , − 3 ) , ( − 3 , 3 ) all have ∣ y ∣ = 3 ; ( 3 , 1 ) has ∣ y ∣ = 1 .
The distance of which of the following points from origin is less than 5 units ?
(A) ( 3 , 4 ) (B) ( 2 , 6 ) (C) ( − 3 , − 4 ) (D) ( 1 , 4 )
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Answer: (D) ( 1 , 4 )
Distance from origin = x 2 + y 2 ( 3 , 4 ) : 5; ( 2 , 6 ) : 40 ; ( − 3 , − 4 ) : 5; ( 1 , 4 ) : 17 < 5
The distance of point P ( 1 , − 1 ) from x -axis is :
(A) 1(B) − 1 (C) 0(D) 2
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Answer: (A) 1
Distance of ( x , y ) from the x -axis = ∣ y ∣ = ∣ − 1∣ = 1
In the figure given below, points P, Q, R divides the line segment AB in four equal parts. The point Q divides PB in the ratio
(A) 1 : 3(B) 2 : 3(C) 1 : 2(D) 1 : 1
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Answer: (C) 1 : 2
Let each part be k . Then P Q = k and QB = QR + R B = 2 k . P Q : QB = 1 : 2
The point P divides the line segment AB in the ratio 3 : 1 as shown below : The value of P B A B is
(A) 3(B) 4 1 (C) 4(D) 3 1
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Answer: (C) 4
A P : P B = 3 : 1 ; let A P = 3 k , P B = k .A B = 4 k , so P B A B = k 4 k = 4
In the following figure, P and Q are points of trisection of line segment AB : the value of P B A B =
(A) 1(B) 1.5(C) 3 2 (D) 2
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Answer: (B) 1.5
A P = P Q = QB = k , so A B = 3 k and P B = 2 k .P B A B = 2 k 3 k = 1.5
The distance of the point A ( − 3 , − 4 ) from x -axis is
(A) 3(B) 4(C) 5(D) 7
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Answer: (B) 4
Distance of a point ( x , y ) from the x -axis is ∣ y ∣ . For A ( − 3 , − 4 ) , distance = ∣ − 4∣ = 4 units.
The distance of point ( a , − b ) from x -axis is
(A) a(B) − a (C) b(D) − b
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Answer: (C) b
Distance of a point ( x , y ) from the x -axis is ∣ y ∣ . For ( a , − b ) , distance = ∣ − b ∣ = ∣ b ∣ , which is b when b > 0 .
The distance of point P ( 3 a , 4 a ) from y -axis is
(A) 3a(B) − 3 a (C) 4a(D) − 4 a
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Answer: (A) 3a
Distance of a point ( x , y ) from the y -axis is ∣ x ∣ . For P ( 3 a , 4 a ) , distance = ∣3 a ∣ , which is 3 a when a > 0 .
The distance between the points ( 2 , − 3 ) and ( − 2 , 3 ) is :
(A) 2 13 units(B) 5 units(C) 13 2 units(D) 10 units
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Distance = ( 2 + 2 ) 2 + ( − 3 − 3 ) 2 = 16 + 36 = 52 = 2 13 units.
The diameter of a circle is of length 6 cm. If one end of the diameter is ( − 4 , 0 ) , the other end on x-axis is at :
(A) (0, 2)(B) (6, 0)(C) (2, 0)(D) (4, 0)
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Answer: (C) (2, 0)
The other end is ( x , 0 ) with ∣ x − ( − 4 ) ∣ = 6 . So x = 2 or x = − 10 ; of the options only ( 2 , 0 ) fits.
The mid-point of the line segment joining the points ( − 1 , 3 ) and ( 8 , 2 3 ) is :
(A) ( 2 7 , − 4 3 ) (B) ( 2 7 , 2 9 ) (C) ( 2 9 , − 4 3 ) (D) ( 2 7 , 4 9 )
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Answer: (D) ( 2 7 , 4 9 )
Mid-point = ( 2 − 1 + 8 , 2 3 + 2 3 ) = ( 2 7 , 4 9 ) .
The distance of the point (5, 4) from the origin is
(A) 41(B) 41 (C) 3(D) 9
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Distance = 5 2 + 4 2 = 25 + 16 = 41
Assertion (A) : The point (0, 4) lies on y – axis. Reason (R) : The x -coordinate of a point, lying on y – axis, is zero.
(A) Both Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A).(B) Both Assertion (A) and Reason (R) are correct but Reason (R) is not the correct explanation of Assertion (A).(C) Assertion (A) is true, but Reason (R) is false.(D) Assertion (A) is false, but Reason (R) is true.
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Answer: (A) Both Assertion (A) and Reason (R) are correct and Reason (R) is the correct explanation of Assertion (A).
Every point on the y-axis has x -coordinate 0, so R is true. The point (0, 4) has x -coordinate 0, so it lies on the y-axis; A is true. R explains A. Answer: (A)
The distance of the point (3, 4) from the origin is
(A) 25(B) 5(C) 7(D) 1
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Answer: (B) 5
Distance = 3 2 + 4 2 = 25 = 5
The distance between the points A ( − 1 , 5 ) and B ( 6 , − 2 ) is :
(A) 2 7 (B) 7 2 (C) 49(D) 14
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A B = ( 6 + 1 ) 2 + ( − 2 − 5 ) 2 = 49 + 49 .A B = 98 = 7 2 .
Assertion (A) : The distance of P ( a , b ) from origin is a 2 + b 2 . Reason (R) : The distance between two points A ( x 1 , y 1 ) and B ( x 2 , y 2 ) is ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 .
(A) Both Assertion (A) and Reason (R) are true. Reason (R) is the correct explanation of Assertion (A).(B) Both Assertion (A) and Reason (R) are true. Reason (R) is not the correct explanation of Assertion (A).(C) Assertion (A) is true, but Reason (R) is false.(D) Assertion (A) is false, but Reason (R) is true.
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Answer: (D) Assertion (A) is false, but Reason (R) is true.
By the distance formula (R is true), O P = ( a − 0 ) 2 + ( b − 0 ) 2 = a 2 + b 2 . This is not a 2 + b 2 in general, so A is false.
The distance between the points A ( 5 , − 4 ) and B ( 4 , − 5 ) is
(A) 2 units(B) 2 units(C) 1 unit(D) 9 2 units
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A B = ( 4 − 5 ) 2 + ( − 5 + 4 ) 2 = 1 + 1 .A B = 2 units.
If the distances of the point P ( x , y ) from (1, 0) and (0, 1) are equal, then which of the following is true ?
(A) x + y = 0 (B) x = y + 1 (C) y = x + 1 (D) x = y
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Answer: (D) x = y
( x − 1 ) 2 + y 2 = x 2 + ( y − 1 ) 2 − 2 x + 1 = − 2 y + 1 , so x = y .
The distance between the points ( 2 , − 1 ) and ( − 1 , − 5 ) is :
(A) 15 units(B) 5 units(C) 25 units(D) 41 units
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Answer: (B) 5 units
Distance = ( − 1 − 2 ) 2 + ( − 5 + 1 ) 2 = 9 + 16 = 25 = 5 units.
If C ( 1 , − 1 ) is the mid-point of the line segment AB joining points A ( 4 , x ) and B ( − 2 , 4 ) , then value of x is :
(A) 5 (B) − 5 (C) 6 (D) − 6
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Answer: (D) − 6
Mid-point of AB has y-coordinate 2 x + 4 . 2 x + 4 = − 1 ⇒ x + 4 = − 2 ⇒ x = − 6 .
The distance of the point ( 4 , 5 ) from x-axis is :
(A) 5(B) 4(C) 9(D) 1
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Answer: (A) 5
The distance of a point from the x-axis is the absolute value of its y-coordinate. So the distance is 5.
The midpoint of the line segment joining the points ( − 6 , − 4 ) and ( 0 , 4 ) is :
(A) ( − 6 , 0 ) (B) ( − 3 , 0 ) (C) ( − 6 , 8 ) (D) ( − 6 , 4 )
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Answer: (B) ( − 3 , 0 )
Mid-point = ( 2 − 6 + 0 , 2 − 4 + 4 ) = ( − 3 , 0 ) .
The mid-point of the line segment AB joining A ( − 2 , 8 ) and B ( − 6 , 4 ) is :
(A) (2, 6)(B) ( − 4 , 12 ) (C) ( − 4 , 6 ) (D) ( 4 , − 6 )
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Answer: (C) ( − 4 , 6 )
Mid-point = ( 2 − 2 + ( − 6 ) , 2 8 + 4 ) . = ( − 4 , 6 ) .
AD is a median of △ A B C with vertices A( 5 , − 6 ) , B( 6 , 4 ) and C( 0 , 0 ) . Length AD is equal to :
(A) 68 units(B) 2 15 units(C) 101 units(D) 10 units
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D is the mid-point of BC: D = ( 2 6 + 0 , 2 4 + 0 ) = ( 3 , 2 ) . A D = ( 5 − 3 ) 2 + ( − 6 − 2 ) 2 = 4 + 64 = 68 units.
If the distance between the points ( 3 , − 5 ) and ( x , − 5 ) is 15 units, then the values of x are :
(A) 12 , − 18 (B) − 12 , 18 (C) 18, 5(D) − 9 , − 12
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Answer: (B) − 12 , 18
Distance = ( x − 3 ) 2 + 0 2 = ∣ x − 3∣ = 15 . So x − 3 = ± 15 , giving x = 18 or x = − 12 .
The centre of a circle is at ( 2 , 0 ) . If one end of a diameter is at ( 6 , 0 ) , then the other end is at :
(A) (0, 0)(B) (4, 0)(C) ( − 2 , 0 ) (D) ( − 6 , 0 )
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Answer: (C) ( − 2 , 0 )
The centre is the mid-point of the diameter. Let the other end be ( x , y ) . 2 6 + x = 2 gives x = − 2 ; 2 0 + y = 0 gives y = 0 .Other end = ( − 2 , 0 ) .
Point P divides the line segment joining the points A(4, − 5 ) and B(1, 2) in the ratio 5:2. Co-ordinates of point P are
(A) ( 2 5 , 2 − 3 ) (B) ( 7 11 , 0 ) (C) ( 7 13 , 0 ) (D) ( 0 , 7 13 )
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Answer: (C) ( 7 13 , 0 )
By the section formula with m 1 : m 2 = 5 : 2 : x = 5 + 2 5 ( 1 ) + 2 ( 4 ) = 7 13 y = 7 5 ( 2 ) + 2 ( − 5 ) = 7 0 = 0 So P is ( 7 13 , 0 ) .
XOYZ is a rectangle with vertices X(− 3 , 0), O(0, 0), Y(0, 4) and Z(x , y). The length of its each diagonal is
(A) 5 units(B) 5 units(C) x 2 + y 2 units(D) 4 units
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Answer: (A) 5 units
The diagonals of a rectangle are equal, so each diagonal = XY. X Y = ( 0 + 3 ) 2 + ( 4 − 0 ) 2 = 9 + 16 = 5 units
The distance between the points ( a cos θ , − a sin θ ) and ( a sin θ , a cos θ ) is
(A) a(B) a 2 (C) 0(D) 2a
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d 2 = ( a sin θ − a cos θ ) 2 + ( a cos θ + a sin θ ) 2 = a 2 [( sin θ − cos θ ) 2 + ( sin θ + cos θ ) 2 ] = a 2 × 2 ( sin 2 θ + cos 2 θ ) = 2 a 2 d = a 2
Assertion (A) : The point which divides the line segment joining the points A (1, 2) and B(− 1 , 1) internally in the ratio 1 : 2 is ( 3 − 1 , 3 5 ) Reason (R) : The coordinates of the point which divides the line segment joining the points A (x 1 , y 1 ) and B(x 2 , y 2 ) in the ratio m 1 : m 2 are ( m 1 + m 2 m 1 x 2 + m 2 x 1 , m 1 + m 2 m 1 y 2 + m 2 y 1 )
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).(C) Assertion (A) is true, but Reason (R) is false.(D) Assertion (A) is false, but Reason (R) is true.
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Answer: (D) Assertion (A) is false, but Reason (R) is true.
Reason is the section formula, so R is true. Using it with m 1 : m 2 = 1 : 2 : x = 3 1 ( − 1 ) + 2 ( 1 ) = 3 1 , y = 3 1 ( 1 ) + 2 ( 2 ) = 3 5 . The point is ( 3 1 , 3 5 ) , not ( 3 − 1 , 3 5 ) , so A is false. Answer: (D).
The fourth vertex D of a parallelogram ABCD whose three vertices are A(− 2 , 3), B(6, 7) and C(8, 3) is :
(A) (0, 1)(B) (0, − 1 )(C) (− 1 , 0)(D) (1, 0)
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Answer: (B) (0, − 1 )
Diagonals of a parallelogram bisect each other, so midpoint of AC = midpoint of BD. Midpoint of AC = ( 2 − 2 + 8 , 2 3 + 3 ) = ( 3 , 3 ) . 2 6 + x = 3 gives x = 0 ; 2 7 + y = 3 gives y = − 1 .D = (0, − 1 ).
Assertion (A) : Mid-point of a line segment divides the line segment in the ratio 1 : 1. Reason (R) : The ratio in which the point (− 3 , k) divides the line segment joining the points (− 5 , 4) and (− 2 , 3) is 1 : 2.
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).(C) Assertion (A) is true, but Reason (R) is false.(D) Assertion (A) is false, but Reason (R) is true.
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Answer: (C) Assertion (A) is true, but Reason (R) is false.
Assertion: the mid-point is equidistant from both ends, so the ratio is 1 : 1. True. Reason: let the ratio be m : n . Using x-coordinates, m + n m ( − 2 ) + n ( − 5 ) = − 3 . − 2 m − 5 n = − 3 m − 3 n gives m = 2 n , so the ratio is 2 : 1, not 1 : 2. False.A is true, R is false.
The distance between the points ( 3 , 0 ) and ( 0 , − 3 ) is
(A) 2 3 units(B) 6 units(C) 3 units(D) 3 2 units
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Distance = ( 0 − 3 ) 2 + ( − 3 − 0 ) 2 = 9 + 9 = 18 = 3 2 units
The distance between the points ( 2 − 5 , 7 ) and ( 2 − 1 , 7 ) is :
(A) 3(B) 2(C) 4(D) 9
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Answer: (B) 2
Both points have the same y-coordinate 7, so the distance is the difference of the x-coordinates. Distance = − 2 1 − ( − 2 5 ) = 2 4 = 2
In what ratio does x-axis divide the line segment joining the points A ( 2 , − 3 ) and B ( 5 , 6 ) ?
(A) 2 : 3(B) 2 : 1(C) 3 : 4(D) 1 : 2
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Answer: (d) 1 : 2
Let the x-axis divide AB in the ratio k : 1. y-coordinate of the point = k + 1 6 k − 3 = 0 6 k = 3 , so k = 2 1 Ratio = 1 : 2
y-axis divides the line segment joining the points ( − 6 , 2 ) and ( 2 , − 6 ) in the ratio :
(A) 1 : 3(B) 3 : 2(C) 3 : 1(D) 2 : 3
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Answer: (c) 3 : 1
Let the y-axis divide the segment in the ratio k : 1. x-coordinate of the point = k + 1 2 k − 6 = 0 2k = 6, so k = 3 Ratio = 3 : 1
The distance between the points A(0, 6) and B(− 6, 2) is :
(A) 6 units(B) 2 6 units(C) 2 13 units(D) 13 2 units
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AB = ( − 6 − 0 ) 2 + ( 2 − 6 ) 2 = 36 + 16 = 52 . 52 = 2 13 units.
The distance between the points (6, 2) and (− 6, 2) is :
(A) 6 2 units(B) 12 units(C) 2 6 units(D) 6 units
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Answer: (B) 12 units
Distance = ( 6 − ( − 6 ) ) 2 + ( 2 − 2 ) 2 = 144 = 12 units.
The distance of the point (5, 0) from the origin is
(A) 0(B) 5(C) 5 (D) 5 2
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Answer: (B) 5
Distance = ( 5 − 0 ) 2 + ( 0 − 0 ) 2 = 25 = 5 .
If (2, 4) is the mid-point of the line-segment joining (6, 3) and (a, 5), then the value of a is
(A) 2(B) 4(C) − 4 (D) − 2
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Answer: (D) − 2
2 6 + a = 2 , so 6 + a = 4 and a = − 2 .(Check: 2 3 + 5 = 4 .)
Distance of the point (6, 5) from the y-axis is
(A) 6 units(B) 5 units(C) 61 units(D) 0 unit
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Answer: (A) 6 units
The distance of a point from the y-axis is the absolute value of its x-coordinate. Distance = 6 units.
In what ratio, does x-axis divide the line segment joining the points A(3, 6) and B(–12, –3) ?
(A) 1 : 2(B) 1 : 4(C) 4 : 1(D) 2 : 1
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Answer: (D) 2 : 1
Let the x-axis divide AB in the ratio k : 1. y-coordinate of the point = k + 1 k ( − 3 ) + 1 ( 6 ) = 0 . − 3 k + 6 = 0 , so k = 2 .Ratio = 2 : 1
The distance between the points ( 0 , 2 5 ) and ( − 2 5 , 0 ) is
(A) 2 10 units(B) 4 10 units(C) 2 20 units(D) 0
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Distance = ( − 2 5 − 0 ) 2 + ( 0 − 2 5 ) 2 = 20 + 20 = 40 = 2 10 units
Assertion (A) : Point P(0, 2) is the point of intersection of y-axis with the line 3 x + 2 y = 4 . Reason (R) : The distance of point P(0, 2) from x-axis is 2 units.
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).(B) Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).(C) Assertion (A) is true but Reason (R) is false.(D) Assertion (A) is false but Reason (R) is true.
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Answer: (B) Both A and R are true but R is not the correct explanation of A.
On the y-axis x = 0, so 2 y = 4 , y = 2. The line meets the y-axis at (0, 2). A is true. Distance of (0, 2) from the x-axis = |y| = 2 units. R is true. R does not explain why (0, 2) lies on the line, so R is not the correct explanation of A.
The end-points of a diameter of a circle are (2, 4) and (–3, –1). The radius of the circle is
(A) 2 5 (B) 2 5 5 (C) 2 5 2 (D) 5 2
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Diameter = ( 2 + 3 ) 2 + ( 4 + 1 ) 2 = 50 = 5 2 . Radius = 2 5 2 = 2 5 2
The coordinates of the vertex A of a rectangle ABCD whose three vertices are given as B(0, 0), C(3, 0) and D(0, 4) are :
(A) (4, 0)(B) (0, 3)(C) (3, 4)(D) (4, 3)
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Answer: (C) (3, 4)
BC lies along the x-axis and BD along the y-axis, so the right angle at B is between BC and BD. The fourth vertex A is opposite B, so the diagonals are AB and CD and they bisect each other. Midpoint of CD = ( 2 3 , 2 ) , so A = ( 2 × 2 3 − 0 , 2 × 2 − 0 ) = ( 3 , 4 ) .
The area of the triangle formed by the line a x + b y = 1 with the coordinate axes is :
(A) ab (B) 2 1 ab (C) 4 1 ab (D) 2 ab
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Answer: (B) 2 1 ab
The line meets the x-axis at ( a , 0 ) and the y-axis at ( 0 , b ) . The triangle with the origin is right-angled with legs a and b . Area = 2 1 ab
The ratio in which the x-axis divides the line segment joining the points ( − 2 , 3 ) and ( 6 , − 7 ) is :
(A) 1 : 3(B) 3 : 7(C) 7 : 3(D) 1 : 2
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Answer: (B) 3 : 7
Let the ratio be k : 1 . The point on the x-axis has y-coordinate 0. k + 1 − 7 k + 3 = 0 ⇒ k = 7 3 Ratio = 3 : 7
The distance of the point ( − 1 , 7 ) from x-axis is :
(A) − 1 (B) 7(C) 6(D) 50
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Answer: (B) 7
Distance of a point ( x , y ) from the x-axis is ∣ y ∣ . For ( − 1 , 7 ) it is ∣7∣ = 7 .
The distance of the point ( − 6 , 8 ) from origin is :
(A) 6(B) − 6 (C) 8(D) 10
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Answer: (D) 10
Distance = ( − 6 ) 2 + 8 2 = 36 + 64 = 100 = 10
The points ( − 4 , 0 ) , ( 4 , 0 ) and ( 0 , 3 ) are the vertices of a :
(A) right triangle(B) isosceles triangle(C) equilateral triangle(D) scalene triangle
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Answer: (B) isosceles triangle
Let A( − 4 , 0 ) , B( 4 , 0 ) , C( 0 , 3 ) . AB = 8, AC = 16 + 9 = 5 , BC = 16 + 9 = 5 Two sides are equal (and 5 2 + 5 2 = 8 2 ), so it is an isosceles triangle.
The distance between the points P ( − 3 11 , 5 ) and Q ( − 3 2 , 5 ) is :
(A) 6 units(B) 4 units(C) 2 units(D) 3 units
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Answer: (D) 3 units
Both points have y-coordinate 5, so PQ = − 3 2 − ( − 3 11 ) = 3 9 = 3 units.
Assertion (A) : If the points A(4, 3) and B(x, 5) lie on a circle with centre O(2, 3), then the value of x is 2. Reason (R) : Centre of a circle is the mid-point of each chord of the circle.
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).(C) Assertion (A) is true, but Reason (R) is false.(D) Assertion (A) is false, but Reason (R) is true.
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Answer: (C) Assertion (A) is true, but Reason (R) is false.
OA = ( 4 − 2 ) 2 + 0 2 = 2 . OB = OA: ( x − 2 ) 2 + ( 5 − 3 ) 2 = 4 , so ( x − 2 ) 2 = 0 , x = 2. A is true. The centre is the mid-point only of a diameter, not of every chord. R is false.
If end points of a diameter of a circle are ( − 5 , 4 ) and ( 1 , 0 ) , then the radius of the circle is :
(A) 2 13 units(B) 13 units(C) 4 2 units(D) 2 2 units
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Diameter = ( 1 + 5 ) 2 + ( 0 − 4 ) 2 = 36 + 16 = 52 = 2 13 units. Radius = 13 units.
The distance of the point (– 6, 8) from x-axis is
(A) 6 units(B) – 6 units(C) 8 units(D) 10 units
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Answer: (C) 8 units
The distance of a point (x, y) from the x-axis is |y|. For (–6, 8) it is 8 units.
The distance of the point (– 4, 3) from y-axis is
(A) – 4(B) 4(C) 3(D) 5
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Answer: (B) 4
The distance of a point (x, y) from the y-axis is |x|. For (–4, 3) it is 4 units.
The distance between the points (0, 5) and (–3, 1) is :
(A) 8 units(B) 5 units(C) 3 units(D) 25 units
Show answer & solution
Answer: (B) 5 units
Distance = ( − 3 − 0 ) 2 + ( 1 − 5 ) 2 = 9 + 16 = 5 units
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